Chemistry 102 Summary June 18Th Ideal Gas Law: PV =

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Chemistry 102 Summary June 18Th Ideal Gas Law: PV = Chemistry 102 Summary June 18th Ideal Gas Law: PV = nRT - P = pressure (atm) - V = volume ( L) - n = number of moles (mol) - R = ideal gas constant (0.08206 Latm/molK) - T = temperature (K), where K = ˚C + 273 - The ideal gas law is the result of the discovery of three seminal laws. Development of ideal gas law: (a) Boyle’s Law: Pressure and Volume (at constant temperature and number of moles) are inversely related. - As pressure increases the volume decreases. - Mathematically PV = constant or V = constant (1/P) - Boyle’s law doesn’t hold at high pressure only at very low pressures. Question: Sketch a plot of P versus Volume? What about Volume versus 1/P? Question: Why are pressure and volume related in an inverse fashion? Consider this room - imagine the doors, windows and cracks were sealed. What would happen if the walls started to move in? Answer: (b) Charles’ Law: Volume of a gas is directly proportional to temperature at constant pressure and number of moles. - As temperature increases the volume increases. - Mathematically V = constant (T) - Temperature is in K = ˚C + 273 - Absolute zero refers to 0 K. 0 K is the lowest possible temperature and is a theoretical value that has never been reached experimentally. Question: Sketch a plot of V vs T in terms of K and in ˚C? Why are they different? Question: Why are volume and temperature directly related? Consider a balloon. Balloon: Can be thought of as a constant pressure system. A balloon expands or contracts in order for the internal pressure exerted by the gas inside the balloon to exactly equal the external atmospheric pressure. Demonstration: What will happen if liquid N2 (T = 77.2 K or -196 ˚C) is poured over a balloon? Result: Balloon collapses. - Temperature is related to the average velocity of the gas molecules. - As temperature increases, the average speed of the gas molecules increases. - When liquid N2 is poured over the balloon the temperature of the air inside of the balloon decreases, therefore the average velocity of the gas molecules also decreases. - This phenomenon leads to less forceful and less frequent collisions with the walls of the container. - This in turn leads to a decrease in pressure inside the balloon, remember the balloon is a constant pressure system, as a result there is a mismatch between the external and internal pressure and to compensate the balloon contracts. The reason for this decrease in volume is to increase the pressure inside the balloon (in other words to re-establish a match of external and internal pressures in the balloon). (c) Avogadro’s Law: At constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of a gas present. Stated in an alternative manner, equal volumes of gas contain equal moles of gas at constant temperature and pressure. - Mathematically: V = constant (n) Example: for any gas, 2L of a gas contains twice as many moles of gas as 1 L of a gas. Question: Why does Avogadro’s law hold? Consider two balloons, one is twice the size of the other, why? Answer: Remember, the pressure inside both balloons is the same. The larger balloon has more moles of gas. In order for the internal pressure to equal the external pressure, the balloon with more gas molecules must have a larger volume (larger surface area) in order for the collisions per unit area to be the same. Question (Chapter 5 #96): At STP (refers to conditions of standard pressure, 1.0 atm and temperature, 273K), 1.0 L Br2 reacts completely with 3.0 L of F2 , producing 2.0 L of a product. What is the formula of the product? (All substances are gases) Answer: - All of the work of Boyle, Charles and Avogadro is summarized into the ideal gas law: PV = nRT. Ideal Gas Law Problems 1) What will be the effect on the volume of one mole of an ideal gas if the pressure is doubled and the temperature is halved? 2) Lung capacity for a typical person is 2.0 L. If air at 20.˚C and 1.0 atm fills the lungs, how many molecules of air are present? 3) 0.30 g of a gas occupied a volume of 82.0 mL at 3.00 atm pressure at 27˚C. Calculate the molar mass of the gas. 4) Calculate the density of SF6 at STP. Dalton’s Law of Partial Pressures: For a mixture of gases in a container, the total pressure exerted is the sum of the pressures that each gas would exert if it were alone: PTOT = P1 + P2 + P3……… 1) The stopcock between a 3.0 L bulb containing oxygen at 295 torr and a 2.00 L bulb containing nitrogen at 530 torr is opened. What is the total pressure of the gas in the mixture? (Assume T remains constant) 2) A sample of N2 gas is collected over water at 20.˚C and a total pressure of 1.00 atm. The volume of gas collected is 250.0 mL. What mass of N2 is collected? (At 20.˚C the vapor pressure of water is 17.5 torr) .
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