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Octal & Number Systems Digital Electronics Lesson 2.4 Specific Combo Circuits & Misc Topics

What, More Number Systems? Why do we need more number systems? • Humans understand

Check out my ten digits ! • Digital electronics (computers) understand binary

Octal & Hexadecimal • Since computers have 32, 64, and even 128 busses, displaying numbers in binary is cumbersome. Number Systems • on a 32 bit data bus would look like the following: 0110 1001 0111 0001 0011 0100 1100 1010 • Hexadecimal (base 16) and octal (base 8) number systems are Digital Electronics used to represent binary data in a more compact form. • This presentation will present an overview of the process for converting numbers between the decimal number system and the hexadecimal & octal number systems. 2

Converting To and From Decimal Counting . . . 2, 8, 10, 16

Decimal Binary Octal Hexadecimal 0 00000 0 0 1 00001 1 1 Decimal10 2 00010 2 2 3 00011 3 3 0 1 2 3 4 5 6 7 8 9 Successive Weighted 4 00100 4 4 Division Multiplication 5 00101 5 5 Weighted Successive Multiplication Division 6 00110 6 6

Successive Weighted 7 00111 7 7 Division Multiplication 8 01000 10 8 Octal 9 01001 11 9 8 Hexadecimal16 10 01010 12 A 0 1 2 3 4 5 6 7 8 9 A B E F 0 1 2 3 4 5 6 7 11 01011 13 B Binary2 12 01100 14 C 13 01101 15 D 0 1 14 01110 16 E 15 01111 17 F 16 10000 20 10 17 10001 21 11 3 18 10010 22 12 4 19 10011 23 13

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Conversion Process Decimal ↔ BaseN Review: Decimal ↔ Binary (Any base including Binary , Octal , Hexidecimal ) 2 8 16

Successive Successive Division Division

a) Divide the decimal number by 2; the remainder is the LSB of the binary a) Divide the decimal number by N; the remainder is the LSB of the ANY number. BASE Number . b) If the quotation is zero, the conversion is complete. Otherwise repeat step b) If the quotient is zero, the conversion is complete. Otherwise repeat step (a) using the quotation as the decimal number. The new remainder is the (a) using the quotient as the decimal number. The new remainder is the next most significant bit of the . next most significant bit of the ANY BASE number.

Weighted Weighted Multiplication Multiplication

a) Multiply each bit of the binary number by its corresponding bit-weighting a) Multiply each bit of the ANY BASE number by its corresponding bit- factor (i.e., Bit-0→20=1; Bit-1→21=2; Bit-2→22=4; etc). weighting factor (i.e., Bit-0→N0; Bit-1→N1; Bit-2→N2; etc). b) Sum up all of the products in step (a) to get the decimal number. b) Sum up all of the products in step (a) to get the decimal number. 5 6

Decimal ↔ Octal Conversion Example: Dec → Octal

The Process: Successive Division Example:

• Divide the decimal number by 8; the remainder is the LSB of the octal Convert the decimal number 18910 into its octal equivalent. number . • If the quotation is zero, the conversion is complete. Otherwise repeat step (a) using the quotation as the decimal number. The new remainder is the next most significant bit of the octal number.

Example:

Convert the decimal number 9410 into its octal equivalent.

11 8 94 r  6  LSB

1  9410 = 1368 8 11 r  3

0 8 1 r  1  MSB 7 8

Project Lead The Way, Inc. Copyright 2009 2 Octal & Hexadecimal Number Systems Digital Electronics Lesson 2.4 Specific Combo Circuits & Misc Topics

Example: Dec → Octal Octal ↔ Decimal Process

Example: The Process: Weighted Multiplication

Convert the decimal number 18910 into its octal equivalent. • Multiply each bit of the Octal Number by its corresponding bit- weighting factor (i.e., Bit-0→80=1; Bit-1→81=8; Bit-2→82=64; etc.). Solution: • Sum up all of the products in step (a) to get the decimal number.

23 8 189 r  5  LSB Example: Convert the octal number 1368 into its decimal equivalent. 2  18910 = 2758 8 23 r  7

0 1 3 6 8 2 r  2  MSB 82 81 80 Bit-Weighting  136 8 = 9410 64 8 1 Factors

64 + 24 + 6 = 9410 9 10

Example: Octal → Dec Example: Octal → Dec

Example: Example:

Convert the octal number 1348 into its decimal equivalent. Convert the octal number 1348 into its decimal equivalent.

Solution: 1 3 4

82 81 80  134 = 92 64 8 1 8 10

64 + 24 + 4 = 9210

11 12

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Decimal ↔ Hexadecimal Conversion Example: Dec → Hex

The Process: Successive Division Example:

• Divide the decimal number by 16; the remainder is the LSB of the Convert the decimal number 42910 into its hexadecimal equivalent. hexadecimal number. • If the quotation is zero, the conversion is complete. Otherwise repeat step (a) using the quotation as the decimal number. The new remainder is the next most significant bit of the hexadecimal number. Example:

Convert the decimal number 9410 into its hexadecimal equivalent.

5 16 94 r  E  LSB

0  94 = 5E 16 5 r  5  MSB 10 16 13 14

Example: Dec → Hex Hexadecimal ↔ Decimal Process

Example: The Process: Weighted Multiplication

Convert the decimal number 42910 into its hexadecimal equivalent. • Multiply each bit of the hexadecimal number by its corresponding bit-weighting factor (i.e., Bit-0→160=1; Bit-1→161=16; Bit- 2→162=256; etc.). Solution: • Sum up all of the products in step (a) to get the decimal number. 26 16 429 r  D (13)  LSB Example:

1 Convert the octal number 5E16 into its decimal equivalent. 16 26 r  A (10)  42910 = 1AD16 = 1ADH

0 5 E 16 1 r  1  MSB 161 160  5E = 94 Bit-Weighting 16 10 16 1 Factors

80 + 14 = 9410

15 16

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Example: Hex → Dec Example: Hex → Dec

Example: Example:

Convert the hexadecimal number B2EH into its decimal equivalent. Convert the hexadecimal number B2EH into its decimal equivalent.

Solution: B 2 E

162 161 160  B2E = 2862 256 16 1 H 10

2816 + 32 + 14 = 286210

17 18

Example: Hex → Octal Example: Hex → Octal

Example: Example:

Convert the hexadecimal number 5AH into its octal equivalent. Convert the hexadecimal number 5AH into its octal equivalent. Solution: First convert the hexadecimal number into its decimal equivalent, then convert the decimal number into its octal equivalent. 11 5 A 8 90 r  2  LSB 161 160 1 16 1 8 11 r  3 0 80 + 10 = 9010 8 1 r  1  MSB

19  5AH = 1328 20

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Example: Octal → Binary Example: Octal → Binary

Example: Example:

Convert the octal number 1328 into its binary equivalent. Convert the octal number 1328 into its binary equivalent. Solution: First convert the octal number into its decimal equivalent, then convert the decimal number into its binary equivalent. 45 1 3 2 2 90 r  0  LSB 82 81 80 22 2 45 r  1 64 8 1 11 2 22 r  0  1328 = 10110102 64 + 24 + 2 = 90 5 10 2 11 r  1 2 2 5 r  1 1 2 2 r  0 21 0 22 2 1 r  1  MSB

Binary ↔ Octal ↔ Hex Shortcut Example: Binary ↔ Octal ↔ Hex Because binary, octal, and hex number systems are all powers of two Example: (which is the reason we use them) there is a relationship that we can exploit to make conversion easier. Using the shortcut technique, convert the hexadecimal number A616 into its binary and octal equivalent. Use your to check your 1 0 1 1 0 1 0 2 = 132 8 = 5A H answers. To convert directly between binary and octal, group the binary into sets of 3 (because 23 = 8). You may need to pad with leading zeros.

0 0 1 0 1 1 0 1 0 2 = 1 3 2 8

1 3 2 0 0 1 0 1 1 0 1 0 To convert directly between binary and hexadecimal number systems, group the binary bits into sets of 4 (because 24 = 16). You may need to pad with leading zeros. 0 1 0 1 1 0 1 0 = 5 A 2 16 23 24 5 A 0 1 0 1 1 0 1 0

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Example: Binary ↔ Octal ↔ Hex

Example:

Using the shortcut technique, convert the hexadecimal number A616 into its binary & octal equivalent. Use your calculator to check your answers. Solution: First convert the hexadecimal number into binary by expanding the hexadecimal digits into binary groups of (4).

A 6 16

 A616 = 101001102 1 0 1 0 0 1 1 0 Convert the binary number into octal by grouping the binary bits into groups of (3).

0 1 0 1 0 0 1 1 0  101001102 = 2468

25 2 4 6

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