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Outline • Polarized (Linear & Circular) • Birefringent Materials • Quarter- Plate & Half-Wave Plate

Reading: Ch 8.5 in Kong and Shen

1 True / False

1. The frequency ω p is the frequency above which a material becomes a plasma.

 2. The magnitude of the E -field of this wave is 1

E =(ˆx +ˆy)ej(ωt−kz)

3. The wave above is polarized 45o with respect to the x-axis.

2 Microscopic Lorentz Oscillator Model

k ω2 = spring o m

ωo ω p

3 Sinusoidal Uniform Plane

Ey = A1cos(ωt − kz)

EEyx==AA12coscos((ωtωt−−kzkz))

4   ˜ j(ωt−kz) 45° Ex(z,t)=ˆxRe Eoe E   ˜ j(ωt−kz) Ey(z,t)=ˆyRe Eoe Ey E E x yˆ Ey E Ex Ex E xˆ  The complex Ey E amplitude, ˜ Ex E o ,is the E same for Ey both components.

E Therefore Ex E Ex zˆ and y are always in E Ey . Ex Where is the ? E Ey

5 Superposition of Sinusoidal Uniform Plane Waves

Can it only be at 45o ?

6 Arbitrary-Angle

E-field variation over time y (and space)

Here, the y-component is in phase with the x-component, x but has different magnitude.

7 Arbitrary-Angle Linear Polarization

Specifically: 0° linear (x) polarization: E y/Ex =0 90° linear (y) polarization: E y/Ex = ∞ 45° linear polarization: Ey/Ex =1 Arbitrary linear polarization: Ey/Ex = constant

8 Circular (or Helical) Polarization yˆ

˜ Ex(z,t)=ˆxEosin(ωt − kz) Ey ˜ E Ey(z,t)=ˆyEocos(ωt − kz) xˆ

… or, more generally, Ex ˜ j(ωt−kz) Ex(z,t)=ˆxRe{−jEoe } ˜ j(ωt−kz) Ey(z,t)=ˆyRe{jEoe }

The complex amplitude of the x- E zˆ component is -j times the complex amplitude of the y-component. The resulting E-field rotates counterclockwise around the Ex and Ey are always propagation-vector 90    (looking along z-axis).

If projected on a constant z plane the E-field vector would rotate clockwise !!!

9 Right vs. Left Circular (or Helical) Polarization ˜ Ex(z,t)=−xˆEosin(ωt − kz) E-field variation ˜ Ey(z,t)=ˆyEocos(ωt − kz) over time (at z = 0) yˆ

… or, more generally, ˜ j(ωt−kz Ex(z,t)=ˆxRe{+jEoe } xˆ ˜ j(ωt−kz) Ey(z,t)=ˆyRe{jEoe }

Here, the complex amplitude of the x-component is +j times the complex amplitude of the y-component. The resulting E-field rotates

clockwise around the So the components are always propagation-vector 90        (looking along z-axis).   If projected on a constant z plane the E-field vector would rotate counterclockwise !!!

10 Unequal arbitrary-relative-phase components yield

Ex(z,t)=ˆxEoxcos(ωt − kz) E-field variation over time yˆ Ey(z,t)=ˆyEoycos(ωt − kz − θ) (and space)

where xˆ … or, more generally, j(ωt−kz) Ex(z,t)=ˆxRe{Eoxe }

j(ωt−kz−θ) Ey(z,t)=ˆyRe{Eoye } The resulting E-field can rotate clockwise or counter- clockwise around the k-vector … where are arbitrary (looking along k). complex amplitudes

11 Sinusoidal Uniform Plane Waves

Left IEEE Definitions: Right

12 A linearly polarized wave can be represented as a sum of two circularly polarized waves

13 A linearly polarized wave can be represented as a sum of two circularly polarized waves

˜ E (z,t)=ˆxE˜ sin(ωt − kz) Ex(z,t)=−xˆEosin(ωt − kz) x o ˜ ˜ Ey(z,t)=ˆyEocos(ωt − kz) Ey(z,t)=ˆyEocos(ωt − kz)

CIRCULAR LINEAR CIRCULAR

14 for Linear and Circular Polarizations

CASE 1: CASE 2: Linearly polarized light with magnitude E o oriented 45o Circularly polarized light with E with respect to the x-axis. magnitude o . S = E2/(2η) 2 in o Sin = Eo /η Wire grid

2 2 Sout = Eo /(2η) Sout = Eo /(4η) What is the average power at the input and output?

15 Todays Culture Moment

Image is in the public domain. vision

16 Anisotropic Material

The molecular "spring constant" can be different for different directions

If , then the material has a single axis and is called uniaxial

17 Microscopic Lorentz Oscillator Model

In the transparent regime … yi xi

xr yr

18 Uniaxial Crystal

Optic axis Uniaxial have one for light polarized along the optic axis (ne)

Extraordinary and another for light polarized in polarizations either of the two directions perpendicular to it (no).

Ordinary Light polarized along the optic axis polarizations is called the extraordinary ,

and light polarized perpendicular to it is called the ordinary ray.

Ordinary… These polarization directions are the crystal principal axes. Extraordinary…

19 Birefringent Materials

o-ray

e-ray no

ne

Image by Arenamotanus http://www.flickr.com/photos/ arenamontanus/2756010517/ on flickr

All transparent crystals with non-cubic lattice structure are birefringent.

20 Polarization Conversion Linear to Circular

inside

Polarization of output wave is determined by…

21 Quarter-Wave Plate Circularly polarizedyˆ output left circular output E xˆ 45o Ey λ/4

Ex fast axis

linearly polarized input

Example:

If we are to make quarter-wave plate using (no = 1.6584, ne = 1.4864), for incident light wavelength of = 590 nm, how thick would the plate be ?

dcalcite QWP = (590nm/4) / (no-ne) = 858 nm

22 Half-Wave Plate

The phase difference between the waves linearly polarized parallel and perpendicular to the optic axis is a half cycle

Optic axis

45o

LINEAR IN  LINEAR OUT

23 yˆ Key Takeaways Ey EM Waves can be linearly, circularly, or E elliptically polarized. xˆ Ex A circularly polarized wave can be represented as a sum of two linearly polarized waves having π/ 2 phase shift.

A linearly polarized wave can be represented as a sum of two circularly polarized waves. E In the general case, waves are elliptically polarized.

Waveplates can be made from birefringent materials:

Quarter wave plate: λ/4=( no − ne)d (gives π/ 2 phase shift) Half wave plate: λ/2=( no − ne)d (gives π phase shift)

24 MIT OpenCourseWare http://ocw.mit.edu

6.007 Electromagnetic Energy: From Motors to Spring 2011

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