What Is the System Used to Name Chemical Compounds?
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Carbon Dioxide - Made by FILTERSORB SP3
Technical Article MAR 2015 Chemistry of drinking water Carbon dioxide - made by FILTERSORB SP3 Carbon dioxide is a molecule with the chemical formula CO2. The linear molecule consists of a Carbon atom O C O that is doubly bonded with two Oxygen atoms. CO2 exists in water in the form of dissolved temporary hardness Ca(HCO3)2. Carbon dioxide is only water soluble when pressure is maintained. As the pressure drops CO2 will escape to air as gas. This event is characterized by the CO2 bubbles forming in /L ] Normal Seawater water. Human use carbon dioxide in many meq different ways. The most familiar example is Coca-Cola, Soft Drinks and Beer to make them fizzy. Carbon dioxide has a specific solubility in [ Alkalinity water as CO2 + H2O ⇌ H2CO3. At any given pH there is an exact mathematical relationship between H2CO3 and both bicarbonate (HCO3) and Carbonate (CO3). For example at a pH of about 9.3 in Drinking pH water the carbonate concentration is 100 The theoretical relationship between times that of carbonic acid (H2CO3). At carbonate alkalinity and pH for seawater higher pH this multiplier rises and (green and freshwater (blue) equilibrated consequently there are more HCO and 3 with the atmosphere (350 ppm carbon CO present 3 dioxide) www.watchwater.de Water ® Technology FILTERSORB SP3 WATCH WATER & Chemicals Making the healthiest water How SP3 Water functions in human body ? Answer: Carbon dioxide is a waste product of the around these hollow spaces will spasm and respiratory system, and of several other constrict. chemical reactions in the body such as the Transportation of oxygen to the tissues: Oxygen creation of ATP. -
A Complete Guide to Benzene
A Complete Guide to Benzene Benzene is an important organic chemical compound with the chemical formula C6H6. The benzene molecule is composed of six carbon atoms joined in a ring with one hydrogen atom attached to each. As it contains only carbon and hydrogen atoms, benzene is classed as a hydrocarbon. Benzene is a natural constituent of crude oil and is one of the elementary petrochemicals. Due to the cyclic continuous pi bond between the carbon atoms, benzene is classed as an aromatic hydrocarbon, the second [n]- annulene ([6]-annulene). It is sometimes abbreviated Ph–H. Benzene is a colourless and highly flammable liquid with a sweet smell. Source: Wikipedia Protecting people and the environment Protecting both people and the environment whilst meeting the operational needs of your business is very important and, if you have operations in the UK you will be well aware of the requirements of the CoSHH Regulations1 and likewise the Code of Federal Regulations (CFR) in the US2. Similar legislation exists worldwide, the common theme being an onus on hazard identification, risk assessment and the provision of appropriate control measures (bearing in mind the hierarchy of controls) as well as health surveillance in most cases. And whilst toxic gasses such as hydrogen sulphide and carbon monoxide are a major concern because they pose an immediate (acute) danger to life, long term exposure to relatively low level concentrations of other gasses or vapours such as volatile organic compounds (VOC) are of equal importance because of the chronic illnesses that can result from that ongoing exposure. Benzene, a common VOC Organic means the chemistry of carbon based compounds, which are substances that results from a combination of two or more different chemical elements. -
Chemical Formula
Chemical Formula Jean Brainard, Ph.D. Say Thanks to the Authors Click http://www.ck12.org/saythanks (No sign in required) AUTHOR Jean Brainard, Ph.D. To access a customizable version of this book, as well as other interactive content, visit www.ck12.org CK-12 Foundation is a non-profit organization with a mission to reduce the cost of textbook materials for the K-12 market both in the U.S. and worldwide. Using an open-content, web-based collaborative model termed the FlexBook®, CK-12 intends to pioneer the generation and distribution of high-quality educational content that will serve both as core text as well as provide an adaptive environment for learning, powered through the FlexBook Platform®. Copyright © 2013 CK-12 Foundation, www.ck12.org The names “CK-12” and “CK12” and associated logos and the terms “FlexBook®” and “FlexBook Platform®” (collectively “CK-12 Marks”) are trademarks and service marks of CK-12 Foundation and are protected by federal, state, and international laws. Any form of reproduction of this book in any format or medium, in whole or in sections must include the referral attribution link http://www.ck12.org/saythanks (placed in a visible location) in addition to the following terms. Except as otherwise noted, all CK-12 Content (including CK-12 Curriculum Material) is made available to Users in accordance with the Creative Commons Attribution-Non-Commercial 3.0 Unported (CC BY-NC 3.0) License (http://creativecommons.org/ licenses/by-nc/3.0/), as amended and updated by Creative Com- mons from time to time (the “CC License”), which is incorporated herein by this reference. -
Introduction, Formulas and Spectroscopy Overview Problem 1
Chapter 1 – Introduction, Formulas and Spectroscopy Overview Problem 1 (p 12) - Helpful equations: c = ()() and = (1 / ) so c = () / ( ) c = 3.00 x 108 m/sec = 3.00 x 1010 cm/sec a. Which photon of electromagnetic radiation below would have the longer wavelength? Convert both values to meters. -1 = 3500 cm = 4 x 1014 Hz = (1/) = (c / ) = (1/ ) = (3.0 x 108 m/s) / (4 x 1014 s-1) = (1/ cm-1)(1 m/100 cm) = 2.9 x 10-6 m = 7.5 x 10-7 m = longer wavelength = lower energy b. Which photon of electromagnetic radiation below would have the higher frequency? Convert both values to Hz. = 400 cm-1 = 300 nm = (1/ ) = 1/ [(400 cm-1)(100 cm / 1 m)] = (c/) 8 -5 9 = 2.5 x 10-5 m = (3.0 x 10 m/s) / (2.5 x 10 nm)(1m / 10 nm) v = (3.0 x 108 m/s) / (300 nm)(1m / 109 nm) = (c/) v = 1.0 x x 1015 s-1 = (3.0 x 108 m/s) / (2.5 x 10-5 m) v = 1.2 x 1013 s-1 higher frequency c. Which photon of electromagnetic radiation below would have the smaller wavenumber? Convert both values to cm-1. = 1 m = 6 x 1010 Hz = (1 / ) -1 = ( / c) = (1 / 1m) = 1 m-1 100 cm = 100 cm-1 100 cm-1 -1 = (6 x 1010 s-1 / 3.0 x 108 m/s) = 200 m-1 -1 1 m -1 = 20,000 cm smaller wavenumber 1 m Problem 2 (p 14) - Order the following photons from lowest to highest energy (first convert each value to kjoules/mole). -
Chemistry: Empirical & Molecular Formulas
Chemistry: Empirical & Molecular Formulas Name______________________ 1) What is the empirical formula for C15H30O5H5? 2) A compound has an empirical formula of C2H4O3N. Its molar mass is 359 g. What is the molecular formula? 3) A compound contains 12.7 g iron & 7.29 g oxygen. Its molar mass is 87.85 g. What is its empirical formula? What is its molecular formula? 4) A compound contains 65.6% carbon, 9.45% hydrogen & 25.0% oxygen. Its molar mass is 1922.85 g. What is its empirical formula? What is its molecular formula? 5) A compound contains 92.2% carbon & 7.75% hydrogen. It has a molar mass of 118 g. What is its empirical formula? What is its molecular formula? 6) A compound has an empirical formula of C2H5O3N. Its molar mass is 454 g. What is its molecular formula? 7) What is the empirical formula for C20H32O4N4? 8) A compound contains 69.6% carbon, 9.76% hydrogen & 20.6% oxygen. Its molar mass is 465.72 g. What is its empirical formula? What is its molecular formula? 9) A compound contains 42.044 g carbon & 7.956 g hydrogen. Its molar mass is 114.26 g. What is its empirical formula? What is its molecular formula? 10) A compound contains 30.79 g copper & 19.31 g oxygen. Its molar mass is 207 g. What is its empirical formula? What is its molecular formula? 11) A compound contains 40.9% carbon, 4.58% hydrogen & 54.5% oxygen. Its molar mass is 176.1 g. What is its empirical formula? What is its molecular formula? 12) A compound has an empirical formula of CH2O & a gram molecular mass of 180.16 g. -
WS 4.2: Empirical Formula Problems
Name: Answer Key Period: ______ Date: __________ Chem B odds for HW and evens for review WS 4.2: Empirical Formula Problems Directions: Determine the empirical formula for the following substances. If a molecular formula cannot be reduced, write “cannot be reduced in the box for empirical formula” Molecular Formula Empirical Formula Molecular Formula Empirical Formula 1) C6H6 CH 2) C10H18 C5H9 3) C8H18 C4H9 4) C7H15O2 Not reducible 5) WO2 Not reducible 6) N2H4 NH2 7) C2H6O2 CH3O 8) P3F6 PF2 9) X39Y13 X3Y 10) IF5 Not reducible 11) C4H10 C2H5 12) N2O5 Not reducible 13) C6H12O6 CH2O 14) N2O4 NO2 15) P2F4 PF2 16) SF6 Not reducible 17) SO3 Not reducible 18) N2Cl4 NCl2 19) N2Br4 NBr2 20) P2O5 Not reducible Directions: Solve the following problems. You may need to use a separate sheet of paper. 1) What is the empirical formula for a compound which 3) Barry Um has a sample of a compound which weighs 200 contains 0.0134 g of iron, 0.00769 g of sulfur and 0.0115 g of grams and contains only carbon, hydrogen, oxygen and oxygen? nitrogen. By analysis, he finds that it contains 97.56 grams of carbon, 4.878 g of hydrogen, 52.03 g of oxygen and 45.53 g of nitrogen. Find its empirical formula. 3 FeSO C5H3N2O2 2) A compound is found to contain 53.7 % iron and 46.27 % sulfur. Find its empirical formula. 4) What is the empirical formula for a compound which contains 80.3% zinc and the rest is oxygen? Fe2S3 ZnO 5) Rubbing alcohol was found to contain 60.0 % carbon, 13.4 9) Give the name and empirical formula of a compound % hydrogen, and the remaining mass was due to oxygen. -
2. Molecular Stucture/Basic Spectroscopy the Electromagnetic Spectrum
2. Molecular stucture/Basic spectroscopy The electromagnetic spectrum Spectral region fooatocadr atomic and molecular spectroscopy E. Hecht (2nd Ed.) Optics, Addison-Wesley Publishing Company,1987 Per-Erik Bengtsson Spectral regions Mo lecu lar spec troscopy o ften dea ls w ith ra dia tion in the ultraviolet (UV), visible, and infrared (IR) spectltral reg ions. • The visible region is from 400 nm – 700 nm • The ultraviolet region is below 400 nm • The infrared region is above 700 nm. 400 nm 500 nm 600 nm 700 nm Spectroscopy: That part of science which uses emission and/or absorption of radiation to deduce atomic/molecular properties Per-Erik Bengtsson Some basics about spectroscopy E = Energy difference = c /c h = Planck's constant, 6.63 10-34 Js ergy nn = Frequency E hn = h/hc /l E = h = hc / c = Velocity of light, 3.0 108 m/s = Wavelength 0 Often the wave number, , is used to express energy. The unit is cm-1. = E / hc = 1/ Example The energy difference between two states in the OH-molecule is 35714 cm-1. Which wavelength is needed to excite the molecule? Answer = 1/ =35714 cm -1 = 1/ = 280 nm. Other ways of expressing this energy: E = hc/ = 656.5 10-19 J E / h = c/ = 9.7 1014 Hz Per-Erik Bengtsson Species in combustion Combustion involves a large number of species Atoms oxygen (O), hydrogen (H), etc. formed by dissociation at high temperatures Diatomic molecules nitrogen (N2), oxygen (O2) carbon monoxide (CO), hydrogen (H2) nitr icoxide (NO), hy droxy l (OH), CH, e tc. -
H2CS) and Its Thiohydroxycarbene Isomer (HCSH
A chemical dynamics study on the gas phase formation of thioformaldehyde (H2CS) and its thiohydroxycarbene isomer (HCSH) Srinivas Doddipatlaa, Chao Hea, Ralf I. Kaisera,1, Yuheng Luoa, Rui Suna,1, Galiya R. Galimovab, Alexander M. Mebelb,1, and Tom J. Millarc,1 aDepartment of Chemistry, University of Hawai’iatManoa, Honolulu, HI 96822; bDepartment of Chemistry and Biochemistry, Florida International University, Miami, FL 33199; and cSchool of Mathematics and Physics, Queen’s University Belfast, Belfast BT7 1NN, Northern Ireland, United Kingdom Edited by Stephen J. Benkovic, The Pennsylvania State University, University Park, PA, and approved August 4, 2020 (received for review March 13, 2020) Complex organosulfur molecules are ubiquitous in interstellar molecular sulfur dioxide (SO2) (21) and sulfur (S8) (22). The second phase clouds, but their fundamental formation mechanisms have remained commences with the formation of the central protostars. Tempera- largely elusive. These processes are of critical importance in initiating a tures increase up to 300 K, and sublimation of the (sulfur-bearing) series of elementary chemical reactions, leading eventually to organo- molecules from the grains takes over (20). The subsequent gas-phase sulfur molecules—among them potential precursors to iron-sulfide chemistry exploits complex reaction networks of ion–molecule and grains and to astrobiologically important molecules, such as the amino neutral–neutral reactions (17) with models postulating that the very acid cysteine. Here, we reveal through laboratory experiments, first sulfur–carbon bonds are formed via reactions involving methyl electronic-structure theory, quasi-classical trajectory studies, and astro- radicals (CH3)andcarbene(CH2) with atomic sulfur (S) leading to chemical modeling that the organosulfur chemistry can be initiated in carbonyl monosulfide and thioformaldehyde, respectively (18). -
Ambient Water Quality Criteria for Polycyclic Aromatic Hydrocarbons (Pahs)
Ambient Water Quality Criteria For Polycyclic Aromatic Hydrocarbons (PAHs) Ministry of Environment, Lands and Parks Province of British Columbia N. K. Nagpal, Ph.D. Water Quality Branch Water Management Division February, 1993 ACKNOWLEDGEMENTS The author is indebted to the following individual and agencies for providing valuable comments during the preparation of this document. Dr. Ray Copes BC. Ministry of Health, Victoria, BC. Dr. G. R. Fox Environmental Protection Div., BC. MOELP, Victoria, BC. Mr. L. W. Pommen Water Quality Branch, BC. MOELP, Victoria, BC. Mr. R. J. Rocchini Water Quality Branch, BC. MOELP, Victoria, BC. Ms. Sherry Smith Eco-Health Branch, Conservation and Protection, Environment Canada, Hull, Quebec Mr. Scott Teed Eco-Health Branch, Conservation and Protection, Environment Canada, Hull, Quebec Ms. Bev Raymond Integrated Programs Branch, Inland Waters, Environment Canada, North Vancouver, BC. 1.0 INTRODUCTION Polycyclic aromatic hydrocarbons (PAHs) are organic compounds which are non- essential for the growth of plants, animals or humans; yet, they are ubiquitous in the environment. When present in sufficient quantity in the environment, certain PAHs are toxic and carcinogenic to plants, animals and humans. This document discusses the characteristics of PAHs and their effects on various water uses, which include drinking Ministry of Environment Water Protection and Sustainability Branch Mailing Address: Telephone: 250 387-9481 Environmental Sustainability PO Box 9362 Facsimile: 250 356-1202 and Strategic Policy Division Stn Prov Govt Website: www.gov.bc.ca/water Victoria BC V8W 9M2 water, aquatic life, wildlife, livestock watering, irrigation, recreation and aesthetics, and industrial water supplies. A significant portion of this document discusses the effects of PAHs upon aquatic life, due to its sensitivity to PAHs. -
Empirical and Molecular Formula Notes • the Empirical Formula of A
Empirical and Molecular Formula Notes The empirical formula of a compound shows the ratio of elements present in a compound The molecular formula of a compound shows how many atoms of each element are present in a molecule of a compound. o Example: the compound butene has a molecular formula of C4H8. The empirical formula of butene is CH2 because there is a 1:2 ratio of carbon atoms to hydrogen atoms. Finding the molecular formula when given the empirical formula The molecular formula is just a multiple of the empirical formula. Take a look at butene: o CH2 x n = C4H8 so n=4. What is the molar mass of butene? . If the empirical formula of a compound is CH2, then you can find the molar mass of the empirical formula: 12.0+ 2(1.0) = 14.0 g/mol . 14.0 g/mol x 4 = 56 g/mol What if I have a compound with an empirical formula of CH2 that has a molar mass of 84 g/mol. What is the molecular formula of this compound? o 14.0 g/mol x n = 84 g/mol so n = 6 o CH2 x 6 = C6H12 Try a few: 1. What is the empirical formula of C8H10? C6H12O6? 2. What is the molecular formula of a molecule that has an empirical formula of NO2 and a molar mass of 92 g/mol? 3. Consider a molecule that has an empirical formula of SO3 and a molecular formula of S3O9. What is the molar mass of the molecule? Calculating empirical formula from percent composition Answer this question: What is the empirical formula of a compound that contains 25.53% Mg and 74.47% Cl? Steps: 1. -
The Life and Times of Carbon, Student Workbook
ELL Chemistry Assignment # 2 Name: __________________________________ Period: Teacher:_____________________ Collecting Carbon Lesson 1 | page 1 of 4 Where Can We Find Carbon? Carbon compounds are take up carbon dioxide from three-fourths of the dry weight everywhere around us. They the air, and use photosynthesis of plants is carbohydrates. In are in our foods, plastics, soils, to turn carbon dioxide into other words, when you look at in water, in the air, and in our carbohydrates. Carbohydrates plant matter (the stem, leaves, bodies. Carbon compounds can are carbon compounds that roots, and grains) you are come in three physical forms: store energy in the forms we call looking largely at carbohydrates. gas, liquid, and solid. Plants “starches” and “sugars.” About Animals (including humans) get their carbohydrates by eating plants, but they do not store much of what they consume. In fact, less than 1% of the body weight of animals is made up of carbohydrates. The main forms of carbon are: nonliving (abiotic) in rocks, soils, and sediments, and in water, such as bicarbonate, carbonate; living (biotic), such as plant and animal matter and dead organic matter; and carbon-based gases, such as carbon dioxide (CO2), methane (CH4), and carbon monoxide (CO). Chemists use a special system to describe compounds. They use a chemical formula of symbols that indicate the elements that make up chemical compounds. A chemical formula is also called a “molecular formula.” The chemical formula of carbon dioxide is CO2 indicating one carbon atom bonded to two oxygen atoms. The symbol for carbon is C; for hydrogen is H; for oxygen is O; for silica is Si. -
Ijmp.Jor.Br V
INDEPENDENT JOURNAL OF MANAGEMENT & PRODUCTION (IJM&P) http://www.ijmp.jor.br v. 10, n. 8, Special Edition Seng 2019 ISSN: 2236-269X DOI: 10.14807/ijmp.v10i8.1046 A NEW HYPOTHESIS ABOUT THE NUCLEAR HYDROGEN STRUCTURE Relly Victoria Virgil Petrescu IFToMM, Romania E-mail: [email protected] Raffaella Aversa University of Naples, Italy E-mail: [email protected] Antonio Apicella University of Naples, Italy E-mail: [email protected] Taher M. Abu-Lebdeh North Carolina A and T State Univesity, United States E-mail: [email protected] Florian Ion Tiberiu Petrescu IFToMM, Romania E-mail: [email protected] Submission: 5/3/2019 Accept: 5/20/2019 ABSTRACT In other papers already presented on the structure and dimensions of elemental hydrogen, the elementary particle dynamics was taken into account in order to be able to determine the size of the hydrogen. This new work, one comes back with a new dynamic hypothesis designed to fundamentally change again the dynamic particle size due to the impulse influence of the particle. Until now it has been assumed that the impulse of an elementary particle is equal to the mass of the particle multiplied by its velocity, but in reality, the impulse definition is different, which is derived from the translational kinetic energy in a rapport of its velocity. This produces an additional condensation of matter in its elemental form. Keywords: Particle structure; Impulse; Condensed matter. [http://creativecommons.org/licenses/by/3.0/us/] Licensed under a Creative Commons Attribution 3.0 United States License 1749 INDEPENDENT JOURNAL OF MANAGEMENT & PRODUCTION (IJM&P) http://www.ijmp.jor.br v.