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Home , Electrostatics

Electrostatics and Introduction

Hi, I’m Phil!

§ MCAT Content writer

§ Tutored and taught for 10+ years

§ Attended University of Nebraska Medical Center as an MD/PhD student. Electrostatics

One of the four fundamental of :

§ § § Strong Nuclear § Weak Nuclear

The last two aren’t on the MCAT. YAY! Electrostatics

Difference between electrostatics and magnetism

§ Electrostatics: u Magnetism: Study of stationary charges Moving charges Electrostatics

Electrostatic Gravity! : F= GmM/ r^2 F= kqQ/ r^2 Electrostatics

Newtons! Force: = Nm F= kqQ/ r^2

Joules! Energy = Force x distance Energy: U= kqQ/ r

Energy = (kqQ/ r^2) (r) Electrostatics

Newtons! This spot is 10 m above the ground, How much Force: energy will a 1 kg object have if I put it in the F= kqQ/ r^2 spot?

2 kg? Joules! Energy: U= kqQ/ r 10 m 3 kg? Electrostatics

Newtons A single charge will create Force: a . If we put in F= kqQ/ r^2 another charge, it will have energy. Joules J/C Energy: Potential Voltage = Joules/ U= kqQ/ r V= kq/ r Electrostatics

Newtons N/C! Force: Electric F= kqQ/ r^2 E= kq/ r^2 Electric fields are similar to voltage, but are N/C

Joules J/C Energy: Potential U= kqQ/ r V= kq/ r Electrostatics Force: F= kqQ/r^2 E= kq/r^2

Energy: Voltage U= kqQ/r V= kq/r 2m from a positive charge, there is a voltage of 30 . How much energy will a 2C charge have if I place it there? U = qv à 30V x 2 C = 60 J

U= Fr How much energy if I put a 3C charge at 4m?

V=Er At 4m, we have doubled the radius, so the Voltage is U=qV cut in half to 15 V. F=qE U = qV à 3C x 15 V = 45 J How much force will there be if I place a 6 C charge at 6m?

At 6m, the voltage drops to 10V. Combining the 2 equations: U= Fr & U = qv à Fr = qV F = qV/r à F = (6C)(10V)/(6m) = 10N Electrostatics 2m from a positive charge, there is a voltage of 30 Volts. Force: Electric field If I place a 2kg & -2C charge at 6m, how fast will it be going once F= kqQ/r^2 E= kq/r^2 it reaches 2m?

Using the methods we used before, we see that the charge will have -20J Energy: Voltage at 6m, and then -60J at 2m.

U= kqQ/r V= kq/r This means it loses 40J of electrostatic potential energy, but gains 40J of KE.

40 = ½ mv^2 à m is 2, so the equation becomes: U= Fr 40 = v^2 . V=Er This means it will be going between 6 and 7 m/s. U=qV F=qE Magnetism

Magnetic fields are created by moving charges

Magnetic fields exert forces on other moving charges.

�� � = 2��

I

� = 1.256 x 10−6 N/A^2 Magnetism

Right-hand-rule #1

Thumb = direction of current Fingers = curl with (which is circular)

I Magnetism

Right-hand-rule #1

Thumb = direction of current Fingers = curl with magnetic field (which is circular)

I Magnetism

Magnetic fields exert forces on other moving charges. These moving charges could be :

Particles (like a ) B = 3 Teslas F = qvBsin theta

Current carrying wires 5 m F = ILBsin theta I = 2 Amps Magnetism

What about direction?

Right-hand-rule #2

Thumb = direction of velocity/ Current B = 3 Teslas Fingers = direction of B

Palm = direction of force 5 m

I = 2 Amps Magnetism

I have a machine that gives a positive charge and then shoots them into a room with a magnetic field at a set speed. What happens as I fire them into Right-hand-rule #2 Q the room? Thumb = direction of velocity/ Current Fingers = direction of B Palm = direction of force Magnetism

When wiring up a power plant, I run two wires in parallel, as shown. Will they exert forces on each other?

Right-hand-rule #1 Thumb = direction of current Fingers = curl with magnetic field (which is circular)

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