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Physical Chemistry Laboratory, I CHEM 445 Experiment 5 Heat Capacity Ratio for Gases (Revised, 1/10/03)

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Physical Chemistry Laboratory, I CHEM 445 Experiment 5 Heat Capacity Ratio for Gases (Revised, 1/10/03) 1 Physical Chemistry Laboratory, I CHEM 445 Experiment 5 Heat Capacity Ratio for Gases (Revised, 1/10/03) The heat capacity for a substance is the amount of heat needed to raise the temperature of the substance by 1 oC or 1 K. The heat capacities depend on the chemical nature of the substance, on the physical state of the substance, on the temperature, and on whether P or V is held constant during the process: CP or CV. For liquids and solids, CV ≈ CP and the two terms are often used interchangeably. However, for ideal gases, it is well known (Tinoco, Jr., Sauer, and Wang or Noggle) that − − CP = CV + R (1) − In this equation, C = molar heat capacity of the gas, either at constant pressure or at constant volume. The bar over a symbol refers to that quantity per mol of substance. The molar heat capacities are defined by the equations, − − − ∂ E − ∂ H CV = and CP = (2) ∂T ∂T V P For a monatomic gas, there is no rotational or vibrational energy and if the temperature is relatively low, only the ground electronic state of the species is populated to any extent. Consequently, only translational energy is involved; and from kinetic theory, − 3R − 5R CV = and CP = (3) 2 2 For polyatomic gases, there are additional forms of energy that contribute to the heat capacity. − − − − E = E(trans) + E(rot) + E(vib) (4) For many simple diatomic molecules, however, the vibrational contribution to the heat 5R capacity is small, and in the neighborhood of room temperature,C = . However, the V 2 heat capacities of diatomic molecules increase with increasing temperature as the vibrational modes become active. The heat capacities of polyatomic molecules are more complex and less predictable. The equipartition principle predicts that the heat capacity depends on the number of vibrational degrees of freedom in the molecule that is determined by the number of atoms in the molecule. The equipartition model is incorrect in its predictions but is useful because it does indicate that the heat capacity will increase with increasing molecular complexity (number of atoms or number of bonds). 2 − C V (linear, N atoms) = 5R/2 + (3N – 5)R (5) − C V (non-linear, N atoms) = 3R + (3N – 6)R (6) Heat capacities play a prominent part in the Carnot cycle for determining the efficiency of an engine. For the reversible adiabatic expansion of one mol of a perfect gas, − − − − RT dE = − PdV and d E = CV dT and P = − (7) V These equations can be combined and integrated to give the standard equation found in most physical chemistry texts, − − T2 V2 CV ln = − Rln (8) − T1 V1 There is a predicted and observed decrease in temperature for the reversible adiabatic expansion of an ideal (or any) gas. There is a classical experiment for the determination of the ratios of the heat capacities of gases, CP/CV = γ, based on rapidly releasing a gas from a large container at a pressure somewhat higher than atmospheric pressure, P1, until the gas reaches atmospheric pressure, P2. The temperature of the gas decreases during this adiabatic expansion. The container is quickly closed and the gas returns to ambient temperature and the final pressure is measured, P3. [1, 2, 3] There are two theoretical developments for the analysis of this experiment. In one case the experiment is treated as a reversible adiabatic expansion of a gas (considered in this case to be ideal) from P1 and T1 to P2 and T2 followed by warming the gas at constant volume to the initial temperature, T1 and final pressure, P3. If one substitutes R = CP – CV from Eq. (1) into Eq. (8), one obtains the following − CP equation, in which γ = − . CV − − − T2 V2 T2 V2 CV ln = − C − C ln or ln = − γ −1 ln (9) ()P V − () − T1 T1 V1 V1 Continuing with the standard development, one obtains the following equation for T and V from the adiabatic expansion of an ideal gas. Using the perfect gas equation, one can also obtain an equation relating P and V for the adiabatic expansion of an ideal gas. − ()γ−1 − γ − − T2 V1 γ γ P1 V2 = and P V1 = P V2 or = (10) − 1 2 − T1 P2 V2 V1 3 The gas then warms to T1 (the initial and room temperature) at constant volume, − V 2 and P3. Therefore, the following equation holds. − − − V2 P1 PV2 = P V1 or = (11) 3 1 − P3 V1 Because the pressures can be measured directly, one replaces the ratio of the volumes per mol in Eq. (10) by its equivalent in terms of pressures from Eq. (11) to get the following: γ P1 P1 P1 P1 = or ln = γ ln (12) P2 P3 P2 P3 Eq. (12) can then be rearranged to give the final equation needed to calculate γ, the ratio of heat capacities of the gas from experimental data. P ln 1 P γ = 2 (13) P1 ln P3 In the alternative analysis [2], the process is considered as an adiabatic expansion from (P1, T1) against a constant pressure, P2, to (P2, T2), and, therefore, not reversible. Then the system warms to the original temperature and a new pressure at constant volume (P3, T1). For the adiabatic expansion against a constant pressure, one begins with the following differential equation (again using molar quantities for volume and heat capacity). − − − − CV dT = − P2dV or CV (T2 − T1) = − P2 (V2 − V1) (14) One may use the perfect gas equation to replace V and then replace R with its equivalent from Eq. 1 to obtain the following expression. − − P2 − P1 P2 T2 CV = − CP − (15) P1 P1 T1 The temperature, T2, after the adiabatic expansion from P1 to P2 can be calculated from the perfect gas equation from the final pressure, P3, after the gas has returned to the initial temperature, T1. T T 2 = 1 (16) P2 P3 Substituting and rearranging, one gets the following equation to calculate the ratio of heat capacities of the gas. P 1 −1 P γ = 2 (17) P1 −1 P3 These two equations, (13) and (17), look very different; however, they give similar results because the ratios, P1/P2 and P1/P3 are only slightly larger than one. One 4 can show the similarity of Eq. (13) and Eq. (17) by a Taylor’s series expansion of Eq. (13) about 1. Experimental Procedure: The WEB is occasionally useful. You may find pictures of apparatus similar to ours on the WEB page for the University of Florida Physical Chemistry Lab, Fall. 2000. (There are probably others). Note that they do 11 experiments in their (16 week) semester: http://www.chem.ufl.edu/~itl/4411L f00/welcome.html You are to measure the ratio of heat capacities, γ, for two gases: N2 and CO2. The gas cylinders are in the corner of the lab and are connected to the two carboys (ballast jars) by plastic tubing. Only N2 is used with one carboy and only CO2, with the other. The lines from the gas cylinders to the ballast jars should be properly connected and should not be rearranged. Check with the Lab Instructor before using the gas cylinders. There are three valves on each rubber stopper that closes each carboy. One valve controls the line between the gas cylinder and the carboy. Another valve controls the exit from the carboy to the atmosphere. The third valve controls the connection between the carboy and the manometer. The stopper occasionally slips and should be strapped down during waiting periods. The valves on the stopper and on the gas cylinder should be tightened only “finger-tip tight”. Do not tighten excessively: such effort does not prevent leaks and ruins the valves. Open the gas cylinders and all valves (cylinder and top of carboy) and let the gas flow through the lines and the carboy for ~ 10 minute at a modest gas flow rate. The time and flow rate are not critical. A pressure of ~5 PSI (pounds per square inch) on the regulator should be sufficient. A flow of 5 – 10 SCF/H (standard cubic feet per hour), as indicated by the flow meter, is adequate. There is a flow meter attached to each line: one on the wall by the gas cylinder and the other on the manometer at the station. Sometimes the ball sticks in the top of the flow meter and can be dislodged by a gentle tap with the base of a screwdriver. It is often useful for one person to adjust the valves on the gas cylinder and the other person to read the flow meters. If there is no gas flow, it is likely that one of the valves is closed. After the gas has flushed the carboy for several (5 or so) minutes, reduce the flow of the gas from the cylinder coming into the carboy, slowly close the valve that lets the gas out of the carboy, and allow the pressure to increase until there is a difference of 50 – 60 cm of manometer fluid (di-n-butyl phthalate) between the two sides of the manometer. Close the valve letting gas into the cylinder (as well as the valve letting the gas out of the carboy) and turn off the fine control valve at the cylinder. If all of the valves are shut, the pressure should remain constant. Let the system sit for ~ 10 minutes for the gas to reach 5 room temperature (measured on a thermometer on the manometer stand), as indicated by a constant manometer reading. Record this final pressure difference, ∆P1, and room temperature.
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