LECTURE 9 IDEAL GAS & KINETIC THEORTY Lecture Instructor: Kazumi Tolich Lecture 9
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¨ Reading chapter 13-3 to 13-4. ¤ Ideal gasses ¤ Kinetic theory Ideal gas
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¨ In an ideal gas, intermolecular interactions are negligible. ¤ The molecules obey Newton’s laws of motion, and move about in a random manner. ¤ The molecules collide elastically with each other or container walls, and have no other interactions.
¨ The behavior of real gasses is well approximated by an ideal gas.
¨ An equation of state for an ideal gas relating the pressure P, volume V, number of molecules N and the temperature T (in Kelvin) is given by PV = NkT where k = 1.38 × 10-23 J/K is called the Boltzmann constant. Ideal gas: 2
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¨ A more natural measure of the number of molecules is the mole.
¨ A mole of substance is the amount that contains Avogadro’s number, 23 NA=6.022 × 10 , of molecules. ¨ Atomic or molecular mass of a substance is the mass of one mole of that substance.
¨ The equation of state for an ideal gas in terms of the number of moles n is given by PV = nRT where R = 8.31 J/(molK) is the universal gas constant. Clicker question 1 & 2
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¨ In the morning, when the
temperature is Ti = 288 K, a bicyclist finds that the absolute pressure in his tires is
Pi = 505 kPa. That afternoon, he finds that the pressure in the tires
has increased to Pf = 552 kPa. Ignoring the expansion of the tires, find the afternoon temperature. Isotherms
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¨ If the temperature and the number of molecules in a gas are held constant, an ideal gas follows Boyle’s law: PV = nRT
PiVi = PfVf constant P = V
¨ These curves are called isotherms. Demo: 1
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¨ Boyle’s law ¤ Demonstration of Boyle’s law n The higher the volume, the lower the pressure n The lower the volume, the higher the pressure
constant P = V Example: 2
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¨ A cylindrical flask is fitted with an airtight piston that is free to slide up and down. A mass rests on top of the piston. Contained within the flask is an ideal gas at a constant temperature of T = 313 K. Initially the pressure applied by the
piston and the mass is Pi = 137 kPa, and the height of the piston above the base of the flask is
hi = 23.4 cm. When additional mass is added to the piston, the height of the piston decreases to
hf = 20.0 cm. Find the new pressure applied by the piston, Pf. Constant pressure
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¨ If the pressure and the number of molecules in a gas are held constant, an ideal gas follows Charles’s law: V nR = T P V V i = f Ti Tf V = (constant)T Example: 3
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¨ A cylindrical flask is fitted with an airtight piston that is free to slide up and down. A mass rests on top of the piston. The initial
temperature of the system is Ti = 313 K, and the pressure of the gas is held constant at P = 137 kPa. The temperature is now increased until the height of the piston rises
from hi = 23.4 cm to hf = 26.0 cm. Find the final temperature of the gas, Tf. Demo: 2
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¨ Molecular motion demonstrator ¤ Demonstration of random molecular motion Pressure in the kinetic theory of gasses
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¨ The kinetic theory of gasses relates microscopic quantities (position, velocity) to macroscopic ones (pressure, temperature).
¨ Pressure is the result of collisions between the gas molecules and the walls of the container.
¨ The pressure of a gas P is directly proportional to the average kinetic energy of its
molecules Kav.
2! N $ 2! N $! 1 2 $ P = # &Kav = # mv & 3"V % 3"V %" 2 %av N (N >> 1) is the number of molecules, V is the volume of the gas, m is the mass of a molecule, and v is the speed of a molecule. Internal energy of an ideal gas
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¨ The average kinetic energy of a gas molecule is directly proportional to the Kelvin temperature T.
¤ The hotter the temperature, the faster on average the molecules are moving.
! 1 2 $ 3 # mv & = Kav = kT " 2 %av 2
¨ The internal energy of a substance is the sum of its potential and kinetic energies.
¨ For an ideal gas of N point-like molecules, the internal energy is from their translational kinetic energy. 3 3 U = NkT = nRT 2 2 Speed distribution of molecules
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¨ The molecules in a gas have a range of speeds.
¨ The overall distribution of speeds for molecules (the Maxwell-Boltzmann distribution) remain constant for a given gas.
¨ The Maxwell distribution indicates which speeds are most likely to occur in a given gas.
¨ For gas molecules, the rms speed, vrms, is given by 3kT 3RT v = v2 = = rms ( )av m M Clicker question: 3
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¨ One mole of oxygen molecule has a mass of 32.0 g. For oxygen in air at a room temperature of 20.0 °C, calculate the followings. a) The average translational kinetic energy b) The rms speed Example: 5
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¨ The rms speed of a sample of gas is increased by one percent. What is the percent change in temperature of the gas?