Euclidean Geometry:An Introduction to Mathematical Work

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Euclidean Geometry:An Introduction to Mathematical Work Euclidean Geometry: An Introduction to Mathematical Work Math 3600 Spring 2019 Circles, Coming ’Round Again One of the most useful results about circles is Proposition III.20 which relates an inscribed angle in a circle to a central angle in that circle. Let us try to see what happens when the angle does not sit on the circumference of the circle. 10.1 Conjecture. Let ¡ be a circle with center O. Let X be a point in the interior of the circle, and suppose that two lines ` and m intersect at X so that ` meets ¡ at points A and A0 and m meets ¡ at B and B 0. Then twice angle AXB is congruent to angle AOB and angle A0OB 0 taken together. 10.2 Question. Consider the situation from the last conjecture, but instead assume that X lies outside ¡. What happens here? Formulate a conjecture. 10.3 Conjecture. If two chords of a circle subtend different acute angles at points of a circle, then the smaller angle belongs to the shorter chord. 10.4 Conjecture. If a triangle has two different angles, then the smaller an- gle has the longer angle bisector (measured from the vertex to the opposite side). 10.5 Conjecture (Steiner-Lehmus). If a triangle has two angle bisectors which are congruent (measured from the vertex to the opposite side), then the triangle is isosceles. 10.6 Conjecture. Let BC be a chord of circle C , let BCÙ be the arc of C which is bounded by B and C and does not contain the center of C . Let M be the midpoint of BCÙ. For a point A on the arc BCÙ, show that as A moves along the arc from B to M, the sums AB AC increase. Å The next theorem is very pretty, and is commonly attributed to Archimedes. 10.7 Conjecture (Archimedes’ Theorem of the Broken Chord). Let AB and BC be two chords of a circle C , where BC is greater than AB. (Such a con- figuration is sometimes called a “broken chord.”) Let M be the midpoint of arc ABC and F the foot of the perpendicular from M to chord BC. Then F is the midpoint of the broken chord, that is, AB and BF taken together are congruent to FC..
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