TẠP CHÍ KHOA HỌC −−− SỐ 31/2019 1
TR¦êNG §¹I HäC thñ ®« hµ néi Hanoi Metropolitan university
Tạp chí
SCIENCE JOURNAL OF HANOI METROPOLITAN UNIVERSITY
ISSN 2354-1504
Số 31 − khoa häc tù nhiªn vµ c«ng nghÖ
th¸ng 5 −−− 2019
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T¹P CHÝ KHOA HäC TR¦êNG §¹I HäC THñ §¤ Hµ NéI SCIENTIFIC JOURNAL OF HANOI METROPOLITAN UNIVERSITY (Tạp chí xu ất b ản đị nh kì 1 tháng/s ố)
Tæng Biªn tËp Editor-in-Chief §Æng V¨n Soa Dang Van Soa
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Héi đång Biªn tËp Editorial Board Bïi V¨n Qu©n Bui Van Quan §Æng Thµnh H−ng Dang Thanh Hung NguyÔn M¹nh Hïng Nguyen Manh Hung NguyÔn Anh TuÊn Nguyen Anh Tuan Ch©u V¨n Minh Chau Van Minh NguyÔn V¨n M· Nguyen Van Ma §ç Hång C−êng Do Hong Cuong NguyÔn V¨n C− Nguyen Van Cu Lª Huy B¾c Le Huy Bac Ph¹m Quèc Sö Pham Quoc Su NguyÔn Huy Kû Nguyen Huy Ky §Æng Ngäc Quang Dang Ngoc Quang NguyÔn ThÞ BÝch Hµ Nguyen Thi Bich Ha NguyÔn ¸i ViÖt Nguyen Ai Viet Ph¹m V¨n Hoan Pham Van Hoan Lª Huy Hoµng Le Huy Hoang
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GiÊy phÐp ho¹t ®éng b¸o chÝ sè 571/GP-BTTTT cÊp ngµy 26/10/2015 In 200 cuèn t¹i Tr−êng §H Thñ ®« Hµ Néi. In xong vµ nép l−u chiÓu th¸ng 5/2019
TẠP CHÍ KHOA HỌC −−− SỐ 31/2019 3
MỤC L ỤC Trang
1. EQUIVALENCE RELATIONS AND THE APPLICATION OF EQUIVALENCE RELATIONS IN TEACHING FRACTIONS IN PRIMARY ...... 5 Quan h ệ tươ ng đươ ng và ứng d ụng c ủa quan h ệ tươ ng đươ ng trong d ạy h ọc phân s ố ở Tiểu h ọc Nguyen Van Hao, Nguyen Thi Thu Hang, Dao Thi Ngoc Bich
2. A ALGORITHM FOR SOLVING A SEPTADIAGONAL LINEAR SYSTEMS ...... 12 Thu ật toán gi ải h ệ ph ươ ng trình tuy ến tính b ảy đường chéo Nguyen Thi Thu Hoa
3. WEIGHTED MULTILINEAR HARDY-CESÀRO OPERATORS ON SPACES OF HERZ TYPES ...... 20 Toán t ử đa tuy ến tính Hardy-cesàro trên các không gian ki ểu Herz Nguyen Thi Hong
4. APPLYING LINEAR RELATIONSHIPS IN VECTOR SPACES TO SOLVE THE PROBLEM CLASS ABOUT INCIDENCE IN PROJECTIVE SPACE ...... 36 Mối liên h ệ tuy ến tính trong không gian véc t ơ ứng d ụng gi ải các bài toán v ề sự liên thu ộc trong không gian x ạ ảnh Hoang Ngoc Tuyen
5. SEPTIC B – SPLINE COLLOCATION METHOD FOR NUMERICAL SOLUTION OF THE mGRLW EQUATION ...... 51 Ph ươ ng pháp collocation v ới B – spline b ậc 7 gi ải ph ươ ng trình mGRLW Nguyen Van Tuan
6. APPLICATIONS COMBINATORIAL THEORY IN TEACHING MATHS AT PRIMARY SCHOOLS ...... 62 Ứng d ụng lí thuy ết t ổ hợp trong d ạy h ọc toán Tiểu h ọc Dao Thi To Uyen, Nguyen Van Hao
7. RADION EFFECTS ON BHABHA SCATTERING ...... 68 Ảnh h ưởng c ủa radion lên tán x ạ Bhabha Ha Huy Bang, Pham Que Duong, Nguyen Thi Thu Huyen, Nguyen Thi Thuy Linh
8. INTERACTION ENERGY BETWEEN ELECTRONS AND LONGITUDINAL OPTICAL PHONON IN POLARIZED SEMICONDUCTOR QUANTUM WIRES ...... 74 Năng l ượng t ươ ng tác gi ữa Electrons và Phonon quang d ọc trong dây l ượng t ử bán d ẫn phân c ực Dang Tran Chien
9. POWER OF THE CONTROLLER IN CONTROLLED JOINT REMOTE STATE PREPARATION OF AN ARBITRARY QUBIT STATE ...... 85 Quy ền l ực c ủa ng ười điều khi ển trong đồng vi ễn t ạo tr ạng thái l ượng t ử một qubit b ất kì có điều khi ển Nguyen Van Hop
4 TRƯỜNG ĐẠI HỌC THỦ ĐÔ H NỘI
10. APPLICATION OF ORIGIN SOFTWARE TO RESEARCH FLUORESCE EMISSION SPECTRUM DATA ...... 93 Ứng d ụng ph ần m ềm Origin trong nghiên c ứu s ố li ệu ph ổ phát x ạ hu ỳnh quang Ho Xuan Huy
11. THE HEAT CAPACITY Cv OF THE SYSTEM OF THE q - DEFORMED HARMONIC OSCILLARORS ...... 101 Nhi ệt dung Cv c ủa h ệ các dao động t ử điều hòa bi ến d ạng q Luu Thi Kim Thanh, Man Van Ngu
12. QUANTUM THEORY OF ABSORPTION OF ELECTROMAGNETIC WAVE IN TWO - DIMENSIONAL GRAPHENE ...... 107 Lý thuy ết l ượng tử h ấp th ụ sóng điện t ừ trong Graphene hai chi ều Nguyen Vu Nhan, Tran Anh Tuan, Do Tuan Long, Nguyen Quang Bau
13. THE FIRST STEP TO ISOLATE AND DETERMINE THE STRUCTURE OF SOME ORGANIC COMPOUNDS OF THE TICH DUONG MUSHROOMS (RHOPALOCNEMIS PHALLOIDES JUNGHUN) COLLECTED IN SON LA ...... 117 Bước đầu phân l ập và xác định c ấu trúc m ột s ố hợp ch ất h ữu c ơ c ủa cây n ấm tích d ươ ng (rhopalocnemis phalloides junghun) thu t ại Sơn La Pham Van Cong, Nguyen Thi Hai, Seng Cay Hom Ma Ni, Son Am Phon Keo Pa Sot
14. RESEARCH ON MANUFACTURING MATERIALS FROM LATERITE TO TREAT WASTEWATER IN NOODLE PRODUCTION VILLAGES, NOODLES IN SUBURBAN AREAS OF HANOI ...... 122 Nghiên c ứu ch ế tạo v ật li ệu x ử lí n ước th ải làng ngh ề sản xu ất bún, bánh ph ở tại khu v ực ngo ại thành Hà N ội t ừ đá ong Pham Van Hoan, Ngo Thanh Son, Nguyen Xuan Trinh, Ngo Thi Van Anh
TẠP CHÍ KHOA HỌC −−− SỐ 31/2019 5
EQUIVALENCE RELATIONS AND THE APPLICATION OF EQUIVALENCE RELATIONS IN TEACHING FRACTIONS IN PRIMARY
Nguyen Van Hao 1, Nguyen Thi Thu Hang 2, Dao Thi Ngoc Bich 3 1Department of Mathematics, Hanoi Pedagogical University 2 2Department of Primary Education, Hanoi Pedagogical University 2 3Department of basic science, Viet Tri University of industry
Abstract: In this paper, we would like to present the application of equivalence relations in teaching fractions in Primary. Keywords: Equivalence relations, the application of equivalence relations. Email: [email protected] Received 21 April 2019 Accepted for publication 25 May 2019
1. INTRODUCTION
In Primary, the content of Math knowledge is the first knowledge of Mathematics, although simple but is the basic knowledge, foundation for each student's future learning process. One of the basic views when developing programs and textbooks for Primary Mathematics it is the presentation of mathematical knowledge in the light of modern advanced mathematics. So, the application of advanced mathematics in teaching mathematics in Primary has extremely significant. In this paper, we illustrate an in-depth understanding of equivalence relations that is important in orienting and teaching some fractional problems in Primary.
2. CONTENT
2.1. Preliminaries To present some applications on equivalence relations in teaching fractions in Primary, we would like to repeat some of the most basic knowledge about this concept. For more details on this problem, we can refer to the references [1] and [2] .
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2.1.1. Two - way relationship Define 1. A certain S subset of Descartes multiplication X× Y is called the two - way relationship above on X× Y .
One element (x ; y ) ∈ S we say x has a two - way relationship S with y and from now, we write xSy instead of writing is (x ; y ) ∈ S . When Y= X to simply say S is a two-way relationship on X instead of speaking S is a two - way relationship on X× X .Example. For two set X = {1,2,3} and Y= { a , b }. Then, Descartes multiplication of X and Y is XY× = (1; ababab ),(1; ),(2; ),(2; ),(3; ),(3; ) { } Thus, we immediately see that in Descartes multiplication X× Y , the following subsets are the two-way relationship on X× Y
S= (1; aba ),(1; ),(2; ) 1 { } S= (2; bab ),(3; ),(3; ) 2 { } S= (1; aaa ),(2; ),(3; ) 3 { } In the conventional way, we write the two-way relationship between the elements in the above relationship, respectively is
1Sa ,1 Sb ,2 Sa 1 1 1 2Sb ,3 Sa ,3 Sb 2 2 2 1Sa ,2S a ,3 Sa 3 3 3 2.1.2. Equivalence relations
Define 2. A two - way relationship S on the set X is called an equivalence relation if the following three conditions are satisfied: then (i ) Reflex: For every x∈ X xSx . (ii ) Symmetry: For every x, y∈ X if xSy then ySx .
(iii ) Bridge: For every xyz, , ∈ X if xSy and ySz then xSz . When two - way relationship S is equivalence relations, we often change S by symbol “ ∼ ” and if a∼ b then read is “ a equivalent to b ”.
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Define 3. Suppose that “ ∼ ” is a equivalence relations on set X and a∈ X . Set of all elements x∈ X , they are equivalent with a denoted by C( a ) or a . It mean that
a= Ca( ) = x ∈ Xx : ∼ a { } This is called a class equivalent to a according to the equivalence relation “ ∼ ” on the set X.
2.1.3. The nature of fractions
Let ℕ be a natural number set and ℕ* = ℕ \ {0} . On the Descartes product a c ℕ× ℕ * , we define relationship “ ∼ ” as follows for any , ∈ℕ × ℕ * we say that b d a c ∼ if and only if a× d = b × c . b d It is easy to check that “ ∼ ” is equivalence relations. Each pair of numbers in order (a ; b ) with a ∈ ℕ and b ∈ ℕ* we call a non - negative fraction. The set all non -
+ + ℕ× ℕ * negative fractions, we denote ℚ . Nh ư v ậy ℚ = ∼ . The concept of non - negative fractions in this curriculum is consistent with the concept of fractions formed in Primary schools. This way of forming fractions is the foundation for building rational numbers ℚ .
2.2. The applications of equivalence relations in teaching fractions in Primary In the primary mathematics program, fractions are formed based on equivalence relations. Therefore, we can understand the fraction problems easily and teaching for students when understanding the theory of equivalence relations. We illustrate that through a number of problems below.
2.2.1. Some typical problems
Problem 1 ([3], Exercise153,page19) . Find x to have equal fractions
2 12 14 1 a) = c) = 3 x 56 x 24 x x 2 b) = d) = 36 12 125 5
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Method 1 . The teacher suggests that students use nature of the two equal fractions to solve this problem. Guide students to reduce to the same denominator or compact fractions was known to get new fractions has a numerator or denominator similar to the fraction containing x . a) We have
2 2× 6 12 = = . 3 3× 6 18 12 12 It is easy to see that the two fractions and have numerator equal to 12 so 18 x these two fractions are equal, the denominator must be equal. Then, we have 2 12 = 3 x 12 12 = 18 x x = 18
Thus x = 18 . b) We have
24 24 : 3 8 = = . 36 36 : 3 12 8 x It is easy to see that the two fractions and have denominator equal to 12 so 12 12 these two fractions are equal, the numerator must be equal. It folows that 24 x = 36 12 8 x = 12 12 x = 8 Thus x = 8. Parts c) and d) same as parts a) and b).
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Method 2. Teachers guide students to solve the above problem based on the theory of equivalence relations. This method helps students solve faster, no need to transform known fractions to get a new fraction with a numerator or denominator by numerator or denominator of fraction containing x. Based on this nature, we can guide students to solve as follows 2 12 a) = 3 x It means that
2×x = 3 × 12 or
2×x = 36. Students apply the formula to find unknown factors to find x x = 36 : 2 x = 18 Thus x = 18 . Part b),c) and d) same as part a).
11 Problem 2 [3],Exercie157,page19 . Give fraction . Need to add both the ( ) 16 numerator and denominator of that fraction with the same number is how many to get a 4 new fraction which value is ?. 5 The teacher suggested that when adding both the numerator and the denominator of 11 the fraction with the same number, subtraction the denominator and numerator of the 16 new fraction remain unchanged and equal
16− 11 = 5 . On the other hand, we have the ratio between the denominator and the numerator of 5 the new fraction is . Then, the problem takes the form of finding two numbers when 4 knowing the subtraction and the ratio of the two numbers. We have a diagram New denominator
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New numerator
New numerator is
5 : (5− 4) × 4 = 20 The number to be added to the numerator and the denominator of the old fraction is
20− 11 = 9 . Try again 11+ 9 20 4 = = . 16+ 9 25 5 So, the natural number need to look for is 9.
2.2.2. Some similar problems
Problem 3 ([3],Exercise152, page 19) . Find x is a natural number, know x a) Fraction has a value of 4. 33 5 1 b) Fraction has a value of . x 2 Problem 4 ([3],Exercise197, page 19) . Need to reduce both the numerator and 3 1 denominator of the fraction how many units to get the new fraction equal to ?. 5 2 Problem 5 ([3],Exercise160, page 20) . Need to add the numerator and 13 5 denominator of the fraction how many units to get the new fraction equal to ?. 19 7 Problem 6 ([4],Exercise 3, page 112) . Write the appropriate number in the box
50 10 3 9 a) = = b) = = = 75 3 5 10 20
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Problem 7 ([4],Exercise3, page 114) . Write the appropriate number in the box
54 27 3 = = = 72 12
Problem 8 ([5],Exercise 4, page 4) . Write the appropriate number in the box
6 a) 1 = b) 0 = 5
3. CONCLUSION
In this article, we present some application of equivalence relations in teaching fractions in Primary to find solutions to present the answer accordance with level of primary students. Application of equivalence relations will help teacher guide students solve problems and help improve teaching effctiveness.
REFERENCES
1. Nguy ễn Đình Trí, Tạ Văn Đĩnh, Nguy ễn H ồ Qu ỳnh (2009), Toán cao c ấp t ập 1, - Nxb Giáo d ục. 2. Tr ần Diên Hi ển, Nguy ễn Ti ến Tài, Nguy ễn V ăn Ng ọc (2001), Lý thuy ết s ố, - Nxb Đại h ọc S ư ph ạm. 3. Nguy ễn Áng, Dươ ng Qu ốc Ấn, Hoàng Th ị Ph ước H ảo (2017), Toán b ồi d ưỡng h ọc sinh l ớp 4 , - Nxb Giáo d ục Vi ệt Nam. 4. Đỗ Đình Hoan, Nguy ễn Áng, Vũ Qu ốc Chung, Đỗ Ti ến Đạt, Đỗ Trung Hi ệu, Tr ần Diên Hi ển, Đào Thái Lai, Ph ạm Thanh Tâm, Ki ều Đức Thành, Lê Ti ến Thành, Vũ D ươ ng Th ụy (2017), Toán 4, - Nxb Giáo d ục Vi ệt Nam. 5. Đỗ Đình Hoan, Nguy ễn Áng, Đặng T ự Ân, Vũ Qu ốc Chung, Đỗ Ti ến Đạt, Đỗ Trung Hi ệu, Đào Thái Lai, Tr ần V ăn Lý, Ph ạm Thanh Tâm, Ki ều Đức Thành, Lê Ti ến Thành, Vũ D ươ ng Th ụy (2017), Toán 5 , - Nxb Giáo d ục Vi ệt Nam.
QUAN H Ệ TƯƠ NG ĐƯƠ NG VÀ ỨNG D ỤNG C ỦA QUAN H Ệ TƯƠ NG ĐƯƠ NG TRONG D ẠY H ỌC PHÂN S Ố Ở TI ỂU H ỌC
Tóm t ắắắt: Trong bài báo này, chúng tôi trình bày ứng d ụng c ủa quan h ệ tươ ng đươ ng trong d ạy h ọc phân s ố ở Ti ểu h ọc. TTTừừừ khóa: quan h ệ tươ ng đươ ng, ứng d ụng c ủa quan h ệ tươ ng đươ ng.
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A ALGORITHM FOR SOLVING A SEPTADIAGONAL LINEAR SYSTEMS
Nguyen Thi Thu Hoa Hanoi Metropolitan University
Abstract: In this paper, we present efficient computational and symbolic algorithm for solving a septadiagonal linear system. Using computer algebra systems such as Maple, Mathematica, Matlab, Python is straightforward. Some example are given. All calculations are implemented by some codes produced in Python. Keywords: Septadiagonal matrices; Linear systems; Computer algebra systems (CAS).
Email: [email protected] Received 13 March 2019 Accepted for publication 25 May 2019
1. INTRODUCTION
The septadiagonal linear system (SLS) take the following form: (1) where AX = Y D E F G 0 ... 0 0 0 0 0 C1 D 11 E F 1 G 1 ... 0 B2 C 2 D 2 E 2 ...... 0 A= A3334 B C D ...... G N3− (2) 0 A B ...... F 4 4 N− 2 ...... CN1− D N1 − E N1 − 0 ... 0 A B C D N N N N
N is a positive integer number, . This kind of linear systemsN arise ≥ 4, in X areas = x of, … science , x , Yand = engiy , …neering , y ,[2, x ,3, y 4,∈ 5]. So in recent years, researchers solve these systems. The author in [] presented the efficient computational algorithms for solving nearly septadiagonal linear systems. The algorithms depend on the LU factorization of the nearly pentadiagonal matrix. In [], the authors discussed a symbolic algorithm for solving septadiagonal linear systems via transformations, …
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In this paper,we introduce efficient algorithm base on the LU factorization of the septadiagonal matrix. This work is organized as follow: in Section 2, numerical algorithm for solving SLS are presented. In Section 3, the numerical results are discussed. In the last Section, Section 5, conclusion of the work is presented.
2. NUMERICAL ALGORITHM FOR SOLVING SLS
In this section, we are going to build a new numerical algorithm for computing the solution of septadiagonal linear system. Assume that α α α β β β γ γ γ γ′ γ′ γ′ = ,…, , = ,…, ,γ =γ ,…,γ ,α μβ =γ μ , …γ′ , μ , = ,…, , = , … , , = ,…, , , , , μ , , ∈ . If use the LU decomposition of the matrix A , then we have:
1 0 ... 0 β0 α 0 µ 0 G 0 0 ... 0 γ1 10... 00 βαµ1 1 1 G00 1 γ'2 γ 2 ...... A= A3 γ ' 3 ...... 0 ... G N− 3 . (3) 0 A ...... 0 α µ 4 N2− N2 − ...... 1 0 βN1− α N1 − 0 ... 0 ANNNγ ' γ 1 0 ... 0 β N
Assume that
βαµG 0 ... 0 x ψ 0 0 0 0 0 0 0βαµ1111 G00x 11 ψ ...... ...... G N− 3 = . (4) α µ N2− N2 − βN1− α N1 − 0 ... 0β x ψ N N N From (3) and (4) we have
β=0D, 00 α= E, 00 µ= F, 0
C1 γ=1,FG,D µ= 11101 −γ β= 1 −αγα= 011 ,E 110 −γµ , β0
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' ' B2 C 220− γ α ' γ=2, γ= 2 ,E α= 222120 −γµ−γ G, β0 β 1 ' β2 =D 2 −αγ 12 −µγ 02
µ2 =F 2 −γ 21 G ,
αi− 3 Bi− A i ' βi− 3 γi = βi− 2
' µi− 3 Ci−γα ii2− − A i βi− 3 γi = , βi− 1
' Gi− 3 ' α=iE i −γµ−γ ii1−− ii2i G,DA β= i − i −αγ−µγ i1i −− i2i , βi− 3
Gi− 3 ' β=iDA i − i −αγ−µγµ= i1i− i2ii − ,FG, i −γ ii1 − βi− 3 G β=DA −i− 3 −αγ−µγµ=' ,FG, −γ i i iβ i1i− i2ii − i ii1 − i− 3 i=3,…,N−2.
αN− 4 BN1−− A N1 − ' βN− 4 ' γ=N1− ,E α= N1− N1 − −γµ−γ N1N2N1N3 −− −− G, βN− 2
' AN1−µ N − 4 C N1−−γ N1 − α N3 − − βN− 4 γN− 1 = , βN− 2
' G N− 4 ' α=N1−E N1 −−−−−− −γµ−γ N1N2 N1N3N1 G,DA β= N1 − − N1 − −αγ−µγ N2N1 −−−− N3N1 , βN− 4
αN− 3 ' µ N− 3 BANN− C NNN2N −γα−− A ' βN− 3 β N− 3 γ=N, γ= N , βN2− β N1−
G N− 3 ' β=ND N − A N −αγ−µγ N1N− N2N − . βN− 3 It is to see that, the LU decomposition (3) exists only if β ≠0,i=1,…,n−1.
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Algorithm . To solve the general septadiagonal linear system (1), we may procced as follows: Step 1. Set
β=0D, 00 α= E, 00 µ= F. 0 Step 2. Compute
C1 γ=1,FG,D µ= 11101 −γ β= 1 −αγα= 011 ,E 110 −γµ , β0 ' ' B2 C 220− γ α ' γ=2, γ= 2 ,E α= 222120 −γµ−γ G, β0 β 1 ' β2 =D 2 −αγ 12 −µγ 02 µ =F −γ G . 2 2 21 Step 3. For i = 3…, N – 2 compute
αi− 3 Bi− A i ' βi− 3 γi = βi− 2
' µi− 3 Ci−γα ii2− − A i βi− 3 γi = , βi− 1
' Gi− 3 ' α=iE i −γµ−γ ii1−− ii2i G,DA β= i − i −αγ−µγ i1i −− i2i , βi− 3
Gi− 3 ' β=iDA i − i −αγ−µγµ= i1i− i2ii − ,FG, i −γ ii1 − βi− 3
Gi− 3 ' β=iDA i − i −αγ−µγµ= i1i− i2ii − ,FG, i −γ ii1 − βi− 3 Step 4. Compute
αN− 4 BN1−− A N1 − ' βN− 4 ' γ=N1− ,E α= N1− N1 − −γµ−γ N1N2N1N3 −− −− G, βN− 2
' AN1−µ N − 4 C N1−−γ N1 − α N3 − − βN− 4 γN− 1 = , βN− 2
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' G N− 4 ' α=N1−E N1 −−−−−− −γµ−γ N1N2 N1N3N1 G,DA β= N1 − − N1 − −αγ−µγ N2N1 −−−− N3N1 , βN− 4
αN− 3 ' µ N− 3 BANN− C NNN2N −γα−− A ' βN− 3 β N− 3 γ=N, γ= N , βN2− β N1−
G N− 3 ' β=ND N − A N −αγ−µγ N1N− N2N − . βN− 3 Step 5. Compute the solution
ψN ψ−α N1−x NN1 − ψ−α−µ N2 −−− x N1N2 x NN2 − x,xN= N1− = ,x N2 − = , βN β N− 1 β N− 2 for i = N – 3, N – 2,…, 0 compute
ψ−ix i1i+ α− x i2i + µ− xG i3i + xi = , βi
' where: ψ=0y, 01 ψ= y 1 −γψ 102 , ψ= y 2 −γψ−γψ 21 20 and for i = 3, …, N we have
Aiψ i− 3 ' ψ=iy i − −γψ ii1ii2− −γψ − . βi− 3
3. PYTHON CODE AND ILLUSTRATIVE EXAMPLES
In this section, we give Python code to solve septadiagonal linear systems. After that this code is used for some examples.
3.1. Python code to solve septadiagonal linear systems We have Python code to solve septadiagonal linear systems: Code python giai he pttt 7 dg cheo Beta[0] = D[0] if Beta[0]== 0: Beta[0]= s D[0]= s Alpha[0] = E[0] Mu[0] = F[0] Gamma[1] = C[1]/Beta[0] Mu[1] = F[1] - Gamma[1] * G[0]
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Beta[1] = D[1] - Alpha[0]*Gamma[1] if Beta[1]== 0: Beta[1]= s Alpha[1] = E[1] - Gamma[1]*Mu[0] Gamma_P[2] = B[2]/Beta[0] Gamma[2] = (C[2] - Gamma_P[2]*Alpha[0])/Beta[1] Alpha[2] = E[2] - Gamma[2]*Mu[1] - Gamma_P[2]*G[0] Beta[2] = D[2] - Alpha[1]*Gamma[2] - Mu[0]*Gamma_P[2] if Beta[2]== 0: Beta[2]= s Mu[2] = F[2] - Gamma[2]*G[1] for i in range(3,N-1): Gamma_P[i] = (B[i] - A[i]*Alpha[i-3]/Beta[i-3])/Beta[i-2] Gamma[i] = (C[i] - Gamma_P[i]*Alpha[i-2] - A[i]*Mu[i-3]/Beta[i-3])/Beta[i-1] Alpha[i] = E[i] - Gamma[i]*Mu[i-1] - Gamma_P[i]*G[i-2] Beta[i] = D[i] - A[i] * G[i-3]/Beta[i-3] - Alpha[i-1]*Gamma[i] - Mu[i-2]*Gamma_P[i] if Beta[i]== 0: Beta[i]= s Mu[i] = F[i] - Gamma[i]*G[i-1] Gamma_P[N-1] = (B[N-1] - A[N-1]*Alpha[N-4]/Beta[N-4])/Beta[N-3] Gamma[N-1] = (C[N-1] - Gamma_P[N-1]*Alpha[N-3] - A[N-1]*Mu[N-4]/Beta[N-4])/Beta[N-2] Alpha[N-1] = E[N-1] - Gamma[N-1]*Mu[N-2] - Gamma_P[N-1]*G[N-3] Beta[N-1] = D[N-1] - A[N-1]*G[N-4]/Beta[N-4] - Alpha[N-2]*Gamma[N-1] - Mu[N- 3]*Gamma_P[N-1] if Beta[N-1]== 0: Beta[N-1]= s Gamma_P[N] = (B[N] - A[N]*Alpha[N-3]/Beta[N-3])/Beta[N-2] Gamma[N] = (C[N] - Gamma_P[N]*Alpha[N-2] - A[N]*Mu[N-3]/Beta[N-3])/Beta[N-1] Beta[N] = D[N] - A[N]*G[N-3]/Beta[N-3] - Alpha[N-1]*Gamma[N] - Mu[N-2]*Gamma_P[N] if Beta[N]== 0: Beta[N]= s Psi[0] = f[0] Psi[1] = f[1] - Gamma[1]*Psi[0] Psi[2] = f[2] - Gamma[2]*Psi[1] - Gamma_P[2]*Psi[0]
18 TRƯỜNG ĐẠI HỌC THỦ ĐÔ H NỘI for i in range (3,N+1): Psi[i] = f[i] - A[i]*Psi[i-3]/Beta[i-3] - Gamma[i]*Psi[i-1] - Gamma_P[i]*Psi[i-2] delta = [0 for i in range(N+1)] delta[N] = Psi[N]/Beta[N] delta[N-1] = (Psi[N-1] - delta[N]*Alpha[N-1])/Beta[N-1] delta[N-2] = (Psi[N-2] - delta[N-1]*Alpha[N-2] - Mu[N-2]*delta[N])/Beta[N-2] for i in range(N-3,-1,-1): delta[i] = (Psi[i] - delta[i+1] * Alpha[i] - delta[i+2] * Mu[i] - G[i]*delta[i+3])/Beta[i].
3.2. Illustrative examples Example 1. Find the solution of the following septadiagonal linear system following:
x0+++ 2x 12 3x 4x 3 = 30 −++++3x4xx0 12 2xx 34 = 21 2x−++++ x5x 7x 8x2x = 95 0 12 3 45 x0++++++ 3x4x 123 5x 6x 456 x x = 82 x++ 5x 2x +++ 3x 4x 5x = 99 123 456 2x+ 3x +++ 4x 5x x = 75 23 456 x+++ x 2xx = 28. 3 4 56 Solution . We have N = 6, D = (1, 4, 5, 5,3, 5, 1), E = (2, 1, 7, 6, 4, 1), F = (3, 2, 8, 1, 5), G = (4, 1, 2, 1), A = (1, 1, 2, 1), B = (2, 3, 5, 3, 1), C = (-3, -1, 4, 2, 4, 2), y = (30, 21, 95, 82, 99, 75, 28). The numerical result is x = (1, 2, 3, 4, 5, 6, 7). Example 2. Find the solution of the following septadiagonal linear system following:
81− 123324 0 0 x0 − 222 −13 4 1 3320 x1 212 12− 10157 82 x − 71 2 = . 112 2 1425 6 4 x3 − 96 0 15234 x 42 4 0 02345x 24 5 Solution . From the above system, we see that, N = 5, D = (81, 4, 15, 25, 3, 5), E = (-12, 1, 7, 6, 4), F = (33, 3, 8, 4), G = (24, 32, 2), A = (112, 1, 2), B = (12, 3, 5, 3), C = (-13, -10, 14, 2, 4). We find approximation solution of this equation x = (-1, 12, 3, -4, 5, 2).
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4. CONCLUSION
In this work, we used the LU factorization of the septadiagonal matrix to biuld a new algorithm. Using numerical examples we have obtained that the Algorithm works well. Hence, it may be come auseful tool for solving linear systems of septadiagonal type.
REFERENCES
1. S. S. Askar and A. A. Karawia (2015), “On solving pentadiagonal linear systems via transformations”, Mathematical Problems in Engineering , Vol. 2015 , pp.1-9. 2. S.Battal Gazi Karakoça, Halil Zeybek (2016), “Solitary - wave solutions of the GRLW equation using septic B - spline collocation method”, Applied Mathematics and Computation , Vol. 289 , pp.159-171. 3. H. Che, X. Pan, L. Zhang and Y. Wang (2012), “Numerical analysis of a linear - implicit average scheme for generalized Benjamin - Bona - Mahony - Burgers equation”, J . Applied Mathematics , Vol. 2012 , pp.1-14. 4. D. J. Evans and K. R. Raslan (2005), “Solitary waves for the generalized equal width (GEW) equation”, International J. of Computer Mathematics , Vol. 82(4) , pp.445-455. 5. C. M. García - Lospez, J.I.Ramos (2012), “Effects of convection on a modified GRLW equation”, Applied Mathematics and Computation , Vol. 219 , pp.4118-4132. 6. Halil Zeybek, S.Battal Gazi Karakoça (2016), “A numerical investigation using lumped Galerkin approch with cubic B – spline”, Springer Plus, 5:199. 7. A. A. Karawia and S. A. El-Shehawy (2009), “Nearly pentadiagonal linear systems”, Math. NA, Vol. 26 , pp.1-7.
THU ẬT TOÁN GI ẢI H Ệ PHƯƠ NG TRÌNH TUY ẾN TÍNH BẢY ĐƯỜNG CHÉO
Tóm t ắắắttt: Trong bài báo này, chúng ta trình bày thu ật toán hi ệu qu ả để gi ải các h ệ ph ươ ng trình tuy ến tính bảy đường chéo. Thu ật toán trình bày thích h ợp v ới các ngôn ng ữ l ập trình nh ư Maple, Matlab, Mathematica, Python. Các k ết qu ả s ố được trình bày bằng ngôn ng ữ l ập trình Python minh h ọa hi ệu qu ả c ủa thu ật toán. TTTừừừ khóa : Ma tr ận b ảy đường chéo, h ệ ph ươ ng trình tuy ến tính, tính toán các h ệ đạ i s ố.
20 TRƯỜNG ĐẠI HỌC THỦ ĐÔ H NỘI
WEIGHTED MULTILINEAR HARDYHARDY----CESCESCES RORO OPERATORS ON SPACES OF HERZ TYPES
Nguyen Thi Hong Hanoi Metropolitan University
Abstract: The aim of this paper is investigated the boundedness of the weighted multilinear Hardy-Cesàro operators on weighted functional spaces of Herz types. Keywords: Weighted bilinear Hardy-Cesàro operator; Herz spaces; Morrey-Herz spaces.
Email: [email protected] Received 23 March 2019 Accepted for publication 25 May 2019
1. INTRODUCTION
Let me give a brief history of results on these operators. In 1984, Carton-Lebrun and Fosset [1] considered a Hausdorff operator of special kind, which is called the weighted Hardy operator such as the following , (1.1) The authors showed = the boundedness of, ∈ on Lebesgue. spaces and space. In 2001, J. Xiao [16] obtained that is bounded on if and only if (1.2) Meanwhile, the corresponding < ∞. operator norm was worked out. The result seems to be of interest as it is related closely to the classical Hardy integral inequality. Also, J. Xiao obtained the bounds of which sharpened and extended the main result of Carton-Lebrun and Fosset in [1]. In 2012, Chuong and Hung [6] introduced the weighted Hardy-Cesàro operator, a more general form of in the real case as Definition 1.1. Let , s be measurable functions. The weighted Hardy-Cesàro operator : 0,1 → 0,, associated ∞ : 0,1 to →the parameter curve , is defined by , , : =
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(1.3) , for all measurable complex = valued functions , on . With certain conditions on functions and , the authors [6] proved is bounded on weighted Lebesgue spaces and weighted spaces. The corresponding , operator norms are worked out too. The authors also give a necessary condition on the weight function , for the boundedness of the commutators of operator on with symbols in . , In 2015, Hung and Ky introduced the weighted multilinear Hardy-Cesàro operator which was defined as following Definition 1.2. Let be measurable functions. Given , ∈ , : 0,1 be→ measurable 0, ∞ , functions., . . . , ∶ 0,1 → The weighted multilinear Hardy-Cesàro, . . . , : → operator , is defined by , , (1.4) , , where , … , = , ∏ In [22], = the , . . .authors , . obtain the sharp bounds of on the product of Lebesgue , spaces and central Morrey spaces. They also proved sufficient , and necessary conditions of the weighted functions so that the commutators of (with symbols in central , space) are bounded on the product of central Morrey spaces. , In 2014, Gong, Fu, Ma investigate the weighted multilinear Hardy operators (see [20]) on the product Herz spaces and the product Morrey-Herz spaces, respectively. They obtained the bounds of this operators on the product these spaces. From all above analysis, it makes me investigate the boundedness and norm of operator in (1.4) from product of spaces of Herz and Morrey-Herz. The paper is organized as followed. In Section 2 we give the notation and definitions that we shall use in the sequel. In Section 3 we state the main results on the boundedness of on the product of Herz spaces. In Section 4, we present the main results on the , boundedness , of on the product of Morrey-Herz spaces. , , 2. BASIC NOTIONS AND LEMMAS
Since Herz space is a natural generalization of weighted Lebesgue spaces with power weights, researcher are also interested in studying the boundedness of on the Herz , spaces. To make the description more clear below, we review the definition , of the Herz
22 TRƯỜNG ĐẠI HỌC THỦ ĐÔ H NỘI spaces now. In the following and , for , , and = ; for = \ and is the = characteristic { ∈ : | |function≤ 2 of a set ∈ . = = , = ∈ Definition 2.1. Let The homogeneous Herz ∈ spaces ,0<