DOCSLIB.ORG

MATH 304 Linear Algebra Lecture 29: Orthogonal Sets. the Gram-Schmidt Process

Total Page：16

File Type：pdf, Size：1020Kb

Download full-text PDF Read full-text
MATH 304 Linear Algebra Lecture 29: Orthogonal Sets. the Gram-Schmidt Process MATH 304 Linear Algebra Lecture 29: Orthogonal sets. The Gram-Schmidt process. Orthogonal sets Let V be an inner product space with an inner product h·, ·i and the induced norm k · k. Definition. A nonempty set S ⊂ V of nonzero vectors is called an orthogonal set if all vectors in S are mutually orthogonal. That is, 0 ∈/ S and hx, yi = 0 for any x, y ∈ S, x =6 y. An orthogonal set S ⊂ V is called orthonormal if kxk = 1 for any x ∈ S. Remark. Vectors v1, v2,..., vk ∈ V form an orthonormal set if and only if 1 if i = j hv , v i = i j 0 if i =6 j Examples. • V = Rn, hx, yi = x · y. The standard basis e1 = (1, 0, 0,..., 0), e2 = (0, 1, 0,..., 0), . , en = (0, 0, 0,..., 1). It is an orthonormal set. • V = R3, hx, yi = x · y. v1 = (3, 5, 4), v2 = (3, −5, 4), v3 = (4, 0, −3). v1 · v2 = 0, v1 · v3 = 0, v2 · v3 = 0, v1 · v1 = 50, v2 · v2 = 50, v3 · v3 = 25. Thus the set {v1, v2, v3} is orthogonal but not orthonormal. An orthonormal set is formed by v1 v2 1 2 normalized vectors w = kv1k, w = kv2k, v3 3 w = kv3k. π • V = C[−π, π], hf , gi = f (x)g(x) dx. π Z− f1(x) = sin x, f2(x) = sin 2x, ..., fn(x) = sin nx, ... π hfm, fni = sin(mx)sin(nx) dx −π Z π 1 = cos(mx − nx) − cos(mx + nx) dx. −π 2 Z π sin(kx) π cos(kx) dx = =0 if k ∈ Z, k =6 0. −π k x=−π Z π π k =0 =⇒ cos(kx) dx = dx = 2π. −π −π Z Z 1 π hfm, fni = cos(m − n)x − cos(m + n)x dx 2 −π Z π if m = n = 0 if m =6 n Thus the set {f1, f2, f3,... } is orthogonal but not orthonormal. It is orthonormal with respect to a scaled inner product π 1 hhf , gii = f (x)g(x) dx. π π Z− Orthogonality =⇒ linear independence Theorem Suppose v1, v2,..., vk are nonzero vectors that form an orthogonal set. Then v1, v2,..., vk are linearly independent. Proof: Suppose t1v1 + t2v2 + ··· + tk vk = 0 for some t1, t2,..., tk ∈ R. Then for any index 1 ≤ i ≤ k we have ht1v1 + t2v2 + ··· + tk vk , vi i = h0, vi i = 0. =⇒ t1hv1, vi i + t2hv2, vi i + ··· + tk hvk , vi i = 0 By orthogonality, ti hvi , vi i = 0 =⇒ ti = 0. Orthonormal bases Let v1, v2,..., vn be an orthonormal basis for an inner product space V . Theorem Let x = x1v1 + x2v2 + ··· + xnvn and y = y1v1 + y2v2 + ··· + ynvn, where xi , yj ∈ R. Then (i) hx, yi = x1y1 + x2y2 + ··· + xnyn, 2 2 2 (ii) kxk = x1 + x2 + ··· + xn . Proof: (ii) followsp from (i) when y = x. n n n n hx, yi = xi vi , yj vj = xi vi , yj vj * i=1 j=1 + i=1 * j=1 + X n nX Xn X = xi yj hvi , vj i = xi yi . i=1 j=1 i=1 X X X Let v1, v2,..., vn be a basis for an inner product space V . Theorem If the basis v1, v2,..., vn is an orthogonal set then for any x ∈ V hx, v1i hx, v2i hx, vni x = v1 + v2 + ··· + vn. hv1, v1i hv2, v2i hvn, vni If v1, v2,..., vn is an orthonormal set then x = hx, v1iv1 + hx, v2iv2 + ··· + hx, vnivn. Proof: We have that x = x1v1 + ··· + xnvn. =⇒ hx, vi i = hx1v1 + ··· + xnvn, vi i, 1 ≤ i ≤ n. =⇒ hx, vi i = x1hv1, vi i + ··· + xnhvn, vi i =⇒ hx, vi i = xi hvi , vi i. Let V be a vector space with an inner product. Suppose that v1,..., vk ∈ V are nonzero vectors that form an orthogonal set. Given x ∈ V , let hx, v1i hx, vk i p = v1 + ··· + vk , o = x − p. hv1, v1i hvk , vk i Let W denote the span of v1,..., vk . Theorem (a) o ⊥ w for all w ∈ W (denoted o ⊥ W ). (b) kok = kx − pk = min kx − wk. w∈W Thus p is the orthogonal projection of the vector x on the subspace W . Also, p is closer to x than any other vector in W , and kok = dist(x, p) is the distance from x to W . Orthogonalization Let V be a vector space with an inner product. Suppose x1, x2,..., xn is a basis for V . Let v1 = x1, hx2, v1i v2 = x2 − v1, hv1, v1i hx3, v1i hx3, v2i v3 = x3 − v1 − v2, hv1, v1i hv2, v2i ................................................. hxn, v1i hxn, vn−1i vn = xn − v1 −···− vn−1. hv1, v1i hvn−1, vn−1i Then v1, v2,..., vn is an orthogonal basis for V . The orthogonalization of a basis as described above is called the Gram-Schmidt process. Normalization Let V be a vector space with an inner product. Suppose v1, v2,..., vn is an orthogonal basis for V . v1 v2 vn Let w1 = , w2 = ,..., wn = . kv1k kv2k kvnk Then w1, w2,..., wn is an orthonormal basis for V . Theorem Any finite-dimensional vector space with an inner product has an orthonormal basis. Remark. An infinite-dimensional vector space with an inner product may or may not have an orthonormal basis..
Load more

Recommended publications
  • Introduction to Linear Bialgebra
    View metadata, citation and similar papers at core.ac.uk brought to you by CORE provided by University of New Mexico University of New Mexico UNM Digital Repository Mathematics and Statistics Faculty and Staff Publications Academic Department Resources 2005 INTRODUCTION TO LINEAR BIALGEBRA Florentin Smarandache University of New Mexico, [email protected] W.B. Vasantha Kandasamy K. Ilanthenral Follow this and additional works at: https://digitalrepository.unm.edu/math_fsp Part of the Algebra Commons, Analysis Commons, Discrete Mathematics and Combinatorics Commons, and the Other Mathematics Commons Recommended Citation Smarandache, Florentin; W.B. Vasantha Kandasamy; and K. Ilanthenral. "INTRODUCTION TO LINEAR BIALGEBRA." (2005). https://digitalrepository.unm.edu/math_fsp/232 This Book is brought to you for free and open access by the Academic Department Resources at UNM Digital Repository. It has been accepted for inclusion in Mathematics and Statistics Faculty and Staff Publications by an authorized administrator of UNM Digital Repository. For more information, please contact [email protected], [email protected], [email protected]. INTRODUCTION TO LINEAR BIALGEBRA W. B. Vasantha Kandasamy Department of Mathematics Indian Institute of Technology, Madras Chennai – 600036, India e-mail: [email protected] web: http://mat.iitm.ac.in/~wbv Florentin Smarandache Department of Mathematics University of New Mexico Gallup, NM 87301, USA e-mail: [email protected] K. Ilanthenral Editor, Maths Tiger, Quarterly Journal Flat No.11, Mayura Park, 16, Kazhikundram Main Road, Tharamani, Chennai – 600 113, India e-mail: [email protected] HEXIS Phoenix, Arizona 2005 1 This book can be ordered in a paper bound reprint from: Books on Demand ProQuest Information & Learning (University of Microfilm International) 300 N.
    [Show full text]
  • A New Description of Space and Time Using Clifford Multivectors
    A new description of space and time using Clifford multivectors James M. Chappell† , Nicolangelo Iannella† , Azhar Iqbal† , Mark Chappell‡ , Derek Abbott† †School of Electrical and Electronic Engineering, University of Adelaide, South Australia 5005, Australia ‡Griffith Institute, Griffith University, Queensland 4122, Australia Abstract Following the development of the special theory of relativity in 1905, Minkowski pro- posed a unified space and time structure consisting of three space dimensions and one time dimension, with relativistic effects then being natural consequences of this space- time geometry. In this paper, we illustrate how Clifford’s geometric algebra that utilizes multivectors to represent spacetime, provides an elegant mathematical framework for the study of relativistic phenomena. We show, with several examples, how the application of geometric algebra leads to the correct relativistic description of the physical phenomena being considered. This approach not only provides a compact mathematical representa- tion to tackle such phenomena, but also suggests some novel insights into the nature of time. Keywords: Geometric algebra, Clifford space, Spacetime, Multivectors, Algebraic framework 1. Introduction The physical world, based on early investigations, was deemed to possess three inde- pendent freedoms of translation, referred to as the three dimensions of space. This naive conclusion is also supported by more sophisticated analysis such as the existence of only five regular polyhedra and the inverse square force laws. If we lived in a world with four spatial dimensions, for example, we would be able to construct six regular solids, and in arXiv:1205.5195v2 [math-ph] 11 Oct 2012 five dimensions and above we would find only three [1].
    [Show full text]
  • 21. Orthonormal Bases
    21. Orthonormal Bases The canonical/standard basis 011 001 001 B C B C B C B0C B1C B0C e1 = B.C ; e2 = B.C ; : : : ; en = B.C B.C B.C B.C @.A @.A @.A 0 0 1 has many useful properties. • Each of the standard basis vectors has unit length: q p T jjeijj = ei ei = ei ei = 1: • The standard basis vectors are orthogonal (in other words, at right angles or perpendicular). T ei ej = ei ej = 0 when i 6= j This is summarized by ( 1 i = j eT e = δ = ; i j ij 0 i 6= j where δij is the Kronecker delta. Notice that the Kronecker delta gives the entries of the identity matrix. Given column vectors v and w, we have seen that the dot product v w is the same as the matrix multiplication vT w. This is the inner product on n T R . We can also form the outer product vw , which gives a square matrix. 1 The outer product on the standard basis vectors is interesting. Set T Π1 = e1e1 011 B C B0C = B.C 1 0 ::: 0 B.C @.A 0 01 0 ::: 01 B C B0 0 ::: 0C = B. .C B. .C @. .A 0 0 ::: 0 . T Πn = enen 001 B C B0C = B.C 0 0 ::: 1 B.C @.A 1 00 0 ::: 01 B C B0 0 ::: 0C = B. .C B. .C @. .A 0 0 ::: 1 In short, Πi is the diagonal square matrix with a 1 in the ith diagonal position and zeros everywhere else.
    [Show full text]
  • Orthogonal Projection, Low Rank Approximation, and Orthogonal Bases
    Week 11 Orthogonal Projection, Low Rank Approximation, and Orthogonal Bases 11.1 Opening Remarks 11.1.1 Low Rank Approximation * View at edX 463 Week 11. Orthogonal Projection, Low Rank Approximation, and Orthogonal Bases 464 11.1.2 Outline 11.1. Opening Remarks..................................... 463 11.1.1. Low Rank Approximation............................. 463 11.1.2. Outline....................................... 464 11.1.3. What You Will Learn................................ 465 11.2. Projecting a Vector onto a Subspace........................... 466 11.2.1. Component in the Direction of ............................ 466 11.2.2. An Application: Rank-1 Approximation...................... 470 11.2.3. Projection onto a Subspace............................. 474 11.2.4. An Application: Rank-2 Approximation...................... 476 11.2.5. An Application: Rank-k Approximation...................... 478 11.3. Orthonormal Bases.................................... 481 11.3.1. The Unit Basis Vectors, Again........................... 481 11.3.2. Orthonormal Vectors................................ 482 11.3.3. Orthogonal Bases.................................. 485 11.3.4. Orthogonal Bases (Alternative Explanation).................... 488 11.3.5. The QR Factorization................................ 492 11.3.6. Solving the Linear Least-Squares Problem via QR Factorization......... 493 11.3.7. The QR Factorization (Again)........................... 494 11.4. Change of Basis...................................... 498 11.4.1. The Unit Basis Vectors,
    [Show full text]
  • Orthogonal Bases and the -So in Section 4.8 We Discussed the Problem of Finding the Orthogonal Projection P
    Orthogonal Bases and the -So In Section 4.8 we discussed the problemR. of finding the orthogonal projection p the vector b into the V of , . , suhspace the vectors , v2 ho If v1 v,, form a for V, and the in x n matrix A has these basis vectors as its column vectors. ilt the orthogonal projection p is given by p = Ax where x is the (unique) solution of the normal system ATAx = A7b. The formula for p takes an especially simple and attractive Form when the ba vectors , . .. , v1 v are mutually orthogonal. DEFINITION Orthogonal Basis An orthogonal basis for the suhspacc V of R” is a basis consisting of vectors , ,v,, that are mutually orthogonal, so that v v = 0 if I j. If in additii these basis vectors are unit vectors, so that v1 . = I for i = 1. 2 n, thct the orthogonal basis is called an orthonormal basis. Example 1 The vectors = (1, 1,0), v2 = (1, —1,2), v3 = (—1,1,1) form an orthogonal basis for . We “normalize” ‘ R3 can this orthogonal basis 1w viding each basis vector by its length: If w1=—- (1=1,2,3), lvii 4.9 Orthogonal Bases and the Gram-Schmidt Algorithm 295 then the vectors /1 I 1 /1 1 ‘\ 1 2” / I w1 0) W2 = —— _z) W3 for . form an orthonormal basis R3 , . ..., v, of the m x ii matrix A Now suppose that the column vectors v v2 form an orthogonal basis for the suhspacc V of R’. Then V}.VI 0 0 v2.v ..
    [Show full text]
  • Orthonormal Bases in Hilbert Space APPM 5440 Fall 2017 Applied Analysis
    Orthonormal Bases in Hilbert Space APPM 5440 Fall 2017 Applied Analysis Stephen Becker November 18, 2017(v4); v1 Nov 17 2014 and v2 Jan 21 2016 Supplementary notes to our textbook (Hunter and Nachtergaele). These notes generally follow Kreyszig’s book. The reason for these notes is that this is a simpler treatment that is easier to follow; the simplicity is because we generally do not consider uncountable nets, but rather only sequences (which are countable). I have tried to identify the theorems from both books; theorems/lemmas with numbers like 3.3-7 are from Kreyszig. Note: there are two versions of these notes, with and without proofs. The version without proofs will be distributed to the class initially, and the version with proofs will be distributed later (after any potential homework assignments, since some of the proofs maybe assigned as homework). This version does not have proofs. 1 Basic Definitions NOTE: Kreyszig defines inner products to be linear in the first term, and conjugate linear in the second term, so hαx, yi = αhx, yi = hx, αy¯ i. In contrast, Hunter and Nachtergaele define the inner product to be linear in the second term, and conjugate linear in the first term, so hαx,¯ yi = αhx, yi = hx, αyi. We will follow the convention of Hunter and Nachtergaele, so I have re-written the theorems from Kreyszig accordingly whenever the order is important. Of course when working with the real field, order is completely unimportant. Let X be an inner product space. Then we can define a norm on X by kxk = phx, xi, x ∈ X.
    [Show full text]
  • Lecture 4: April 8, 2021 1 Orthogonality and Orthonormality
    Mathematical Toolkit Spring 2021 Lecture 4: April 8, 2021 Lecturer: Avrim Blum (notes based on notes from Madhur Tulsiani) 1 Orthogonality and orthonormality Definition 1.1 Two vectors u, v in an inner product space are said to be orthogonal if hu, vi = 0. A set of vectors S ⊆ V is said to consist of mutually orthogonal vectors if hu, vi = 0 for all u 6= v, u, v 2 S. A set of S ⊆ V is said to be orthonormal if hu, vi = 0 for all u 6= v, u, v 2 S and kuk = 1 for all u 2 S. Proposition 1.2 A set S ⊆ V n f0V g consisting of mutually orthogonal vectors is linearly inde- pendent. Proposition 1.3 (Gram-Schmidt orthogonalization) Given a finite set fv1,..., vng of linearly independent vectors, there exists a set of orthonormal vectors fw1,..., wng such that Span (fw1,..., wng) = Span (fv1,..., vng) . Proof: By induction. The case with one vector is trivial. Given the statement for k vectors and orthonormal fw1,..., wkg such that Span (fw1,..., wkg) = Span (fv1,..., vkg) , define k u + u = v − hw , v i · w and w = k 1 . k+1 k+1 ∑ i k+1 i k+1 k k i=1 uk+1 We can now check that the set fw1,..., wk+1g satisfies the required conditions. Unit length is clear, so let’s check orthogonality: k uk+1, wj = vk+1, wj − ∑ hwi, vk+1i · wi, wj = vk+1, wj − wj, vk+1 = 0. i=1 Corollary 1.4 Every finite dimensional inner product space has an orthonormal basis.
    [Show full text]
  • Bases for Infinite Dimensional Vector Spaces Math 513 Linear Algebra Supplement
    BASES FOR INFINITE DIMENSIONAL VECTOR SPACES MATH 513 LINEAR ALGEBRA SUPPLEMENT Professor Karen E. Smith We have proven that every finitely generated vector space has a basis. But what about vector spaces that are not finitely generated, such as the space of all continuous real valued functions on the interval [0; 1]? Does such a vector space have a basis? By definition, a basis for a vector space V is a linearly independent set which generates V . But we must be careful what we mean by linear combinations from an infinite set of vectors. The definition of a vector space gives us a rule for adding two vectors, but not for adding together infinitely many vectors. By successive additions, such as (v1 + v2) + v3, it makes sense to add any finite set of vectors, but in general, there is no way to ascribe meaning to an infinite sum of vectors in a vector space. Therefore, when we say that a vector space V is generated by or spanned by an infinite set of vectors fv1; v2;::: g, we mean that each vector v in V is a finite linear combination λi1 vi1 + ··· + λin vin of the vi's. Likewise, an infinite set of vectors fv1; v2;::: g is said to be linearly independent if the only finite linear combination of the vi's that is zero is the trivial linear combination. So a set fv1; v2; v3;:::; g is a basis for V if and only if every element of V can be be written in a unique way as a finite linear combination of elements from the set.
    [Show full text]
  • Ch 5: ORTHOGONALITY
    Ch 5: ORTHOGONALITY 5.5 Orthonormal Sets 1. a set fv1; v2; : : : ; vng is an orthogonal set if hvi; vji = 0, 81 ≤ i 6= j; ≤ n (note that orthogonality only makes sense in an inner product space since you need to inner product to check hvi; vji = 0. n For example fe1; e2; : : : ; eng is an orthogonal set in R . 2. fv1; v2; : : : ; vng is an orthogonal set =) v1; v2; : : : ; vn are linearly independent. 3. a set fv1; v2; : : : ; vng is an orthonormal set if hvi; vji = 0 and jjvijj = 1, 81 ≤ i 6= j; ≤ n (i.e. orthogonal and unit length). n For example fe1; e2; : : : ; eng is an orthonormal set in R . 4. given an orthogonal basis for a vector space V , we can always find an orthonormal basis for V by dividing each vector by its length (see Example 2 and 3 page 256) n 5. a space with an orthonormal basis behaves like the euclidean space R with the standard basis (it is easier to work with basis that are orthonormal, just like it is n easier to work with the standard basis versus other bases for R ) 6. if v is a vector in a inner product space V with fu1; u2; : : : ; ung an orthonormal basis, Pn Pn then we can write v = i=1 ciui = i=1hv; uiiui Pn 7. an easy way to find the inner product of two vectors: if u = i=1 aiui and v = Pn i=1 biui, where fu1; u2; : : : ; ung is an orthonormal basis for an inner product space Pn V , then hu; vi = i=1 aibi Pn 8.
    [Show full text]
  • Determinants Math 122 Calculus III D Joyce, Fall 2012
    Determinants Math 122 Calculus III D Joyce, Fall 2012 What they are. A determinant is a value associated to a square array of numbers, that square array being called a square matrix. For example, here are determinants of a general 2 × 2 matrix and a general 3 × 3 matrix. a b = ad − bc: c d a b c d e f = aei + bfg + cdh − ceg − afh − bdi: g h i The determinant of a matrix A is usually denoted jAj or det (A). You can think of the rows of the determinant as being vectors. For the 3×3 matrix above, the vectors are u = (a; b; c), v = (d; e; f), and w = (g; h; i). Then the determinant is a value associated to n vectors in Rn. There's a general definition for n×n determinants. It's a particular signed sum of products of n entries in the matrix where each product is of one entry in each row and column. The two ways you can choose one entry in each row and column of the 2 × 2 matrix give you the two products ad and bc. There are six ways of chosing one entry in each row and column in a 3 × 3 matrix, and generally, there are n! ways in an n × n matrix. Thus, the determinant of a 4 × 4 matrix is the signed sum of 24, which is 4!, terms. In this general definition, half the terms are taken positively and half negatively. In class, we briefly saw how the signs are determined by permutations.
    [Show full text]
  • Math 2331 – Linear Algebra 6.2 Orthogonal Sets
    6.2 Orthogonal Sets Math 2331 { Linear Algebra 6.2 Orthogonal Sets Jiwen He Department of Mathematics, University of Houston [email protected] math.uh.edu/∼jiwenhe/math2331 Jiwen He, University of Houston Math 2331, Linear Algebra 1 / 12 6.2 Orthogonal Sets Orthogonal Sets Basis Projection Orthonormal Matrix 6.2 Orthogonal Sets Orthogonal Sets: Examples Orthogonal Sets: Theorem Orthogonal Basis: Examples Orthogonal Basis: Theorem Orthogonal Projections Orthonormal Sets Orthonormal Matrix: Examples Orthonormal Matrix: Theorems Jiwen He, University of Houston Math 2331, Linear Algebra 2 / 12 6.2 Orthogonal Sets Orthogonal Sets Basis Projection Orthonormal Matrix Orthogonal Sets Orthogonal Sets n A set of vectors fu1; u2;:::; upg in R is called an orthogonal set if ui · uj = 0 whenever i 6= j. Example 82 3 2 3 2 39 < 1 1 0 = Is 4 −1 5 ; 4 1 5 ; 4 0 5 an orthogonal set? : 0 0 1 ; Solution: Label the vectors u1; u2; and u3 respectively. Then u1 · u2 = u1 · u3 = u2 · u3 = Therefore, fu1; u2; u3g is an orthogonal set. Jiwen He, University of Houston Math 2331, Linear Algebra 3 / 12 6.2 Orthogonal Sets Orthogonal Sets Basis Projection Orthonormal Matrix Orthogonal Sets: Theorem Theorem (4) Suppose S = fu1; u2;:::; upg is an orthogonal set of nonzero n vectors in R and W =spanfu1; u2;:::; upg. Then S is a linearly independent set and is therefore a basis for W . Partial Proof: Suppose c1u1 + c2u2 + ··· + cpup = 0 (c1u1 + c2u2 + ··· + cpup) · = 0· (c1u1) · u1 + (c2u2) · u1 + ··· + (cpup) · u1 = 0 c1 (u1 · u1) + c2 (u2 · u1) + ··· + cp (up · u1) = 0 c1 (u1 · u1) = 0 Since u1 6= 0, u1 · u1 > 0 which means c1 = : In a similar manner, c2,:::,cp can be shown to by all 0.
    [Show full text]
  • CLIFFORD ALGEBRAS Property, Then There Is a Unique Isomorphism (V ) (V ) Intertwining the Two Inclusions of V
    CHAPTER 2 Clifford algebras 1. Exterior algebras 1.1. Definition. For any vector space V over a field K, let T (V ) = k k k Z T (V ) be the tensor algebra, with T (V ) = V V the k-fold tensor∈ product. The quotient of T (V ) by the two-sided⊗···⊗ ideal (V ) generated byL all v w + w v is the exterior algebra, denoted (V ).I The product in (V ) is usually⊗ denoted⊗ α α , although we will frequently∧ omit the wedge ∧ 1 ∧ 2 sign and just write α1α2. Since (V ) is a graded ideal, the exterior algebra inherits a grading I (V )= k(V ) ∧ ∧ k Z M∈ where k(V ) is the image of T k(V ) under the quotient map. Clearly, 0(V )∧ = K and 1(V ) = V so that we can think of V as a subspace of ∧(V ). We may thus∧ think of (V ) as the associative algebra linearly gener- ated∧ by V , subject to the relations∧ vw + wv = 0. We will write φ = k if φ k(V ). The exterior algebra is commutative | | ∈∧ (in the graded sense). That is, for φ k1 (V ) and φ k2 (V ), 1 ∈∧ 2 ∈∧ [φ , φ ] := φ φ + ( 1)k1k2 φ φ = 0. 1 2 1 2 − 2 1 k If V has finite dimension, with basis e1,...,en, the space (V ) has basis ∧ e = e e I i1 · · · ik for all ordered subsets I = i1,...,ik of 1,...,n . (If k = 0, we put { } k { n } e = 1.) In particular, we see that dim (V )= k , and ∅ ∧ n n dim (V )= = 2n.
    [Show full text]