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13.021 – Marine Hydrodynamics, Fall 2004 Lecture 14

Copyright °c 2004 MIT - Department of Ocean Engineering, All rights reserved.

13.021 - Marine Hydrodynamics Lecture 14

4.0 - Real Fluid Effects (ν 6= 0)

Potential Flow Theory: = 0.

Observed experiment (real fluid ν << 1 but 6= 0): Drag 6= 0.

4.1 - Drag on a Bluff Body Consider a sphere of diameter d

D(Drag) ν U ρ

D 2 Dimensional Analysis: CD = 1 2 where S is the projected area πd /4 and the in 2 ρU S this case is: Ud Re = ν

The Drag coefficient is a function of the Reynolds number: CD = CD(Re)

1 CD

0.5

0.25

Re 3x10 5

2 Drag coefficient (CD) for a sphere for Re > 10 .

Total Drag = pressure drag + skin friction drag (profile drag) D (form drag) (shear drag, viscous drag) | {z } | {z } Drag force Drag dueRR to tangential due to normal stress ° τttdSˆ RRstress (pressure) ° pndSˆ where tˆ is the tangential unit vector and τt is the surface shear stress.

For a bluff body ⇔ appreciable flow separation/wake behind the body. Then, pressure drag >> friction drag.

Flowseparation

RealFlow PotentialFlow

2 D ≈C ( frontal area ) (P − P ) D µ ¶ s ∞ 1 = C S ρU 2 D 2

In general CD = CD (Re) - for typical bluff body, e.g. sphere. There are two main regimes of interest:

∼ 5 1. Laminar regime: Reno separation < Re < Recritical (= 3 × 10 ) for a smooth sphere

with perfect inflow

Separationpt

• Widewake LaminarWake • Earlyseparation Drag Width~Diameter • ‘Large’C =O(1) D

Stagnationpt Separationpt NoStagnationpt

2. Turbulent Regime: Re > Recritical

Separationpt

TurbulentWake • Narrowwake Width~Diameter/2 • delayedseparation • SmallerC D

Stagnationpt Separationpt NoStagnationpt

3 Consider a cylinder:

L U

D/L CD = 1 2 2 ρU d 2 For Re > 10 , the drag coefficient (CD) for a cylinder is:

CD

1.2

0.6

Re 3x10 5

For bodies with fixed separation points, the Drag coefficient is ≈ constant. Consider a flat plate or disc:

Separationpt

Separationpt

4 CD ≈ 1.2

Boundary Layers and flow separation

µ * ¶∗ L ∂v ¡ ¢∗ ν ¡ ¢∗ + *v · ∇*v = ... + ∇2*v UT ∂t |{z}UL 1 ReL

For most flows of interest to us ReL >> 1, i.e., can be ignored if U, L govern the problem, thus potential flow can be assumed. In the context of potential flow theory, drag = 0! Potential flow (no τij) ∂u allow slip at boundary, but in reality,no slip on boundary, otherwise τ ∼ ν ∂y → ∞ at the boundary.

Prandtl: There is some length scale δ ( thickness δ << L) over which velocity goes from zero on the wall to the potential flow velocity U outside the boundary layer.

U u=U

U δ<

u=0

Estimate δ: inside the boundary layer, viscous effects are of the same order as the inertial effects. r ∂2U ∂U U U 2 ν δ2 δ ν 1 √ ν 2 ∼ U → ν 2 ∼ → ∼ 2 → ∼ = << 1 As ReL ↑, δ ↓ ∂y ∂x δ L UL L L UL ReL δ Generally: ReL >> 1, L << 1, thus potential flow is good outside a very thin boundary layer (i.e., provided no separation - a real fluid effect). For Reynolds number not >> 1(Re ∼ O(1)), then thick boundary layer ( δ ∼ O(L)) and Prandtl’s boundary layer idea not useful. If separation occurs, then boundary layer idea is not valid.

5 Boundary layers help understand flow separation.

Example: Flow past a circle. U is the potential flow tangential velocity on the circle and x is the distance along the circle surface. dp dU Steady N. S. equation: = −ρU dx dx

x y

U=U max

Uo U=0 U=0

dU du dx > 0 Acceleration dx < 0 Deceleration dp dp dx < 0 ‘Favorable’ pressure gradient dx > 0 ‘Adverse’ pressure gradient

6 X3 X2 X4 X1 X5

X >X X=X y 2 1 y 1

P P p p

u u G G ω U2>U 1 ω U1 P>p Flowisbeing pushedtoattach

X > X X >X y 3 2 y 4 3

P P p

u u U3 U2 ∂u G U4 U3 = ,0 ω = 0 τ ∂y 3>0 τ4=0

X4isdefinedasthepointof separation

X >X y 5 4

P

u U5 U4

SeparatedFlow τ5<0 Flowreversal

A better way to think about separation is in terms of diffusion of vorticity:

7 ω=0outsideB.L. y y

P P

ω ω ω ω (y) 4=0 (y) ω1 2 ω3 ωremoved fromfluid ωadded tofluid bydiffusion

Think of vorticity as heat; ω(y) is like a temperature distribution. Note:

* * DV * Dω = ... + ν∇2V and = ... + ν∇2ω* Dt Dt

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