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Neutrino . The Basics

Milind Diwan (Brookhaven Naonal Lab.)

Summer Student Lecture BNL 7/15/2016

1 Outline

• Brief review of properties • Historical material • in the of • Neutrino interaction rules • Neutrino cross sections and interaction characteristics • Summary

This is a fast survey of various types of neutrino interactions. The intention is to provide the tools and basics to allow simple calculations. This is very much from an experimental perspective.

2 What are neutrinos ? n pe⌫¯ ! e

• A particle with no . Predicted in 1930 by Pauli, and detected in 1957 by Reines and Cowan. • It is emitted in . And has no other types of interactions. • It has 1/2 unit of , and therefore is classified as a (or particle of .) • Neutrino is extremely light. • Neutrinos are produced in flavors ! • Neutrino is left handed ! Or has no mirror image ! • Neutrinos are as numerous as in the . • Important component of . May be responsible for matter/ asym. From the : 1011 neutrinos/cm2/sec

3 Some history

• By 1930 many confusing results concerning nuclear structure - Quantum Mechanics established. BUT - Spin and statistics of odd (A-Z) nuclei is wrong if made of and . e.g. N14 (Z=7) has spin of 1. (a cannot be a + since it would then have spin of 1 or 0, but neutron was not known then) - Nuclear spin is integer for all even A and half- integer for odd A. - Why is the beta spectrum from the nucleus continuous and not quantized ?

4 spectrum ? • Nucleus spits out only single electrons. • There are no other mechanisms for energy to be lost. • There are no unaccounted gamma rays.

Bismuth 210 (beta 5 day) -> Po 210 (alpha 140 days) -> Pb 206

Po210 Alpha energy was well known at that time to be 5 MeV. After it is Confirm that only the mean subtracted in a fit, = ratio of heat from Bi210 to Po210. This gives the average energy of the Bi210 Beta well below the maximum. beta energy leads to heating. 5 Then were is rest going ? The experimental results and the understanding of the quantum mechanics could only mean either

1) No event by event energy conservation or

2) Another penetrating particle.

6 Pauli Fermi

Soon after Pauli’s observation, an almost complete theory of beta decay was developed by Fermi (1933). This theory with important modifications allows calculation of decay and interaction rates.

We will discuss the interactions first before discussing the modern understanding of the physics of neutrinos.

7 of matter

Quark Number = +1/3 Number = +1

Generation

First

Second

Third

•Stable matter is formed from the first generation only. •Fermion are created and destroyed in particle/ pairs only. • and is strictly conserved at observable energies. •There is no definitive understanding of -Generations, Charge quantization, - versus -The left/right 8 What else do we know and how do we know it ?

• Neutrinos are definitely massive with extremely small - from oscillation experiments. • Neutrino is the most abundant particle of matter with probably only 3 active types - and precision EW. • Neutrino flavor states are not described by unique mass eigenstates, but are superpositions.

direct mass limit

oscillation hint: 0.05 eV

9 Neutrinos in Cosmology • The most abundant particle is the : ~400/cc • The most abundant matter particle is the neutrino at 56/cc of each type. • CNB (1.95K) is a relic of the similar to the CMB (2.725K). Neutrinos decoupled at 2 sec while photons decoupled at ~400,000 yrs (3000 K, z~1000) • For the period before photons decoupled, neutrinos played a crucial role in the development of cosmic structures and initial burning of . • Neutrinos carry away 100 X energy in photons from core-collapse . • What is the typical wavelength of a CNB neutrino? (KB = 8.6 10-11 MeV/K)

10 Interactions of quarks and leptons

Gravity Electromagnetic Weak Strong

Boson Photon W, Z Spin/ 2+ 1- 1+,1- 1-

Mass (GeV) 0 0 80.2,91.2 0

Source mass electric charge

Range (m) ∞ ∞ 10-18 <10-15

2 2 2 4 3 Strength GM /4π�c α = e /4π�c GFM c /(�c) αs

5x10-40 1/137 1.17x10-5 <1 M = 1 GeV/c2, h = 1, c = 1, Calculate the relative strengths. There is as yet no quantum theory of , Mpl=(�c/G)1/2 11 The

gW gW �μ �μ �e e

0 W+- Z e e d u gW gW because the charge of the because the charge of the lepton and target changes lepton and target stays the same g2 G = lim w 4πα F 2 2 2 g ~ e ⇒ G ≈ q →0 (−q + M ) w F 2 W MW •q2 is the square of 4- transferred. It is always negative (Prove this). •The neutrino has only weak interactions. •Because of the large mass of W, Z, very short ranged and weak. Neutrinos cannot make bound states. •In ordinary neutrino interactions q2 can be ignored and the strength of the 2 -38 2 2 interactions (or cross section) is proportional to GF =5x10 cm /GeV •Electroweak theory relates GF , electric charge, the of the W, Z .

12 Particle Flux

Take unit volume ΔV of particles is Na per cm3 Let T = the length of track within volume V is Va relative to the target per unit time Δt

Then flux per unit area per unit time = Na x Va Then Flux = T/ΔV/Δt

As particles penetrate material slab of thickness dx, there is a reduction in the flux

x F(x) F(0)e−σρ Here λ is the mean free path and σ is the cross = section and ρ is the density of targets. But for neutrino interactions the mean free path λ = 1/ (σρ) is so long that only the flux reduction can be completely ignored and only leading term used. 13 How to calculate neutrino event rate ?

• Events = Flux (/cm2/sec)*Cross-section(cm2)*Targets • Targets are the number of particle targets in a detector volume. Detector itself serves as the target for interactions. • 1 ton of water ~ 6 x 1029 protons and and ~3x1029 electrons • Practical experiments will have efficiency as a function of energy. • Typical cross section is 10-38 cm2 x Energy (GeV) • Neutrinos from various sources have huge energy range: eV to 1015 eV. • Cross sections for low energies can be extremely small. • Calculate the mean free path of 1 GeV neutrinos through the earth. 14 Weak interactions of neutrinos

Particles of a given kind are all identical. All electrons are absolutely identical. There are no birth marks. Nevertheless, there are 3 kinds of electron type particles called flavors.

Associated Particle Symbol Mass Neutrino

Electron e 1 �e

Muon µ 200 �μ

Tau τ 3500 �τ

Negative Electrical Neutral Charged

All these have anti-particles with opposite charge. However, for neutral neutrinos the exact meaning of having anti-particles is not yet clear. 15 Neutrino creation • At creation the lepton flavor is preserved. This is known from experiments to extreme precision.

µ �e � ν µ e+ μ+ μ-

e+

+ �e ν µ �e µ ν µ e+ + e- �µ μ

Each of the numbers Le, Lµ, Lτ is conserved in an interaction. The particles get (+1) and anti-particles get (-1)

(The new understanding of neutrinos says that this is in fact violated in flight) 16 Neutrino Detection

e- μ- τ- �e �µ �τ

Recoil particles

�e �µ �τ �e �µ �τ

• The neutrino has no charge and so it is invisible as it enters a detector. Only very rarely it interacts and leaves charged particles that can be detected. • Neutrino collision on in detectors produces a charged lepton. (Charged Current) • The electron, , have very different signatures in a detector. • Neutrino can also collide and scatter away leaving observable energy.(Neutral Current) 17 Muon decay �e

W+- e+ 2 5 + + + GF mµ µ Γ(µ → e ν eν ) = τ = h / Γ = 2.197µs µ 192π 3 µ

ν µ + for anti- and - for muons

� is measured between muon x E / E spin direction and electron = e max direction. 2 d N 2 Pμ is muon ∼ x [(3− 2x) ± Pµ cosθ(2x −1)] dxd(cosθ) polarization.

• The weak integration violates parity. And one can determine that the neutrino is left handed and antineutrino is right handed. Their mirror images are not produced in weak interactions.

• The value of GF is determined by muon lifetime. Calculate GF from the measured muon lifetime and mass. What could be missing ?

• The three parameters of electro-weak interactions are: GF, α, Z0 mass. 18 Parity Violation

N + − N − !" !" P = = ±(σ i p) / E = ±β N + + N −

Weak negative for Interaction positive for anti-fermions

LH Z RH • P is polarization in which N+ are particles with spin aligned with velocity and N- are with spin opposite. σ is the spin of the particle with absolute value of 1. • Weak charged current interactions violate parity maximally. They are chiral. Only particles that have P=-β and anti-particles with P=+β have weak interactions. • Since neutrinos have only weak interactions and no mass, neutrinos are only left-handed. P = -1. now called helicity. Anti-neutrinos then have P=+1. • In extremely high energy collisions (mass is neglected) Helicity is conserved if interactions are vector or axial. Scalar interactions do not conserve helicity.

Mass is an example of an interactions that flips helicity ! • 19 Experimental data on V-A.

Polarization in beta decay versus velocity.

20 Neutrino Electron Scattering

g - - μ �μ μ �μ e W+- J = 0 Cross section should e- �e be isotropic with no g �e angular dependence in CM 2 s = (pν + pe ) µ E = (m2 − m2 ) / 2m ≈ 11GeV t = (p − p )2 = q2 = −Q2 thrs µ e e νµ µ 2 2 u = (p − p ) θ < 2 me Eµ νµ νe E − E 2 2 2 pe.q ν µ dσ (ν e → ν l) 2m E G ⎛ m − m ⎞ y = = l e = e ν F 1− µ e pe.pν Eν ⎜ ⎟ dy π ⎝ 2meE ⎠ y is the inelasticity ν 2 At high energy -s < t < 0 σ ≈ GF s π

• What is the threshold for the similar process for production ? • Why do neutrino cross sections increase with energy while Electromagnetic cross sections decrease as ~1/s? 21 Anti-Neutrino Electron Scattering μ- ν μ- e ν e e- g g

W- e- J= 1, Jz = 1 ν µ ν µ There can be no backscattering. Only one spin projection is allowed

2 2 2 dσ (ν ee → νll) 2meEνGF ⎛ 2 mµ − me ⎞ = ⎜ (1− y) − (1− y)⎟ dy π ⎝ 2meEν ⎠ σ ≈ G2 s 3π F When y=1 all incoming kinetic energy is lost from the beam neutrino. • Helicity plays a central role in determining cross sections of neutrinos versus anti-neutrinos. Cross section is reduced by factor 3.

Think through the cross sections if the scattering is off . • 22 Neutrino Electron Elastic ν gL Fermion gL gR �μ �μ Neutrino +1/2 0 0 Z electron, muon, tau -1/2+Sin2�W Sin2�W

up type quarks +1/2-2/3Sin2�W -2/3Sin2�W - - e e e e gL,gR down type quarks -1/2+1/3Sin2�W +1/3Sin2�W

M 2 v e e 2 W J = 0 term Sin θW = 1− = 0.223 gV = 2gL (gL + gR ) 2 M Z v e e J = 1 term gA = 2gL (gL − gR ) 2 dσ meGF Ev ⎡ 2 2 2 2 2 mey ⎤ (ν µe) = ⎢(gV + gA ) + (gV − gA ) (1− y) − (gV − gA ) ⎥ dy 2π ⎣ Ev ⎦ 2 dσ meGF Ev ⎡ 2 2 2 2 2 mey ⎤ (ν µe) = ⎢(gV − gA ) + (gV + gA ) (1− y) − (gV − gA ) ⎥ dy 2π ⎣ Ev ⎦ • In neutral current scattering both Left and Right charged particles contribute. The contribution of the Right is proportional to the weak mixing: Sin2�W. • Here y is now defined as the fraction of energy lost to the electron. 23 • Plot the angular distribution of the first two terms. Recall (�2 < 2me/Ee) 1 4 ν + e− → ν + e− ⇒ + sin2 θ + sin4 θ = 0.54 e e 4 W 3 W 1 1 4 ν + e− → ν + e− ⇒ + sin2 θ + sin4 θ = 0.22 e e 12 3 W 3 W 1 ν + e− → ν + µ− ⇒ e µ 3 − − ν µ + e → ν e + µ ⇒ 1 1 4 ν + e− → ν + e− ⇒ − sin2 θ + sin4 θ = 0.093 µ µ 4 W 3 W 1 1 4 ν + e− → ν + e− ⇒ − sin2 θ + sin4 θ = 0.075 µ µ 12 3 W 3 W

2G2 m E σ = F e v = 1.72 ×10−41 cm2 GeV−1 × (E / GeV ) 0 π v

The cross sections are small due to the target mass of the electron. The first two cross sections have both charged and neutral current components. 24 (IBD) + ν e + p → e + n

Constants can be ) 2 obtained from 8 neutron beta decay Vector/ cm Fermi 6 -42 Axial/Gamow-Teller 4 2 2

GF |Vud | 2 2 (10 σ σ (E ) = ( f + 3 f )E p 2 ν 2π V A e e −42 2 2 0 = 0.0952 ×10 Ee pe (cm / MeV ) 0 2 4 6 8 10 Neutrino Energy (MeV)

• Vector term is forward in angle, Axial term is backwards. Overall slightly backwards.

• Threshold is due to (n-p) mass difference and positron mass. Eth = 1.806 MeV • Only works for free proton targets and electron anti-neutrinos. No analog for electron neutrinos since there are no free neutrons ! • Neutrino Energy = Detected Energy - 2 electron mass + 1.806 MeV.

25 Very low energy nuclear cross sections

− ν e + (N,Z) → e + (N −1,Z +1) + ve + (N,Z) → e + (N +1,Z −1)

Ethr ~ M f − M i + me

−43 σ ~ 10 Ee peF(Z f ,Ee )(2J f +1)

Coulomb corrections

Exact calculation depends on type of transition: Fermi, G-T, forbidden, etc. Archive: 1205.6003 • Low energy cross sections on nuclear targets poorly measured ( errors ±20%) • Needed for elemental abundances and supernova physics. • Muon and Tau neutrinos below threshold for CC reactions <100 MeV • There can be gammas from de-excitation of nuclear final states. NC reactions only have de-excitation gammas as signature. • 26 Quasi-elastic Scattering

− ν µ + n → µ + p + ν µ + p → µ + n

The data have inconsistencies because nuclear effects are still a work-in-progress.

A single parameter is used to characterize MA ~ 1 GeV.

• The vector(L+R) and axial(L-R) scattering amplitudes become much more complicated on nuclei at low energies because of the internal structures.

2 • The simple gV , gA are replaced by form factors that depend on the Q or the momentum transfer of the reaction. • The cross sections are much larger because they are now proportional to the mass. • If the can be treated as free, calculate the neutrino energy in terms of muon E,� 27 Cross sections at a few GeV

Nucleon intact

Nucleon Excited

Nucleon Breaks up

Cross section prediction for various processes add up to exhibit a linear dependence of the total cross section on E

• The intermediate energy range has many final states. Many of these have not been measured well. • This modeling is an active part of the field as new data becomes available. (List all � and anti-� nucleon single producing modes.) 28 Deep Inelastic Scattering g �μ μ- 0.677+-0.014 W+-

g*Vckm xP P{ X 0.334+-0.008

y = Ehad / Eν −q2 Q2 x ≡ = 2P i q 2M N Ehad 2 2 Q = −mµ + 2Eν i (Eµ − pµ Cosθµ )

2 2 2 dσ (νq) / dy ∝ GF M N xEν dσ (ν q) / dy ∝ GF M N xEν (1− y) •In case of high energies, the scattering is off quarks in the nucleons. •But quarks carry only some fraction of the nucleon momentum. In the ‘infinite momentum frame’ it is shown to be ~x. •Since scattering is off mostly quarks, the y distributions follow the usual rule for � and anti-�, but the total ratio differs from 1/3 because of the sea -anti-quarks. 29 Very High Energies

CC −36 2 0.363 σ νN ≈ 5.53×10 cm (Eν / GeV ) NC −36 2 0.363 σ νN ≈ 2.31×10 cm (Eν / GeV )

There is a resonance due to formation of the W only for

− − ν e + e → νl + l 2 Eres = MW / 2me = 6300TeV

Gandhi et al, Astroparticle Phys. 5, 81, 1996 • > 106 GeV, the cross sections do not grow linearly. • � and anti-� cross sections are nearly identical. Why? Uncertainties arise from quark/antiquark distributions. • 30 Tau neutrino interactions

ντ + N → τ + X

Eth = 3.5GeV

Tau lepton properties.

mass = 1.777 GeV −13 τ life = 2.3×10 sec

~17% of the decays are to a single muon +neutrinos and ~17% to electron and neutrinos. Formaggio/Zeller RevModPhys.84.1307

• CC interactions of the tau neutrino are suppressed due to the high energy threshold. (Calculate the threshold).

Tau decays to low multiplicity states making it difficult to identify. • 31 Conclusion

• This lecture was about the basics of neutrino interacons. • The basics have been known since the 1980s. • Knowledge of interacons on complex nuclei is not yet precise. This will be needed in the future. • Very low energy interacons also have very important applicaons for . • In the next lecture I will describe the technology of detectors for these measurements.

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