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AP GRAMA / WARD SACHIVALAYAM - 2019
Panchayat Secretary Gr. VI -DIGITAL ASSISTANT
Questions with Detailed Solutions
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AP GRAMA / WARD SACHIVALAYAM - 2019 Panychayat Secretary Gr.VI-Digital Assistant Questions with Detailed Solutions
PART – A (3) Muncipalities Act
(4) Cantonment Boards Act 01. Gautamiputra Satakarni was praised by this 03. Ans: (3) inscription as “Kshatriya Darpa Mardana”.
(1) Nasik Inscription 04. Find out the correct sentence with reference (2) Gandhara Inscription to society (3) Chandraprabha Inscription (1) Society can exist without population (4) Nanaghat Iscription (2) Society is a sovereign body 01. Ans: (1) (3) Society originated prior to the State
(4) Society has territorial boundaries 02. Protem Chairman of the Constituent 04. Ans: (3) Assembly of India is
(1) Rajendra Prasad 05. According to the National Youth Policy, (2) Sarat Chandra Sinha 2014 (NYP 2014), the age group of youth is (3) Sachchidananda Sinha (1) 15 – 29 years (4) Yashwant Sinha (2) 14 – 28 years 02. Ans: (3) (3) 16 – 30 years
(4) 17 – 31 years 03. Another name of the Constitution (74th 05. Ans: (1) Amendment) Act, 1992 is
(1) Nagarapalika Act (2) Panchayati Raj Act
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2 Panchayat Secretary Gr. VI
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3 Digital Assistant _ Question & Solutions
06. An important river in Manipur and Mizoram 10. In a certain code “ FLOWER” is coded as is 36 and SUNFLOWER is coded as 81. Then (1) Kameng how is FOLLOWS coded? (2) Barak (1) 25 (2) 81 (3) Lohit (3) 49 (4) 64 (4) Subansiri 10. Ans: (3) 06. Ans: (2) 11. If P Q implies (P2 + Q2), 07. In Andhra Pradesh, high quality talc then 8 (3 2) =
soapstone is available in Anantapur District (1) 648 (2) 86 near the town of (3) 233 (4) 104 (1) Dharmavaram (2) Kalyandurg 11. Ans: (3) (3) Kadiri (4) Tadipatri 07. Ans: (4) 12. In May 2019, the World Health Organization declared these two countries 08. The Government of Andhra Pradesh has as “malaria-free”. accorded high priority for accelerated (1) Bolivia and Botswana development of tribes by implementing (2) Albania and Angola (1) Technical Development Programmes (3) Bulgaria and Burundi (2) Professional Development Programmes (4) Argentina and Algeria (3) Psychological Development Programmes 12. Ans: (4) (4) Socio-economic Development Programmes 08. Ans: (4) 13. The newly identified 80th organ in the human body is 09. Six smart people can read 12 books in six (1) Mesentery hours. How many books can three of these (2) Interstitium smart people read in nine hours? (3) Jejunum (1) Three (2) Six (4) Cochlear (3) Twelve (4) Nine 13. Ans: (1) 09. Ans: (4)
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14. On 6th July, 2019, this city in India was 16. Ans: (2) recognized and declared as a Heritage city by UNESCO. 17. The Satavahana Kingdom was divided into (1) Madurai – Tamil Nadu Janapadas, Aaharas and Gramas. The (2) Udaipur – Rajasthan Aahara was headed by (3) Jaipur – Rajasthan (1) Amatya (2) Prince (4) Agra – Uttar Pradesh (3) Rajuka (4) Mahamatra 14. Ans: (3) 17. Ans: (1)
15. Recently this country has passed the 18. The hymns of the Vedas are explained in an Protection from Online Falsehoods and orthodox manner in Manipulation Bill 2019 in its Parliament. (1) The Upanishads (1) Singapore (2) The Aranyakas (2) Australia (3) The Brahmanas (3) England (4) The Puranas (4) Denmark 18. Ans: (3) 15. Ans: (1) 19. The Preamble of the Indian Constitution 16. Consider the following statements: declared India as a Republic. In this context, A. Insoluble volatile mixtures like alcohol the term ‘Republic’ denotes the following and benzene are separated by steam sentence: distillation. (1) There will be no hereditary rule
B. Mixtures of solids like KCL and KNO3 (2) The head of the State is a nominated from a salt solution are separated by person fractional crystallization. (3) There will be special status for upper C. Insoluble volatile mixtures like classes acetone and methyl alcohol are (4) Supreme Court exercises control over separated by fractional distillation. Union Executive Which of these statements is/are correct? 19. Ans: (1) (1) A only (2) A and C only (3) B only (4) B and C only
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5 Digital Assistant _ Question & Solutions
20. The type of society found in some backward 24. Skill development/training of construction regions in Africa, Asia and Europe is workers should be considered and pursued (1) Industrial (2) Agrarian as part of the benefits to the workers and (3) Modern (4) Tribal their families. The Andhra Pradesh 20. Ans: (4) Government had indentified the following institution for this purpose: 21. The previous name of the National Council (1) Central Institute of Tool Design of Senior Citizens (NCSC), 2012 is (2) National Institute of Construction (1) National Commission for Experienced Management and Research People (3) Indian Institute of Infrastructure and (2) National Council for Older Persons Construction (3) National Committee for Middle-aged (4) National Academy of Construction Persons 24. Ans: (4) (4) National Corporation for Enlightened People 25. If means +, – means , means , and + 21. Ans: (2) 48436 means , then = 116284 22. In India, Tobacco crop was introduced at (1) 0 (2) 8 first by (3) 12 (4) 16 (1) British traders 25. Ans: (1) (2) Dutch traders (3) French traders cba 26. If a 5 = b: 7 = c : 8, then is equal (4) Portuguese traders a 22. Ans: (4) to (1) 2 (2) 4 23. All newly converted residential schools are 1 (3) 7 (4) being provided the required 4 (1) Educational support 26. Ans: (2) (2) Infrastructural support (3) Moral support (4) Nutritional support 23. Ans: (2)
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6 Panchayat Secretary Gr. VI
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7 Digital Assistant _ Question & Solutions
27. Refer to the graph and answer the question 30. Which of the following is / are correctly
370 matched? 360 Name Date of Assumption of 350 Office 340 A. D.Sanjivaiah – 11.01.1960 330 B. K.Brahmananda Reddy – 25.09.1971 320 Jan Feb Mar Apr May June July C. J.Vengal Rao – 06.03.1978 Consumer Price Index in 2008-09 D. K. Vijaya Bhaskara Reddy – 09.10.1992 In how many month was CPI greater than 350 as per the graph? (1) B only (1) One (2) Two (2) B and C (3) Three (4) Four (3) A and D 27. Ans: (2) (4) C only 30. Ans: (3) 28. Siri, Assistant, Alexa and Cortana are software agents and virtual/voice assistants 31. The Article concerning the State Election that perform certain tasks. The above four Commission is respectively belong to (1) 243 I (2) 243 P (1) Microsoft, Amazon, Google, Apple (3) 324 I (4) 243 K (2) Amazon, Google, Apple, Microsoft 31. Ans: (4) (3) Microsoft, Amazon, Apple, Google (4) Apple, Google, Amazon, Microsoft 32. The last subject in the Eleventh Schedule 28. Ans: (4) added through the Constitution (Seventy – third Amendment) Act, 1992 is 29. The famous philosopher Acharya Nagarjuna (1) Maintenance of Community Assets was in the Court of (2) Regulation of Slaughter houses (1) Yagnasri Satakarni (3) Agriculture (2) Pulomavi – III (4) Urban Planning (3) Satakarni –I 32. Ans: (1) (4) Sri Mukha 29. Ans: (1)
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8 Panchayat Secretary Gr. VI
33. Anubhav Mantapa was established by 36. Ans: (2) Basava for achieving a (1) New spiritual order 37. The source of funding for Andhra Pradesh (2) New religious order State Christian (Minorities) Finance (3) New social order Corporation is (4) New family order (1) The Government of Andhra Pradesh 33. Ans: (3) (2) The Anglo-Indian Community (3) Faith–based Grants 34. Forests that grow under rainfall of over (4) Stewardship Foundation 200cm and annual temperature above 22 37. Ans: (1) are know as (1) Tropical evergreen and 38. If in a certain language, MADRAS is coded Semi-evergreen forests as NBESBT, how is BOMBAY coded in (2) Tropical deciduous forests that language? (3) Tropical thorn forests (1) CPNCBX (4) Littoral and Swamp forests (2) CPNCBZ 34. Ans: (*) (Most probable answer is 4) (3) CPOCBZ
(4) CQOCBZ 35. Sajja crop in Andhra Pradesh is largely 38. Ans: (2) grown in these districts.
(1) Kurnool and Anantapur 39. In an examination, 75% of the students (2) Chittoor and Kadapa passed in English, 90% passed in (3) Guntur and Prakasam Mathematics and 70% passed in both (4) Visakhapatnam and Prakasam English and Mathematics. If 40 students 35. Ans: (4) failed in both the subjects, find the total 36. The Mahatma Gandhi National Rural number of students. Employment Guarantee Scheme was (1) 800 (2) 450 launched on 2nd February, 2006 in Andhra (3) 250 (4) 350 Pradesh in the district of 39. Ans: (1) (1) Kadapa (2) Anantapur (3) Srikakulam (4) Guntur
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9 Digital Assistant _ Question & Solutions
40. If X + Y > 0 when X > Y, then which of the 44. Consider the following Statements following cannot be true? A. Metals are malleable and ductile (1) X = 3 and Y = 0 B. Non–metals are brittle and ductile (2) X = 6 and Y = –1 C. Non–metals have high melting and (3) X = –3 and Y = 0 boiling points (4) X = 3 and Y = –3 Which of these statements is /are correct? 40. Ans: (4) (1) A, B and C (2) A and C only 41. The ratio between the present ages of A and (3) B and C only B is 3:5 respectively. If the difference (4) A only between B’s present age and A’s age after 4 44. Ans: (4) years is 2 what is the total of A’s and B’s present age (in years)? 45. Consider the following statements (1) 24 (2) 32 A. The unit of density is kg/m3 (3) 48 (4) 27 B. The density of water is 100 kg/ m3 41. Ans: (1) C. Relative density has no units Which of the above statements is /are 42. The Central Cabinet Minister Gajendra Correct ? Singh Shekhawat holds the portfolio ‘Jal (1) A, B and C (2) A and C only Shakti’. He belongs to the State of (3) A and B only (4) B only (1) Haryana (2) Rajasthan 45. Ans: (2) (3) Punjab (4) Gujarat 46. Choose the correct sequence labelled as P, 42. Ans: (2) Q, R, S to produce the correct sentence.
Whom I taught / the student/ a teacher / became 43. Digi Locker is an P Q R S (1) Online money storage facility (1) RSPQ (2) QRSP (2) Online ornaments storage facility (3) SPRQ (4) QPSR (3) Online documents storage facility 46. Ans: (4) (4) Online Stemcell storage facility Ans: The student whom I taught became a 43. Ans: (3) teacher.
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47. I have been living in Hyderabad ______50. When ______you going to get a new 20 years. laptop? Choose the best option to fill in the blank. Choose the correct option to fill in the (1) for (2) since blank. (3) from (4) before (1) is (2) are 47. Ans: (1) (3) do (4) will Sol: ‘for’ is used with a period of time. 50. Ans: (2) Sol: The helping verb ‘are’ should be used with 48. I am going to stand for ______next ‘you’. Parliament election. Choose the correct option to fill in the PART – B blank. (1) the (2) a 51. A full binary tree with 2n + 1 nodes (3) an (4) No article required contains 48. Ans: (4) (1) n leaf nodes (2) n non-leaf nodes 49. Choose the part labelled as A, B, C, D that (3) n – 1 leaf nodes has an error (4) n – 1 non-leaf nodes The teacher / which inspired me most/ 51. Ans: (2) (A) (B) at school / was called Ms. Neelima. 52. The total number of different trees that are (C) (D) possible with six nodes is (1) A (2) B (1) 64 (2) 4 (3) C (4) D (3) 58 (4) 12 49. Ans: (2) 52. Ans: (*) (The correct answer is 132) Sol: The teacher is a person so the relative Sol: The total number of different trees that are pronoun should be ‘who’ possible with 6 nodes Answer is not in the option Formula is : (C(2n,n)/n+1)*n! Number of distinct binary search trees formula is Catallan number : C(2n,n)/n+1
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If ( N = 3 ) then distinct trees are 5 55. Consider the following program segment: I = 6720, j = 4 * * * * * while ((i%j) = = 0) / / / \ \ \ * * * * * * { / \ / \ i = i/j; * * * * j = j + 1; } After that, there are 3!=6 ways that the data On termination j will have the value could be allocated among the nodes ,Total = (1) 4 (2) 8 (3) 9 (4) 6720 5 x 6 = 30. 55. Ans: (3) Total trees =(C(2n,n)/n+1)*n!===5 * 3! = 5 * 6 = 30 56. What will be the output of the following C But here in the problem N = 6 code? So number of distinct trees are # include
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13 Digital Assistant _ Question & Solutions
being overloaded or is a function of abstract 61. How many IP addresses are available to a class or something like this, since we are not company with a class ‘B’ address? sure about all these, we can’t say whether it (1) 8192 (2) 16384 can show polymorphism or not. (3) 32768 (4) 65536 61. Ans: (4) 58. Select emp_name from department where Sol: For class B network least significant 16 bits dept_name LIKE ______Computer of IP(V ) (32 bits) address are for Host ID. Science; Which one of the following has to 4 Then maximum possible IP addresses in be included in the blank to select the class B is 216. dept_name which has Computer Science as
its ending string? 62. ______layer of OSI model is responsible (1) % (2) – (3) || (4) $ for the process-to-process delivery of the 58. Ans: (1) entire message. Sol: % sign indicates 0 or many characters. (1) Data link Layer (2) Network Layer 59. The number of attributes in a relation is (3) Transport Layer (4) Session Layer called as its 62. Ans: (3) (1) Cardinality (2) Degree Sol: Transport layer provide communication (3) Tuples (4) Entity between two end processes. 59. Ans: (2)
Sol: The number of attributes of a relation is 63. A cathode ray tube converts called a degree of a relation. (1) Voltage into current
(2) AC voltage into DC voltage 60. Start and stop bits are used in serial (3) DC voltage into AC voltage communication for (4) Electrical signals into visual signals (1) Error detection 63. Ans: (4) (2) Error correction Sol: When electron gun generates electron beam (3) Synchronization it gets accelerated and then goes and strikes (4) Slowing down the communication phosphor coating provided behind 60. Ans: (3) fluorescent screen. Due to phosphor Sol: In Asynchronous transmission, every excitation visible light will be produced. character is preceded by a start bit and
followed by one or more stop bits.
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64. Figure of merit of a receiver is given as 67. Which of the following is not an advantage SNR of digital modulation? (1) o SNR I (1) Greater noise immunity SNR (2) Greater security (2) i SNR o (3) Easier multiplexing
(3) (SNR)i(SNR)o (4) Less band width requirement (4) None of the above 67. Ans: (4) 64. Ans: (1) Sol: Digital modulation requires more Sol: Figure of merit of a receiver (FOM) bandwidth. So, less bandwidth requirement N/S )SNR( is not an advantage of digital modulation. = oo = o N/S ii )SNR( i N/S )SNR( 68. The most commonly used connections for Noise factor = ii = i N/S oo )SNR( o power systems as step-up and step-down
transformers are 65. Mixing is used in communication to (1) Star – Delta, Star – Star (1) Raise the carrier frequency (2) Delta – Star, Star – Delta (2) Lower the carrier frequency (3) Star – Star, Delta – Delta (3) Alter the deviation (4) Star – Delta, Delta – Star (4) Change the carrier frequency to any 68. Ans: (2) required value Sol: If transformation ratio of transformer is x: 1 65. Ans: (4)
Sol: Mixer is used to change the carrier Conne Secondary Line Voltages frequency. ctions Voltage
v1 - V1 : 100% 66. What device is used to demodulate a time x division multiplexed analog wave? v1 Y – Y V1 : 100% (1) High pass filter (2) Low pass filter x (3) Band stop filter (4) Band pass filter v1 - Y V1 : 3 173% 66. Ans: (2) x Sol: A low pass filter is used to demodulate a V1 Y - V1 : 57% TDM analog wave x3
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15 Digital Assistant _ Question & Solutions
The /Y transformer connection offers speed but the rotor couldn’t able to catch the highest secondary terminal voltage (73% quick reversal as that of the stator poles due more) among all the Transformer connections to mechanical inertia of the rotor. Then the for the same applied voltage and turns ratio. stator is subjected to clockwise torque and The Y/ transformer connection produces counter clockwise torque. Therefore average 42.3% less terminal voltage when compared torque is equal to zero during starting to / (or) Y/Y connections. condition. Hence synchronous motor is not self starting. 69. In general daily applications, the electrical fan operates with a ______induction 71. In series circuits, the expression for quality motor. factor is
(1) Single phase (2) Two phase (1) fr (2) Band Width (BW)
(3) Three phase (4) Poly phase (3) fr/BW (4) BW/fr 69. Ans: (1) 71. Ans: (3) Sol: Single phase induction motors are small Sol: Series RLC circuit – Series Resonance rating induction motors, so these are called I R L + VR + VL fractional KW induction motors. These are + + VC C V used for domestic purpose.
Z N/W is in S.S. 70. Synchronous motors are generally not self- V = 0 I = = Im (∵ LC combination starting as R (1) the direction of rotation is not fixed is like a short circuit) (2) the direction of instantaneous torque = I = 0 I reverses after half cycle
(3) the starters cannot be used on these Im
I machines m 2 (4) starting winding is not provided on
these machines
0 fL f fH 70. Ans: (2) 0 f BW Sol: In brief, when the supply is given to the
stator, the stator poles rotate at synchronous
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17 Digital Assistant _ Question & Solutions
75. Paging involves breaking logical memory f ffWB 0 LH Q into blocks of same size called as f (1) Pages Q 0 B.W (2) Segments L 1 Where Q = 0 (3) Fragments R CR 0 (4) Frames
72. Zener diode is used as 75. Ans: (1) (1) Rectifier (2) Amplifier 76. The desirable criteria for CPU scheduling (3) Regulator algorithm is (4) Oscillator (1) Maximize CPU utilization and 72. Ans: (3) Minimize response time Sol: Zener diode is used as regulator (2) Maximize CPU utilization and Maximize response time 73. The cross over distortion is due to (3) Minimize CPU utilization and (1) Power supply fluctuation Minimize response time (2) Cut-in voltage of transistor (4) Minimize CPU utilization and (3) Bias voltage Maximize response time (4) Input signal 76. Ans: (1) 73. Ans: (2) Sol: Cross-over distortion is due to cut-in voltage 77. Round Robin Scheduling of transistor. (1) allows interactive tasks quicker access to the processor 74. A ______process generates I/O requests (2) is quite complex to implement infrequently using more of its time doing (3) gives each task the same chance at the computations. processor (1) I/O bound (4) allows processor-bound tasks more (2) Swapped time in the processor (3) Mixed 77. Ans: (3) (4) CPU-bound 74. Ans: (4)
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78. ______approach structures the assign it's equivalent number in operating system by removing all non- hexadecimal representation. essential components from the kernel and implementing them as system and user-level 81. How many AND gates and OR gates are programs. required to realize Y = CD + EF +G? (1) Monolithic kernel (1) 3 OR gates, 2 AND gates (2) Micro kernel (2) 2 OR gates, 2 AND gates (3) Macro kernel (3) 3 OR gates, 3 AND gates (4) Mini kernel (4) 1 AND gates, 3 OR gates 78. Ans: (2) 81. Ans: (2) Sol: Y = CD + EF + G 79. Which of the following Gates are used as C basic building blocks ? D (1) AND, OR and NOT Y E (2) NAND and NOR F G (3) X-OR and X-NOR (4) AND and NAND Two OR gates and two AND gates are 79. Ans: (1) required. Sol: AND, OR and NOT are used as basic building blocks. 82. The number of bits in operation code required for a computer with 64 distinct 80. Convert binary to Hexadecimal operations is
(111111110010)2 (1) 64 (2) 06
(1) (EE 2)16 (2) (FF 2)16 (3) 32 (4)05
(3) (EF 2)16 (4) (FD 2)16 82. Ans: (2) 80. Ans: (2) Sol: Number of distinct operation with 'n' Sol: binary - 1111 1111 0010 number of bits = 2n. Hexadecimal - F F 2 So 2n = 64 Binary to hexadecimal conversion was n = 6 done by grouping 4 digits in binary representation from right to left and
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19 Digital Assistant _ Question & Solutions
83. The operation performed in each clock pulse Operand is obtained indirectly from address is called provided in instruction. (1) Micro operation (2) Micro instruction 86. Reverse Polish notation is often called (3) Micro program (1) Postfix (4) Macro instruction (2) Prefix 83. Ans: (1) (3) Infix Sol: Micro operation means operations (4) None of the above performed in one clock pulse. 86. Ans: (4)
84. ______converts the programs written in 87. Prefix of A–B/C * D $ E is Assembly language into Machine language. (1) –/*$ ACBDE (1) Compiler (2) Interpreter (2) /–ABCD *$DE (3) Linker (4) Assembler (3) –A*/BC$DE 84. Ans: (4) (4) –A/BC*$DE Sol: Assembly language programs are translated 87. Ans: (3) into machine language by assembler. 88. Main ( ) 85. The address of operand’s address is [ available in instruction. This address mode int I = 5; is called as print f(“%d”, I = + + I = = 6); (1) Direct Addressing mode ] (2) Register Addressing mode The output is (3) Register Indirect Addressing mode (1) 1 (2) 5 (3) 6 (4) 0 (4) Indirect Addressing mode 88. Ans: (1) 85. Ans: (4) Sol: 89. By default any real number in ‘C’ is treated Instruction Memory as Address operand (1) a float (2) a double
(3) a long double (4) a real address 89. Ans: (2)
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21 Digital Assistant _ Question & Solutions
90. Which of the following operators cannot be 94. Which protocol is used to convert IP address overloaded? to MAC address? (1) [ ] (2) - > (3) ? : (4) * (1) IP (2) RARP 90. Ans: (3) (3) ln ARP (4) ARP 94. Ans: (4) 91. Minimal super key is otherwise known as Sol: ARP (Address Resolution Protocol) used to (1) Candidate key (2) Foreign key map IP (logical) address into MAC (3) Primary key (4) Unique key (physical) address. 91. Ans: (1) 95. Class ______has the greatest number of Sol: Minimum super key is called candidate hosts per given network address. key. (1) B (2) A
(3) D (4) C 92. A rectangle in an entity-relationship 95. Ans: (2) diagram represents Sol: In class A 24 bits host ID, class B 16 bits (1) Attributes (2) Tables host ID and In class C 8 bits host ID (3) Entity sets (3) Database In class A maximum possible no. of hosts 92. Ans: (3) are (224 – 2) hosts.
93. Baud means the 96. In a CRO, the intensity control regulates the (1) Number of bits transmitted per unit (1) Voltage applied to the cathode time (2) Voltage applied to the focusing anode (2) Number of bytes transmitted per unit (3) Voltage applied to the accelerating time anode (3) Rate at which the signal changes per (4) Voltage applied to the control grid second 96. Ans: (4) (4) None of the above Sol: Intensity control varies control grid potential 93. Ans: (3) and in turn varies brightness of image Sol: Rate at which the signal changes per displayed. second.
Baud Rate = No. of signals changes per sec.
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22 Panchayat Secretary Gr. VI
Control Preaccelerating Focusing 2 nd Accelerating 99. The number of reflectors in Yagi-Uda Anode Anode Anode antenna is/are (1) One (2) Two Cathode (3) Three (4) Four 99. Ans: (1) +Va Sol: A Yagi-Uda antenna is a directional antenna Intensity Focus Control Control consists of a driven element, a single
Fig: Cathode Ray Tube reflector and one or more director.
97. Thermistors have ______100. The back emf of a dc motor is zero when (1) Positive temperature coefficient (1) The motor is running at its rated speed (2) Negative temperature coefficient (2) The motor is running at 80% of its (3) Zero temperature coefficient rated speed (4) Infinite temperature coefficient (3) The motor is about to start 97. Ans: (2) (4) The motor is running at 20% of its
rated speed 98. The expression for band width (BW) of a 100. Ans: (3) PCM system, where ‘v’ is the number of ZNP bits/sample and fm is modulating frequency, Sol: E b A60 is given by At starting, speed N = 0, 1 (1) BW (2) vfBW m then back emf is zero. vf2 m
(3) vf2BW m (4) vfBW m 101. Which of the following is a primary source of energy in a nuclear power station? 98. Ans: (4) (1) Uranium (2) Lignite Sol: Bandwidth of PCM for v-bit encoder is (3) Peat (4) Natural gas vf BW s 2 101. Ans: (1)
But fs = sampling frequency = 2fm Sol: The primary source of energy in a nuclear power station is uranium BW vfm
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23 Digital Assistant _ Question & Solutions
102. Which of the following types of plates is condenses to water and is injected back used as an earthing electrode? into the ground to be used again. Most (1) Aluminium (2) Galvanized Iron geothermal power plants are flash steam (3) Steel (4) Brass plants. 102 Ans: (2) Binary cycle power plants transfer the Sol: Plate Earthing System: In this type of heat from geothermal hot water to another system, a plate is made up of copper or GI liquid. The heat causes the second liquid to (galvanized iron) which are placed turn to steam, which is used to drive a vertically in the ground pit less than generator turbine. 3meters from the earth. For a better electrical grounding system, one should 104. Find the value of V, if the current in the 3 maintain the earth moisture condition resistor is zero (0 Amp).
around the plate earthing system. 1 3 5
103. Which of the following is used to generate 5 V 2 4 power in a geothermal station? V (1) Heat in the air (2) Heat in the Ionosphere (3) Heat inside the Earth (1) 3.5 V (2) 6.5 V (4) Heat of the Sun (3) 7.5 V (4) 8.5 V 103. Ans: (3) 104. Ans: (3) Sol: 3-types of geothermal power plants: Sol: 3 5 1 Va Vb Dry steam plants use steam directly from 5V V a geothermal reservoir to turn generator 2 4 turbines. The first geothermal power plant was built in 1904 in Tuscany, Italy, where In question given that, the current in the
natural steam erupted from the earth. 3 resistor is zero i.e Va = Vb Flash steam plants take high-pressure hot 25 4V water from deep inside the earth and 12 54 convert it to steam to drive generator V = 7.5 volt turbines. When the steam cools, it
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105. In superposition theorem, while 106. When voltage feedback (Negative) is considering the effect of one voltage applied to an amplifier, its input impedance source. ______. (1) All other current sources are open (1) is decreased circuited and voltage sources are (2) is increased short circuited (3) remains the same (2) All other current and voltage sources (4) None of the above are open circuited 106. Ans: (2) (3) All other current and voltage sources Sol: When voltage feedback is applied to an are short circuited amplifier, its input impedance increases. (4) All other current sources are short Because the feedback is series-shunt circuited and voltage sources are feedback. open circuited 107. What is responsible for upper 3-dB 105. Ans: (1) frequency in frequency response of Sol: Superposition theorem amplifier with transistor? In a linear network with several (1) Internal capacitance of transistor independent sources, the response in a (2) Bypass capacitance particular branch when all the sources are (3) Coupling capacitors
acting simultaneously is equal to the linear (4) Both bypass and coupling capacitors 107. Ans: (1) sum of individual responses calculated by Sol: Because of Junction capacitance (or) taking one independent source at a time. internal capacitance of transistor the gain All the ideal voltage sources are eliminated will drop at upper 3-dB frequency in from the network by shorting the sources, frequency response of amplifier.
all the ideal current sources are eliminated 108. CPU scheduler is also known as from the network by opening the sources (1) Long term scheduler and do not disturb the dependent sources (2) Job scheduler
present in the network. (3) Short term scheduler (4) Medium term scheduler
108. Ans: (3)
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25 Digital Assistant _ Question & Solutions
109. Which among the following statements Sol: Given binary 1100101.001010 is/are true related to dynamic loading? To convert to octal number system group 3 A. A routine is not loaded until it is digits into 1 digit. called B. Unused routine is never loaded So = 001 100 101 . 001 010 1 4 5 . 1 2 C. Requires special support from the
operating system 112. If (84)x is equal to (64)y where x and y
(1) A only (2) A and B only represent base ‘x’ and base ‘y’ number (3) B and C only (4) A, B and C systems respectively, what could be the 109. Ans: (4) possible values of x and y? (1) x = 12 y = 9 110. For a number system, with base n, the (2) x = 6 y = 9 number of different symbols in the number (3) x = 12 y = 18 system will be (4) x = 9 y = 12 (1) n – 1 (2) n 112. Ans: (4)
(3) n + 1 (4) 2n Sol: (84)x = (64)y 110. Ans: (2) 8x + 4 = 6y + 4 Sol: For base-n number system the number of 8x = 6y different symbols in that system are ‘n’. From the options, for x = 9 & y = 12 the Ex:- for base-8(octal) number system, above equation is satisfied. numbers available in the octal number system are 0,1,2,3,4,5,6,7. So, number of 113. When the subroutine is called, then address different symbols in the number system is of the instruction following the CALL 8. instruction is stored in the (1) Stack
111. The octal equivalent of (1100101.001010)2 (2) Program Counter is (3) Accumulator (1) 624.12 (2) 145.12 (4) Subroutine register (3) 154.12 (4) 145.21 113. Ans: (1) 111. Ans: (2) Sol: Stack is used to hold the address of instructions during subroutine.
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27 Digital Assistant _ Question & Solutions
114. Interrupt driven I/O i = 20 (1) has its main drawback in the printf(“%d”, i); software overhead of interrupts } (2) may be better than busy waiting I/O, The output of the above program is since, less hardware support is (1) 20 required (2) 0 (3) is equal or faster than DMA for a (3) Error, i undefined signal word register (4) Garbage value (4) Both (1) and (3) 117. Ans: (3) 114. Ans: (4) 118. main ( ) 115. The maximum number of nodes at level ‘i’ { of a binary tree is Int a = 6, b = 10, x; X = a&b; (1) 2i–1, i 0 printf(“%d”, x); (2) 2i, i 0 } (3) 2i+1, i 1 The value of x is (4) 2logi, i 1 (1) 2 (2) 10 (3) 5 (4) 7 115. Ans: (2) 118. Ans: (1)
116. Evaluate the following postfix notation 119. What are the elements present in the array A : 6, 9, 2 + * 12, 3 /– of the following ‘C’ code : (1) 62 int array [5] = [5]; (2) 66 (1) 5, 5, 5, 5, 5 (3) 83 (2) 5, 0, 0, 0, 0 (4) 72 (3) Compilation error 116. Ans: (1) (4) Declaration error
119. Ans: (2) 117. main ( )
{ extern int i;
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120. In C++, which of the following access 124. Public key cryptography is also called specifier is used as a default in a class (1) Single key cryptography definition? (2) Symmetric key cipher (1) Protected (3) Asymmetric cipher (2) Public (4) Conventional cryptography (3) Private 124. Ans: (3) (4) Friend Sol: In public (asymmetric) key cryptography 120. Ans: (3) two different keys (public and private) key is used for encryption and decryption. 121. Independent multi-valued dependences can be eliminated in 125. Which layer of OSI model is responsible (1) Boyce-Codd Normal Form for compression and decompression of (2) Third Normal Form data? (3) Fourth Normal Form (1) Application layer (4) Fifth Normal Form (2) Presentation layer 121. Ans: (3) (3) Session layer (4) Transport layer 122. The union operation automatically 125. Ans: (2) ______unlike the select clause. Sol: In OSI model, compression and (1) Adds tuples decompression of data are responsibility of (2) Eliminates unique tuples presentation layer. (3) Adds common tuples (4) Eliminates duplicates 126. Input impedance of an electronic voltmeter 122. Ans: (4) is (1) Low (2) High 123. Length of Ethernet address is ______bytes. (3) Medium (4) Zero (1) 2 (2) 4 126. Ans: (2) (3) 6 (4) 16 Sol: Because it consists of an amplifier at input 123. Ans: (3) side, so input impedance is high. Sol: Ethernet (MAC) address 48 bits Size of Ethernet (MAC) address 6 bytes
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29 Digital Assistant _ Question & Solutions
127. What will be frequency of the signal Sol: Due to lossy cable or attenuator, noise Asin(4t + ) ? figure increases. So, the figure of merit is (1) 2 Hz (2) 0.5 Hz decreases.
(3) 4 Hz (4) 0.25 Hz 127. Ans: (1) 130. A transformer is a device used to Sol: Asin(2ft + ) = Asin(4t + ) (1) Convert energy f = 2Hz (2) Generate energy (3) Change the level of energy 128. The modulation index in Frequency utilization Modulation (FM) is defined as (4) Transmit the energy at same level (1) Ratio of frequency deviation to the 130. Ans: (4) modulating frequency Sol: As Transformer transfers same amount of (2) Ratio of frequency deviation to the power from primary circuit to secondary carrier frequency circuit, it can be treated as constant power (3) Ratio of carrier frequency to the device. (If we consider time duration, frequency deviation Energy levels are same for one circuit to (4) Ratio of modulation frequency to the another circuit) frequency deviation 128. Ans: (1) 131. Which of the following is the correct Sol: Modulation index in FM defined as the representation of the regulation of a ratio of frequency deviation to the transformer?
f 2 VV 2 modulating signal frequency (1) loadfull loadno 100 f V m 2 loadfull
VV 129. The figure of merit in superheterodyne (2) 2 loadfull 2 loadno 100 V receiver can be decreased only by 2 loadno (1) having first stage as Mixer VV (3) 2 loadno 2 loadfull 100 (2) having first stage as Attenuator V 2 loadfull (3) having first stage as Amplifier VV (4) 2 loadno 2 loadfull 100 (4) having first stage as Filter V 2 loadno 129. Ans: (2) 131. Ans: (4)
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1 VV 133. Ans: (4) Sol: Regulation down = 1 2 1 V1 Sol: The direction of induced emf or current
1 can be find by applying this rule. 1 VV 2 Regulation up = Fore finger indicates direction of flux V2 Thumb indicates direction of motion of Where, V1 = No load voltage and 1 conductor V2 = Full load voltage. Center finger indicates direction of Note: Unless and otherwise specified, induced emf or current. regulation in the sense regulation down only. 134. The power developed by a synchronous motor will be maximum when the load 132. The armature core of a DC machine is angle is made up of (1) zero (2) 90 (1) Solid aluminium (3) 45 (4) 120 (2) Laminated aluminium 134. Ans: (2) (3) Solid steel EV Sol: P sin (4) Laminated steel Xs 132. Ans: (4) When, = 90, Power output is maximum. Sol: Armature core is made with silicon steel.
Core is laminated to reduce the eddy 135. In the given half wave rectifier circuit with current loss since armature current is sinusoidal input, having ideal diode and alternating. load RL, the DC current flowing through
the circuit is Idc. Calculate the DC voltage 133. The direction of generated EMF is across ideal diode. determined by
(1) Lenz’s law
(2) Faraday’s law of electromagnetic Idc R induction L
(3) Fleming’s left hand rule
(4) Fleming’s right hand rule
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31 Digital Assistant _ Question & Solutions
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(1) Idc RL 137. Ans: (1) (2) 0 (zero) Sol: To find the thevenin’s resistance, short
(3) –Idc RL circuit all the voltage sources and open
(4) Infinite circuit all the current sources in the circuit. 135. Ans: (2)
Sol: Since diode is ideal and forward bias, 138. ______scheduling algorithm exhibits voltage drop across the diode is zero. convey effect. 136. Which of the following device is a voltage (1) First Come First Serve controlled device ? (2) Shortest-Job-First (1) Bi-Polar Junction Transistor (BJT) (3) Round Robin (2) Field Effect Transistor (FET) (4) Priority (3) Silicon Controlled Rectifier (SCR) 138. Ans: (1) (4) None of the above 136. Ans: (3) 139. In contiguous memory allocation, the Sol: Field effect transistor (FET) is a voltage following strategy can be used for effective controlled device. BJT and SCR are utilization of memory current controlled devices. (1) First Fit (2) Best Fit 137. The Thevenin’s resistance is calculated (3) Worst Fit considering (4) Last Fit (1) All current sources are open 139. Ans: (2) circuited and voltage sources are
short circuited 140. ______is the concept in which a (2) All current and voltage sources are process is copied into main memory from short circuited the secondary memory according to the (3) All current and voltage sources are requirement. open circuited (1) Paging (2) Segmentation (4) All current sources are short (3) Swapping (4) Demand Paging circuited and voltage sources are 140. Ans: (4) open circuited
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33 Digital Assistant _ Question & Solutions
141. Consider the equation (136)8 = (a4)b with 143. Ans: (4) ‘a’ and ‘b’ as unknown values. The Sol: 2's complement of 0101101 is 1010011
possible values of ‘a’ and ‘b’ can be 1011001 (+)1010011 (1) a = 10, b = 9 1 0101100 (2) a = 2, b = 15 (EAC) (3) a = 3, b = 11 As end around carry is present so, the (4) a = 11, b = 3 result is positive. 141. Ans: (*) 144. Which of the following statements is true ? Sol: (136)8 = (a4)b S1: The dual of NAND function is NOR 1 82 + 3 81 + 6 80 = a b1 + 4 b0 S2: The dual of XOR function is XNOR 64 + 24 + 6 = ab + 4
94 = ab + 4 (1) Only S1 is true ab = 90 (2) Only S2 is true From the given options for a = 10, b = 9 (3) Both S1 and S2 are true will satisfy the above equation. (4) Both S1 and S2 are false If the base is 9 the number 'a' lies between 0 144. Ans: (3) to 8. So, no option is correct. Sol: The dual of NAND function is NOR
dual )NOR(BABABA)NAND(AB 142. An example of error correcting code is S1 is true (1) Parity check The dual of XOR function is XNOR (2) Hamming code BABA)XOR(BA (3) BCD (4) Gray code dual )XNOR(ABBA)BA)(BA( 142. Ans: (2) S2 is true Sol: Hamming code is an example for error correcting code. 145. ______holds the address of the next instruction to be executed.
143. Subtracting (0101101)2 from (1011001)2 (1) Accumulator using 2’s complement, the result is (2) Program counter (1) 0111001 (2) 0110110 (3) Address register (3) 0101111 (4) 0101100 (4) Instruction register
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145. Ans: (2) 148. A computer with cache access time of 100 Sol: Program counter is a pointer register that nsec, and main memory access time of holds address of the next instruction to be 1000 nsec and a hit ratio of 0.9 produces executed an average access time of _____. (1) 200 nsec (2) 400 nsec 146. The sequence of operations performed by (3) 550 nsec (4) 1000 nsec CPU in processing an instruction 148. Ans: (1) constitutes a/an _____ cycle. Sol: Average memory access time = Hit (1) Instruction (2) Interrupt ratioCache access time + miss (3) Fetch (4) Machine ratio[cache access time+main memory 146. Ans: (1) access time] Sol: Instruction cycle means the time taken to = 0.9100 + 0.1(100 + 1000) process a complete instruction. = 90 + 110 = 200 nsec 147. Which of the following data transfer is used for data transfer without the role of 149. The best case running time of Bubble sort processor ? is (1) Synchronous (1) O (n log n) (2) O (n) (2) Asynchronous (3) O (log n) (4) O (n2) (3) Direct Memory Access 149. Ans: (2) (4) Interrupt driven 147. Ans: (3) 150. A complete binary tree with ‘n’ nodes is Sol: DMA is a method that allows an represented sequentially. Then for any input/output device to send or receive data nodes with index i, the left child is at directly to or from the main memory by (1) 2 i (2) 2i + 1 passing the CPU to speedup memory (3) i + 2 (4) 2i + 2 operations. 150. Ans: (1)
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35 Digital Assistant _ Question & Solutions
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