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General: When • , ¯ (inversely proportional) Formula: P·V = constant or P1V1 = P2V2

Restrictions: P1 and P2 must be in the same units 12 • The Laws V1 and V2 must be in the same units Boyle’ Law (P and V) (1 of 8) Convert using conversion factors using the fact that 1 atm = 760 mmHg = 760 = 101.3 kPa = 14.7 psi lb psi = in2 101.3 kPa Example: 730 mmHg = 97.3 kPa 760 mmHg

Graphically:

V 1/V 12 • The Boyle’s Law Lab (2 of 8) P P In our lab, we had to add the atmospheric to our because gauges only measure the pressure ABOVE . 1 Consistent (“ good”) data form a straight line (P vs. ). V

K = ° + 273 °C = – 273 Examples: 0 °C + 273 = 237 K 25 °C + 273 = 298 K 100 °C + 273 = 373 K 12 • The Gas Laws 300 K – 273 = –27 °C Scale (3 of 8) The Kelvin scale is used in gas law problems because the pressure and of a gas depend on the kinetic or of the particles. The Kelvin scale is proportional to the KE of the particles… that is, 0 K () means 0 . 0 °C is simply the point of water.

Charles’ Law General: When • , V• (directly proportional) V V V Formula: = constant or 1 = 2 T T1 T2 12 • The Gas Laws Restrictions: T must be in Charles’ Law (V and T) V1 and V2 must be in the same units Gay-Lussac’s Law (P and T) Gay-Lussac’s Law (4 of 8) General: When T• , P• (directly proportional) P P P Formula: = constant or 1 = 2 T T1 T2 Restrictions: T must be in Kelvins P1 and P2 must be in the same units P·V P ·V P ·V Formula: = constant or 1 1 = 2 2 T T1 T2 Restrictions: T must be in Kelvins V1 and V2 must be in the same units 12 • The Gas Laws P1 and P2 must be in the same units The Combined Gas Law (5 of 8) STP (“standard temperature and pressure”) is often used as one of the two conditions T = 0 °C = 273 K P = 1 atm = 760 mmHg = 101.3 kPa Each of the three gas laws is really a special case of this law. Example: If T1 = T2, the law becomes P1V1 = P2V2

Formula: P·V = ··T or PV = nRT where P = pressure V = volume n = number of moles 12 • The Gas Laws R = the constant The T = temperature (in Kelvins) The value of R depends on the P and V units used. (6 of 8) PV R = so you can use the info to calculate R nT (101.3 kPa)(22.4 ) L·kPa R = = 8.31 (1 )(273 K) mol·K L·mmHg L·atm R = 62.4 = 0.0821 mol·K mol·K

When you have a of , you can determine the pressure exerted by each gas separately. This is called the of each gas. Since each gas has the same to cause pressure (see 12 • The Gas Laws card #8) the partial pressure of a gas depends on how ’s Law of Partial Pressure much of the mixture is composed of each gas (in moles) Example: Consider air, a mixture of mostly O2 and N2 (7 of 8) P P moles O2 O2 moles N2 N2 = = moles total Ptotal moles total Ptotal P P P Also: total = O2 + N2 This idea is used when a gas is collected over water P P P P atm = gas + H2O H2O is found on a chart

The gas laws (to 3 significant digits) for all gases… that is, all gases have the same power to cause pressure. At the same temperature, the KE of each gas is the same. 1 2 KE = /2 · … if two particles have different 12 • The Gas Laws , their are also different. So… Why Do All Gases Cause the Same Pressure? 2 Graham’s Law SMALL particles move FAST mv (8 of 8) LARGE particles move SLOWLY mv2 We can use this idea with numbers as well: (Graham’s Law) 2 2 KEA = KEB mAvA = mBvB [another version of this formula is on pg 323 of the text]