Day 2
Particle Accelerators and Beam Optics
Mike Syphers Northern Illinois University Fermi National Accelerator Laboratory
Exotic Beams Summer School Argonne National Laboratory
July 2017 [email protected] Outline §Lecture 1 •Overview of types and uses of accelerators •Single-pass vs. repetitive systems •Transverse vs. longitudinal motion Questions? •Beams and particle distributions •Transverse beam optics
§Lecture 2 •Dispersion •Longitudinal beam dynamics »bunchers, re-bunchers; buckets and bunches •Optics modules •Accelerators for nuclear and high energy physics •Future directions
Summer 2017 MJS EBSS 2017 2 Quick Review B~ = B0y xˆ + B0x yˆ
A 1 T m @By B⇢ = · pu B = Q 300 MeV/c/u 0 x=0 ✓ ◆ @x |
2 2 x +2↵xx0 + x0 = ✏/⇡ x 10 x0 = 1 x’ x0 1 x0 ✓ ◆ ✓ F ◆✓ 0 ◆
x
x2 h i ✏ = ⇡ x2 x 2 xx 2 ⌘ ✏/⇡ h ih 0 i h 0i 2 p x0 ↵ h i K ⌘ ✏/⇡ ⌘ ↵ ✓ ◆ T xx0 Ki = Mi Ki 1 Mi ↵ h i ⌘ ✏/⇡ 1 1 xrms(s)= ✏ (s)/⇡ ✏ xrms / p / pp p
Summer 2017 MJS EBSS 2017 3 Bending through Dipole Field
L B L L ✓ = = · ⇢ (B⇢) B~ q B L = · · ρ p
dθ
Summer 2017 MJS EBSS 2017 4 Dispersion p qB L B⇢ = ✓ = · q p
The bend angle (and/or dipole magnet: ✓ p p0 + p = focusing strength) depends ✓0 p upon momentum p0 p [i.e., in “opposite” at exit, to lowest order, x0 = ✓ Similar to index of 0 p direction of bend] refraction depending upon 1 p x `✓ frequency ⇡ 2 0 p likewise, for quadrupole: dipole steering “error” due x to a different momentum p0 + p —> “dispersion” p0 p f = f0(1 + ) focusing “error” due to a p different momentum Trajectory differences due to momentum differences referred to as “dispersion” —> “chromatic aberration" x(s) and, D(s, p/p) D(s) ⇡ ⌘ p/p “dispersion function”
Summer 2017 MJS EBSS 2017 5 Dispersion [2] (see E&S text for details…) Equation of Motion:
B0 1 1 B p p 1 1 p x + 0 + 0 x = x00 +( + 2 )x =0 becomes 00 2 B⇢ ⇢ 1+ p/p B⇢ p0 + p · ⇢0(s) ⇢0 p0 + p ⇢✓ ◆
let x = D p/p, particular solution (must add the homogeneous solution, which we have found previously) betatron oscillation
then, p 1 B0 p0 p 1 p 1 p D00 + + D = p 1+ p/p B⇢ p + p · ⇢ (s)2 p ⇢ p + p a driven betatron oscillation, 0 ⇢✓ ◆ 0 0 0 0 0 with a constant driving term. keep only terms linear in the relative momentum deviation, The “driver” is the dipole field p B0 1 p 1 p D00 + + D = within a bending magnet p B⇢ ⇢2 p ⇢ p 0 ✓ 0 ◆ 0 0 0 1 D00 + KD= ⇢0
so, solutions are plus sin pK` & cos pK` const.
Summer 2017 MJS EBSS 2017 6 1 D00 + KD= Dispersion [3] ⇢0
In terms of matrices… 1 s K = 0 : D00 = ,D0 = + D0 ⇢ ⇢ 0 1 s2 D = D + D0 s + in the limit of short, or “thin” 0 0 2 ⇢ elements, a bending magnet 1 2 D 1 s s /⇢ D0 primarily changes the slope of the 2 D0 = 01 s/⇢ D0 dispersion function by an amount 0 1 1 0 00 1 1 0 1 1 equal to the bend angle of the @ A @ A @ A magnet 1/! = 0 : same 2x2 as before D 0 D M 0 D0 = 0 D0 otherwise, the D transports roughly 0 1 1 0 01✓ ◆ 1 0 1 1 like a betatron oscillation @ A @ A @ A So, can use matrix methods (3x3 now; and 2x2 in “vertical” plane) to solve for: x, ↵x, x