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MATH 4140/MATH 5140: Abstract Algebra II MATH 4140/MATH 5140: Abstract Algebra II Farid Aliniaeifard April 30, 2018 Contents 1 Rings and Isomorphism (See Chapter 3 of the textbook) 2 1.1 Definitions and examples . .2 1.2 Units and Zero-divisors . .6 1.3 Useful facts about fields and integral domains . .6 1.4 Homomorphism and isomorphism . .7 2 Polynomials Arithmetic and the Division algorithm 9 3 Ideals and Quotient Rings 11 3.1 Finitely Generated Ideals . 12 3.2 Congruence . 13 3.3 Quotient Ring . 13 4 The Structure of R=I When I Is Prime or Maximal 16 5 EPU 17 p 6 Z[ d], an integral domain which is not a UFD 22 7 The field of quotients of an integral domain 24 8 If R is a UDF, so is R[x] 26 9 Vector Spaces 28 10 Simple Extensions 30 11 Algebraic Extensions 33 12 Splitting Fields 35 13 Separability 38 14 Finite Fields 40 15 The Galois Group 43 1 16 The Fundamental Theorem of Galois Theory 45 16.1 Galois Extensions . 47 17 Solvability by Radicals 51 17.1 Solvable groups . 51 18 Roots of Unity 52 19 Representation Theory 53 19.1 G-modules and Group algebras . 54 19.2 Action of a group on a set yields a G-module . 54 20 Reducibility 57 21 Inner product space 58 22 Maschke's Theorem 59 1 Rings and Isomorphism (See Chapter 3 of the text- book) 1.1 Definitions and examples Definition. A ring is a nonempty set R equipped with two operations (usually written as addition (+) and multiplication(.) and we denote the ring with its operations by (R,+,.)) that satisfy the following axioms. For all a; b; c 2 R: (1) If a 2 R and b 2 R, then a + b 2 R. [Closure for addition] (2) a + (b + c) = (a + b) + c. [Associative addition] (3) a + b = b + a. [Commutative addition] (4) There is an element 0R in R such that a + 0R = a = 0R + a for every a 2 R. [Zero element] (5) For every a 2 R, there exists an element b 2 R such that a+b = 0 = b+a. [additive Inverse element] (6) If a 2 R and b 2 R, then a:b 2 R. [Closed for multiplication] (7) a:(b:c) = (a:b):c (8) a:(b + c) = a:b + a:c and (a + b):c = a:c + b:c [Distributive laws] Remark. Note that axioms 1; 2; 3; 4; and 5 shows that (R; +) is an abelian group. Example 1.1. Z, Zn, and M2(R) are rings. Definition. A commutative ring is a ring R that satisfies the axiom: (9) a:b = b:a for all a; b 2 R. [Commutative multiplication] 2 Definition. A ring with identity is a ring R that contains an element 1R satisfying this axiom: (10) a:1R = a = 1R:a for all a 2 R [Multiplicative identity] Definition. An integral domain is a commutative ring R with identity 1R 6= 0 that satisfies this axiom: (11) whenever a; b 2 R and a:b = 0, then a = 0R or b = 0R. The end of the lecture 1 3 Lecture 2, January 19, 2018 A ring is a nonempty set R together with two operations (+) and (.) such that (i) (R,+) is an abelian group. (ii) for all a; b 2 R, a:b 2 R. (iii) for all a; b; c 2 R, a:(b:c) = (a:b):c. (iv) for all a; b; c 2 R, we have a:(b + c) = a:b + a:c and (a + b):c = a:c + b:c. Then a ring is commutative if a:b = b:a for all a; b 2 R. It has an identity if there is an element 1 2 R such that a:1 = 1:a = a. An integral domain is a commutative ring with identity 1 that satisfy the axiom: if ab = 0, then a = 0 or b = 0. Example 1.2. Z; R; and Q are integral domains. Z6 is a ring but not an integral domain. The elements of Z6 are f0; 1; 2; 3; 4; 5g. In Z6, we have 2 + 3 = 5, 5 + 4 = 3 and 5 + 3 = 2. Also, if we compute 2:3 = 0 we see that Z6 is not an integral domain. Example 1.3. Let R be the ring of real numbers. Then R[x] is a ring with the following addition and multiplication: if 2 f(x) = 1 + 3x + x 2 R[x] and 3 g(x) = −3x + x 2 R[x]; then f(x) + g(x) = 1 + x2 + x3 and f(x)g(x) = −3x + x3 − 9x2 + 3x4 − 3x3 + x5 = −3x − 9x2 − 2x3 + 3x4 + x5: Also, the polynomial e(x) = 1 is the identity element and 0(x) = 0 is the zero element. Theorem 1.4. Let R and S be rings. Define the following addition and multiplication on the Cartisian Product R × S by (r; s) + (r0 ; s0 ) = (r + r0 ; s + s0 ) and (r; s):(r0 ; s0 ) = (r:r0 ; s:s0 ): Then R × S is a ring. If R and S are both commutative, so does R × S. If both R × S have identity then so does R × S. In the following proposition we will present some properties of the elements of a ring. Proposition 1.5. Let R be a ring and a; b 2 R. Then (i) 0:a = a:0 = 0. 4 (ii) (−a):b = a:(−b) = −(a:b). (iii) if R has identity 1, then the identity is unique and (−a) = (−1):a. Proof. 1. (i) 0:a = (0 + 0):a = 0:a + 0:a ) 0:a = 0a + 0a ) 0:a = 0: 2. (ii) a:b + (−a):b = (a + (−a)):b = 0:b = 0 ) a:b + (−a):b = 0 ) (−a):b = −(ab): The rest left to the reader. Definition. A subset S of a ring R is a subring of R if it is a ring with the same addition and multiplication as R. To show that a subset S of R is a subring of R, you only need to check that S is nonempty and (i) S is closed under multiplication. (ii) S is closed under subtraction, i.e., if a; b 2 R, then a − b 2 R. p p Example 1.6. Define Z[ 2] = fa + b 2 : a; b 2 Zg is a subring of R. p p p p Proof. Let a + b 2 2 Z[ 2] and c + d 2 2 Z[ 2]. Then p p p p (a + b 2)(c + d 2) = (ac + 2bd) + (ad + cb) 2 2 Z[ 2] and p p p p (a + b 2) − (c + d 2) = (a − c) + (b − d) 2 2 Z[ 2]: p Therefore Z[ 2] is a subring of R. Definition. A Field is a commutative ring R with identity 1R 6= 0 that satisfies this axiom: (12) For each a 6= 0R in R, there is an element b 2 R such that ab = 1 = ba. The element b is called the inverse of a and is denoted by a−1. Example 1.7. (i) Q, R and C are fields. (ii) Zp when p is a prime number is a field. 5 Week 2, Lecture 1 1.2 Units and Zero-divisors Definition. An element a in a ring R with identity is called a unit if there exists u 2 R such that au = 1R = ua. Example 1.8. (i) Units of Z are 1 and −1. (ii) Units of Z6 are 1 and 5. In general the set of units of Zn is fk : k and n are coprime g. (iii) Units of the rings of 2 × 2 matrices M2(R) are the invertible matrices. Definition. An element a in R is a zero-divisor provided that (i) a 6= 0R. (ii) There exists a nonzero element c 2 R such that ac = 0R or ca = 0R. Remark. An integral domain contains no zero-divisors. Example 1.9. (i) 2 and 3 are zero-divisors in Z6 since 2:3 = 0. (ii) zero-divisors of the rings of 2 × 2 matrices M2(R) are the non-invertible matrices. a b Because if is a non-invertible matrix we have det(A) = ad − bc = 0, and c d a b d −b 0 0 we multiply = c d −c a 0 0 A ring D with identity 1D in which every non-zero element is a unit is called a Division ring. Note that any field is a commutative division ring. 1.3 Useful facts about fields and integral domains Theorem 1.10. Every finite field F is an integral domain. Proof. Every field is a commutative ring with identity, so it is enough to show that if ab = 0, then a = 0 or b = 0. Assume that ab = 0 but a 6= 0 and b 6= 0. Then ab = 0 ) a−1(ab) = 0 ) 1:b = 0 ) b = 0; which is a contradiction. Theorem 1.11. Every finite integral domain R is a field. Proof. As every integral domain is a commutative ring with identity, it is enough to show that every non-zero element in R has an inverse in R. Let a1; : : : ; an be all of nonzero distinct elements of R. Let a be an arbitrary nonzero element in R. Then for any ai we have aai 6= 0 otherwise since R is in integral domain we have a = 0 or ai = 0 which is not possible. Therefore, aa1; : : : ; aan are nonzero elements in R. Moreover, they are distinct because if for some distinct i and j, aai = aaj, then aai − aaj = 0 ) a(ai − aj) = 0: 6 Since R is an integral domain and a 6= 0, we must have ai −aj = 0, and so ai = aj, which is not possible.
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