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Home , Rectangle, Right triangle

Geometry

More A lot of geometry questions on the GRE pertain to , so I want to cover more material about them than I did in our last session.

Acute : An angle that is less than 90 degrees. Obtuse angle: An angle that is more than 90 degrees.

Acute triangles: all three are acute (less than 90 degrees). Obtuse triangles: One of the angles is obtuse and the other two are acute. Right triangles: It has one (90 degree angle) and two acute angles.

Classification of Triangles: of Measure of Name: the sides the angles

Scalene all 3 are different all 3 are different

Isosceles 2 are the same 2 are the same

Equilateral all 3 the same all 3 the same

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One of the things that we mentioned last time was Pythagorean’s Theorem (which applies ONLY to right triangles): B

a c a2 + b2 = c2

C b A

1 Here are the relationships between a, b, and c for right, obtuse, and right triangles: a2 + b2 = c2 if and only if angle C is a right angle ( ABC is a ). a2 + b2 < c2 if and only if angle C is a obtuse (Triangle ABC is an obtuse triangle). a2 + b2 > c2 if and only if angle C is an acute angle (Triangle ABC is an acute triangle).

Here are the right triangles that appear the most often on the GRE: The 30o-60o-90o triangle: The sides are x, x 3 , and 2x:

If you know the length of the shorter leg (x), Multiply it by 3 to get the longer leg, and Multiply it by 2 to get the . If you know the length of the longer leg (x 3 ), Divide it by 3 to get the shorter leg, and Multiply the shorter leg by 2 to get the hypotenuse. If you know the length of the hypotenuse (2x), Divide it by 2 to get the shorter leg, and Multiply the shorter leg by 3 to get the longer leg.

2 The 45o-45o-90 o triangle: The sides are x, x, and x 2 :

By multiplying the length of a leg by 2 , you get the hypotenuse. By dividing the hypotenuse by 2 , you get the length of each leg. ======

In the diagram, if BC = 6 , what is the value of CD?

A. 2 2

B. 4 2

C. 2 3

D. 2 6

E. 4

Solution: Choice (E) Triangle ABC is a 30o-60o -90o triangle, and you are given the longer leg, which you can use to find the other two sides: 66 Divide the longer leg BC by 3 to get the shorter leg AB = ==2 3 3 Multiply AB by 2 to get the hypotenuse AC = 2 2 Triangle DAC is a 45o-45o-90o triangle, and you now know the length of its leg AC. To get the hypotenuse DC: Multiply AC by 2 : DC = (22)( 2) == (2)(2)4

3 The measures of the three angles in a triangle are in the ratio of 1:1:2. Which of the following statements must be true? Indicate all such statements. A. The triangle is isosceles B. The triangle is a right triangle C. The triangle is equilateral

Solution: Choices (A) and (B) You could create a “Ratio Box” to help you organize your thoughts: side 1 side 2 side 3 Total ratio 1 1 2 4 multiply by ? real 180o

We know that for a triangle, the sum of the angles is 180o. 4 would need to be “multiplied by” 45o in order to equal 180o side 1 side 2 side 3 Total ratio 1 1 2 4 multiply by 45o real 180o

Now go ahead and multiply the others by 45o to see what each of the angles would have to be: side 1 side 2 side 3 Total ratio 1 1 2 4 multiply by 45o 45o 45o 45o real 45o 45o 90o 180o

So this would be a 45o-45o-90o triangle. Since two of the angles have the same measure, the triangle is isosceles, and since one of the angles is 90o, it is a right triangle. ======In the last session we mentioned that the of a triangle is calculated using this formula: 1 Abh= 2

4 DEFG is a . What is the area of triangle DFH?

A. 3

B. 4.5

C. 6

D. 7.5

E. 10

Solution: Choice (B) Triangle DGH is a right triangle, so you can use Pythagorean’s Theorem to find the length of the leg GH: 32 + (GH)2 = 52 →− GH = 25 9== 16 4 Since GF = DE = 7, HF = 7 – 4 = 3. Triangle DFH has a base of HF = 3, and a height of DG = 3 11 So the area is A== bh = (3)(3) 4.5 22

What is the of triangle ABC?

A. 48

B. 48+ 12 2

C. 48+ 12 3

D. 60

E. 60+ 6 3

Solution: Choice (C) Triangle ABD is a right triangle, so you can use Pythagorean’s Theorem to solve for the leg AD: AD = 1522−9 = 225− 81== 144 12 Triangle ADC is a 30o-60o -90o triangle, whose shorter leg x is 12. The hypotenuse 2x is AC = 24. And the other leg x 3 is CD = 12 3. Perimeter = 24 +15 + 9 + 12 3 = 48 + 12 3

5 Remember covering this last time?: Know these relationships between the angles and sides of a triangle: • The longest side is opposite the largest interior angle. The shortest side is opposite the smallest interior angle. Equal sides are opposite equal angles. • The length of any one side of a triangle must be less than the sum of the other two sides and greater than the difference between the other two sides. So take any two sides of a triangle, add them together, then subtract one from the other, and the third side must lie between those two numbers.

The of two sides of a triangle are 7 and 11. Quantity A Quantity B

The length of 4 the third side

A. Quantity A is greater B. Quantity B is greater C. Quantities A and B are equal. D. It is impossible to determine which quantity is greater.

Solution: Choice (A) The length of the third side must be: 11-7 < third side < 7+11 4 < third side < 18 The third side is greater than 4.

Polygons A is a closed geometric figure made up of segments. The simplest polygon has three sides and is a triangle. A polygon with four sides is a . The only other ones you need to be familiar with are: A polygon with five sides is a . A polygon with six sides is a . A polygon with eight sides is an . A polygon with ten sides is a .

Every quadrilateral has two . When you draw in either one, you divide the quadrilateral into two triangles. Since the sum of the three angles in any triangle is 180o, the sum of the angles in any quadrilateral has to be (2)(180o ) = 360o

6 This same process can be applied to any polygon, dividing it into triangles by drawing in all of the diagonals that emanate from one :

A Pentagon is divided into three triangles, so the sum of the angles in any pentagon has to be (3)(180o ) = 540o A Hexagon is divided into four triangles, so the sum of the angles in any hexagon has to be (4)(180o ) = 720o

Is there a pattern here? Yes! Just count the number of sides, subtract 2, and then multiply the result by 180o. ======What is the measure, in degrees, of each interior angle in a regular decagon?

Solution: 144o A decagon has 10 sides, and two less than this is 8. Multiplying 8 by 180o tells us the sum of all the angles is 1440o. All 10 angles equal each other, so divide 10 into 1440o to find the size of each interior angle: 1440o ÷ 10 = 144o

A is a quadrilateral in which both pairs of opposite sides are . Opposite sides are equal. Opposite angles are equal. Consecutive angles add up to 180o The two diagonals bisect each other. The divides the parallelogram into two triangles that have the exact same size and .

A Rectangle is a parallelogram, so the same properties above apply to it, plus these: The measure of each angle in a rectangle is 90o. The diagonals of a rectangle have the same length.

7 A is a rectangle, so the same properties for apply to it, plus these: All four sides have the same length. Each diagonal divides the square into two 45o-45o-90o right triangles. The diagonals are to each other.

A is a quadrilateral in which one pair of sides IS parallel and the other pair of sides is NOT parallel. The parallel sides are called the bases.

Here are the Area Formulas you need to know: Area for a Parallelogram: Area = (base)(height) Area for a Rectangle: Area = (length)(width) 2 1 2 Area for a Square: Area = (side) also: Area = d 2 1 Area for a Trapezoid: Area = base+ base height 2 ( 12)( )

Two rectangles with the same perimeter can have different . Two rectangles with the same area can have different .

For a given perimeter, the rectangle with the largest area is a Square. For a given area, the rectangle with the smallest perimeter is a Square.

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Quantity A Quantity B

The area of a 10 rectangle whose perimeter is 12

A. Quantity A is greater B. Quantity B is greater C. Quantities A and B are equal. D. It is impossible to determine which quantity is greater.

Solution: Choice (B) There are a lot of different areas whose perimeters are 12. The largest area would be created by a 3x3 square, which is 9.

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WXYZ is a parallelogram

Quantity A Quantity B

Diagonal WY Diagonal XZ

A. Quantity A is greater B. Quantity B is greater C. Quantities A and B are equal. D. It is impossible to determine which quantity is greater.

Solution: Choice (B) Angle Z is an acute angle, so (WY)2 < a2 + b2 Angle Y is an obtuse angle, so (XZ) 2 > a2 + b2 So XZ > WY

9 More on C π == d C = π d C = 2π r π is approximately 3.14 (a little more than 3). The degree measure of a complete is 360o. Area = πr2 o x If an arc measures x , the length of the arc is 2rπ 360 ( ) x and the area of the sector formed by the arc and the two radii is πr2 360 ( ) ======

Each of the triangles is equilateral.

Quantity A Quantity B

The area of the 6π shaded region

A. Quantity A is greater B. Quantity B is greater C. Quantities A and B are equal. D. It is impossible to determine which quantity is greater.

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Solution: Choice (C) Because the triangles are equilateral, the two non-shaded central angles are 60o each giving us a sum of 120o (imagine “combining” the two non-shaded regions together). 120 1 2 The white area is = of the circle, so the shaded area is of the circle. 360 3 3 The area of the entire circle is ππr3922== π 2 The shaded area is two-thirds of this: (9ππ )= 6 3

Solid Geometry Volume The volume of a three-dimensional figure is found by multiplying the area of the two- dimensional figure by the height. Rectangular solid: Volume = (Area of a rectangle)×(depth) = length×width×height Circular : Volume = ()×(height) = πrh2

A diagonal of a box is the longest that can be drawn between two points on the box. To find the length of the diagonal of a box use this formula: abcd222++= 2 where a, b, and c are the of the rectangular box, and d is the length of the diagonal.

Just so you know, this formula is just an extension of the . EG is the diagonal of the rectangular base EFGH. Since the sides of the base are 3 and 4, you can use Pythagorean’s Theorem to find that EG is 5. Now, triangle CGE is a right triangle whose legs are 12 and 5, so you can use Pythagorean’s Theorem on it to find that EG (the diagonal of the box) is 13. So you could have solved it this way, but it’s a little faster to use abcd222++= 2

11 Surface Area For a rectangular box the surface area is the sum of the areas of all of its sides. For a cylinder the surface area is the sum of : the area of its side: (circumference of the base)(height) = 2π (radius)(height) the area on the top: π (radius)2 the area on the bottom: π (radius)2 ======

A 5-foot-long cylindrical pipe has an inner diameter of 6 feet and an outer diameter of 8 feet. If the total surface area (inside and out, including the ends) is kπ , what is the value of k?

A. 7 B. 40 C. 48 D. 70 E. 84

Solution: Choice (E) Draw a sketch: Surface area of a side of a cylinder is A = 2π rh, so the area of the exterior is 2π (4)(5) = 40π , and the area of the interior is 2π (3)(5) = 30π . The area of EACH shaded end is the area of the outer circle minus the area of the inner circle: π (4)2 - π (3)2 16π - 9π 7π So the total surface area is: 40π + 30π + 7π + 7 π = 84π Total Surface Area = kπ = 84π k = 84

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