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2013 Maximally Epistemic Interpretations of the Quantum State and Contextuality Matthew .S Leifer Chapman University, [email protected]

O. J. E. Maroney University of Oxford

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Recommended Citation Leifer, M.S., Maroney, O.J.E., 2013. Maximally Epistemic Interpretations of the Quantum State and Contextuality. Phys. Rev. Lett. 110, 120401. doi:10.1103/PhysRevLett.110.120401

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Comments This article was originally published in Physical Review Letters, volume 110, in 2013. DOI: 10.1103/ PhysRevLett.110.120401

Copyright American Physical Society

This article is available at Chapman University Digital Commons: http://digitalcommons.chapman.edu/scs_articles/523 week ending PRL 110, 120401 (2013) PHYSICAL REVIEW LETTERS 22 MARCH 2013

Maximally Epistemic Interpretations of the Quantum State and Contextuality

M. S. Leifer* and O. J. E. Maroney1,† 1Faculty of Philosophy, University of Oxford, 10 Merton Street, Oxford, OX1 4JJ, United Kingdom (Received 25 August 2012; published 20 March 2013) We examine the relationship between quantum contextuality (in both the standard Kochen-Specker sense and in the generalized sense proposed by Spekkens) and models of quantum theory in which the quantum state is maximally epistemic. We find that preparation noncontextual models must be maximally epistemic, and these in turn must be Kochen-Specker noncontextual. This implies that the Kochen-Specker theorem is sufficient to establish both the impossibility of maximally epistemic models and the impossibility of preparation noncontextual models. The implication from preparation noncontextual to maximally epistemic then also yields a proof of Bell’s theorem from an Einstein-Podolsky-Rosen-like argument.

DOI: 10.1103/PhysRevLett.110.120401 PACS numbers: 03.65.Ta, 03.65.Ud

The nature of the quantum state has been debated since parameters that increases exponentially with Hilbert space the early days of quantum theory. Is it a state of knowledge dimension. See Ref. [10] for a discussion of these impli- or information (an epistemic state), or is it a state of cations. However, the auxiliary assumptions used in the physical reality (an ontic state)? One of the reasons for proofs of the onticity of quantum states carry over into being interested in this question is that many of the phe- these corollaries whereas the original proofs of these nomena of quantum theory are explained quite naturally in results [5,9,11] did not require them. For this reason, it is terms of the epistemic view of quantum states [1]. For interesting to look for results addressing the distinction example, the fact that nonorthogonal quantum states can- between ontic and epistemic quantum states that are not be perfectly distinguished is puzzling if they corre- weaker than completely ontic, but can be proved without spond to distinct states of reality. However, on the auxiliary assumptions, since such results may sit near the epistemic view, a quantum state is represented by a proba- top of a hierarchy of no-go theorems. bility distribution over ontic states, and nonorthogonal Recently, one of us introduced a stronger notion of what quantum states correspond to overlapping probability it means for the quantum state to be epistemic and proved distributions. Indistinguishability is explained by the fact that it is incompatible with the predictions of quantum that preparations of the two quantum states would some- theory without any auxiliary assumptions [12]. An onto- times result in the same ontic state, and in those cases logical model is maximally c -epistemic if the quantum there would be nothing existing in reality that could dis- probability of obtaining the outcome ji when measuring a tinguish the two. system prepared in the state jc i is entirely accounted for Several theorems have recently been proved showing by the overlap between the corresponding probability dis- that the quantum state must be an ontic state [2,3]. Most tributions in the ontological model. This property is of these have been proved within the ontological models required if the epistemic explanation of the indistinguish- framework [4], which generalizes the hidden variable ability of nonorthogonal states is to be strictly true. It is approach used to prove earlier no-go results, such as satisfied by the c -epistemic model of two-dimensional Bell’s theorem [5] and the Bell-Kochen-Specker theorem Hilbert spaces proposed by Kochen and Specker [4,7], [6,7]. However, each of these new theorems rests on aux- and its analog is satisfied by the epistemic toy model of iliary assumptions, of varying degrees of reasonableness. Spekkens [1]. For example, the Pusey-Barrett-Rudolph theorem [2] In this Letter, we explain how this stronger notion of assumes that the ontic states of two systems prepared in quantum state epistemicity relates to other no-go theorems, a product state are statistically independent, and the particularly the traditional notion of noncontextuality used Colbeck-Renner result [3] employs a strong ‘‘free choice’’ in proofs of the Kochen-Specker theorem and Spekkens’ assumption that rules out deterministic theories a priori. notion of preparation contextuality. Briefly, Kochen- An explicit counterexample shows that these proofs cannot Specker noncontextuality applies to deterministic models, be made to work without such auxiliary assumptions [8]. and says that if an outcome corresponding to some projec- The requirement of ontic quantum states is perhaps the tor is certain to occur in one measurement then outcomes strongest constraint on hidden variable theories that has corresponding to the same projector in other measurements been proved to date. It immediately implies preparation must also be certain to occur. Preparation noncontextuality contextuality (within the generalized approach to contex- says that preparation procedures corresponding to the same tuality of Spekkens [9]), a version of Bell’s theorem, and density operator must be assigned the same probability that the ontic state space must be infinite, with a number of distribution. Our results can be summarized as

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Preparation noncontextual ) Maximallyc -epistemic ) Kochen-Specker noncontextual: (1)

Both implications are strict, which we demonstrate with The traditional notion of noncontextuality used in proofs specific examples of models that are Kochen-Specker non- of the Kochen-Specker theorem is the combination of two contextual but not maximally c -epistemic, and maximally conditions: 1. An ontological model is outcome determi- c -epistemic but not preparation noncontextual. Since the nistic if MðjÞ2f0; 1g almost everywhere on , for all no-go theorem for maximally epistemic models does not M 2 M, ji2M. 2. An ontological model is measure- require auxiliary assumptions, these implications provide a ment noncontextual if, whenever M, M0 2 M contain a stronger proof of preparation contextuality and Bell’s theo- common state ji, MðjÞ¼M0 ðjÞ almost every- rem than those obtained from other no-go theorems for where on . c -epistemic models. Theorem 1: If an ontological model of M is maximally We are interested in ontological models that reproduce c -epistemic then it is also outcome deterministic and the quantum predictions for a set of prepare-and-measure measurement noncontextual. experiments. The experimenter can perform measurements Proof.—The proof closely parallels that of the ‘‘quantum of a set of orthonormal bases M ¼fM1;M2; ...g on the deficit theorem’’ [16]. As mentioned above, for any ji2 system. Let P ¼[M2MM denote the set of quantum states P , MðjÞ¼1 almost everywhere on for every that occur in one or more of these bases. Prior to the M 2 M that contains ji. Hence, it is also equal to 1 measurement, the experimenter can prepare the system in almost everywhere on \ c , since c has positive any of the states in P . measure. In order to reproduce the , the ontolog- An ontological model for M specifies a measure ical model must satisfy d c P space ( , ) of ontic states. Each state j i2 is Z associated with a probability distribution c ðÞ [13,15] 2 MðjÞc ðÞd ¼jhjc ij ; (3) over and each measurement M 2 M is associated with aP set of positive response functions MðjÞ that satisfy 1 but a maximally c -epistemic theory must also satisfy ji2M Mð j Þ¼ for all 2 . The ontological model Z is required to reproduce the Born rule, which means that 2 8jc i2P , M 2 M, ji2M, MðjÞc ðÞd ¼jhjc ij : (4) Z 2 MðjÞc ðÞd ¼jhjc ij : (2) Given that these two equations must hold for all jc i2P , comparing them yields MðjÞ¼0 almost everywhere For each state jc i2P , define c ¼fjc ðÞ > 0g. on n. Thus, the model is outcome deterministic. Since We assume that ¼[jc i2P c , since otherwise there will the same argument holds for every M in which ji appears, be superfluous ontic states that are never prepared. Two the model is measurement noncontextual. j important facts, of which we make repeated use, are that in The implication in this theorem is strict; i.e., there exist c c 2 1 M order to reproduce jh j ij ¼ in Eq. (2), for every Kochen-Specker noncontextual models that are not c c 1 that contains j i it must be the case that Mð j Þ¼ maximally c -epistemic. An example is provided by the almost everywhere on c , and for all orthogonal ji2M, M 2 Bell-Mermin model [6,17], in which consists of all such that jhjc ij ¼ 0, MðjÞ¼0 almost everywhere orthonormal bases in a two-dimensional Hilbert space. The on c . This implies that c \ is of measure zero for ontic state space of the model consists of the Cartesian c orthogonal j i and j i. product of two copies of the unit sphere ¼ S2 S2, and A c -ontic ontological model is one in which, for any ~ ~ ~ we denote the ontic states as ¼ð1; 2Þ, where j 2 S2. pair of nonorthogonal quantum states jc i ji, c \ For a state jc i, let c~ denote the corresponding Bloch is of measure zero. This means that, if one knows the vector. The distribution associated with jc i in the onto- ontic state then the prepared quantum state can be identi- ~ ~ logical model is a product c ðÞ¼c ð1Þc ð2Þ, fied almost surely. Conversely, if c \ has positive ~ ~ c~ c~ measure for some pair of states, then the model is where c ð 1Þ¼ ð 1 Þ is a point measure on ~ 1 c -epistemic. [18] and c ð2Þ¼4 is the uniform measure on S2.Itis R An ontological model is maximally c -epistemic if easy to see that this model is not maximally c -epistemic d c 2 c P c c ð Þ ¼jh j ij for every j i, j i2 . because c \ ¼;for distinct j i and j i due to the c RSince MðjÞ¼1 almost everywhere on , then -function term. In fact the model is ontic. d c 2 The response functions of the model are Mð j Þ c ð Þ ¼jh j ij . The probability of obtaining the outcome ji when measuring a system pre- ~ ~ MðjÞ¼ð~ ð1 þ 2ÞÞ; (5) pared in the state jc i is entirely accounted for by the overlap between c and . where is the Heaviside step function

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ðxÞ¼1;x>0 (6) probability 1=2 and j?i with probability 1=2. The result- 1 ing density operators, 1 and 2, satisfy 1 ¼ 2 ¼ 2 , ¼ 0;x 0: (7) where is the projector onto the subspace spanned by jc i This model is outcome deterministic because only takes and j i. Let 1 ¼ c [ c ? and 2 ¼ [ ? be the 1 the values 0 and 1, and it is measurement noncontextual supports of the corresponding distributions, 1 ¼ 2 ð c þ 1 because the right-hand side of Eq. (5) does not depend on M. c ? Þ and 2 ¼ 2 ð þ ? Þ, in the ontological model. It is straightforward to check that the model reproduces the Now, 1 \ is assigned nonzero probability by 1, quantum predictions. whereas 2 assigns probability zero to . This is because In order to understand the connection between maxi- is disjoint from by definition and ? must assign mally c -epistemic models and preparation contextuality, zero probability to any set of ontic states that assign we need to describe how (proper) mixtures are represented nonzero probability to ji in a measurement of any in ontological models. Assume that, in addition to prepar- orthonormal basis that contains it. Hence 1 and 2 ing the pure states in P , the experimenter can also prepare must be distinct because their supports differ by a set of mixtures of them by generating classical randomness (by positive measure. j flipping coins, rolling dice, etc.) with probability distribu- A simple corollary of this theorem is that, whenever the tion pj and then preparing a different state jc ji2P states jc ?i and j?i are in P for every jc i, ji2P , dependingP on the outcome, resulting in the density operator then any preparation noncontextual ontological model is ¼ jpjjc jihc jj [19]. The classical randomness is also maximally c -epistemic. As in the case of Kochen- assumed to be independent of the ontic state of the quan- Specker contextuality, this implication is strict; i.e., there tum system, so that the distribution over ontic states asso- are maximally c -epistemic models that are preparation E p ; c ciatedP with preparing the ensemble ¼f j j jig is contextual. An example is provided by the Kochen- p Specker model [7], which again takes M to be all ortho- E ¼ j j c j ð Þ. An ontological model is preparation noncontextual if EðÞ depends only on the density opera- normal bases in a two-dimensional Hilbert space. This tor , and not on the specific ensemble decomposition, E ¼ time, the ontic state space is just a single copy of the unit S ~ S fpj; jc jig, used to prepare it. Otherwise the model is sphere ¼ 2 and the ontic states are unit vectors 2 2. preparation contextual. The probability distribution associated with a quantum c Theorem 2: Suppose an ontological model of M is not state j i is maximally c -epistemic, so that there exist states jc i, 1 ð~Þ¼ ðc~ ~Þc~ ~ ji2P such that c (12) Z 2 c ðÞd < jhjc ij : (8) and the response function associated with a quantum state ji is P c ? ? ~ ~ Then, if includes the states j i, j i that satisfy MðjÞ¼ð Þ: (13) hc ?jc i¼0 and h?ji¼0, and are in the subspace spanned by jc i and ji, then the model is also preparation It is straightforward to check that this model reproduces the contextual. quantum predictions. Proof.—By Eq. (2), for any M containing ji, The model is maximally c -epistemic because ¼ Z fjð~ ~Þ¼1g and thus c 2 d jh j ij ¼ Mð j Þ c ð Þ (9) Z 2 ~ jhjc ij ¼ MðjÞc ðÞd (14) Z Z d d; Mð j Þ c ð Þ ¼ c ð Þ (10) Z ~ ~ ~ ¼ ð Þc ðÞd (15) where the last line follows because MðjÞ¼1 almost everywhere on . By assumption, the inequality must be Z ~ strict, so we have ¼ c ðÞd: (16) Z Z MðjÞc ðÞd < MðjÞc ðÞd: (11) On the other hand, the model is preparation contextual as can be seen by considering the two preparations 1. This means that there must be a set of ontic states that Prepare jþzi with probability 1=2 and jzi with proba- is disjoint from , is assigned nonzero probability by c , bility 1=2. 2. Prepare jþxi with probability 1=2 and jxi and is such that MðjÞ > 0 for 2 . Now, consider with probability 1=2. Both preparations correspond to the 1 the two mixed preparations: 1. Prepare jc i with probabil- maximally mixed state, but the distributions 2 ðþz þ zÞ ? 1 ity 1=2 and jc i with probability 1=2. 2. Prepare ji with and 2 ðþx þ xÞ are different. In particular, both þz

120401-3 week ending PRL 110, 120401 (2013) PHYSICAL REVIEW LETTERS 22 MARCH 2013 and z are zero on the equator whereas þx and x are without auxiliary assumptions, that the support of every both nonzero here. distribution in an ontological model must contain a set Theorem 1 implies that any proof of the Kochen-Specker of states that are not shared by the distribution correspond- theorem is sufficient to establish that maximally c -epistemic ing to any other quantum state, then these results would models are impossible for Hilbert spaces of dimension follow. Whether this can be proved is an important greater than two. Unlike the proof in Ref. [12], however, open question. this does not establish a bound on how close to maximally We would like to thank Chris Timpson for helpful dis- c -epistemic one can get. Further, the Kochen-Specker theo- cussions. O. J. E. M. is supported by the John Templeton rem allows a finite precision loophole [20]thatcanbe Foundation. exploited to allow noncontextual theories to get arbitrarily close to quantum statistics, so it seems unlikely that this proof could be made robust against experimental error. Combining the two theorems also shows that the *[email protected] Kochen-Specker theorem is enough to establish prepara- http://mattleifer.info † tion contextuality. While it was known that preparation [email protected] [1] R. W. Spekkens, Phys. Rev. A 75, 032110 (2007). noncontextuality implies outcome for models 8 of quantum theory [9], it is a novel implication that it also [2] M. F. Pusey, J. Barrett, and T. Rudolph, Nat. Phys. , 476 (2012). implies measurement noncontextuality. This demonstrates [3] R. Colbeck and R. Renner, Phys. Rev. Lett. 108, 150402 that the distinction between ontic and epistemic quantum (2012); M. J. W. Hall, arXiv:1111.6304; L. Hardy, states is useful for understanding the relationship between arXiv:1205.1439; M. Schlosshauer and A. Fine, Phys. existing no-go theorems. Rev. Lett. 108, 260404 (2012). Finally, the type of preparation contextuality established [4] N. Harrigan and R. W. Spekkens, Found. Phys. 40, 125 by our results can be used to prove Bell’s theorem. Briefly, (2010). if jc i and ji are states such that [5] J. S. Bell, Physics (Long Island City, N.Y.) 1, 195 (1964); Z Reprinted in J. S. Bell, Speakable and Unspeakable In 2 c ðÞd < jhjc ij (17) Quantum Mechanics, (Cambridge University Press, England, Cambridge, 2004), 2nd ed., pp. 13–21. then we can demonstrate nonlocality using a maximally [6] J. S. Bell, Rev. Mod. Phys. 38, 447 (1966). 1 ? ? 17 entangled state pffiffi ðjc iAjc iB þjc iAjc iBÞ. Since the [7] S. Kochen and E. P. Specker, J. Math. Mech. , 59 (1967). 2 [8] P. G. Lewis, D. Jennings, J. Barrett, and T. Rudolph, reduced on Bob’s system is Phys. Rev. Lett. 109, 150404 (2012). 1 [9] R. W. Spekkens, Phys. Rev. A 71, 052108 (2005). ¼ ðjc ihc jþjc ?ihc ?jÞ 2 (18) [10] M. Leifer, The Quantum Times 6, 1 (2011), newsletter of 1 the APS Topical Group on Quantum Information. ¼ ðjihjþj?ih?jÞ; (19) [11] L. Hardy, Stud. Hist. Phil. Mod. Phys. 35, 267 (2004); 2 A. Montina, Phys. Rev. A 77, 022104 (2008). by the Schro¨dinger-HJW theorem [21] there are two mea- [12] O. J. E. Maroney, arXiv:1207.6906. surements that Alice can perform, the first of which will [13] More generally, is a measurable space and states are jc i jc ?i 50:50 associated with probability measures c . For ease of collapse Bob’s system to or with proba- bilities, and the second of which will collapse it to ji or exposition, we have assumed that is equipped with a canonical measure d with respect to which all the mea- j?i with 50:50 probabilities. However, Theorem 2 estab- sures c are absolutely continuous, so that we have well- lishes that these two ensembles cannot correspond to the defined densities c ¼ dc =d. This assumption is not same probability distribution over ontic states. Thus, the strictly necessary. A more general measure theoretic treat- distribution on Bob’s side must depend on the choice of ment will appear in Ref. [14]. measurement that Alice makes, which implies Bell non- [14] M. Leifer, ‘‘Bounds on the Epistemic Interpretation of locality. This argument generalizes the proof of Ref. [4], Quantum States from Contextuality Inequalities’’ (to be which showed that local theories would have to be published). c -epistemic. In fact, we see that they would have to be [15] More generally, a distribution is associated with the pro- maximally c -epistemic. Filling in the formal details of this cedure for preparing a pure state rather than the state itself argument can be done in a similar way to Ref. [4]. to allow for preparation contextuality. Assuming prepara- While the impossibility of a maximally c -epistemic tion noncontextuality for pure states does no harm in the present context because our argument only establishes theory clarifies what can be proved about contextuality preparation contextuality for mixed states. based on the distinction between ontic and epistemic inter- [16] N. Harrigan and T. Rudolph, arXiv:0709.4266. pretations of the quantum state without auxiliary assump- [17] N. D. Mermin, Rev. Mod. Phys. 65, 803 (1993). tions, it is not sufficient to establish the constraints on the [18] This does not satisfy the absolute continuity assumption, size of the ontic state space that follow from having but a more technical version of Theorem 1 holds without fully ontic quantum states [11]. If one could prove, it [14].

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[19] For present purposes, it would be sufficient to allow only Hist. Phil. Mod. Phys. 35, 151 (2004); R. Hermens, ibid. 50:50 mixtures. 42, 214 (2011). [20] D. A. Meyer, Phys. Rev. Lett. 83, 3751 (1999); A. Kent, [21] E. Schro¨dinger, Proc. Cambridge Philos. Soc. 32, 446 ibid. 83, 3755 (1999); R. K. Clifton and A. Kent, Proc. R. (1936); L. P. Hughston, R. Jozsa, and W. K. Wootters, Soc. A 456, 2101 (2000); J. Barrett and A. Kent, Stud. Phys. Lett. A 183, 14 (1993).

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