6Entropy & the Boltzmann
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Chapter 3. Second and Third Law of Thermodynamics
Chapter 3. Second and third law of thermodynamics Important Concepts Review Entropy; Gibbs Free Energy • Entropy (S) – definitions Law of Corresponding States (ch 1 notes) • Entropy changes in reversible and Reduced pressure, temperatures, volumes irreversible processes • Entropy of mixing of ideal gases • 2nd law of thermodynamics • 3rd law of thermodynamics Math • Free energy Numerical integration by computer • Maxwell relations (Trapezoidal integration • Dependence of free energy on P, V, T https://en.wikipedia.org/wiki/Trapezoidal_rule) • Thermodynamic functions of mixtures Properties of partial differential equations • Partial molar quantities and chemical Rules for inequalities potential Major Concept Review • Adiabats vs. isotherms p1V1 p2V2 • Sign convention for work and heat w done on c=C /R vm system, q supplied to system : + p1V1 p2V2 =Cp/CV w done by system, q removed from system : c c V1T1 V2T2 - • Joule-Thomson expansion (DH=0); • State variables depend on final & initial state; not Joule-Thomson coefficient, inversion path. temperature • Reversible change occurs in series of equilibrium V states T TT V P p • Adiabatic q = 0; Isothermal DT = 0 H CP • Equations of state for enthalpy, H and internal • Formation reaction; enthalpies of energy, U reaction, Hess’s Law; other changes D rxn H iD f Hi i T D rxn H Drxn Href DrxnCpdT Tref • Calorimetry Spontaneous and Nonspontaneous Changes First Law: when one form of energy is converted to another, the total energy in universe is conserved. • Does not give any other restriction on a process • But many processes have a natural direction Examples • gas expands into a vacuum; not the reverse • can burn paper; can't unburn paper • heat never flows spontaneously from cold to hot These changes are called nonspontaneous changes. -
Calculating the Configurational Entropy of a Landscape Mosaic
Landscape Ecol (2016) 31:481–489 DOI 10.1007/s10980-015-0305-2 PERSPECTIVE Calculating the configurational entropy of a landscape mosaic Samuel A. Cushman Received: 15 August 2014 / Accepted: 29 October 2015 / Published online: 7 November 2015 Ó Springer Science+Business Media Dordrecht (outside the USA) 2015 Abstract of classes and proportionality can be arranged (mi- Background Applications of entropy and the second crostates) that produce the observed amount of total law of thermodynamics in landscape ecology are rare edge (macrostate). and poorly developed. This is a fundamental limitation given the centrally important role the second law plays Keywords Entropy Á Landscape Á Configuration Á in all physical and biological processes. A critical first Composition Á Thermodynamics step to exploring the utility of thermodynamics in landscape ecology is to define the configurational entropy of a landscape mosaic. In this paper I attempt to link landscape ecology to the second law of Introduction thermodynamics and the entropy concept by showing how the configurational entropy of a landscape mosaic Entropy and the second law of thermodynamics are may be calculated. central organizing principles of nature, but are poorly Result I begin by drawing parallels between the developed and integrated in the landscape ecology configuration of a categorical landscape mosaic and literature (but see Li 2000, 2002; Vranken et al. 2014). the mixing of ideal gases. I propose that the idea of the Descriptions of landscape patterns, processes of thermodynamic microstate can be expressed as unique landscape change, and propagation of pattern-process configurations of a landscape mosaic, and posit that relationships across scale and through time are all the landscape metric Total Edge length is an effective governed and constrained by the second law of measure of configuration for purposes of calculating thermodynamics (Cushman 2015). -
Useful Constants
Appendix A Useful Constants A.1 Physical Constants Table A.1 Physical constants in SI units Symbol Constant Value c Speed of light 2.997925 × 108 m/s −19 e Elementary charge 1.602191 × 10 C −12 2 2 3 ε0 Permittivity 8.854 × 10 C s / kgm −7 2 μ0 Permeability 4π × 10 kgm/C −27 mH Atomic mass unit 1.660531 × 10 kg −31 me Electron mass 9.109558 × 10 kg −27 mp Proton mass 1.672614 × 10 kg −27 mn Neutron mass 1.674920 × 10 kg h Planck constant 6.626196 × 10−34 Js h¯ Planck constant 1.054591 × 10−34 Js R Gas constant 8.314510 × 103 J/(kgK) −23 k Boltzmann constant 1.380622 × 10 J/K −8 2 4 σ Stefan–Boltzmann constant 5.66961 × 10 W/ m K G Gravitational constant 6.6732 × 10−11 m3/ kgs2 M. Benacquista, An Introduction to the Evolution of Single and Binary Stars, 223 Undergraduate Lecture Notes in Physics, DOI 10.1007/978-1-4419-9991-7, © Springer Science+Business Media New York 2013 224 A Useful Constants Table A.2 Useful combinations and alternate units Symbol Constant Value 2 mHc Atomic mass unit 931.50MeV 2 mec Electron rest mass energy 511.00keV 2 mpc Proton rest mass energy 938.28MeV 2 mnc Neutron rest mass energy 939.57MeV h Planck constant 4.136 × 10−15 eVs h¯ Planck constant 6.582 × 10−16 eVs k Boltzmann constant 8.617 × 10−5 eV/K hc 1,240eVnm hc¯ 197.3eVnm 2 e /(4πε0) 1.440eVnm A.2 Astronomical Constants Table A.3 Astronomical units Symbol Constant Value AU Astronomical unit 1.4959787066 × 1011 m ly Light year 9.460730472 × 1015 m pc Parsec 2.0624806 × 105 AU 3.2615638ly 3.0856776 × 1016 m d Sidereal day 23h 56m 04.0905309s 8.61640905309 -
Chemistry C3102-2006: Polymers Section Dr. Edie Sevick, Research School of Chemistry, ANU 5.0 Thermodynamics of Polymer Solution
Chemistry C3102-2006: Polymers Section Dr. Edie Sevick, Research School of Chemistry, ANU 5.0 Thermodynamics of Polymer Solutions In this section, we investigate the solubility of polymers in small molecule solvents. Solubility, whether a chain goes “into solution”, i.e. is dissolved in solvent, is an important property. Full solubility is advantageous in processing of polymers; but it is also important for polymers to be fully insoluble - think of plastic shoe soles on a rainy day! So far, we have briefly touched upon thermodynamic solubility of a single chain- a “good” solvent swells a chain, or mixes with the monomers, while a“poor” solvent “de-mixes” the chain, causing it to collapse upon itself. Whether two components mix to form a homogeneous solution or not is determined by minimisation of a free energy. Here we will express free energy in terms of canonical variables T,P,N , i.e., temperature, pressure, and number (of moles) of molecules. The free energy { } expressed in these variables is the Gibbs free energy G G(T,P,N). (1) ≡ In previous sections, we referred to the Helmholtz free energy, F , the free energy in terms of the variables T,V,N . Let ∆Gm denote the free eneregy change upon homogeneous mix- { } ing. For a 2-component system, i.e. a solute-solvent system, this is simply the difference in the free energies of the solute-solvent mixture and pure quantities of solute and solvent: ∆Gm G(T,P,N , N ) (G0(T,P,N )+ G0(T,P,N )), where the superscript 0 denotes the ≡ 1 2 − 1 2 pure component. -
Lecture 6: Entropy
Matthew Schwartz Statistical Mechanics, Spring 2019 Lecture 6: Entropy 1 Introduction In this lecture, we discuss many ways to think about entropy. The most important and most famous property of entropy is that it never decreases Stot > 0 (1) Here, Stot means the change in entropy of a system plus the change in entropy of the surroundings. This is the second law of thermodynamics that we met in the previous lecture. There's a great quote from Sir Arthur Eddington from 1927 summarizing the importance of the second law: If someone points out to you that your pet theory of the universe is in disagreement with Maxwell's equationsthen so much the worse for Maxwell's equations. If it is found to be contradicted by observationwell these experimentalists do bungle things sometimes. But if your theory is found to be against the second law of ther- modynamics I can give you no hope; there is nothing for it but to collapse in deepest humiliation. Another possibly relevant quote, from the introduction to the statistical mechanics book by David Goodstein: Ludwig Boltzmann who spent much of his life studying statistical mechanics, died in 1906, by his own hand. Paul Ehrenfest, carrying on the work, died similarly in 1933. Now it is our turn to study statistical mechanics. There are many ways to dene entropy. All of them are equivalent, although it can be hard to see. In this lecture we will compare and contrast dierent denitions, building up intuition for how to think about entropy in dierent contexts. The original denition of entropy, due to Clausius, was thermodynamic. -
Solutions Mole Fraction of Component a = Xa Mass Fraction of Component a = Ma Volume Fraction of Component a = Φa Typically We
Solutions Mole fraction of component A = xA Mass Fraction of component A = mA Volume Fraction of component A = fA Typically we make a binary blend, A + B, with mass fraction, m A, and want volume fraction, fA, or mole fraction , xA. fA = (mA/rA)/((mA/rA) + (m B/rB)) xA = (mA/MWA)/((mA/MWA) + (m B/MWB)) 1 Solutions Three ways to get entropy and free energy of mixing A) Isothermal free energy expression, pressure expression B) Isothermal volume expansion approach, volume expression C) From statistical thermodynamics 2 Mix two ideal gasses, A and B p = pA + pB pA is the partial pressure pA = xAp For single component molar G = µ µ 0 is at p0,A = 1 bar At pressure pA for a pure component µ A = µ0,A + RT ln(p/p0,A) = µ0,A + RT ln(p) For a mixture of A and B with a total pressure ptot = p0,A = 1 bar and pA = xA ptot For component A in a binary mixture µ A(xA) = µ0.A + RT xAln (xA ptot/p0,A) = µ0.A + xART ln (xA) Notice that xA must be less than or equal to 1, so ln xA must be negative or 0 So the chemical potential has to drop in the solution for a solution to exist. Ideal gasses only have entropy so entropy drives mixing in this case. This can be written, xA = exp((µ A(xA) - µ 0.A)/RT) Which indicates that xA is the Boltzmann probability of finding A 3 Mix two real gasses, A and B µ A* = µ 0.A if p = 1 4 Ideal Gas Mixing For isothermal DU = CV dT = 0 Q = W = -pdV For ideal gas Q = W = nRTln(V f/Vi) Q = DS/T DS = nRln(V f/Vi) Consider a process of expansion of a gas from VA to V tot The change in entropy is DSA = nARln(V tot/VA) = - nARln(VA/V tot) Consider an isochoric mixing process of ideal gasses A and B. -
Gibbs Paradox of Entropy of Mixing: Experimental Facts, Its Rejection and the Theoretical Consequences
ELECTRONIC JOURNAL OF THEORETICAL CHEMISTRY, VOL. 1, 135±150 (1996) Gibbs paradox of entropy of mixing: experimental facts, its rejection and the theoretical consequences SHU-KUN LIN Molecular Diversity Preservation International (MDPI), Saengergasse25, CH-4054 Basel, Switzerland and Institute for Organic Chemistry, University of Basel, CH-4056 Basel, Switzerland ([email protected]) SUMMARY Gibbs paradox statement of entropy of mixing has been regarded as the theoretical foundation of statistical mechanics, quantum theory and biophysics. A large number of relevant chemical and physical observations show that the Gibbs paradox statement is false. We also disprove the Gibbs paradox statement through consideration of symmetry, similarity, entropy additivity and the de®ned property of ideal gas. A theory with its basic principles opposing Gibbs paradox statement emerges: entropy of mixing increases continuously with the increase in similarity of the relevant properties. Many outstanding problems, such as the validity of Pauling's resonance theory and the biophysical problem of protein folding and the related hydrophobic effect, etc. can be considered on a new theoretical basis. A new energy transduction mechanism, the deformation, is also brie¯y discussed. KEY WORDS Gibbs paradox; entropy of mixing; mixing of quantum states; symmetry; similarity; distinguishability 1. INTRODUCTION The Gibbs paradox of mixing says that the entropy of mixing decreases discontinuouslywith an increase in similarity, with a zero value for mixing of the most similar or indistinguishable subsystems: The isobaric and isothermal mixing of one mole of an ideal ¯uid A and one mole of a different ideal ¯uid B has the entropy increment 1 (∆S)distinguishable = 2R ln 2 = 11.53 J K− (1) where R is the gas constant, while (∆S)indistinguishable = 0(2) for the mixing of indistinguishable ¯uids [1±10]. -
Thermodynamic Temperature
Thermodynamic temperature Thermodynamic temperature is the absolute measure 1 Overview of temperature and is one of the principal parameters of thermodynamics. Temperature is a measure of the random submicroscopic Thermodynamic temperature is defined by the third law motions and vibrations of the particle constituents of of thermodynamics in which the theoretically lowest tem- matter. These motions comprise the internal energy of perature is the null or zero point. At this point, absolute a substance. More specifically, the thermodynamic tem- zero, the particle constituents of matter have minimal perature of any bulk quantity of matter is the measure motion and can become no colder.[1][2] In the quantum- of the average kinetic energy per classical (i.e., non- mechanical description, matter at absolute zero is in its quantum) degree of freedom of its constituent particles. ground state, which is its state of lowest energy. Thermo- “Translational motions” are almost always in the classical dynamic temperature is often also called absolute tem- regime. Translational motions are ordinary, whole-body perature, for two reasons: one, proposed by Kelvin, that movements in three-dimensional space in which particles it does not depend on the properties of a particular mate- move about and exchange energy in collisions. Figure 1 rial; two that it refers to an absolute zero according to the below shows translational motion in gases; Figure 4 be- properties of the ideal gas. low shows translational motion in solids. Thermodynamic temperature’s null point, absolute zero, is the temperature The International System of Units specifies a particular at which the particle constituents of matter are as close as scale for thermodynamic temperature. -
Chemical Engineering Thermodynamics
CHEMICAL ENGINEERING THERMODYNAMICS Andrew S. Rosen SYMBOL DICTIONARY | 1 TABLE OF CONTENTS Symbol Dictionary ........................................................................................................................ 3 1. Measured Thermodynamic Properties and Other Basic Concepts .................................. 5 1.1 Preliminary Concepts – The Language of Thermodynamics ........................................................ 5 1.2 Measured Thermodynamic Properties .......................................................................................... 5 1.2.1 Volume .................................................................................................................................................... 5 1.2.2 Temperature ............................................................................................................................................. 5 1.2.3 Pressure .................................................................................................................................................... 6 1.3 Equilibrium ................................................................................................................................... 7 1.3.1 Fundamental Definitions .......................................................................................................................... 7 1.3.2 Independent and Dependent Thermodynamic Properties ........................................................................ 7 1.3.3 Phases ..................................................................................................................................................... -
Chemistry 163B Absolute Entropies and Entropy of Mixing
Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) Chemistry 163B Absolute Entropies and Entropy of Mixing 1 APPENDIX A: Hf, Gf, BUT S (no Δ, no “sub f ”) Hºf Gºf Sº 2 1 Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) Third Law of Thermodynamics The entropy of any perfect crystalline substance approaches 0 as Tô 0K S=k ln W for perfectly ordered crystalline substance W ô 1 as Tô 0K S ô 0 3 to calculate absolute entropy from measurements (E&R pp. 101-103, Figs 5.8-5.10) T2 CP S ABCDE,,,, dT ABCDE,,,, T T1 H S T ABCD E S S S S III II III I g 0 + + + + S298.15 SK(0 ) SA S SB S 0 23.66 III II 23.66 43.76 II I at 23.66K at4 3.76K + + + SC + S SD + S SE 43.7654 .39 I 54.3990.20 g 90.30298.15 at54 .39K at90.20 K 4 2 Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) full calculation of Sº298 for O2 (g) (Example Problem 5.9, E&R pp103-104 [96-97]2nd) SJ K11 mol S(0K ) 0 SA 0 23.66 8.182 S III II at 23.66K 3.964 SB 23.66 43.76 19.61 S II I at 43.76K 16.98 SC 43.76 54.39 10.13 S I at 54.39K 8.181 SD 54.39 90.20 27.06 Sg at 90.20K 75.59 SE 90.20 298.15 35.27 total 204.9 J K-1 mol-1 5 Sreaction from absolute entropies nAA + nBB ônCC + nDD at 298K 0000 SnSnSnSnS298 298 298 298 reaction CCDAB D A B SK00()298 S reaction i 298 i i S 0 are 3rd Law entropies (e.g. -
Ideal Gas Law
ATMO 551a Fall 2010 Ideal gas law The ideal gas law is one of the great achievements of Thermodynamics. It relates the pressure, temperature and density of gases. It is VERY close to true for typical atmospheric conditions. It assumes the molecules interact like billiard balls. For water vapor with its large permanent electric dipole moment, it does not quite behave as an ideal gas but even it is close. The microscopic version of the ideal gas law is P = n kB T where P is pressure in pascals, n is the number density of the gas in molecules per cubic meter -23 and T is the temperature in Kelvin and kB is Boltzmann’s constant = 1.38x10 J/K. For typical atmospheric conditions, n is huge and kB is always tiny. So there is a different “macroscopic” version of the ideal gas law with numbers that are easier to work with. Avogadro’s number is the number of molecules in a “mole” where a mole is defined such that 1 mole of a molecules has a mass in grams equal to the mass of an individual molecule in atomic mass units (amu). For example, 1 mole of hydrogen atoms has a mass of ~1 gram. The number 23 -1 of molecules in a mole is given by Avogadro’s number, NA = 6.02214179(30)×10 mol . We multiply and divide the first equation by NA to get P = n kB T = n/NA kBNA T = N R* T where N is the number of moles per unit volume = n/NA and R* is the ideal gas constant = kB NA. -
Lecture 25 - Kinetic Theory of Gases; Pressure
PHYS 172: Modern Mechanics Fall 2010 Lecture 25 - Kinetic theory of gases; pressure Chapter 12.8, bits of Chapter 13 CLICKER QUESTION #1 Reading Question (Sections 12.7–12.8) There is only a trace amount of helium in the air we breathe. Why? A. There never was much helium on Earth to begin with. B. At ordinary temperatures, most helium atoms have speeds greater than the escape velocity. C. Most of the helium can be found at very high altitudes, not at the surface. D. The low mass helium atoms are more likely to gradually escape from the Earth. E. Since helium does not bond to other elements, it is less likely to be trapped on Earth. CLICKER QUESTION #1 Reading Question (Sections 12.7–12.8) There is only a trace amount of helium in the air we breathe. Why? B. At ordinary temperatures, most helium atoms have speeds greater than the escape velocity. NO!! But A FEW do. D. The low mass helium atoms are more likely to gradually escape from the Earth. The rare tail of the Maxwell Boltzmann distribution. Summary of Statistical Mechanics (Chapter 12 - Entropy) (q + N − 1)! Ω= Counting states q!(N − 1)1 S = kB lnΩ Entropy 1 ∂S ≡ T ∂Eint Temperature ΔE ΔEatom 1 system C = = Heat capacity ΔT N ΔT ΔE − P(ΔE) ∝ e kT Boltzmann distribution Rhetorical Question How do we know that the definition of temperature that we got from statistics & entropy agrees with standard definitions? 1 ∂S ≡ T ∂Eint The most common definition of temperature comes from the ideal gas law: PV=(#ofMoles)RT, or P = nkT.