Definition of the Ideal Gas
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Thermodynamics Notes
Thermodynamics Notes Steven K. Krueger Department of Atmospheric Sciences, University of Utah August 2020 Contents 1 Introduction 1 1.1 What is thermodynamics? . .1 1.2 The atmosphere . .1 2 The Equation of State 1 2.1 State variables . .1 2.2 Charles' Law and absolute temperature . .2 2.3 Boyle's Law . .3 2.4 Equation of state of an ideal gas . .3 2.5 Mixtures of gases . .4 2.6 Ideal gas law: molecular viewpoint . .6 3 Conservation of Energy 8 3.1 Conservation of energy in mechanics . .8 3.2 Conservation of energy: A system of point masses . .8 3.3 Kinetic energy exchange in molecular collisions . .9 3.4 Working and Heating . .9 4 The Principles of Thermodynamics 11 4.1 Conservation of energy and the first law of thermodynamics . 11 4.1.1 Conservation of energy . 11 4.1.2 The first law of thermodynamics . 11 4.1.3 Work . 12 4.1.4 Energy transferred by heating . 13 4.2 Quantity of energy transferred by heating . 14 4.3 The first law of thermodynamics for an ideal gas . 15 4.4 Applications of the first law . 16 4.4.1 Isothermal process . 16 4.4.2 Isobaric process . 17 4.4.3 Isosteric process . 18 4.5 Adiabatic processes . 18 5 The Thermodynamics of Water Vapor and Moist Air 21 5.1 Thermal properties of water substance . 21 5.2 Equation of state of moist air . 21 5.3 Mixing ratio . 22 5.4 Moisture variables . 22 5.5 Changes of phase and latent heats . -
Entropy: Ideal Gas Processes
Chapter 19: The Kinec Theory of Gases Thermodynamics = macroscopic picture Gases micro -> macro picture One mole is the number of atoms in 12 g sample Avogadro’s Number of carbon-12 23 -1 C(12)—6 protrons, 6 neutrons and 6 electrons NA=6.02 x 10 mol 12 atomic units of mass assuming mP=mn Another way to do this is to know the mass of one molecule: then So the number of moles n is given by M n=N/N sample A N = N A mmole−mass € Ideal Gas Law Ideal Gases, Ideal Gas Law It was found experimentally that if 1 mole of any gas is placed in containers that have the same volume V and are kept at the same temperature T, approximately all have the same pressure p. The small differences in pressure disappear if lower gas densities are used. Further experiments showed that all low-density gases obey the equation pV = nRT. Here R = 8.31 K/mol ⋅ K and is known as the "gas constant." The equation itself is known as the "ideal gas law." The constant R can be expressed -23 as R = kNA . Here k is called the Boltzmann constant and is equal to 1.38 × 10 J/K. N If we substitute R as well as n = in the ideal gas law we get the equivalent form: NA pV = NkT. Here N is the number of molecules in the gas. The behavior of all real gases approaches that of an ideal gas at low enough densities. Low densitiens m= enumberans tha oft t hemoles gas molecul es are fa Nr e=nough number apa ofr tparticles that the y do not interact with one another, but only with the walls of the gas container. -
Appendix B: Property Tables for Water
Appendix B: Property Tables for Water Tables B-1 and B-2 present data for saturated liquid and saturated vapor. Table B-1 is presented information at regular intervals of temperature while Table B-2 is presented at regular intervals of pressure. Table B-3 presents data for superheated vapor over a matrix of temperatures and pressures. Table B-4 presents data for compressed liquid over a matrix of temperatures and pressures. These tables were generated using EES with the substance Steam_IAPWS which implements the high accuracy thermodynamic properties of water described in 1995 Formulation for the Thermodynamic Properties of Ordinary Water Substance for General and Scientific Use, issued by the International Associated for the Properties of Water and Steam (IAPWS). Table B-1: Properties of Saturated Water, Presented at Regular Intervals of Temperature Temp. Pressure Specific volume Specific internal Specific enthalpy Specific entropy T P (m3/kg) energy (kJ/kg) (kJ/kg) (kJ/kg-K) T 3 (°C) (kPa) 10 vf vg uf ug hf hg sf sg (°C) 0.01 0.6117 1.0002 206.00 0 2374.9 0.000 2500.9 0 9.1556 0.01 2 0.7060 1.0001 179.78 8.3911 2377.7 8.3918 2504.6 0.03061 9.1027 2 4 0.8135 1.0001 157.14 16.812 2380.4 16.813 2508.2 0.06110 9.0506 4 6 0.9353 1.0001 137.65 25.224 2383.2 25.225 2511.9 0.09134 8.9994 6 8 1.0729 1.0002 120.85 33.626 2385.9 33.627 2515.6 0.12133 8.9492 8 10 1.2281 1.0003 106.32 42.020 2388.7 42.022 2519.2 0.15109 8.8999 10 12 1.4028 1.0006 93.732 50.408 2391.4 50.410 2522.9 0.18061 8.8514 12 14 1.5989 1.0008 82.804 58.791 2394.1 58.793 2526.5 -
Equation of State of an Ideal Gas
ASME231 Atmospheric Thermodynamics NC A&T State U Department of Physics Dr. Yuh-Lang Lin http://mesolab.org [email protected] Lecture 3: Equation of State of an Ideal Gas As mentioned earlier, the state of a system is the condition of the system (or part of the system) at an instant of time measured by its properties. Those properties are called state variables, such as T, p, and V. The equation which relates T, p, and V is called equation of state. Since they are related by the equation of state, only two of them are independent. Thus, all the other thermodynamic properties will depend on the state defined by two independent variables by state functions. PVT system: The simplest thermodynamic system consists of a fixed mass of a fluid uninfluenced by chemical reactions or external fields. Such a system can be described by the pressure, volume and temperature, which are related by an equation of state f (p, V, T) = 0, (2.1) 1 where only two of them are independent. From physical experiments, the equation of state for an ideal gas, which is defined as a hypothetical gas whose molecules occupy negligible space and have no interactions, may be written as p = RT, (2.2) or p = RT, (2.3) where -3 : density (=m/V) in kg m , 3 -1 : specific volume (=V/m=1/) in m kg . R: specific gas constant (R=R*/M), -1 -1 -1 -1 [R=287 J kg K for dry air (Rd), 461 J kg K for water vapor for water vapor (Rv)]. -
IB Questionbank
Topic 3 Past Paper [94 marks] This question is about thermal energy transfer. A hot piece of iron is placed into a container of cold water. After a time the iron and water reach thermal equilibrium. The heat capacity of the container is negligible. specific heat capacity. [2 marks] 1a. Define Markscheme the energy required to change the temperature (of a substance) by 1K/°C/unit degree; of mass 1 kg / per unit mass; [5 marks] 1b. The following data are available. Mass of water = 0.35 kg Mass of iron = 0.58 kg Specific heat capacity of water = 4200 J kg–1K–1 Initial temperature of water = 20°C Final temperature of water = 44°C Initial temperature of iron = 180°C (i) Determine the specific heat capacity of iron. (ii) Explain why the value calculated in (b)(i) is likely to be different from the accepted value. Markscheme (i) use of mcΔT; 0.58×c×[180-44]=0.35×4200×[44-20]; c=447Jkg-1K-1≈450Jkg-1K-1; (ii) energy would be given off to surroundings/environment / energy would be absorbed by container / energy would be given off through vaporization of water; hence final temperature would be less; hence measured value of (specific) heat capacity (of iron) would be higher; This question is in two parts. Part 1 is about ideal gases and specific heat capacity. Part 2 is about simple harmonic motion and waves. Part 1 Ideal gases and specific heat capacity State assumptions of the kinetic model of an ideal gas. [2 marks] 2a. two Markscheme point molecules / negligible volume; no forces between molecules except during contact; motion/distribution is random; elastic collisions / no energy lost; obey Newton’s laws of motion; collision in zero time; gravity is ignored; [4 marks] 2b. -
Thermodynamics of Ideal Gases
D Thermodynamics of ideal gases An ideal gas is a nice “laboratory” for understanding the thermodynamics of a fluid with a non-trivial equation of state. In this section we shall recapitulate the conventional thermodynamics of an ideal gas with constant heat capacity. For more extensive treatments, see for example [67, 66]. D.1 Internal energy In section 4.1 we analyzed Bernoulli’s model of a gas consisting of essentially 1 2 non-interacting point-like molecules, and found the pressure p = 3 ½ v where v is the root-mean-square average molecular speed. Using the ideal gas law (4-26) the total molecular kinetic energy contained in an amount M = ½V of the gas becomes, 1 3 3 Mv2 = pV = nRT ; (D-1) 2 2 2 where n = M=Mmol is the number of moles in the gas. The derivation in section 4.1 shows that the factor 3 stems from the three independent translational degrees of freedom available to point-like molecules. The above formula thus expresses 1 that in a mole of a gas there is an internal kinetic energy 2 RT associated with each translational degree of freedom of the point-like molecules. Whereas monatomic gases like argon have spherical molecules and thus only the three translational degrees of freedom, diatomic gases like nitrogen and oxy- Copyright °c 1998{2004, Benny Lautrup Revision 7.7, January 22, 2004 662 D. THERMODYNAMICS OF IDEAL GASES gen have stick-like molecules with two extra rotational degrees of freedom or- thogonally to the bridge connecting the atoms, and multiatomic gases like carbon dioxide and methane have the three extra rotational degrees of freedom. -
Questions: Physical Properties and 7 Step Process
Questions: Physical Properties and 7 Step Process 1. Why does a water-saturated sandstone typically have a higher P-wave velocity than a dry sandstone? A saturated sandstone: a. is more dense b. has a larger bulk modulus c. has a larger shear modulus d. has a higher tensile strength 2. The relative permittivity of a given rock is considered large when: a. it contains a lot of pore water b. an applied electric field results in a larger electric dipole moment c. it has a value of 30 d. b and c are correct e. a,b and c are correct 3. You measure a resistance of 16 kΩ between two parallel faces of a 2cm x 2cm x 2cm cube. Determine the resistivity. a. 320 Ωm b. 800000 Ωm c. 32000 Ωm d. 8000 Ωm 4. You are flying a gravity survey over a sedimentary basin. The flight path crosses a known dyke. What would be the expected gravity response and why? a. Gravity high over the dyke; the dyke is more dense than the background b. Gravity low over the dyke; the dyke is less dense than the background c. Gravity high over the dyke; the dyke is less dense than the background d. Gravity low over the dyke; the dyke is more dense than the background 5. You are building a road through known active Karst terrain in Ireland. Which set of physical property contrasts would be most diagnostic for locating regions where sink- holes could form? a. Karstified: low density, Limestone: high density b. Karstified: low resistivity, Limestone: high resistivity c. -
[5] Magnetic Densimetry: Partial Specific Volume and Other Applications
74 MOLECULAR WEIGHT DETERMINATIONS [5] [5] Magnetic Densimetry: Partial Specific Volume and Other Applications By D. W. KUPKE and J. W. BEAMS This chapter consists of three parts. Part I is a summary of the principles and current development of the magnetic densimeter, with which density values may be obtained conveniently on small volumes of solution with the speed and accuracy required for present-day ap- plications in protein chemistry. In Part II, the applications, including definitions, are outlined whereby the density property may be utilized for the study of protein solutions. Finally, in Part III, some practical aspects on the routine determination of densities of protein solutions by magnetic densimetry are listed. Part I. Magnetic Densimeter The magnetic densimeter measures by electromagnetic methods the vertical (up or down) force on a totally immersed buoy. From these measured forces together with the known mass and volume of the buoy, the density of the solution can be obtained by employing Archimedes' principle. In practice, it is convenient to eliminate evaluation of the mass and volume of the buoy and to determine the relation of the mag- netic to the mechanical forces on the buoy by direct calibration of the latter when it is immersed in liquids of known density. Several workers have devised magnetic float methods for determin- ing densities, but the method first described by Lamb and Lee I and later improved by MacInnes, Dayhoff, and Ray: is perhaps the most accurate means (~1 part in 106) devised up to that time for determining the densities of solutions. The magnetic method was not widely used, first because it was tedious and required considerable manipulative skill; second, the buoy or float was never stationary for periods long enough to allow ruling out of wall effects, viscosity perturbations, etc.; third, the technique required comparatively large volumes of the solution (350 ml) for accurate measurements. -
5.5 ENTROPY CHANGES of an IDEAL GAS for One Mole Or a Unit Mass of Fluid Undergoing a Mechanically Reversible Process in a Closed System, the First Law, Eq
Thermodynamic Third class Dr. Arkan J. Hadi 5.5 ENTROPY CHANGES OF AN IDEAL GAS For one mole or a unit mass of fluid undergoing a mechanically reversible process in a closed system, the first law, Eq. (2.8), becomes: Differentiation of the defining equation for enthalpy, H = U + PV, yields: Eliminating dU gives: For an ideal gas, dH = and V = RT/ P. With these substitutions and then division by T, As a result of Eq. (5.11), this becomes: where S is the molar entropy of an ideal gas. Integration from an initial state at conditions To and Po to a final state at conditions T and P gives: Although derived for a mechanically reversible process, this equation relates properties only, and is independent of the process causing the change of state. It is therefore a general equation for the calculation of entropy changes of an ideal gas. 1 Thermodynamic Third class Dr. Arkan J. Hadi 5.6 MATHEMATICAL STATEMENT OF THE SECOND LAW Consider two heat reservoirs, one at temperature TH and a second at the lower temperature Tc. Let a quantity of heat | | be transferred from the hotter to the cooler reservoir. The entropy changes of the reservoirs at TH and at Tc are: These two entropy changes are added to give: Since TH > Tc, the total entropy change as a result of this irreversible process is positive. Also, ΔStotal becomes smaller as the difference TH - TC gets smaller. When TH is only infinitesimally higher than Tc, the heat transfer is reversible, and ΔStotal approaches zero. Thus for the process of irreversible heat transfer, ΔStotal is always positive, approaching zero as the process becomes reversible. -
Chapter 3 3.4-2 the Compressibility Factor Equation of State
Chapter 3 3.4-2 The Compressibility Factor Equation of State The dimensionless compressibility factor, Z, for a gaseous species is defined as the ratio pv Z = (3.4-1) RT If the gas behaves ideally Z = 1. The extent to which Z differs from 1 is a measure of the extent to which the gas is behaving nonideally. The compressibility can be determined from experimental data where Z is plotted versus a dimensionless reduced pressure pR and reduced temperature TR, defined as pR = p/pc and TR = T/Tc In these expressions, pc and Tc denote the critical pressure and temperature, respectively. A generalized compressibility chart of the form Z = f(pR, TR) is shown in Figure 3.4-1 for 10 different gases. The solid lines represent the best curves fitted to the data. Figure 3.4-1 Generalized compressibility chart for various gases10. It can be seen from Figure 3.4-1 that the value of Z tends to unity for all temperatures as pressure approach zero and Z also approaches unity for all pressure at very high temperature. If the p, v, and T data are available in table format or computer software then you should not use the generalized compressibility chart to evaluate p, v, and T since using Z is just another approximation to the real data. 10 Moran, M. J. and Shapiro H. N., Fundamentals of Engineering Thermodynamics, Wiley, 2008, pg. 112 3-19 Example 3.4-2 ---------------------------------------------------------------------------------- A closed, rigid tank filled with water vapor, initially at 20 MPa, 520oC, is cooled until its temperature reaches 400oC. -
AC Measurement System (ACMS) Option User's Manual
Physical Property Measurement System AC Measurement System (ACMS) Option User’s Manual Part Number 1084-100 C-1 Quantum Design 11578 Sorrento Valley Rd. San Diego, CA 92121-1311 USA Technical support (858) 481-4400 (800) 289-6996 Fax (858) 481-7410 Fourth edition of manual completed June 2003. Trademarks All product and company names appearing in this manual are trademarks or registered trademarks of their respective holders. U.S. Patents 4,791,788 Method for Obtaining Improved Temperature Regulation When Using Liquid Helium Cooling 4,848,093 Apparatus and Method for Regulating Temperature in a Cryogenic Test Chamber 5,311,125 Magnetic Property Characterization System Employing a Single Sensing Coil Arrangement to Measure AC Susceptibility and DC Moment of a Sample (patent licensed from Lakeshore) 5,647,228 Apparatus and Method for Regulating Temperature in Cryogenic Test Chamber 5,798,641 Torque Magnetometer Utilizing Integrated Piezoresistive Levers Foreign Patents U.K. 9713380.5 Apparatus and Method for Regulating Temperature in Cryogenic Test Chamber CONTENTS Table of Contents PREFACE Contents and Conventions ...............................................................................................................................vii P.1 Introduction .......................................................................................................................................................vii P.2 Scope of the Manual..........................................................................................................................................vii -
Lab 1 - Physical Properties of Minerals
Page - Lab 1 - Physical Properties of Minerals All rocks are composed of one or more minerals. In order to be able to identify rocks you have to be able to recognize those key minerals that make of the bulk of rocks. By definition, any substance is classified as a mineral if it meets all 5 of the following criteria: - is naturally occurring (ie. not man-made); - solid (not liquid or gaseous); - inorganic (not living and never was alive); - crystalline (has an orderly, repetitive atomic structure); - a definite chemical composition (you can write a discrete chemical formula for any mineral). Identifying an unknown mineral is like identifying any group of unknowns (leaves, flowers, bugs... etc.) You begin with a box, or a pile, of unknown minerals and try to find any group features in the samples that will allow you to separate them into smaller and smaller piles, until you are down to a single mineral and a unique name. For minerals, these group features are called physical properties. Physical properties are any features that you can use your 5 senses (see, hear, feel, taste or smell) to aid in identifying an unknown mineral. Mineral physical properties are generally organized in a mineral key and the proper use of this key will allow you to name your unknown mineral sample. The major physical properties will be discussed briefly below in the order in which they are used to identify an unknown mineral sample. Luster Luster is the way that a mineral reflects light. There are two major types of luster; metallic and non-metallic luster.