Cubelike Puzzles-What Are They and How Do You Solve Them?
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CubeRoot Contents Contents Contents Purple denotes upcoming contents. 1 Preface 2 Signatures of Top Cubers in the World 3 Quotes 4 Photo Albums 5 Getting Started 5.1 Cube History 5.2 WCA Events 5.3 WCA Notation 5.4 WCA Competition Tutorial 5.5 Tips to Cubers 6 Rubik's Cube 6.1 Beginner 6.1.1 LBL Method (Layer-By-Layer) 6.1.2 Finger and Toe Tricks 6.1.3 Optimizing LBL Method 6.1.4 4LLL Algorithms 6.2 Intermediate 进阶 6.2.1 Triggers 6.2.2 How to Get Faster 6.2.3 Practice Tips 6.2.4 CN (Color Neutrality) 6.2.5 Lookahead 6.2.6 CFOP Algorithms 6.2.7 Solve Critiques 3x3 - 12.20 Ao5 6.2.8 Solve Critiques 3x3 - 13.99 Ao5 6.2.9 Cross Algorithms 6.2.10 Xcross Examples 6.2.11 F2L Algorithms 6.2.12 F2L Techniques 6.2.13 Multi-Angle F2L Algorithms 6.2.14 Non-Standard F2L Algorithms 6.2.15 OLL Algorithms, Finger Tricks and Recognition 6.2.16 PLL Algorithms and Finger Tricks 6.2.17 CP Look Ahead 6.2.18 Two-Sided PLL Recognition 6.2.19 Pre-AUF CubeRoot Contents Contents 7 Speedcubing Advice 7.1 How To Get Faster 7.2 Competition Performance 7.3 Cube Maintenance 8 Speedcubing Thoughts 8.1 Speedcubing Limit 8.2 2018 Plans, Goals and Predictions 8.3 2019 Plans, Goals and Predictions 8.4 Interviewing Feliks Zemdegs on 3.47 3x3 WR Single 9 Advanced - Last Slot and Last Layer 9.1 COLL Algorithms 9.2 CxLL Recognition 9.3 Useful OLLCP Algorithms 9.4 WV Algorithms 9.5 Easy VLS Algorithms 9.6 BLE Algorithms 9.7 Easy CLS Algorithms 9.8 Easy EOLS Algorithms 9.9 VHLS Algorithms 9.10 Easy OLS Algorithms 9.11 ZBLL Algorithms 9.12 ELL Algorithms 9.13 Useful 1LLL Algorithms -
Build a Tetrahedral Kite
Aeronautics Research Mission Directorate Build a Tetrahedral Kite Suggested Grades: 8-12 Activity Overview Time: 90-120 minutes In this activity, you will build a tetrahedral kite from Materials household supplies. • 24 straws (8 inches or less) - NOTE: The straws need to be Steps straight and the same length. If only flexible straws are available, 1. Cut a length of yarn/string 4 feet long. then cut off the flexible portion. • Two or three large spools of 2. Take six straws and place them on a flat surface. cotton string or yarn (approximately 100 feet total) 3. Use your piece of string to join three straws • Scissors together in a triangular shape. On the side where • Hot glue gun and hot glue sticks the two strings are extending from it, one end • Ruler or dowel rod for kite bridle should be approximately 20 inches long, and the • Four pieces of tissue paper (24 x other should be approximately 4 inches long. 18 inches or larger) See Figure 1. • All-purpose glue stick Figure 1 4. Tie these two ends of the string tightly together. Make sure there is no room for the triangle to wiggle. 5. The three straws should form a tight triangle. 6. Cut another 4-inch piece of string. 7. Take one end of the 4-inch string, and tie that end to a corner of the triangle that does not have the string ends extending from it. Figure 2. 8. Add two more straws onto the longest piece of string. 9. Next, take the string that holds the two additional straws and tie it to the end of one of the 4-inch strings to make another tight triangle. -
THE GEOMETRY of PYRAMIDS One of the More Interesting Solid
THE GEOMETRY OF PYRAMIDS One of the more interesting solid structures which has fascinated individuals for thousands of years going all the way back to the ancient Egyptians is the pyramid. It is a structure in which one takes a closed curve in the x-y plane and connects straight lines between every point on this curve and a fixed point P above the centroid of the curve. Classical pyramids such as the structures at Giza have square bases and lateral sides close in form to equilateral triangles. When the closed curve becomes a circle one obtains a cone and this cone becomes a cylindrical rod when point P is moved to infinity. It is our purpose here to discuss the properties of all N sided pyramids including their volume and surface area using only elementary calculus and geometry. Our starting point will be the following sketch- The base represents a regular N sided polygon with side length ‘a’ . The angle between neighboring radial lines r (shown in red) connecting the polygon vertices with its centroid is θ=2π/N. From this it follows, by the law of cosines, that the length r=a/sqrt[2(1- cos(θ))] . The area of the iscosolis triangle of sides r-a-r is- a a 2 a 2 1 cos( ) A r 2 T 2 4 4 (1 cos( ) From this we have that the area of the N sided polygon and hence the pyramid base will be- 2 2 1 cos( ) Na A N base 2 4 1 cos( ) N 2 It readily follows from this result that a square base N=4 has area Abase=a and a hexagon 2 base N=6 yields Abase= 3sqrt(3)a /2. -
Kurze Geschichte Des Würfels (Unknown Author)
Kurze Geschichte des Würfels (unknown author) ........................................................................................ 1 Erno Rubik .......................................................................................................................................... 1 Die Herstellung des Original-Rubik-Würfels in Ungarn ................................................................ 3 Die Rubik-Würfel-Weltmeisterschaft ............................................................................................... 6 A Rubik's Cube Chronology (Mark Longridge) .............................................................................................. 8 From five thousand to fifteen millions ....................................................................................................... 11 Toy-BUSINESS KONSUMEX .......................................................................................................................... 14 HISTORY (Nagy Olivér) ................................................................................................................................ 15 Kurze Geschichte des Würfels (unknown author) Jede Erfindung hat ein offizielles Geburtsdatum. Das Geburtsdatum des Würfels ist 1974, das Jahr, in dem der erste funktionsfähige Prototyp entstand und die erste Patentanmeldung entworfen wurde. Der Geburtsort war Budapest, die Hauptstadt Ungarns. Der Name des Erfinders ist inzwischen überall bekannt. Damals war Erno Rubik ein Dozent an der Fakultät für Innenarchitektur an der Akademie -
Math 366 Lecture Notes Section 11.4 – Geometry in Three Dimensions
Section 11-4 Math 366 Lecture Notes Section 11.4 – Geometry in Three Dimensions Simple Closed Surfaces A simple closed surface has exactly one interior, no holes, and is hollow. A sphere is the set of all points at a given distance from a given point, the center . A sphere is a simple closed surface. A solid is a simple closed surface with all interior points. (see p. 726) A polyhedron is a simple closed surface made up of polygonal regions, or faces . The vertices of the polygonal regions are the vertices of the polyhedron, and the sides of each polygonal region are the edges of the polyhedron. (see p. 726-727) A prism is a polyhedron in which two congruent faces lie in parallel planes and the other faces are bounded by parallelograms. The parallel faces of a prism are the bases of the prism. A prism is usually names after its bases. The faces other than the bases are the lateral faces of a prism. A right prism is one in which the lateral faces are all bounded by rectangles. An oblique prism is one in which some of the lateral faces are not bounded by rectangles. To draw a prism: 1) Draw one of the bases. 2) Draw vertical segments of equal length from each vertex. 3) Connect the bottom endpoints to form the second base. Use dashed segments for edges that cannot be seen. A pyramid is a polyhedron determined by a polygon and a point not in the plane of the polygon. The pyramid consists of the triangular regions determined by the point and each pair of consecutive vertices of the polygon and the polygonal region determined by the polygon. -
VOLUME of POLYHEDRA USING a TETRAHEDRON BREAKUP We
VOLUME OF POLYHEDRA USING A TETRAHEDRON BREAKUP We have shown in an earlier note that any two dimensional polygon of N sides may be broken up into N-2 triangles T by drawing N-3 lines L connecting every second vertex. Thus the irregular pentagon shown has N=5,T=3, and L=2- With this information, one is at once led to the question-“ How can the volume of any polyhedron in 3D be determined using a set of smaller 3D volume elements”. These smaller 3D eelements are likely to be tetrahedra . This leads one to the conjecture that – A polyhedron with more four faces can have its volume represented by the sum of a certain number of sub-tetrahedra. The volume of any tetrahedron is given by the scalar triple product |V1xV2∙V3|/6, where the three Vs are vector representations of the three edges of the tetrahedron emanating from the same vertex. Here is a picture of one of these tetrahedra- Note that the base area of such a tetrahedron is given by |V1xV2]/2. When this area is multiplied by 1/3 of the height related to the third vector one finds the volume of any tetrahedron given by- x1 y1 z1 (V1xV2 ) V3 Abs Vol = x y z 6 6 2 2 2 x3 y3 z3 , where x,y, and z are the vector components. The next question which arises is how many tetrahedra are required to completely fill a polyhedron? We can arrive at an answer by looking at several different examples. Starting with one of the simplest examples consider the double-tetrahedron shown- It is clear that the entire volume can be generated by two equal volume tetrahedra whose vertexes are placed at [0,0,sqrt(2/3)] and [0,0,-sqrt(2/3)]. -
Mathematics of the Rubik's Cube
Mathematics of the Rubik's cube Associate Professor W. D. Joyner Spring Semester, 1996{7 2 \By and large it is uniformly true that in mathematics that there is a time lapse between a mathematical discovery and the moment it becomes useful; and that this lapse can be anything from 30 to 100 years, in some cases even more; and that the whole system seems to function without any direction, without any reference to usefulness, and without any desire to do things which are useful." John von Neumann COLLECTED WORKS, VI, p. 489 For more mathematical quotes, see the first page of each chapter below, [M], [S] or the www page at http://math.furman.edu/~mwoodard/mquot. html 3 \There are some things which cannot be learned quickly, and time, which is all we have, must be paid heavily for their acquiring. They are the very simplest things, and because it takes a man's life to know them the little new that each man gets from life is very costly and the only heritage he has to leave." Ernest Hemingway (From A. E. Hotchner, PAPA HEMMINGWAY, Random House, NY, 1966) 4 Contents 0 Introduction 13 1 Logic and sets 15 1.1 Logic................................ 15 1.1.1 Expressing an everyday sentence symbolically..... 18 1.2 Sets................................ 19 2 Functions, matrices, relations and counting 23 2.1 Functions............................. 23 2.2 Functions on vectors....................... 28 2.2.1 History........................... 28 2.2.2 3 × 3 matrices....................... 29 2.2.3 Matrix multiplication, inverses.............. 30 2.2.4 Muliplication and inverses............... -
The Mars Pentad Time Pyramids the Quantum Space Time Fractal Harmonic Codex the Pentagonal Pyramid
The Mars Pentad Time Pyramids The Quantum Space Time Fractal Harmonic Codex The Pentagonal Pyramid Abstract: Early in this author’s labors while attempting to create the original Mars Pentad Time Pyramids document and pyramid drawings, a failure was experienced trying to develop a pentagonal pyramid with some form of tetrahedral geometry. This pentagonal pyramid is now approached again and refined to this tetrahedral criteria, creating tetrahedral angles in the pentagonal pyramid, and pentagonal [54] degree angles in the pentagon base for the pyramid. In the process another fine pentagonal pyramid was developed with pure pentagonal geometries using the value for ancient Egyptian Pyramid Pi = [22 / 7] = [aPi]. Also used is standard modern Pi and modern Phi in one of the two pyramids shown. Introduction: Achieved are two Pentagonal Pyramids: One creates tetrahedral angle [54 .735~] in the Side Angle {not the Side Face Angle}, using a novel height of the value of tetrahedral angle [19 .47122061] / by [5], and then the reverse tetrahedral angle is accomplished with the same tetrahedral [19 .47122061] angle value as the height, but “Harmonic Codexed” to [1 .947122061]! This achievement of using the second height mentioned, proves aspects of the Quantum Space Time Fractal Harmonic Codex. Also used is Height = [2], which replicates the [36] and [54] degree angles in the pentagon base to the Side Angles of the Pentagonal Pyramid. I have come to understand that there is not a “perfect” pentagonal pyramid. No matter what mathematical constants or geometry values used, there will be a slight factor of error inherent in the designs trying to attain tetrahedra. -
Breaking an Old Code -And Beating It to Pieces
Breaking an Old Code -And beating it to pieces Daniel Vu - 1 - Table of Contents About the Author................................................ - 4 - Notation ............................................................... - 5 - Time for Some Cube Math........................................................................... Error! Bookmark not defined. Layer By Layer Method................................... - 10 - Step One- Cross .................................................................................................................................. - 10 - Step Two- Solving the White Corners ................................................................................................. - 11 - Step Three- Solving the Middle Layer................................................................................................. - 11 - Step Four- Orient the Yellow Edges.................................................................................................... - 12 - Step Five- Corner Orientation ............................................................................................................ - 12 - Step Six- Corner Permutation ............................................................................................................. - 13 - Step Seven- Edge Permutation............................................................................................................ - 14 - The Petrus Method........................................... - 17 - Step One- Creating the 2x2x2 Block .................................................................................................. -
Pentagonal Pyramid
Chapter 9 Surfaces and Solids Copyright © Cengage Learning. All rights reserved. Pyramids, Area, and 9.2 Volume Copyright © Cengage Learning. All rights reserved. Pyramids, Area, and Volume The solids (space figures) shown in Figure 9.14 below are pyramids. In Figure 9.14(a), point A is noncoplanar with square base BCDE. In Figure 9.14(b), F is noncoplanar with its base, GHJ. (a) (b) Figure 9.14 3 Pyramids, Area, and Volume In each space pyramid, the noncoplanar point is joined to each vertex as well as each point of the base. A solid pyramid results when the noncoplanar point is joined both to points on the polygon as well as to points in its interior. Point A is known as the vertex or apex of the square pyramid; likewise, point F is the vertex or apex of the triangular pyramid. The pyramid of Figure 9.14(b) has four triangular faces; for this reason, it is called a tetrahedron. 4 Pyramids, Area, and Volume The pyramid in Figure 9.15 is a pentagonal pyramid. It has vertex K, pentagon LMNPQ for its base, and lateral edges and Although K is called the vertex of the pyramid, there are actually six vertices: K, L, M, N, P, and Q. Figure 9.15 The sides of the base and are base edges. 5 Pyramids, Area, and Volume All lateral faces of a pyramid are triangles; KLM is one of the five lateral faces of the pentagonal pyramid. Including base LMNPQ, this pyramid has a total of six faces. The altitude of the pyramid, of length h, is the line segment from the vertex K perpendicular to the plane of the base. -
Megaminx 1/26/12 3:24 PM
Megaminx 1/26/12 3:24 PM Megaminx http://www.jaapsch.net/puzzles/megaminx.htm Page 1 of 5 Megaminx 1/26/12 3:24 PM This is a variant of the Rubik's cube, in the shape of a dodecahedron. It is a very logical progression from the cube to the dodecahedron, as can be seen from the fact that the mechanism is virtually the same, and that many people invented it simultaneously. To quote from Cubic Circular, Issue 3&4, (David Singmaster, Spring&Summer 1982): "The Magic Dodecahedron has been contemplated for some time. So far I have seen photos or models from: Ben Halpern (USA), Boris Horvat (Yugoslavia), Barry Lockwood (UK) and Miklós Kristóf (Hungary), while Kersten Meier (Germany) sent plans in early 1981. I have heard that Christoph Bandelow and Doctor Moll (Germany) have patents and that Mario Ouellette and Luc Robillard (Canada) have both found mechanisms. The Hungarian version is notable as being in production ... and as having planes closer to the centre so each face has a star pattern." "Uwe Mèffert has bought the Halpern and Meier rights, which were both filed on the same day about a month before Kristóf. However there is an unresolved dispute over the extent of overlap in designs." There are several versions that have been made. The standard megaminx has either 6 colours or 12 colours. The face layers are fairly thin, so the edge pieces have some width to them. A version called the Supernova was made in Hungary, and it has 12 colours and thicker face layers which meet exactly at the middle of an edge. -
How to Solve the Rubik's Cube 03/11/2007 05:07 PM
How to Solve the Rubik's Cube 03/11/2007 05:07 PM Rubik's Revolution Rubik's Cubes & Puzzles Rubik Cube Boston's Wig Store Everything you wanted to know Rubiks Cube 4x4, Keychain & Huge selection of Rubik Cube Great selection & service Serving about the all new electronic Twist In Stock Now-Free Shipping items. the Boston area Rubik’s cube Over $75 eBay.com www.mayswigs.com www.rubiksrevolution.com AwesomeAvenue.biz Ads by Goooooogle Advertise on this site How to Solve the Rubik's Cube This page is featured under Recreation:Games:Puzzles:Rubik's Cube:Solutions in Yahoo! My Home Page | My Blog | My NHL Shootout Stats 2006-2007 There are three translations of this page: Danish (Dansk) (Word Document), Japanese (日本語) (HTML) and Portuguese (Português) (HTML). If you want to translate this page, go ahead. Send me an email when you are done and I will add your translation to this list. So you have a Rubik's Cube, and you've played with it and stared at it and taken it apart...need I go on any further? The following are two complete, fool-proof solutions to solving the cube from absolutely any legal position. Credit goes not to me, but to David Singmaster, who wrote a book in 1980, Notes on Rubik's Magic Cube, which explains pretty much all of what you need to know, plus more. Singmaster wrote about all of these moves except the move for Step 2, which I discovered independently (along with many other people, no doubt). I've updated this page to include a second solution to the cube.