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TUTORIAL | SCOPE

THE ANALYSIS OF TABLE 1 CATEGORICAL : FISHER’S Magnesium Placebo Total Jenny V Freeman and Michael J Campbell Felt better 12 3 15 Did not analyse categorical data in small samples 3 14 17 feel better

Total 15 17 32 IN THE PREVIOUS TUTORIAL we have tables that could have been observed, outlined some simple methods for for the same row and column totals as analysing binary data, including the the observed data. These row and Results of the study to examine whether intra-muscular comparison of two proportions using column totals are also known as magnesium is better than placebo for the treatment of the Normal approximation to the marginal totals. What we are trying to chronic fatigue syndrome.† 1 binomial and the Chi-squared test. establish is how extreme our particular However, these methods are only table (combination of cell frequencies) approximations, although they are is in relation to all the possible ones good when the size is large. that could have occurred given the FIGURE 1 When the sample size is small we can marginal totals. evaluate all possible combinations of This is best explained by a simple the data and compute what are known worked example. The data in table 1 (i) (ii) (iii) as exact P-values. come from an RCT comparing intra- muscular magnesium injections with 0 15 1 14 2 13 FISHER’S EXACT TEST placebo for the treatment of chronic When one of the expected values (note: fatigue syndrome.3 Of the 15 patients not the observed values) in a 2 × 2 table who had the intra-muscular 15 2 14 3 13 4 is less than 5, and especially when it is magnesium injections 12 felt better (80 less than 1, then Yates’ correction can per cent) whereas, of the 17 on placebo, (iv) (v) (vi) be improved upon. In this case Fisher’s only three felt better (18 per cent). Exact test, proposed in the mid-1930s There are 16 different ways of 3 12 4 11 5 10 almost simultaneously by Fisher, Irwin rearranging the cell frequencies for the 2 and Yates, can be applied. The null table whilst keeping the marginal totals hypothesis for the test is that there is the same, as illustrated in figure 1 12 5 11 6 10 7 no association between the rows and (right). The result that corresponds to columns of the 2 × 2 table, such that our observed cell frequencies is (xiii). (vii) (viii) (ix) the probability of a subject being in a The general form of table 1 is given particular row is not influenced by in table 2, and under the null 6 9 7 8 8 7 being in a particular column. If the hypothesis of no association Fisher columns represent the study group showed that the probability of obtaining and the rows represent the outcome, the frequencies a, b, c and d in table 2 is 9 8 8 9 7 10 then the null hypothesis could be (a + b)!(c + d)!(a + c)!(b + d)! interpreted as the probability of having (1) (a + b + c + d)!a!b!c!d! (x) (xi) (xii) a particular outcome not being influenced by the study group, and the where x! is the product of all the 9 6 10 5 11 4 test evaluates whether the two study integers between 1 and x, e.g. 5! = 1 × 2 groups differ in the proportions with × 3 × 4 × 5 = 120 (note that for the each outcome. purpose of this calculation, we define 0! 6 11 5 12 4 13 An important assumption for all of as 1). Thus for each of the results (i) to the methods outlined, including (xvi) the exact probability of obtaining (xiii) (xiv) (xv) Fisher’s Exact test, is that the binary that result can be calculated (table 3). data are independent. If the For example, the probability of proportions are correlated then more obtaining (i) in figure 1 is 12 3 13 2 14 1 advanced techniques should be 15!17!15!17! applied. For instance in the leg ulcer = 0.0000002. 32!0!15!15!2! example of the previous tutorial,1 if 3 14 2 15 1 16 there were more than one leg ulcer per From table 3 we can see that the patient, we could not treat the probability of obtaining the observed (xvi) Illustration of all the different ways of outcomes as independent. frequencies for our data is that which rearranging cell frequencies in table 1, P 15 0 The test is based upon calculating corresponds with (xiii), which gives = but with the marginal totals remaining directly the probability of obtaining the 0.0005469 and the probability of the same. results that we have shown (or results obtaining our results or results more more extreme) if the null hypothesis is extreme (a difference that is at 0 17

actually true, using all possible 2 × 2 least as large) is the sum of the M

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M probabilities for (xiii) to (xvi) = 0.000573. EXAMPLE DATA This gives the one-sided P-value for FROM LAST WEEK TABLE 2 obtaining our results or results more Table 4 shows the data from the extreme, and in order to obtain the two- previous tutorial. It is from a sided P-value there are several randomised controlled trial of Column 1 Column 2 Total approaches. The first is to simply community leg ulcer clinics,5 comparing double this value, which gives P = the cost effectiveness of community leg Row 1 a b a + b 0.0001146. A second approach is to add ulcer clinics with standard nursing together all the probabilities that are care. The columns represent the two Row 2 c d c + d the same size or smaller than the one treatment groups, specialist leg ulcer for our particular result; in this case, clinic (clinic) and standard care (home), a + b + Total a + b b + d all probabilities that are less than or and the rows represent the outcome c + d equal to 0.0005469, which are (i), (ii), variable, in this case whether the leg General form of table 1. (iii), (xiii), (xiv), (xv) and (xvi). This gives a ulcer has healed or not. two-sided value of P = 0.001033. For this example the two-sided P- Generally the difference is not great, value from Fisher’s Exact test is 0.599 though the first approach will always and in this case we cannot reject the TABLE 3 give a value greater than the second. A null hypothesis and would decide that third approach, which is recommended there is a insufficient evidence to a Total a b c d P-value by Swinscow and Campbell,4 is a difference between the two groups. compromise and is known as the mid-P i 0 15 15 2 0.0000002 method. All the values more extreme SUMMARY than the observed P-value are added This tutorial has described in detail ii 1 14 14 3 0.0000180 up and these are added to one half of Fisher’s Exact test, for analysing simple iii 2 13 13 4 0.0004417 the observed value. This gives P = 2 × 2 contingency tables when the 0.000759. assumptions for the Chi-squared test iv 3 12 12 5 0.0049769 are not met. It is tedious to do by hand, v 4 11 11 6 0.0298613 COMPARISON OF TESTS but nowadays is easily computed by The criticism of the first two methods is most statistical packages. vi 5 10 10 7 0.1032349 that they are too conservative, i.e. if the † When organising data such as this is it good vii 6 9 9 8 0.2150728 null hypothesis was true, over repeated studies they would reject the null practice to arrange the table with the grouping variable forming the columns and the outcome viii 7 8 8 9 0.2765221 hypothesis less often than 5 per cent. variable forming the rows. They are conditional on both sets of ix 8 7 7 10 0.2212177 marginal totals being fixed, i.e. exactly REFERENCES x 9 6 6 11 0.1094916 15 people being treated with magnesium and 15 feeling better. How- xi 10 5 5 12 0.0328475 ever if the study were repeated, even xii 11 4 4 13 0.0057426 with 15 and 17 in the magnesium and 1 Freeman JV, Julious SA. The placebo groups respectively, we would analysis of categorical data. xiii 12 3 3 14 0.0005469 not necessarily expect exactly 15 to feel Scope 2007; 16(1): 18–21. xiv 13 2 2 15 0.0000252 better. The mid-P value method is less 2 Armitage P, Berry PJ, conservative, and gives approximately Matthews JNS. Statistical xv 14 1 1 16 0.0000005 the correct rate of type I errors (false methods in medical xvi 15 0 0 17 0.0000000 positives). research. 4th ed. Oxford: In either case, for our example, the Blackwell Publishing, 2002. P-value is less than 0.05, the nominal Probabilities of each of the tables above, 3 Cox IM, Campbell MJ, calculated using formula 1. level for and we can conclude that there is evidence of a Dowson D. Red blood cell statistically significant difference in the magnesium and chronic fatigue syndrome. Lancet proportions feeling better between the 1991; 337: 757–60. TABLE 4 two treatment groups. However, in common with other non-parametric 4 Swinscow TDV, Campbell Treatment Outcome Total tests, Fisher’s Exact test is simply a MJ. Statistics at square one. Clinic Home hypothesis test. It will merely tell you 10th ed. London: BMJ whether a difference is likely, given the Books, 2002. Healed 22 (18%) 17 (15%) 39 null hypothesis (of no difference). It 5 Morrell CJ, Walters SJ, gives you no information about the Dixon S, Collins K, Brereton Not healed 98 (82%) 77 (85%) 194 likely size of the difference, and so LML, Peters J et al. Cost whilst we can conclude that there is a effectiveness of community significant difference between the two leg ulcer clinic: randomised Total 120 (100%) 113 (100%) 233 treatments with respect to feeling controlled trial. Brit Med J better or not, we can draw no 1998; 316: 1487–91. 2 × 2 of treatment (clinic/home) by conclusions about the possible size of outcome (ulcer healed/not healed) for the leg ulcer study. the difference.

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