Gravity-And--Electrostatic.Pdf

Journal of Space Exploration Hypothesis | Vol 9 Iss 4 ISSN: 2319-9822 Gravity and Electrostatic * Shriprakash V. Pendse Mumbai University, Ramdas Road, Mulund East, Mumbai, 400081, India *Corresponding author: Shriprakash V. Pendse, Mumbai University, Ramdas Road, Mulund East, Mumbai, 400081, India, [email protected] Received: November 6, 2020; Accepted: November 12, 2020; Published: November 30, 2020 Abstract Integration of gravity and electrostatic forces and uncertainty principal , standard model origin, effect of space fluid (dark matter). Any energy field increases inertia of system by E=MC2. Curving of space time by matter in 4 d will become stretching of space in 2 d By applying Hooks law and general relativity, energy mass equivalence electrostatic field can be derived from gravitational field. Keywords: General theory of relativity; Special theory of relativity; Hooks law Introduction Laws of physics do not change by adding or removing dimensions. 2 d, 3 d, or 4 d, gravitational force equation remains same. Hence super string theory may not work Space is homogenous fluid at cosmic level with positive elasticity but at quantum level exhibits properties of fluid with properties like quantum surface tension and quantum capillary actionSuch space shows –k elasticity at quantum level With this –k space fluid uncertainty principal can be explained Space fluid changes elasticity from –k to k for attractive forces and –k is maintained for repulsive forces. Each time difference is released as energy which is explained by standard model Gravity is fundamental force ,which do not require particle exchange Integration of gravity with electro magnetic force will be empirical only Gravity do not require particle exchange, rest of the forces require because asymmetric nature of space time due to space fluid (dark matter) [1]. Presumptions We consider space-time as a two dimensional for simplicity of calculation. We can extend this to X, Y, Z and time axis permitted by principal of finite induction. Also mass curves space time in 4 d, so in 2 d curving becomes stretching. Space fluid is homogenous at cosmic level having +ve elasticity. At quantum level, as short distance, space fluid is liquid in nature with K – ve (Elasticity Constant). For M2 ∠∠∠ M1 Citation: Pendse SV. Gravity and Electrostatic. J Space Explor. 2020;9(4):167. ©2020 Trade Science Inc. 1 www.tsijournals.com|November -2020 So neglecting M2 effect on medium (2 d space, 2 d flat masses) FIG. 1. Two mass system M1 and M2. Let of consider two mass system M1 and M2. M1shown in (FIG. 1) stretches space fluid hear after referred of medium by ∆ x potential energy because of stretching is E=½ K ∆ x2. ----- Hooks law. So rate of stretching, d/dx E=d/dx ½ K ∆ x2. ∆E= ½ x 2 K ∆ x2. =K ∆ x New such increase in potential energy will lead to increase in inertia of M1 by ∆M1 .So increase in energy will be ∆E= ∆ M1.C2 ------ (II) From I and II ∆ M1.C2=K ∆x ∴ ∆ x=(∆ M1C^2.)/K So total stretching will be ∆ M1C2. ∴ ∑ ∆ 푥 =∑ 퐾 M1C2 S= --- (III) 퐾 푆 New =V, V is speed of stretching. 푇 푆 M1C2 So = ----- (IV 푇 퐾푇 kinematic equation. v=AT V=U+AT For U=0 So A=V/T (A is acceleration) 2 www.tsijournals.com|November -2020 Substituting in (IV) M1C2 A= 퐾푇2 For Mass M2 F=M × A so for mass M2 M1C2 F= × M2 ------ (V) 퐾푇2 푆 Now Substituting T= 푉 M1C2 F= × M2 퐾푇2 C2V2 M1M2 Hence F= 퐾 푆2 So F=force of gravity C2V2 M1M2 F gravity = 퐾 푆2 Now we know gravitational disturbance travel medium of velocity of light so Substituting V=C C2V2 M1M2 F gravity= 퐾 푆2 C4 M1M2 F gravity= 퐾 푆2 C4 We know =G, gravitations constant 퐾 K is elasticity constant of space fluid (dark matter) For calculating electrostatic force we do following assumptions. Space fluid has negative elasticity index i.e. –K. As short range force are field forces and potential involved individual contribution of potential energy is difficult to determine. As potential is respect to other. So contribution of each charge to field will be considering R tine of charge. R is constant. Short range force like electrostatic, we know coulomb constant is dependent of material, dielectric constant etc. So we can presume energy contribution to field R × Q. When R is constant. Now let us consider case. q2<<<q1 shown in (FIG. 2) Now, q1 is charge. By our presumption energy contribution of each charge to field=Rq1 Now energy Rq1 will lead to increase in inertia by 2 ∆R ∆q1=∆mc Now increase in inertia will led to stretching of space fluid by ∆x. By applying Hooks law 2 2 ∆R ∆q1= ∆m1c = ½ K ∆ x =E Hooks Law ----- (1) Now rate of stretching we differentiate 푑 1 ∆E= K ∆ x2 푑푥 2 ∆E=K ∆x ----- (II) 2 Now ∆E = ∆m1c = K∆x ------ (III) Increase in inertia due to q1 3 www.tsijournals.com|November -2020 FIG. 2. Charge of Q1 and Q2. 2 ∆m1c =∆R ∆q1 ∆R ∆q1 So ∆m1= ------ (IIII) 퐶2 Now from (II) and (III) 2 ∆m1c =k∆x ∆푀 퐶2 So ∆ x= 1 퐾 ∆푅∆ 푞1 Replacing ∆m1= 퐶2 2 ∆푀1 퐶 ∆푅 ∆푞1 2 ∆X= = c 푘 퐾퐶2 ∆푅 ∆푞 ∆X= 1 퐾 ∆푥 ∆푅 ∆푞 Now ∑ == ∑ 1 that is velocity ∆푇 ∆푇퐾 푅푞 So, V= 1 푇퐾 V=U +AT For U=0 V=AT 푉 A= 푇 푅푞 So, A= 1 ------ (IV) 퐾푇2 Now for second charge q2 2 ∆R ∆q2 =∆m2c 2 ∑ ∆R ∆q2 = ∑ ∆m2c 2 Rq2=m2c 4 www.tsijournals.com|November -2020 So increase in inertial mass will be 푅푞2 M2= ------ (V) 퐶2 Now , F=MA Force between q1 and q2 푅푞 푅푞 F 푞 푞 = 2 1 ----- (VI) 1 2 퐾퐶2 푇2 푆 Now, T= 푉 푅2푞 푞 푣2 F 푞 푞 = 1 2 1 2 퐾퐶2 푆2 Now we know gravity stretch travels at velocity of light 푅2 푞 푞 F 푞 푞 = 1 2 c2 1 2 퐾퐶2 푆2 2 푅 푞1푞2 = 퐾 푆2 푅2 Now we know =Coulomb constant 퐾 Now for short distance K is presume to be –ve So electrostatic force becomes − 푅2 푞 푞 F= 1 2 퐾 푆2 Now if q1 +ve, q2 is –ve − 푅2 − 푞 푋 +푞 then F= 1 2 퐾 푆2 푅2 푞 푞 F= 1 2 퐾 푠2 - Attraction for q1 and q2 both same polarity i.e. positive or negative. − 푅2 푞 푞 then F= 1 2 ----- repulsion 푘 푠2 So we can say electrostatic forces are both attractive and repulsive.Why in quantum word space fluid medium has negative elasticity. In short range forces, electron, and proton orbits play important role. As when two charge Particles or magnetic poles comes together at force distance varies and bonds come in to play. Because of above mentioned reason, space fluid becomes discrete tubular structure. Hence medium becomes discrete and tubular. Because of discrete and tubular nature of medium, phenomenon likes similar to quantum surface tension and quantum capillary action take effect. Because of this medium has –ve elasticity. When any force interaction happens objective or tendency of space-time is not increase –K by value, or reverse back to +ve K. So any attractive interactions medium reverse back, to +ve K. and ∆ –K is released energy In any repulsive interaction as not to increase –K excess of ∆ –K is released as energy. As space fluied medium is discrete and tubular nature to achieve energy equilibrium principal, medium cannot emit energy in gravitational waves format. As such wave require homogeneous medium so matter achieves this by emitting particles, or radiations. These radiations are observed as per standard model shown in (FIG. 2). 5 www.tsijournals.com|November -2020 FIG. 3. Space Fluid compression leading to uncetainity principle. Delta D=L(PQ)- L(PR) is approximation. Let us consider case photon hitting proton. Due to compressing space time at quantum level, (instead of hitting at) B, photon hits proton at A. ∆ D is Difference of perimeter of proton. Now, let us calculate deference in momentum of photon. P1=Momentum before collision P2=Momentum after collision X Is radius of proton C=is velocity of light ∆ D is distance deviation P1=M1C c is velocity of light Though photon does not have rest mass, it has inertia as per energy mass equivalence 2 E1=M1푐 M1 is inertial mass of photon due to energy mass equivalence E1 M1= C2 Also we can calculate energy of photon as F is frequency E1=hF1 F1=Frequency before collision F2=Frequency after Collision hF1 M1= by energy mass equivalence, mass of photon C2 So, momentum before collision of photon P1= M1C hF1 = × C C2 hF1 = C Similarly momentum P2 after collision. 6 www.tsijournals.com|November -2020 hF2 P2= C ∆P= P2 – P1 h = (F2 – F1) C F2 – F1=∆F h ∆P= ∆F C 1 Now ∆F= (time difference) F=is frequency ∆T h 1 ∆P= C ∆T We know this time deference arising from facts proton perimeter difference. 1 C So, = ∆T ∆D h C ∆P= × C ∆D h ∆P = ∆D Now, We know diameter D D=2휋x, ∆D=2휋∆x X is radius of proton h ∆P= 2휋∆x h So, ∆P ∆X= 2휋 h ∆P ∆X= Is antigravity field length 2휋 In calculating momentum and position , So we can now say uncertainty in measuring momentum and position, arise out of matter compressing space time at quantum level proton. In reality proton may not be circular, but oval. And path followed by h photon may be curve, Hence, we can say ∆P ∆X ≥ , Proton gravity field is not strong to create deviation.

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