A Brief Introduction to Celestial Mechanics
Harini Chandramouli
University of Minnesota
Climate Seminar October 2, 2018 Outline
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
2 / 24 History Table of Contents
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
3 / 24 A definition we care about more: 3 Celestial mechanics is the study of point particles in R (mostly) moving under the influence of their mutual gravitational attraction. Generally there is an emphasis on the general orbital motions of the solar system bodies.
History Definition
Celestial mechanics is considered to be the study of the motion of objects in outer space. Historically, celestial mechanics applies the principles of physics (classical mechanics) to astronomical objects (e.g. stars, planets) to acquire information on these objects.
4 / 24 3 Celestial mechanics is the study of point particles in R (mostly) moving under the influence of their mutual gravitational attraction. Generally there is an emphasis on the general orbital motions of the solar system bodies.
History Definition
Celestial mechanics is considered to be the study of the motion of objects in outer space. Historically, celestial mechanics applies the principles of physics (classical mechanics) to astronomical objects (e.g. stars, planets) to acquire information on these objects.
A definition we care about more:
4 / 24 History Definition
Celestial mechanics is considered to be the study of the motion of objects in outer space. Historically, celestial mechanics applies the principles of physics (classical mechanics) to astronomical objects (e.g. stars, planets) to acquire information on these objects.
A definition we care about more: 3 Celestial mechanics is the study of point particles in R (mostly) moving under the influence of their mutual gravitational attraction. Generally there is an emphasis on the general orbital motions of the solar system bodies.
4 / 24 History Timeline
Alexandria, ∼140CE, Ptolemy Poland, 1473 - 1543, Nicolaus Copernicus Denmark, 1546 - 1602, Tycho Brahe Germany, 1571 - 1630, Johannes Kepler England, 1643 - 1727, Isaac Newton
5 / 24 History Timeline
Switzerland, 1707 - 1783, Leonard Euler Sardinia, 1736 - 1813, Joseph-Louis Lagrange Prussia, 1804 - 1851, Carl Jacobi USA, 1838 - 1914, George Hill France, 1854 - 1912, Henri Poincare
6 / 24 The Kepler Problem Table of Contents
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
7 / 24 The Kepler Problem The Two-Body Problem
Let us start by looking at a simple case - the two - body problem. The two-body problem is to determine the position and speed of two bodies interacting with each other given their masses, initial positions, and initial velocities. The gravitational two-body problem is a special case in which the two-bodies interact by a central force F , that varies in strength as the inverse of the distance, r, between them.
m1, x1 m2 r m2, x2 m1 Gm m F = 1 2 r2
8 / 24 The Kepler Problem The Two-Body Problem
The differential equations for the gravitational two-body problem are x − x m x¨ = F · 2 1 1 1 r x − x m x¨ = F · 1 2 2 2 r with initial conditions
x1(t0), x2(t0), x˙1(t0), x˙2(t0)
for some initial time t0.
9 / 24 Then, we get the single second order ODE q q¨ = −G(m + m ) . 1 2 |q|3
This is called the Kepler problem. Now we turn our second order ODE into a system of first order ODEs and we have the familiar q˙ = p µq p˙ = − |q|3
The Kepler Problem The Kepler Problem
We can reduce the two-body problem into a simpler problem by letting
q = x2 − x1.
10 / 24 Now we turn our second order ODE into a system of first order ODEs and we have the familiar q˙ = p µq p˙ = − |q|3
The Kepler Problem The Kepler Problem
We can reduce the two-body problem into a simpler problem by letting
q = x2 − x1.
Then, we get the single second order ODE q q¨ = −G(m + m ) . 1 2 |q|3
This is called the Kepler problem.
10 / 24 The Kepler Problem The Kepler Problem
We can reduce the two-body problem into a simpler problem by letting
q = x2 − x1.
Then, we get the single second order ODE q q¨ = −G(m + m ) . 1 2 |q|3
This is called the Kepler problem. Now we turn our second order ODE into a system of first order ODEs and we have the familiar q˙ = p µq p˙ = − |q|3
10 / 24 Conserved Quantities & Orbital Elements Table of Contents
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
11 / 24 Conserved Quantities & Orbital Elements Conserved Quantities
A conserved quantity of a dynamical system is a function of the dependent variables whose value remains constant along each trajectory of the system.
Note: Emmy Noether’s first theorem states that every differentiable symmetry of the action of a physical system has a corresponding conservation law. All the conserved quantities in the Kepler problem relate to a symmetry in the system.
12 / 24 We can then show that d (q × p) = q × p˙ + p × p = −µ|q|−3(q × q) + p × p = 0. dt So, we have q × p = c, a constant vector. We will refer to c as the angular momentum.
Conserved Quantities & Orbital Elements The Conservation of Angular Momentum
Angular momentum is the rotational analog of linear momentum. It is defined for a point particle to be the vector
q × p.
13 / 24 So, we have q × p = c, a constant vector. We will refer to c as the angular momentum.
Conserved Quantities & Orbital Elements The Conservation of Angular Momentum
Angular momentum is the rotational analog of linear momentum. It is defined for a point particle to be the vector
q × p.
We can then show that d (q × p) = q × p˙ + p × p = −µ|q|−3(q × q) + p × p = 0. dt
13 / 24 Conserved Quantities & Orbital Elements The Conservation of Angular Momentum
Angular momentum is the rotational analog of linear momentum. It is defined for a point particle to be the vector
q × p.
We can then show that d (q × p) = q × p˙ + p × p = −µ|q|−3(q × q) + p × p = 0. dt So, we have q × p = c, a constant vector. We will refer to c as the angular momentum.
13 / 24 Integrate both sides and you’ll see that 1 µ |p|2 = + h, 2 |q| where h is our constant of integration and also our energy.
Note: Hamiltonians!
Conserved Quantities & Orbital Elements The Conservation of Energy
The gravitational interaction as described earlier was an internal conservative force and as such we can conclude that the energy is conserved in this system. We can can find an expression for this mathematically as follows: µq p · p˙ = p · − |q|3 p · p˙ = −µ|q|−3(q · q˙) dq p · p˙ = −µ|q|−2 dt
14 / 24 Note: Hamiltonians!
Conserved Quantities & Orbital Elements The Conservation of Energy
The gravitational interaction as described earlier was an internal conservative force and as such we can conclude that the energy is conserved in this system. We can can find an expression for this mathematically as follows: µq p · p˙ = p · − |q|3 p · p˙ = −µ|q|−3(q · q˙) dq p · p˙ = −µ|q|−2 dt Integrate both sides and you’ll see that 1 µ |p|2 = + h, 2 |q| where h is our constant of integration and also our energy.
14 / 24 Conserved Quantities & Orbital Elements The Conservation of Energy
The gravitational interaction as described earlier was an internal conservative force and as such we can conclude that the energy is conserved in this system. We can can find an expression for this mathematically as follows: µq p · p˙ = p · − |q|3 p · p˙ = −µ|q|−3(q · q˙) dq p · p˙ = −µ|q|−2 dt Integrate both sides and you’ll see that 1 µ |p|2 = + h, 2 |q| where h is our constant of integration and also our energy.
Note: Hamiltonians! 14 / 24 Conserved Quantities & Orbital Elements Orbital Elements
eccentricity vector, eccentricity (e) semi-major axis (a) argument of the periapsis (ω) true anomaly (ν) inclination (i)
Figure: orbital plane, yellow, intersects reference plane, grey (wikipedia)
15 / 24 Conserved Quantities & Orbital Elements Another Conserved Quantity!
Another constant of motion is actually the eccentric axis, e. It can be show using vector identities that d q c × q = . dt |q| |q|3
Then multiplying both sides of this equation by −µ we can derive the following: d q µ = p˙ × c. dt |q| Integrating this statement, we get q µ e + = p × c, |q|
where e is the constant of integration.
16 / 24 The conic particle moves on a conic section of eccentricity e with one focus at the origin → this is Kepler’s first law!
Conserved Quantities & Orbital Elements The Solution to Kepler’s Problem
This can be derived by taking the dot product of both sides of our last equation with q, then changing coordinates (polar coordinates), with coordinates (|q|, ν). We find that the solution is given by
|c|2/µ |q| = . 1 + e cos(ν)
17 / 24 Conserved Quantities & Orbital Elements The Solution to Kepler’s Problem
This can be derived by taking the dot product of both sides of our last equation with q, then changing coordinates (polar coordinates), with coordinates (|q|, ν). We find that the solution is given by
|c|2/µ |q| = . 1 + e cos(ν)
The conic particle moves on a conic section of eccentricity e with one focus at the origin → this is Kepler’s first law!
17 / 24 Regularization Table of Contents
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
18 / 24 A singularity t0 of the Kepler problem is a collision singularity when q(t) approaches a specific point of ∆ as t → t0.
A regularization is a transformation (q, p) → (u, w) where q = 0 corresponds to some u = u0 and |w(s)| → w0 as s → s0.
Regularization Regularization
The collision set, i.e.
m2 ∆ = q |q| = 0 , |q| is the set of points where the m1 distance to the origin is 0.
19 / 24 A singularity t0 of the Kepler problem is a collision singularity when q(t) approaches a specific point of ∆ as t → t0.
A regularization is a transformation (q, p) → (u, w) where q = 0 corresponds to some u = u0 and |w(s)| → w0 as s → s0.
Regularization Regularization
The collision set, i.e.
m2 ∆ = q |q| = 0 , |q| is the set of points where the m1 distance to the origin is 0.
19 / 24 A regularization is a transformation (q, p) → (u, w) where q = 0 corresponds to some u = u0 and |w(s)| → w0 as s → s0.
Regularization Regularization
The collision set, i.e.
m2 ∆ = q |q| = 0 , |q| is the set of points where the m1 distance to the origin is 0.
A singularity t0 of the Kepler problem is a collision singularity when q(t) approaches a specific point of ∆ as t → t0.
19 / 24 Regularization Regularization
The collision set, i.e.
m2 ∆ = q |q| = 0 , |q| is the set of points where the m1 distance to the origin is 0.
A singularity t0 of the Kepler problem is a collision singularity when q(t) approaches a specific point of ∆ as t → t0.
A regularization is a transformation (q, p) → (u, w) where q = 0 corresponds to some u = u0 and |w(s)| → w0 as s → s0.
19 / 24 The Levi-Civita transformation is q = 2z2 w p = z¯ where q, p, z, w ∈ C. We can also utilize the use of a time change.
New differential equations: w z0 = 2 w0 = hz where |p|2 µ |w|2 µ h = − = − . 2 |q| 2|z|2 2|z|2
Regularization Levi-Civita Regularization
2 ∼ Consider the problem in R = C, that is, instead of the vector 2 q = (q1, q2) ∈ R we use the complex notation q = q1 + iq2 ∈ C.
20 / 24 New differential equations: w z0 = 2 w0 = hz where |p|2 µ |w|2 µ h = − = − . 2 |q| 2|z|2 2|z|2
Regularization Levi-Civita Regularization
2 ∼ Consider the problem in R = C, that is, instead of the vector 2 q = (q1, q2) ∈ R we use the complex notation q = q1 + iq2 ∈ C.
The Levi-Civita transformation is q = 2z2 w p = z¯ where q, p, z, w ∈ C. We can also utilize the use of a time change.
20 / 24 Regularization Levi-Civita Regularization
2 ∼ Consider the problem in R = C, that is, instead of the vector 2 q = (q1, q2) ∈ R we use the complex notation q = q1 + iq2 ∈ C.
The Levi-Civita transformation is q = 2z2 w p = z¯ where q, p, z, w ∈ C. We can also utilize the use of a time change.
New differential equations: w z0 = 2 w0 = hz where |p|2 µ |w|2 µ h = − = − . 2 |q| 2|z|2 2|z|2
20 / 24 What is this regularization doing? Removes the singularity at the origin Singularities now lie at infinity Double cover Go around once in the z-plane → go around twice in the q-plane Bounce
Regularization Levi-Civita Regularization
w z0 = 2 w0 = hz
21 / 24 Regularization Levi-Civita Regularization
What is this regularization doing? Removes the singularity at the origin w Singularities now lie at infinity z0 = 2 Double cover w0 = hz Go around once in the z-plane → go around twice in the q-plane Bounce
21 / 24 Other Important Topics Table of Contents
1. History
2. The Kepler Problem
3. Conserved Quantities & Orbital Elements
4. Regularization
5. Other Important Topics
22 / 24 n-body problem Hamiltonian systems Lagrangian points Modern celestial mechanics
Other Important Topics Other Important Topics
23 / 24 Hamiltonian systems Lagrangian points Modern celestial mechanics
Other Important Topics Other Important Topics
n-body problem
23 / 24 Lagrangian points Modern celestial mechanics
Other Important Topics Other Important Topics
n-body problem Hamiltonian systems
23 / 24 Modern celestial mechanics
Other Important Topics Other Important Topics
n-body problem Hamiltonian systems Lagrangian points
23 / 24 Other Important Topics Other Important Topics
n-body problem Hamiltonian systems Lagrangian points Modern celestial mechanics
23 / 24 Other Important Topics
Thank You!
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