Introduction to Renormalization Group
Alex Kovner
University of Connecticut, Storrs, CT
Valparaiso, December 12-14, 2013
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 1 / 40 QUANTUM FIELD THEORY
QUANTUM MECHANICS:
The wave function ψt (x) - probability amplitude to find a particle at point x at time t. SHROEDINGER EQUATION: d i ψ = Hψ dt
QUANTUM FIELD THEORY: A FINITE NUMBER OF QM DEGREES OF FREEDOM AT EVERY SPATIAL POINT φ(x)
WAVE FUNCTIONAL Ψt [φ(x)] - PROBABILITY AMPLITUDE DENSITY TO FIND A GIVEN FIELD CONFIGURATION φ(x) at time t. THERE IS STILL SCHROEDINGER EQUATION, BUT IT IS MUCH LESS USEFUL Ψ[φ] contains too much information, even knowing Ψ it is still hard work to get this information out. USUALLY WE ARE CONTENT WITH LESS. AS PARTICLE PHYSICISTS WE WANT SCATTERING AMPLITUDES. AS CONDENSED MATTER PEOPLE WE WANT CORRELATION FUNCTIONS. Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 2 / 40 GREEN’S FUNCTIONS
D(x1..xn)= 0|T φ(x1)...φ(xn)|0 Here |0 is the vacuum state of the theory; T is the time ordered product, which I will suppress in the following. GREEN’S FUNCTIONS TELL US MOST OF WHAT WE EVER WANT TO KNOW: SCATTERING MATRIX IS CALCULABLE FROM D′s; MUCH INFORMATION ABOUT FIELD DISTRIBUTIONS IN THE VACUUM; REACTION OF THE VACUUM TO EXTERNAL PERTURBATIONS... WE ARE ALWAYS DEALING WITH RELATIVISTIC FIELD THEORIES THIS STILL LEAVES MANY OPTIONS FOR FUNDAMENTAL FIELDS. THEY CAN BE SCALAR (SPIN 0) φ(x), FERMIONS (SPIN 1/2) ψ(x); OR VECTOR (SPIN 1) A (x). WEAlex WILL Kovner CONCENTRATE (UConn) Introduction ON SCALAR to Renormalization THEORIES Group FORDecember MOST 12-14, 2013 OF 3 / 40 CALCULATING GREEN’S FUNCTIONS
A THEORY IS DEFINED BY ITS ACTION (TAKE A SIMPLE THEORY OF ONE SCALAR FIELD)
1 1 2 2 λ 4 S = ∂ φ(x, t)∂ φ(x, t) − m φ(x, t) − φ(x, t) Zx,t h2 2 4! i FUNCTIONAL INTEGRAL APPROACH
iS n D[φ]φ(x1)...φ(xn)e D (φ(x )...φ(xn)) = 1 R D[φ]eiS INFINITELY DIMENSIONAL INTEGRAL - EASIERR SAID THAN DONE. FOR FREE FIELDS λ = 0 THE INTEGRAL IS GAUSSIAN AND EXACTLY SOLVABLE. THERE IS ONLY ONE NONTRIVIAL CONNECTED GREEN’S FUNCTION:
4 µ 2 d p −ipµx i D (x1 − x2)= e Z (2π)4 p2 − m2 + iǫ ǫ → 0 is a regulator, and although it is very important, I will disregard it most of the time.
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 4 / 40 WHEN WE TRANSLATE THIS TO THE LANGUAGE OF PARTICLES, THIS IS THE THEORY OF ONE SPECIES OF SCALAR PARTICLE WITH MASS m. THE EIGENSTATES OF THE HAMILTONIAN (IF WE WERE TO WRITE THEM EXPLICITLY) ARE STATES WITH n PARTICLES OF ARBITRARY 2 2 1/2 MOMENTUM p WITH DISPERSION RELATION Ep =(p + m ) INTERACTING THEORY: FOR WEAK COUPLING (λ ≪ 1) PERTURBATIVE CALCULATIONS USING FEYNMAN DIAGRAMS.
FEYNMAN RULES IN MOMENTUM SPACE
i For each propagator D(p)= p2−m2+iǫ a line. For each vertex iλ a cross. In order λn draw all (topologically distinct) diagramms that can be constructed from n vertices connected by propagators with given number of external points. Energy-Momentum conservation in each vertex Integrate over all loop momenta. Symmetry factors. THE RULES FOLLOW DIRECTLY FROM EXPANSION OF THE FUNCTIONAL INTEGRAL IN POWERS OF λ.
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 5 / 40 HOWEVER IF WE TRY TO CALCULATE EVEN THE SIMPLEST OF THESE GRAPHS WE FIND A PROBLEM.
= + + iλ iλ iλ
= + +permutations iλ iλ iλ THE SIMPLEST CORRECTION TO THE PROPAGATOR INVOLVES THE INTEGRAL
Λ 4 d p 1 2 λ 4 2 2 ∼ λΛ →Λ→∞ ∞ Z0 (2π) p − m THE CORRECTION TO THE FOUR POINT FUNCTION INVOLVES
Λ 4 2 2 d p 1 2 Λ λ 4 2 2 2 2 ∼ λ ln 2 →Λ→∞ ∞ Z0 (2π) (p − m )((k + p) − m ) k THE PROBLEM IS SEEMINGLY WELL POSED, THE RULES OF CALCULATION ARE WELL DEFINED, BUT OUT COME THE DIVERGENCIES. WHAT IS GOING ON? Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 6 / 40 RENORMALIZATION.
FUNDAMENTALLY THE ANSWER IS: THE PARAMETERS WE WRITE IN THE ACTION ( m AND λ) ARE NOT DIRECTLY PHYSICALLY MEASURABLE QUANTITIES. WE MEASURE MASSES OF PHYSICAL PARTICLES AND THEIR SCATTERING AMPLITUDES, RATHER THAN THE ”BARE PARAMETERS”. TO MAKE SENSE OF THE THEORY, WE HAVE TO CALCULATE PHYSICAL QUANTITIES AND REQUIRE THAT THEY ARE FINITE. THE ”BARE PARAMETERS” THEN CAN DEPEND ON THE UV CUTOFF Λ, AS LONG AS PHYSICAL OBSERVABLES DO NOT. 2 4 FOR EXAMPLE WE SHOULD CALCULATE D (p) AND D (pi ) AND EQUATE THEM TO THE QUANTITIES WE MEASURE IN THE EXPERIMENT (PARTICLE MASS AND SCATTERING AMPLITUDE), WHICH ARE OF COURSE FINITE NUMBERS. THESE ARE CALLED NORMALIZATION CONDITIONS. 2 THE BARE COUPLINGS m0 AND λ0 ARE THEN MADE CUTOFF DEPENDENT, IN SUCH A WAY THAT THE NORMALIZATION CONDITIONS ARE SATISFIED.
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 7 / 40 FOR OUR THEORY THIS SCHEMATICALLY MEANS:
m2 2 physical = m0 + + + iλ iλ iλ iλ iλ
+permutations iλphysical = iλ0 + iλ iλ Λ2 m2 = m2 + λ Λ2 + ...; λ = λ + λ2 ln + ... physical 0 0 physical 0 0 m2 2 2 THESE OBSERVABLES MUST REMAIN FINITE IN THE LIMIT Λ /mphysical → ∞. THIS SHOULD HOLD FOR ANY MOMENTUM DEPENDENT GREENS FUNCTION WHEN MOMENTUM IS MUCH SMALLER THAN THE CUTOFF Λ2/p2 → ∞. TO MAKE THESE FINITE, WE NEED 1 λ (Λ) ∼ ; m2 ∼−λΛ2 0 Λ2 0 ln m2
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 8 / 40 n A THEORY IS RENORMALIZABLE IF D (pi ) AT MOMENTA p2 ≪ Λ2 DO NOT DEPEND ON Λ. THEN THE CUTOFF CAN BE REMOVED BY SPECIFYING A FINITE NUMBER OF NORMALIZATION CONDITIONS, AND THE THEORY HAS PREDICTIVE POWER.
WHEN DOES THIS HAPPEN? PERTURBATIVE ANSWER: WHEN THE DIMENSION OF THE COUPLING CONSTANT IN UNITS OF MASS IS NONNEGATIVE: [λ] ≡ ω ≥ 0. Roughly: perturbative expansion is in powers of a dimensionless quantity λΛ−ω. If ω < 0, there are more divergencies order by order in PT and one needs infinite number of NORMALIZATION CONDITIONS to banish them all.
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 9 / 40 HAVE WE SAVED PT?
SO SUPPOSE OUR THEORY SATISFIES CONDITIONS FOR RENORMALIZABILITY. CAN WE NOW DO PT? NOT REALLY! NAIVELY THE BARE PARAMETERS HAVE CUTOFF DEPENDENCE: 1 Λ2 m2 ∼ Λ2; λ ∼ (actuallyλ ∼ ln ) 0 0 Λ2 0 m2 ln m2 IN PT WE HAVE: Λ2 Λ2 x y 2 2 λ( )= λ0 1+ λ0 ln 2 + λ0 ln 2 + ... h m m i
SO WE CANNOT CALCULATE λ( ) IN PT IN λ0. EVEN IF THEY ARE BOTH SMALL, THEY ARE NOT RELATED PERTURBATIVELY.
Alex Kovner (UConn) Introduction to Renormalization Group December 12-14, 2013 10 / 40 WHY IS THE CORRECTION SO BIG?
Λ d4p 1 Λ2 δλ(k2)= −λ2 ∼ λ2 ln Z (2π)4 p2(k − p)2 k2 THE LARGE LOGARITHM COMES FROM THE LOOP MOMENTA WHICH ARE MUCH LARGER THAN THE PHYSICAL MOMENTA AT WHICH WE WANT TO MEASURE λ; |p|≫|k|. THE CORRECTION IS LARGE NOT BECAUSE THE INTERACTION IS STRONG, BUT BECAUSE THERE IS A LOT OF PHASE SPACE TO INTEGRATE OVER. IF WE ONY INTEGRATED UP TO, SAY = 103|k|, WE WOULD GET