materials
Article Idealized 3D Auxetic Mechanical Metamaterial: An Analytical, Numerical, and Experimental Study
Naeim Ghavidelnia 1 , Mahdi Bodaghi 2 and Reza Hedayati 3,*
1 Department of Mechanical Engineering, Amirkabir University of Technology (Tehran Polytechnic), Hafez Ave, Tehran 1591634311, Iran; [email protected] 2 Department of Engineering, School of Science and Technology, Nottingham Trent University, Nottingham NG11 8NS, UK; [email protected] 3 Novel Aerospace Materials, Faculty of Aerospace Engineering, Delft University of Technology (TU Delft), Kluyverweg 1, 2629 HS Delft, The Netherlands * Correspondence: [email protected] or [email protected]
Abstract: Mechanical metamaterials are man-made rationally-designed structures that present un- precedented mechanical properties not found in nature. One of the most well-known mechanical metamaterials is auxetics, which demonstrates negative Poisson’s ratio (NPR) behavior that is very beneficial in several industrial applications. In this study, a specific type of auxetic metamaterial structure namely idealized 3D re-entrant structure is studied analytically, numerically, and experi- mentally. The noted structure is constructed of three types of struts—one loaded purely axially and two loaded simultaneously flexurally and axially, which are inclined and are spatially defined by angles θ and ϕ. Analytical relationships for elastic modulus, yield stress, and Poisson’s ratio of the 3D re-entrant unit cell are derived based on two well-known beam theories namely Euler–Bernoulli and Timoshenko. Moreover, two finite element approaches one based on beam elements and one based on volumetric elements are implemented. Furthermore, several specimens are additively Citation: Ghavidelnia, N.; Bodaghi, manufactured (3D printed) and tested under compression. The analytical results had good agreement M.; Hedayati, R. Idealized 3D Auxetic Mechanical Metamaterial: An with the experimental results on the one hand and the volumetric finite element model results on the Analytical, Numerical, and other hand. Moreover, the effect of various geometrical parameters on the mechanical properties of Experimental Study. Materials 2021, the structure was studied, and the results demonstrated that angle θ (related to tension-dominated 14, 993. https://doi.org/10.3390/ struts) has the highest influence on the sign of Poisson’s ratio and its extent, while angle ϕ (related to ma14040993 compression-dominated struts) has the lowest influence on the Poisson’s ratio. Nevertheless, the compression-dominated struts (defined by angle ϕ) provide strength and stiffness for the structure. Academic Editor: Antonio Santagata The results also demonstrated that the structure could have zero Poisson’s ratio for a specific range of θ and ϕ angles. Finally, a lightened 3D re-entrant structure is introduced, and its results are compared Received: 5 January 2021 to those of the idealized 3D re-entrant structure. Accepted: 16 February 2021 Published: 20 February 2021 Keywords: 3D printing; mechanical metamaterial; auxetics; negative Poisson’s ratio; 3D re-entrant
Publisher’s Note: MDPI stays neutral with regard to jurisdictional claims in published maps and institutional affil- 1. Introduction iations. The Poisson’s ratio is defined as the ratio of the negative value of transverse strain to the longitudinal strain of a body subjected to uniaxial stress [1]. The Poisson’s ratio is usually assumed to be positive (v > 0) for natural materials, which means that the material contracts transversely when stretched longitudinally or expands transversely Copyright: © 2021 by the authors. Licensee MDPI, Basel, Switzerland. when compressed longitudinally [2]. In contrast, there are some materials that reveal the This article is an open access article opposite behavior of common materials and present negative Poisson’s ratio, which means distributed under the terms and that their transverse dimensions increase (or decrease) when they are subjected to axial conditions of the Creative Commons tensile (or compressive) loads [3]. These materials have been given different names in the Attribution (CC BY) license (https:// literature, including anti-rubber, dilational [4], and auxetic materials [5]. The term “auxetic” creativecommons.org/licenses/by/ is currently the most widely accepted name used for materials with a negative Poisson’s 4.0/). ratio. Auxetic behavior has been observed in a few natural materials such as cristobalite
Materials 2021, 14, 993. https://doi.org/10.3390/ma14040993 https://www.mdpi.com/journal/materials Materials 2021, 14, 993 2 of 36
(polymorphic silicones) [6], metals [7], zeolites [8], silicates [9,10], and some biological tissues such as cancellous bone [11], tendons [12], and some animal skins [13,14]. Mechanical metamaterials are man-made materials with unusual mechanical prop- erties and special functionalities not found in nature [15–19]. Negative Poisson’s ratio could be considered as one of such special mechanical properties [20–31]. Due to recent ad- vances in additive manufacturing techniques (3D printing), which provides the possibility of fabrication of rationally-designed materials with the desired accuracy in nano/micro- scale [32–35], the studies concentrated on design and analyzing auxetic metamaterials have been increasing exponentially during the last few years [36–40]. Different geometries with different deformation mechanisms have been introduced for auxetic structures. One of the first auxetic structures was proposed by Roberts [21], the first auxetic foam was presented by Lakes [41], and the first 2D molecular auxetic models (spontaneously forming auxetic phases) were studied by Wojciechowski [22,23]. The term auxetic in the scientific literature was introduced by Evans [24]. The re-entrant hexagonal honeycomb structure is one of the most well-known open-cell auxetic structures [42]. In several studies [43–46], the effect of relative density and re-entrant angle variations on mechanical properties such as Poisson’s ratio and elastic modulus of typical 2D re-entrant structure in the elastic and plastic range have been analyzed for predicting the behavior of the structure. To improve the mechanical properties such as strength and auxeticity of the re-entrant structures and for answering the new requirements in the industry, some researchers have introduced and built novel 3D re-entrant structures inspired by typical 2D re-entrant unit cells and have established analytical and numerical solutions for them [47–50]. The unit cell presented by Yang et al. in 2015 [50] (Figure1a) is one of the successful 3D auxetic structures, which has been solved analytically in two directions and evaluated by experimental and numerical results. In another study, Wang et al. (2016) [51] proposed an interlocking assembly manufacturing technique for fabricating the re-entrant lattice structure proposed by Yang et al. (2015) [50] but with a shifted unit cell (Figure1b), which showed great advantages over additive manufacturing technique. Chen et al. (2017) and Xue et al. (2020) [52,53] applied some modifications to the noted 3D re-entrant auxetic structure by adding some struts to enhance the mechanical properties of the lattice structure, and in particular, to increase the stiffness of this auxetic structure (Figure1c,d). Although the 3D reentrant structures studied in the noted works are successful auxetic structures for many applications, they still lack some geometrical characteristics, which could raise problems in many applications. First of all, even though the noted 3D re-entrant unit cells are symmetrical in the lateral directions, but their geometry is different in the vertical (i.e., loading) direction. Therefore, they exhibit dissimilar mechanical properties in the three main orthogonal directions, which means that they are not truly 3D auxetic structures. Second, the struts at the edge of the noted unit cells are shared by adjacent unit cells in the lattice structure. Since the auxetic structures are useful in many applications (such as biomedical implants [54,55], sandwich panels [56], etc.) that require graded micro- structures, the noted shared struts cause huge complexities and difficulties in constructing truly graded lattice structures. Hence, there remains a gap to propose an ideal unit cell that could overcome these deficiencies of typical 3D re-entrant structure. In this study, a specific type of mechanical metamaterial, namely, an idealized 3D re- entrant structure [41,57] constructed of three strut types, one type loaded purely axially and two types loaded both flexurally and axially, which are inclined and are spatially defined by angles θ and ϕ (see Figure2), is studied to obtain analytical relationships for its mechanical properties. Analytical solutions based on two well-known beam theories namely Euler– Bernoulli and Timoshenko theories are derived. Moreover, two numerical methods one based on volumetric elements and one based on beam elements are implemented for validating the results. A definition for strut effective length has been presented in order to simulate what the struts experience in real-life conditions, and analytical results have been presented based on the effective length. Moreover, a lightened auxetic unit cell extracted from the general re-entrant unit cell (presented in Figure2) is introduced and Materials 2021, 14, 993 3 of 36
its mechanical properties are compared to those of the ideal re-entrant structure. Several specimens have also been additively manufactured and tested under compressive loading Materials 2021, 14, x FOR PEER REVIEWconditions. Finally, the results of the derived analytical and constructed numerical models3 of 36
and the manufactured specimens are compared to one another.
(a) (b)
(c) (d)
FigureFigure 1.1. ReviewReview ofof 3D re-entrant unit cells cells presented presented by by (a (a) )Li Li Yang Yang et et al. al. (2015) (2015) [50], [50 ],(b ()b Xin-Tao) Xin-Tao WangWang et et al. al. (2016)(2016) [[51],51], ((cc)) YuYu ChenChen etet al.al. (2017) [52], [52], and and ( (dd)) Yingying Yingying Xue Xue et et al. al. (2020) (2020) [53]. [53].
In this study, a specific type of mechanical metamaterial, namely, an idealized 3D re- entrant structure [41,57] constructed of three strut types, one type loaded purely axially and two types loaded both flexurally and axially, which are inclined and are spatially defined by angles 𝜃 and 𝜑 (see Figure 2), is studied to obtain analytical relationships for its mechanical properties. Analytical solutions based on two well-known beam theories namely Euler–Bernoulli and Timoshenko theories are derived. Moreover, two numerical methods one based on volumetric elements and one based on beam elements are imple- mented for validating the results. A definition for strut effective length has been presented Materials 2021, 14, x FOR PEER REVIEW 4 of 36
in order to simulate what the struts experience in real-life conditions, and analytical re- sults have been presented based on the effective length. Moreover, a lightened auxetic unit cell extracted from the general re-entrant unit cell (presented in Figure 2) is intro- duced and its mechanical properties are compared to those of the ideal re-entrant struc- Materials 2021, 14, 993 ture. Several specimens have also been additively manufactured and tested under4 ofcom- 36 pressive loading conditions. Finally, the results of the derived analytical and constructed numerical models and the manufactured specimens are compared to one another.
Type I Type II Type III
(a)
(b)
Figure 2. (a) An idealized 3D re-entrant unit cell and its strut types, (b) degrees of freedom (DOFs) of the unit cell. The double arrows represent the rotational degrees of freedom. More illustrations of the unit cell, its dimensions, and boundary conditions can be found in Figures S1–S5.
2. Materials and Methods 2.1. Analytical Solution 2.1.1. Relative Density Each re-entrant unit cell (Figure2a and Figure S1) consists of three types of struts with lengths l1, l2, l3 and cross-sectional areas A1, A2, A3. The unit cell is fully defined with two Materials 2021, 14, 993 5 of 36
unique angles θ and ϕ, the Type-I strut length, and the main cube size (the main cube is the hypothetical cube formed by connecting vertices Di where i = 1 to 8). Angle θ is defined as the angle between Type-II strut and the face diagonals of the main cube, and angle ϕ is defined as the angle between a Type-III strut and the corresponding side of the main cube (Figure2b). Each re-entrant unit cell with mentioned strut lengths ( l1, l2, l3) and character- istic angles (θ, ϕ) occupies a cubic volume with side length of 2(l1 + l3 cos ϕ − l2 sin θ) and 3 hence the volume of Vtotal = 8(l1 + l3 cos ϕ − l2 sin θ) . Because the unit cell is made up of six struts of Type I, 24 struts of Type II, and 24 struts of Type III, the volume occupied by 2 2 2 all struts inside the unit cell is Vstrut = 6πr1l1 + 24πr2l2 + 24πr3l3. Therefore, according to the basic definition of relative density µ = Vstrut , the relative density of a re-entrant unit Vtotal cell is given by 6A l + 24A l + 24A l 3π r2l + 4r2l + 4r2l = 1 1 2 2 3 3 = 1 1 2 2 3 3 µ 3 3 (1) Lunitcell 4(l1 + l3 cos ϕ − l2 sin θ)
2.1.2. Stiffness Matrix In this subsection, analytical relationships for mechanical properties of the 3D re- entrant unit cell such as elastic modulus, Poisson’s ratio, and yield stress are derived as functions of elastic properties of the bulk material (Es, Gs, σys, and vs) and the geometrical dimensions of the unit cell. The re-entrant unit cell has symmetry with respect to its major planes (see Figure S2). Therefore, studying 1/8 of the unit cell is sufficient for obtaining the mechanical properties of the unit cell and, hence, the corresponding lattice structure. Due to the intrinsic symmetries in the geometry of the re-entrant unit cell and the applied boundary conditions on the unit cell, seven unique group of vertices can be recognized, which are denoted by letters A, B, C, D, E, F, and G, as shown in Figure2a. For the sake of brevity and as the vertices named by similar letters demonstrate identical behaviors, in many cases, instead of referring to a vertex as Xi, we refer to it as X (X representing A, B, C, D, E, F, and G). For instance, in many cases, we use the name E instead of E1. If the origin of the coordinate system is considered to be located in the midst of the unit cell, each re-entrant unit cell has four vertical (XY, YZ, and two bisectors of XY and YZ) and one horizontal (XZ) symmetry planes (as shown in Figure S2). All the vertices located in the symmetry planes are only allowed to translate and rotate in their corresponding planes. Vertices Ai and Bi (for i = 1, 2) lie in all of the four vertical symmetry planes, so they are only allowed to translate in the Y direction, and they are constrained rotationally. Therefore, they create two degrees of freedom (DOFs) q8 and q7 at vertices Ai and Bi, respectively. Vertices Ci (for i = 1 to 8) are located in one of the vertical symmetry planes (XY or YZ), and hence they are only allowed to translate horizontally and vertically and rotate in their corresponding planes, which results in three other DOFs (q3, q4, q11). Each vertex Di (for i = 1 to 8) is located in a single vertical symmetry plane (one of two bisectors of YZ and YX), and therefore, it is only allowed to translate horizontally and vertically and rotate in the planes it is located in, which leads to three other DOFs (q5, q6, q10). Vertices Ei and Fi (for i = 1 to 4) are located in one of two vertical symmetry planes (XY or YZ) and the horizontal symmetry plane XZ, so they are only allowed to translate in the X or Z directions without any rotations. This creates two other DOFs q2 and q1 at vertices E and F, respectively. Vertices Gi are located in the horizontal symmetry plane XZ and in one of the vertical bisector symmetry planes (bisectors of XY and YZ). Therefore, these points cannot rotate in any directions and are only allowed to translate horizontally in the bisector of the noted planes, which leads to the final DOF q9. Overall, the system has a total number of 11 DOFs (Figure2b). In this study, two well-known elastic beam theories, namely, Euler–Bernoulli and Timoshenko beam theories, have been implemented for analytical analysis of the re-entrant unit cell. As the beam theories and material models used for the analytical analysis are linear, the overall deformation of each DOF in the system can be considered as the superposition of separate deformations caused by applying individual loads at each DOF. Materials 2021, 14, x FOR PEER REVIEW 6 of 36
translate in the X or Z directions without any rotations. This creates two other DOFs 𝑞 and 𝑞 at vertices E and F, respectively. Vertices 𝐺 are located in the horizontal symmetry plane XZ and in one of the vertical bisector symmetry planes (bisectors of XY and YZ). Therefore, these points cannot rotate in any directions and are only allowed to translate horizontally in the bisector of the noted planes, which leads to the final DOF 𝑞 . Overall, the system has a total number of 11 DOFs (Figure 2b). In this study, two well-known elastic beam theories, namely, Euler–Bernoulli and Materials 2021, 14, 993 Timoshenko beam theories, have been implemented for analytical analysis of the 6re-en- of 36 trant unit cell. As the beam theories and material models used for the analytical analysis are linear, the overall deformation of each DOF in the system can be considered as the superposition of separate deformations caused by applying individual loads at each DOF. Therefore,Therefore, thethe superpositionsuperposition principle could could be be implemented implemented for for obtaining obtaining the the system system of ofequations equations of ofthe the unit unit cell. cell. In this In this approach approach,, each each DOF DOF displaces displaces autonomously autonomously from fromother otherDOFs, DOFs, and when and when a DOF a DOFis displa is displaced,ced, the other the other DOFs DOFs are kept are keptfixed. fixed. By solving By solving the equi- the equilibrium equations for the vertices of the unit cell, the resultant forces are obtained. By librium equations for the vertices of the unit cell, the resultant forces are obtained. By considering this method, the system of equilibrium equations for the structure could be considering this method, the system of equilibrium equations for the structure could be written as {Q} = [K]{q}. In this equation, {Q} is the force vector comprising the external written as {𝑄} = [𝐾]{𝑞}. In this equation, {𝑄} is the force vector comprising the external forces acting on the DOFs, [K] is the stiffness matrix of the system, and the {q} is the forces acting on the DOFs, [𝐾] is the stiffness matrix of the system, and the {𝑞} is the dis- displacement vector. placement vector. Because the derivation of the stiffness matrix elements is based on beam theories, the Because the derivation of the stiffness matrix elements is based on beam theories, the general deformation of a cantilever beam (Figure3) can be considered as the resultant of general deformation of a cantilever beam (Figure 3) can be considered as the resultant of four distinct deformations at the free end of the beam, which are as follows: four distinct deformations at the free end of the beam, which are as follows: (a) a lateral displacement without any rotation, v; (a) a lateral displacement without any rotation, 𝑣; (b) a flexural rotation without any lateral displacement, θ; (b) a flexural rotation without any lateral displacement, 𝜃; (c) a longitudinal elongation or contraction, u; 𝑢 (d)(c) aan longitudinal axial twist, elongationϕ. or contraction, ; (d) an axial twist, 𝜑.
FigureFigure 3. 3.General General deformationdeformation of of a a cantilever cantilever beam beam with with axial axial and and lateral lateral displacements displacements in in addition addi- tion to flexural and torsional rotations in its free end. to flexural and torsional rotations in its free end.
TheThe correspondingcorresponding forcesforces andand momentsmoments requiredrequired toto createcreate eacheach ofof thethe purepure above-above- mentionedmentioned deformationsdeformations areare demonstrateddemonstrated inin FigureFigure4 4 for for the the Euler–Bernoulli Euler–Bernoulli and and Timo- Timo- shenkoshenko beam beam theories. theories. DueDue toto frequentfrequent repetitionrepetition of of some some terms terms demonstrated demonstrated in inFigure Figure4 4 throughoutthroughout thethe wholewhole manuscript, the the terms terms 𝑆S ,i ,𝑊W ,i ,𝑇 T, i𝑉, V, andi, and 𝑈 Uarei are used, used, which which are aredif- differentferent for for Euler–Bernoulli Euler–Bernoulli and and Timoshenko Timoshenko beam beam theories theories and and are are listed listed in in Table Table 1.1 .
Table 1. Parameters defined for summarizing the relationships for Euler–Bernoulli and Timoshenko beam theories.
Term Euler-Bernoulli Theory Timoshenko Theory
Ai Es Ai Es Si li li Gs Ji Gs Ji Wi li li 12Es Ii 1 Ti 3 3 l l l i i + i 12Es Ii κAi Gs V 6Es Ii 1 i l2 l2 i i + 2 6Es Ii κAi Gs 2Es Ii + 2li 4Es Ii κA Gsl 3 Ui l i l2 i + 2 6Es Ii κAi Gs Materials 2021, 14, 993 7 of 36 Materials 2021, 14, x FOR PEER REVIEW 7 of 36
(a)
(b)
(c)
(d)
Figure 4. ForcesFigure and moments 4. Forces required and moments to cause required (a) lateral to cause displacement (a) lateralδ displacementwith no rotation, 𝛿 with (b) flexuralno rotation, rotation (b) θ with no lateral displacement,flexural (c )rotation pure axial 𝜃 with extension, no lateral and displacement, (d) pure twist ( atc) thepure free axial end extension, of a beam and [58 ].(d) pure twist at the free end of a beam [58]. To explain the general procedure for deriving the stiffness matrix elements, we could Table 1. Parametersconsider defined a strut for PQ summarizing with an arbitrary the relationships orientation for Euler–Bernoulli with respect toand the Timo- global X, Y, and Z shenko beamcoordinate theories. system (aligned with a unit vector uPQ), which is deformed by a specific DOF qi at its free end. The schematic representation of such a strut and its deformation due to Euler-Bernoulli Termthe DOF is illustrated in Figure5.Timoshenko As shown in Theory the figure, DOF qi causes a longitudinal and a transverse deformationTheory in the strut PQ. The vector of longitudinal deformation 𝐴 𝐸 𝐴 𝐸 𝑆of strut PQ can be obtained by projecting the vector qi on the strut PQ unit vector, i.e., 𝑙 𝑙 qi·uPQ uPQ. Moreover, the vector of transverse deformation of strut PQ can be obtained − · 𝐺 𝐽 𝐺 𝐽 𝑊as qi qi uPQ uPQ . By multiplying the longitudinal deformation vector of strut PQ by 𝑙 𝑙 the resultant force value of PQ (i.e., Si), the resultant longitudinal force vector for strut 1 PQ can be obtained12𝐸 as 𝐼 q ·uPQ uPQ Si, and by multiplying the transverse deformation i 𝑇vector of strut PQ by the resultant transverse𝑙 force𝑙 value of PQ (i.e., T ), the resultant 𝑙 + i 12𝐸 𝐼 𝜅𝐴 𝐺 transverse force vector for this strut can be obtained as qi − qi·uPQ uPQ Ti. The reaction Materials 2021, 14, x FOR PEER REVIEW 8 of 36
1 6𝐸 𝐼 𝑉 𝑙 2 𝑙 + 6𝐸 𝐼 𝜅𝐴 𝐺 2𝐸 𝐼 2𝑙 + 4𝐸 𝐼 𝜅𝐴 𝐺 𝑙 3 𝑈 𝑙 2 𝑙 + 6𝐸 𝐼 𝜅𝐴 𝐺
To explain the general procedure for deriving the stiffness matrix elements, we could consider a strut PQ with an arbitrary orientation with respect to the global X, Y, and Z coordinate system (aligned with a unit vector 𝒖 ), which is deformed by a specific DOF 𝒒 at its free end. The schematic representation of such a strut and its deformation due to the DOF is illustrated in Figure 5. As shown in the figure, DOF 𝒒 causes a longitudinal and a transverse deformation in the strut PQ. The vector of longitudinal deformation of strut PQ can be obtained by projecting the vector 𝒒 on the strut PQ unit vector, i.e., 𝒒 ·𝒖 𝒖 . Moreover, the vector of transverse deformation of strut PQ can be obtained as 𝒒 − 𝒒 ·𝒖 𝒖 . By multiplying the longitudinal deformation vector of strut PQ by the resultant force value of PQ (i.e., 𝑆 ), the resultant longitudinal force vector for strut PQ
can be obtained as 𝒒 .𝒖 𝒖 𝑆 , and by multiplying the transverse deformation vec-
tor of strut PQ by the resultant transverse force value of PQ (i.e., 𝑇 ), the resultant trans- verse force vector for this strut can be obtained as 𝒒 − 𝒒 ·𝒖 𝒖 𝑇 . The reaction mo- Materials 2021, 14, 993 ment vector, created by the transverse deformation of strut PQ can be found by the cross-8 of 36 product of the unit vector of PQ (i.e., 𝒖 ) and the resultant moment vector of the beam
(i.e., 𝒒 − 𝒒 ·𝒖 𝒖 𝑉 ), which yields − 𝒖 × 𝒒 − 𝒒 ·𝒖 𝒖 𝑉 . The values of
𝑆moment , 𝑇 , and vector, 𝑉 for createdTimoshenko by the and transverse Euler–Bernoulli deformation beam of struttheories PQ canare belisted found in Table by the 1. cross- It is worthproduct noting of the that unit the vector procedure of PQ (i.e.,of obtaininuPQ) andg the the forces resultant and momentmoments vector for a oflateral the beamrota- tional(i.e., q DOFi − qisi· uveryPQ usimilarPQ Vi), to which the above-ment yields − uionedPQ × procedure,qi − qi·uPQ andu PQit couldVi. Thebe easily values per- of formedSi, Ti, and by Vreplacingi for Timoshenko the terms and 𝑆 , 𝑇 Euler–Bernoulli , and 𝑉 with the beam terms theories 𝑊 , 𝑉 , areand listed 𝑈 , respectively. in Table1. It is worthIn noting the following, that the procedurethe detailed of procedure obtaining theof de forcesrivation and of moments the stiffness for a lateralmatrix rotationalelements forDOF three is very distinct similar DOFs to the(𝑞 , above-mentioned 𝑞 , and 𝑞 ) are presented. procedure, The and derivation it could be procedure easily performed of other DOFsby replacing is similar the to terms the onesSi, T ipresented, and Vi with in the the paper, terms Wbuti, Vtheyi, and areU providedi, respectively. in Section S.1.2 and Figure S6.
Materials 2021, 14, x FOR PEER REVIEW 9 of 36
(a)
(b) Figure 5. General deformation of a strut due to 𝑞 =1 (a) magnitude of deformations and (b) re- Figure 5. General deformation of a strut due to qi = 1 (a) magnitude of deformations and (b) resultant forces and moments. sultant forces and moments. In the following, the detailed procedure of derivation of the stiffness matrix elements (a)for threeFirst distinct DOF: 𝑞 DOFs=1 (q1, q2, and q10) are presented. The derivation procedure of other DOFsHere, is similar the elements to the ones of the presented first column in the of paper, the stiffness but they matrix are provided are derived in Sectionby applying S.1.2 theand unit Figure displacement S6. 𝑞 =1 and by keeping all the other DOFs fixed (i.e., = 0). This de- formation type displaces point 𝐹 horizontally in the Z direction. This deformation only (a) First DOF: q1 = 1 causes elongation in strut EF and it does not affect the other struts. The vector of elonga- Here, the elements of the first column of the stiffness matrix are derived by applying ⃗ ⃗ tion of strut EF can be obtained= by projecting the vector 𝒒 on strut EF, i.e., 𝑞 ⃗. the unit displacement q1 1 and by keeping all the other DOFs fixed (i.e., = 0). ⃗ This ⃗ deformation type displaces point F horizontally in the Z direction. This deformation only or in a simpler notation 𝒒 .𝒖 𝒖1 , where 𝒒 is the unit vector parallel to the first causes elongation in strut EF and it does not affect the other struts. The vector of elongation DOF, and 𝒖 is the unit vector parallel to strut 𝐸 𝐹 . The same system of notation will be used in the rest of the document. By multiplying the elongation vector of strut EF by the resultant force parameter of strut EF (i.e., 𝑆 ), the resultant force vector can be obtained
as 𝒒 .𝒖 𝒖 𝑆 . The equilibrium of forces at point 𝐹 in the 𝑞 direction, i.e., the Z direction, provides the 𝐾 element of the stiffness matrix (Figure 6), which is calculated as
𝑄 𝐹 =0 → −𝒒 · 𝒒 ·𝒖 𝒖 𝑆 =0 →𝐾 =𝑄 =4𝑆 (2) , 4 It must be noted that the forces demonstrated in Figure 6 are the only forces that must act on the beam in order for it to deform in the way it is shown. The force the beam applies at each vertex is in the opposite direction of what is shown in Figure 6. The same holds true for all the next derivations. The equilibrium of forces at point 𝐸 in the 𝑞 direction (i.e., in the Z direction) provides the 𝐾 element of the stiffness matrix, which is calculated as
𝑄 𝐹 =0 → +𝒒 · 𝒒 ·𝒖 𝒖 𝑆 =0 →𝐾 =𝑄 =−4𝑆 (3) , 4
Because the displacement of DOF 𝒒 does not have any effect on other DOFs (𝒒 ,𝒒 ,𝒒 ,𝒒 ,𝒒 ,𝒒 ,𝒒 ,𝒒 ,𝒒 ), the remaining elements of the first column of the stiffness matrix are zero. Materials 2021, 14, 993 9 of 36
→ → → E F E F of strut EF can be obtained by projecting the vector q on strut EF, i.e., q · 1 1 1 1 or 1 1 → → E F E F 1 1 1 1 · in a simpler notation q1 uE1 F1 uE1 F1 , where q1 is the unit vector parallel to the first DOF,
and uE1 F1 is the unit vector parallel to strut E1F1. The same system of notation will be used in the rest of the document. By multiplying the elongation vector of strut EF by the resultant force parameter of strut EF (i.e., S1), the resultant force vector can be obtained as · q1 uE1 F1 uE1 F1 S1. The equilibrium of forces at point F1 in the q1 direction, i.e., the Z direction, provides the K11 element of the stiffness matrix (Figure6), which is calculated as Materials 2021, 14, x FOR PEER REVIEW 10 of 36 Q F = 0 → 1 − q · q ·u u S = 0 → K = Q = 4S (2) ∑ z,F1 4 1 1 E1 F1 E1 F1 1 11 1 1
Figure 6. Deformation of strut EF due to 𝑞 =1. Figure 6. Deformation of strut EF due to q1 = 1.
(b) ItSecond must be DOF: noted 𝑞 that=1 the forces demonstrated in Figure6 are the only forces that must act onIn the this beam subsection, in order forthe itelements to deform of inthe the seco waynd it column is shown. of Thethe stiffness force the matrix beam applies are de- atrived. each Therefore, vertex is in we the set opposite 𝑞 =1 direction, and the ofother what DOFs is shown are set in to Figure zero.6 .This The deformation same holds true type fordisplaces all the nextpoint derivations. E horizontally The equilibriumin the Z direction, of forces which at point causesE1 in strut the q 2EFdirection to have (i.e.,a pure in thecontraction Z direction) and provides strut ED the to Khave12 element contractio of then accompanied stiffness matrix, by whichtransverse is calculated displacement. as The vector of contraction of strut EF can be obtained by projecting vector 𝒒 on strut EF, Q2 i.e., 𝒒 .𝒖 F 𝒖 = 0. The→ vector+ q of· contractionq ·u u of strutS = ED0 →canK be= obtainedQ = − 4byS projecting(3) ∑ z ,E1 4 2 1 E1 F1 E1 F1 1 12 2 1 vector 𝒒𝟐 on strut ED, i.e., 𝒒 .𝒖 𝒖 , and the vector of transverse displacement of Because the displacement of DOF q does not have any effect on other DOFs vertex E of strut ED can be calculated as 𝒒1 − 𝒒 .𝒖 𝒖 . (q3, qBy4, qmultiplying5, q6, q7, q 8the, q contraction9, q10, q11) ,vector the remaining of strut EF elements by the resultant of the first force column parameter of the of stiffnessstrut EF matrix (i.e., are𝑆 zero.), the resultant force vector of strut EF can be obtained as (b) Second DOF: q = 1 𝒒 .𝒖 𝒖 𝑆 2. Moreover, by multiplying the elongation vector of strut ED by the resultantIn this force subsection, parameter the of elements strut ED of(i.e., the 𝑆 second), the resultant column force of the vector stiffness can be matrix obtained are derived. Therefore, we set q2 = 1, and the other DOFs are set to zero. This deformation as 𝒒 .𝒖 𝒖 𝑆 . Finally, by multiplying the transverse deformation vector of strut type displaces point E horizontally in the Z direction, which causes strut EF to have a pure ED by the resultant transverse force parameter of strut ED (i.e., 𝑇 ), the resultant trans- contraction and strut ED to have contraction accompanied by transverse displacement. verse force vector of this strut can be obtained as 𝒒 − 𝒒 .𝒖 𝒖 𝑇 . It is worth The vector of contraction of strut EF can be obtained by projecting vector q2 on strut EF, i.e., noting· that the resultant forces obtained for deformation of struts ED at point E must be q2 uE1 F1 uE1 F1 . The vector of contraction of strut ED can be obtained by projecting vector multiplied by four because· there are four similar struts ED connected to point E. The equi- q2 on strut ED, i.e., q2 uE1D1 uE1D1 , and the vector of transverse displacement of vertex E librium of forces at point E in the −𝑞 direction· (i.e., the Z direction), Figure 7b, provides of strut ED can be calculated as q2 q2 uE1D1 uE1D1 . the elementBy multiplying 𝐾 of the the stiffness contraction matrix vector as follows: of strut EF by the resultant force parameter of · 𝑄 strut EF (i.e., S1), the resultant force vector of strut EF can be obtained as q2 uE1 F1 uE1 F1 S1. 𝐹 , =0 → −𝒒 . 𝒒 .𝒖 𝒖 𝑆 +4 𝒒 . 𝒒 .𝒖 𝒖 𝑆 −4 𝒒 . 𝒒 − 𝒒 .𝒖 𝒖 𝑇 =0 4 Moreover, by multiplying the elongation vector of strut ED by the resultant force parameter(4) of strut ED (i.e., S ), the resultant force vector can be obtained as q ·u u S . →𝐾 =𝑄 =4(𝑆 +4sin 𝜃𝑆 + 4 cos 𝜃𝑇 ) 2 2 E1D1 E1D1 2 Finally, by multiplying the transverse deformation vector of strut ED by the resultant transverse force parameter of strut ED (i.e., T2), the resultant transverse force vector of − · this strut can be obtained as q2 q2 uE1D1 uE1D1 T2. It is worth noting that the resultant forces obtained for deformation of struts ED at point E must be multiplied by four because there are four similar struts ED connected to point E. The equilibrium of forces at point E in the q2 direction (i.e., the Z direction), Figure7b, provides the element K22 of the stiffness matrix as follows:
(a) Materials 2021, 14, x FOR PEER REVIEW 10 of 36
Figure 6. Deformation of strut EF due to 𝑞 =1.
(b) Second DOF: 𝑞 =1 In this subsection, the elements of the second column of the stiffness matrix are de- rived. Therefore, we set 𝑞 =1, and the other DOFs are set to zero. This deformation type displaces point E horizontally in the Z direction, which causes strut EF to have a pure contraction and strut ED to have contraction accompanied by transverse displacement. The vector of contraction of strut EF can be obtained by projecting vector 𝒒 on strut EF,
i.e., 𝒒 .𝒖 𝒖 . The vector of contraction of strut ED can be obtained by projecting
vector 𝒒𝟐 on strut ED, i.e., 𝒒 .𝒖 𝒖 , and the vector of transverse displacement of
vertex E of strut ED can be calculated as 𝒒 − 𝒒 .𝒖 𝒖 . By multiplying the contraction vector of strut EF by the resultant force parameter of strut EF (i.e., 𝑆 ), the resultant force vector of strut EF can be obtained as