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Form Code A NAME______

CHM 1025 (Spring 2019)

Exam Review (Brewer)

Instructions: On your Scantron form, enter and bubble your name, UFID, and Form Code (see above). Turn in only your Scantron. You may keep your exam sheet and any other papers. Check bubbling carefully: bubbling errors are non-negotiable. As on all graded events, the loving of moles applies.

1. Which of the following is a properly-written or name?

(1) Na(NO3)2 (2) aluminum (III) (3) monosulfur dioxide (4) K2Cl2 (5) FeCl3

2. Which of the following ionic compounds/names are true?

MgCl2 ( Dicholride) B) Fe2O3 ( (III) Oxide) C) PO3 ( Trioxide) (1) B, and C (2) A only (3) A and B only (4) B only (5) C only

3. An inorganic chemist is researching the crystal field theory and is using (II) Sulfate in her research. She goes to the analytical balancer and measures out 29.34 grams of Copper (II) Sulfate. How many atoms are within the 29.34 g sample?

(1) 6.022*1023 (2) 3.011*1023 (3) 4.3*1023 (4) 8.6*1023 (5) None of the Above

4. The compound (X) contains 49.48 % , 5.191 % , 28.87 % , and 16.48% oxygen by mass. Additionally, X’s molecular weight lies between the domain of Compound Y’s MW and Compound Z’s MW. If MWY = 188 g/mol and MWZ = 200 g/mol. Determine the molecular formula of the compound.

(1) C4H5N2O (2) C8H10N4O2 (3) C8H8N3O3 (4) C10H7N5O2 (5) C8H10N2O

5. If 76.0 mL of 1.85 M NaOH is required to neutralize 91.00 mL of a sulfuric acid, H2SO4, solution, what is the molarity of the sulfuric acid?

(1) 0.193 M H2SO4 (2) 0.386 M H2SO4 (3) 0.773 M H2SO4 (4) 1.55 M H2SO4 (5) 3.10 M H2SO4

6. What is the sum of the coefficients when the reaction is fully balanced?

C3H8 (g) + O2 (g)  CO2 (g) + H2O (g) (1) ten (2) eleven (3) twelve (4) thirteen (5) None of the Above

7. Which of the following is true?

(1) The balanced equation of Ag2SO4 (aq) + AlCl3 (aq)  AgCl (s) + Al2(SO4)3 (aq) is

Ag6(SO4)3 + Al2Cl6  Ag6Cl6 + Al2(SO4)3 (2) The subscripts in a balanced equation tells how many atoms of an element there are per molecule of compound, there are per unit of salt, and mols of element/ per mol of compound. (3) There are three mols of nitrate and three moles of oxygen in Iron (III) Nitrate (4) There are 6.022*1023 mols per 1 atom of matter (5) In balancing an equation, you can add additional compounds to the reaction to balance the reaction out.

8. A 6.00 M solution of dye is diluted by taking 13.00 ml of it and adding enough water to make 100.0 ml solution. Then, 18.00 ml of that solution is diluted to a volume of 500.0 ml. What is the concentration of the diluted dye?

(1) 0.780 M (2) 0.0281 M (3) 0.0400 M (4) 0.00281 M

(5) 0.0780 M

9. Suppose a small bottle of ethanol (CH3CH2OH) is combusted in a lab to form and water vapor. The amount of ethanol found in the bottle was calculated to be 4.20g. However, after the reaction, only 70% of the ethanol reacted properly. How much CO2 gas was produced? (1) 8.02g (2) 0.70g (3) 46.07 g (4) 44.01 g (5) 5.62 g

10. If 4.00 g of element G reacts with 7.00 g of element M to produce 13.00 g of a compound with the formula G3M4, and the atomic mass of M is 160.0 amu, what is the atomic mass of G? (1) 60.5 amu (2) 122.0 amu (3) 72.0 amu (4) 89.5 amu (5) 150 amu

11. A 1.0 g organic compound sample produced 2.36 grams of CO2 and 0.640 grams of H2O during combustion analysis. If the hydrocarbon has a between 110 and 114 g/mol, what is its molecular formula?

(1) C3H6 (2) C3H4O (3) C6H8O2 (4) CH2O3 (5) C4H8

12. Sweetener saccharin (C7H5NO3S) is sometimes dispensed in tablet form. Ten (10) tablets with a total mass of 0.5894 g were dissolved in water. They were oxidized to convert all the to sulfate ion, which was precipitated by adding an excess of chloride solution. The mass of barium sulfate obtained was 0.5032 g. What is the average mass percent of saccharin in the tablets? (1) 67% (2) 40% (3) 65% (4) 39.4% (5) 58.94%

13. If volumes are additive and 80.0 mL of 0.40 M chloride is mixed with 120 mL of a chloride solution to give a new solution in which [Cl-1] is 0.52 M, what is the concentration of the calcium chloride used to make the new solution? (1) 0.60 M (2) 0.30 M (3) 0.072 M (4) 0.036 M (5) 0.52 M

GOOD LUCK, SMILE ON THE EXAM, and remember to love your moles: all 6.022*1023 of them! -UF Teaching Center