LECTURE 22 DISPLACEMENT CURRENT, MAXWELL’S EQUATIONS, AND EM WAVES Lecture 22
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¨ Reading chapter 30-1 to 30-4. ¤ Maxwell’s displacement current ¤ Maxwell’s equations ¤ Electromagnetic waves ¤ Electromagnetic spectrum ¤ Production of EM waves ¤ Antennas ¤ Energy and momentum of an EM wave Ampere-Maxwell law
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¨ Maxwell’s paradox: for the same line integral over curve C, ⃗ Ampere’s law (∮ � �� = � � ) depends on which surface is used.
¤ ⃗ ∮ � �� = � � if we use the current penetrating S1.
¤ ⃗ ∮ � �� = 0 if we use the current penetrating S2. ¨ Maxwell’s solution: he added a displacement current term that depends on the changing electric flux in the gap. � = � Displacement current ⃗ ∮ � �� = � � + � Generalized Ampere’s law Quiz: 1 Example: 1
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¨ A parallel plate capacitor with a radius R = 1.0 cm and a 1.0 mm gap is being charged at the rate of 0.50 C/s. What is the magnetic field strength in the gap at a radius of r = 0.5 cm? Quiz: 2 EM waves
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¨ Faraday’s law and Ampere’s law (with no current) yield a wave equation for electromagnetic waves.
¨ The wave equation indicates the velocity of electromagnetic wave to be 1 � = = 3.0 × 10 m⁄s = � � � ¨ The direction of propagation of an electromagnetic wave is always the direction of the vector product: Moving displacement
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