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Summary of with Dr. Christopher S. Baird University of Massachusetts Lowell

1. General Equations

E: Total electric D: Applied plus interactions P: material polarization, leading to material response field ρtotal: Total ρ: Free or excess charge density ρpol: Polarization (bound) charge density

Gauss' Law leads to the Boundary Condition ρ σ ∇⋅ = total ( − )⋅ = total E ϵ E2 E1 n12 ϵ 0 0 ∇⋅ =ρ ( − )⋅ =σ D D2 D1 n12 ∇⋅ =−ρ ( − )⋅ =−σ P pol P2 P1 n12 pol ∇× = ( − )× = E 0 E2 E1 n12 0 ∇×( − )= (( − )−( − ))× = D P 0 D2 P2 D1 P1 n12 0

Relations of Fields and Charges = /ϵ − /ϵ E D 0 P 0 ρ =ρ+ρ total pol

Electrostatic Potential and Energy ρ ( ) =−∇ Φ Φ( )= 1 ∫ total x' E leads to x π ϵ ∣ − ∣ d x ' 4 0 x x'

1 W = ∫ E⋅D d x 2 2. Linear Isotropic Dielectric Materials ϵ : Electric of the dielectric material ϵ =ϵ/ϵ r 0 : Relative electric permittivity, also called the dielectric constant ϵ−ϵ =ϵ = 0 =(ϵ−ϵ ) D E which leads to P ϵ D and P 0 E

- In linear materials, E, D, and P all have the same general pattern, and only differ in magnitude. ρ ∇⋅(ϵ )=ρ ∇⋅ = E which in regions of uniform material, becomes E ϵ

(ϵ −ϵ )⋅ =σ ( − )× = Boundary Conditions: 2 E2 1 E1 n12 and E2 E1 n12 0

Electrostatic Potential and Energy 1 ρ(x') E=−∇ Φ which in regions of uniform material, leads to Φ(x)= ∫ d x' 4π ϵ ∣x−x'∣ ϵ W = ∫∣E∣2 d x 2

3. Special Cases ϵ=ϵ ϵ = - Outside dielectric materials (free space), 0 or r 1 so that: ϵ−ϵ = 0 P ϵ D becomes P = 0 and

= /ϵ − /ϵ = D E D 0 P 0 becomes E ϵ 0

- Inside perfect dielectric materials, ϵ →∞ so that: ϵ−ϵ = 0 = P ϵ D becomes P D and

= /ϵ − /ϵ E D 0 P 0 becomes E = 0

Therefore, a perfect dielectric acts like a perfect conductor (only in electrostatics).

- Inside regions of uniform, linear dielectric material ∇⋅P=0 so that ρ ∇⋅ =− pol ρ = P ϵ becomes pol 0 so that all polarization charge is on the surface 0 4. Sample Diagram Problem Two conducting spherical shells are concentric. The inner conductor carries a total +Q and the outer conductor carries a total electric charge -Q. The space between the shells, for polar angles less than β, is filled with a uniform dielectric material (shown in blue). The rest of the space between the shells is free space.

Charge Densities - Free charge density shown as plus and minus signs - Polarization charge density shown as circles containing plus and minus signs z ------+ + + + + + -- - + + + + - -+ +------++++ - - ++ ++ - + + - - + + ++Q + ------Q

= /ϵ − /ϵ Field Lines: E D 0 P 0

E D P 5. Another Sample Diagram Problem A solid dielectric sphere has its core removed. This sphere is placed in an originally uniform electric field. There is no conducting material anywhere.

P

- + - + - - + - + - + - + +

D

E

- + - + - - + - + - + - + +