GENERALIZATIONS OF EULER NUMBERS AND
POLYNOMIALS
QIU-MING LUO AND FENG QI
Abstract. In this paper, the concepts of Euler numbers and Euler polynomials are generalized, and some basic properties are investigated.
1. Introduction
It is well-known that the Euler numbers and polynomials can be defined by the following definitions.
Definition 1.1 ([1]). The Euler numbers Ek are defined by the following expansion
∞
2et
e2t + 1
Ek
X
=
tk, |t| ≤ π.
(1.1) (1.2) k!
k=0
In [4, p. 5], the Euler numbers is defined by
ꢀ ꢁ
∞
n
2n
2et/2
et + 1
t
(−1) En
t
X
- = sech
- =
,
|t| ≤ π.
- 2
- (2n)!
- 2
n=0
Definition 1.2 ([1, 4]). The Euler polynomials Ek(x) for x ∈ R are defined by
∞
2ext
et + 1
Ek(x) k!
X
=
tk, |t| ≤ π.
(1.3)
k=0
It can also be shown that the polynomials Ei(t), i ∈ N, are uniquely determined by the following two properties
- Ei0(t) = iEi−1(t), E0(t) = 1;
- (1.4)
- (1.5)
- Ei(t + 1) + Ei(t) = 2ti.
2000 Mathematics Subject Classification. 11B68.
Key words and phrases. Euler numbers, Euler polynomials, generalization. The authors were supported in part by NNSF (#10001016) of China, SF for the Prominent
Youth of Henan Province, SF of Henan Innovation Talents at Universities, NSF of Henan Province (#004051800), Doctor Fund of Jiaozuo Institute of Technology, China.
A
This paper was typeset using A S-LT X.
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1
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- Q.-M. LUO AND F. QI
Euler polynomials are related to the Bernoulli numbers. For information about
Bernoulli numbers and polynomials, please refer to [1, 2, 3, 4].
In this paper, we will give some generalizations of the concepts of Euler numbers and Euler polynomials, and research their basic properties.
2. Generalizations of Euler numbers and polynomials
In this section, we give two definitions, the generalized Euler number and the generalized Euler polynomial, which generalize the concepts of Euler number and Euler polynomial.
Definition 2.1. For positive numbers a, b, c, the generalized Euler numbers Ek(a, b, c) are defined by
∞
2ct b2t + a2t
Ek(a, b, c)
X
=
tk.
(2.1) k!
k=0
Definition 2.2. For any given positive numbers a, b, c and x ∈ R, the generalized Euler polynomials Ek(x; a, b, c) are defined by
∞
2cxt bt + at
Ek(x; a, b, c)
X
=
tk.
(2.2) k!
k=0
If taking a = 1, b = c = e, then Definition 1.1 and Definition 1.2 can be deduced from Definition 2.1 and Definition 2.2 respectively. Thus, the Definition 2.1 and Definition 2.2 generalize the concepts of Euler numbers and polynomials.
3. Some properties of the generalized Euler numbers
In this section, we study some basic properties of the generalized Euler numbers defined in Definition 2.1.
Theorem 3.1. For positive numbers a, b, c and real number x ∈ R, we have
E0(a, b, c) = 1, Ek(1, e, e) = Ek, Ek(1, e1/2, ex) = Ek(x),
(3.1) (3.2)
- ꢀ
- ꢁ
ln c − 2 ln a
Ek(a, b, c) = 2k(ln b − ln a)kEk
,
2(ln b − ln a)
ꢀ ꢁ
k
X
k
Ek(a, b, c) =
- (ln b − ln a)j(ln c − ln a − ln b)k−jEj.
- (3.3)
j
j=0
Proof. The formulae in (3.1) follow from Definition 1.1, Definition 1.2, and Definition 2.1 easily.
- GENERALIZATIONS OF EULER NUMBERS AND POLYNOMIALS
- 3
By Definition 1.2 and Definition 2.1 and direct computation, we have
- ꢂ
- ꢃ
ln c−2 ln a
2ct b2t − a2t
- 2 exp
- · 2t(ln b − ln a)
2(ln b−ln a)
- ꢂ
- ꢃ
==exp 2t(ln b − ln a) + 1
(3.4)
- ꢀ
- ꢁ
∞
ln c − 2 ln a tk
X
2k(ln b − ln a)kEk
.
2(ln b − ln a) k!
k=0
Then, the formula (3.2) follows.
ꢂ ꢃ
P
k
j=0
kj
1
−j
- Substituting Ek(x) =
- 2
- (x− 2 )k−jEj into the formula (3.2) yields the
formula (3.3).
ꢀ
Theorem 3.2. For k ∈ N, we have
ꢀ ꢁ
k−1
X
- ꢄ
- ꢅ
12
kj
Ek(a, b, c) = −
(2 ln b − ln c)k−j + (2 ln a − ln c)k−j Ej(a, b, c), (3.5)
j=0
Ek(a, b, c) = Ek(b, a, c),
(3.6) (3.7)
Ek(aα, bα, cα) = αkEk(a, b, c).
Proof. By Definition 2.1, direct calculation yields
- "
- #
- ꢀ
- ꢁ
- ꢀ
- ꢁ
- t
- t
∞
k
X
12
b2
c
a2
ct
1 =
=
+
Ek(a, b, c)
k!
k=0
- "
- #
- ꢀ
- ꢁ
- ꢀ
- ꢁ
∞
- k
- k
∞
- k
- k
- b2
- a2
t
- X
- X
12
t
- ln
- +
ln ln
Ek(a, b, c)
(3.8) k!
- c
- c
k!
- k=0
- k=0
-
-
- "
- #
ꢀ ꢁ ꢀ
- ꢁ
- ꢀ
- ꢁ
∞
- k
- k−j
- k−j
- X
- X
12
k
b2
c
a2
tk
- =
- +
- ln
Ej(a, b, c)
.
- j
- c
k!
- j=0
- k=0
Equating coefficients of tk in (3.8) gives us
- "
- #
ꢀ ꢁ ꢀ
- ꢁ
- ꢀ
- ꢁ
- k
- k−j
- k−j
kj
b2
c
a2
X
- ln
- +
- ln
Ej(a, b, c) = 0.
(3.9)
c
j=0
Formula (3.5) follows.
The rest formulae follow from Definition 2.1 and formula (3.2).
ꢀ
Remark 3.1. For positive numbers a, b, and c, we have the following
E0(a, b, c) = 1, E1(a, b, c) = ln c − ln a − ln b,
(3.10)
E2(a, b, c) = (ln c − 2 ln a)(ln c − 2 ln b),
E3(a, b, c) = [(ln c − ln a − ln b)2 − 3(ln b − ln a)2](ln c − ln a − ln b).
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- Q.-M. LUO AND F. QI
4. Some properties of the generalized Euler polynomials
In this section, we will investigate properties of the generalized Euler polynomials defined by Definition 2.2.
Theorem 4.1. For any given positive numbers a, b, c and x ∈ R, we have
ꢀ ꢁ
- ꢀ
- ꢁ
kk−j
X
k
- (ln c)k−j
- 1
2
Ek(x; a, b, c) = Ek(x; a, b, c) = Ek(x; a, b, c) = x −
Ej(a, b, c),
(4.1)
j
2j
j=0
ꢀ ꢁ
ꢀ
ꢁ ꢀ
- ꢁ
- ꢀ
- ꢁ
- k
- j
- k−j
X
- k
- b
12ln c − 2 ln a
(ln c)k−j ln
x −
Ej
, (4.2)
- j
- a
2(ln b − ln a)
j=0
ꢀ ꢁꢀ ꢁ
- ꢆ
- ꢇ
- ꢆ
- ꢇ
j
- k
- `
- k−j
- h
- i
(ln c)k−j
- b
- c
12
X X
j−`
kjj`
- ln
- ln
x −
E`, (4.3)
2j
- a
- ab
- j=0
- `=0
- ꢀ
- ꢁ
12
- Ek(a, b, c) = 2kEk
- ; a, b, c
,
(4.4) (4.5)
Ek(x) = Ek(x; 1, e, e).
Proof. By Definition 2.1 and Definition 2.2, we have
∞
2c2xt b2t + a2t tk
X
=
2kEk(x; a, b, c)
(4.6) (4.7) k!
k=0
and
- 2c2xt
- 2ct
==
· c(2x−1)t
- b2t + a2t
- b2t + a2t
!
!
- ∞
- ∞
- k
- k
- X
- X
- t
- t
Ek(a, b, c)
(2x − 1)k(ln c)k
- k!
- k!
- k=0
- k=0
-
-
ꢀ ꢁ
∞
k
kj
tk
.
- X
- X
- =
- (ln c)k−j(2x − 1)k−jEj(a, b, c)
-
-
k!
- j=0
- k=0
tk
k!
- Equating the coefficients of
- in (4.6) and (4.7) yields
ꢀ ꢁ
k
X
k
- 2kEk(x; a, b, c) =
- (ln c)k−j(2x − 1)k−jEj(a, b, c).
j
j=0
Formula (4.1) follows.
The rest formulae follow directly from substituting formulae (3.2) and (3.3) into
12
(4.1) and taking x = in (4.1), respectively.
ꢀ
- GENERALIZATIONS OF EULER NUMBERS AND POLYNOMIALS
- 5
Theorem 4.2. For positive integer 1 ≤ p ≤ k, we have
p
∂
k!
- Ek(x; a, b, c) =
- (ln c)pEk−p(x; a, b, c),
(4.8) (4.9)
∂xp
(k − p)!
Z
x
1
- Ek(t; a, b, c)dt =
- [Ek+1(x; a, b, c) − Ek+1(β; a, b, c)] .
(k + 1) ln c
β
Proof. Differentiating on both sides of formula (4.1) yields
∂
Ek(x; a, b, c) = k(ln c)Ek−1(x; a, b, c).
(4.10)
∂x
Using formula (4.10) and by mathematical induction, the formulae (4.8) follows. Rearranging formula (4.10) produces
1
∂
- Ek(x; a, b, c) =
- Ek+1(x; a, b, c).
(4.11)
(k + 1) ln c ∂x
Formula (4.9) follows from integrating on both sides of formula (4.11).
ꢀ
Theorem 4.3. For positive numbers a, b, c and x ∈ R, we have
ꢀ ꢁ
k
X
k
- Ek(x + 1; a, b, c) =
- (ln c)k−jEj(x; a, b, c),
(4.12)
j
j=0
Ek(x + 1; a, b, c) = 2xk(ln c)k
ꢀ ꢁ
k
(4.13) (4.14)
X
- ꢄ
- ꢅ
kj
- +
- (ln c)k−j − (ln b)k−j − (ln a)k−j Ej(x; a, b, c),
j=0
- ꢀ
- ꢁ
a b
Ek(x + 1; a, b, c) = Ek x; , , c
.
c c
Proof. From Definition 2.2 and straightforward calculation, we have
"
# "
#
- ∞
- ∞
- k
- k
2cxt bt + at
- t
- t
- X
- X
· ct =
Ek(x; a, b, c)
(ln c)k
- k!
- k!
- k=0
- k=0
-
-
(4.15)
ꢀ ꢁ
∞
k
X X
kj
tk
-
-
- =
- (ln c)k−jEj(x; a, b, c)
k!
- j=0
- k=0
and
∞
k
2cxt
2c(x+1)t
t
X
· ct =
=
Ek(x + 1; a, b, c).
(4.16)
- bt + at
- bt + at
k!
k=0
tk
k!
Therefore, from equating the coefficients of follows. in (4.15) and (4.16), formula (4.12)
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- Q.-M. LUO AND F. QI
Similarly, we obtain
∞
k
2c(x+1)t
t
2cxt
X
=
Ek(x + 1; a, b, c) = 2cxt
+
(ct − bt − at) bt + at