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Number 100 Application Note Low Current Series

induced by the burden (or drop) across the entire amme- Basic Current Measurements ter model, and the of the meter itself. In a typical circuit (see Figure 1a), a source causes a current (I) to flow through the circuit. The goal of any electrical current With measurements of currents in the normal range (typi- is to insert an in series with the circuit so cally >1mA), errors caused by ammeter voltage burden, that the current measured on the ammeter is identical to the cur- currents, and noise current are often small enough to be ignored. rent originally flowing through the circuit. To do so, the circuit In these cases, the displayed current reading is simply equal to is broken between points A and B, and the meter is connected the actual current plus or minus inherent meter uncertainty, (UM). as shown in Figure 1b. In the ideal case, the meter would have Meters designed to measure these normal currents generally con- absolutely no effect on the circuit. For practical measurements, sist of a circuit that measures the across however, several error sources may be present. These error a shunt inserted in the series with the circuit being mea- sources can result in substantial uncertainty in the measurement, sured. (See the discussion on shunt that follows.) The as we will now discuss. reading provided by the voltmeter is thus directly proportional to the current flow. Any ammeter can be modeled to consist of the three sepa- rate circuit elements shown in Figure 1b: a shunt resistance (RSH) Unfortunately, the voltage burden (input voltage drop) pro- caused by the input cable connected to the meter; a generator of duced by such meters usually ranges from 200mV to about 2V. unwanted current (IC), which represents mainly currents generat- This voltage drop is sufficient to cause errors with current mea- ed by interconnections; and an internal resistance (RM), which surements below the normal range. To avoid such large voltage includes series cable resistance. Note that RM is in series with an drops, picoammeters and use a high gain amplifier ideal ammeter (MI), having no resistance or of with negative feedback for the input stage. As a result, the volt- its own. age burden is greatly reduced—on the order of 200µV or less. This low voltage burden reduces both measurement errors and Figure 1a: A source the minimum shunt cable resistance that must be maintained to causes a current (I) to Cable Shunt Generated Meter and Internal Resistance Currents Resistance flow through a wire provide a given meter accuracy. Consequently, no special mea- between A and B. sures need be taken to obtain unusually high cable resistance. RS IM RS A Typical picoammeters or electrometers that employ feed- IS I Ð15 I SH IC RM back ammeters generally provide sensitivities to 1fA (10 A) or V V V RSH M less and typical accuracy of 0.1% to 3%.

MI B

V I = Circuit Under Test Ammeter Shunt vs. Feedback Ammeters RS Equivalent Circuit Equivalent Circuit V VM ± IM = ISH IC UM There are two basic techniques for making low current measure- RS RS ments: the shunt method, and the feedback ammeter technique. Indicated Current Voltage Shunt Generated Meter Current to be Burden Current Current Uncertainty The shunt configuration is used primarily in DMMs (digital multi- Measured Error Error Error meters) and in older electrometers where cable causes Figure 1b: When an ammeter and connecting cable are used in place of a wire, a voltage burden (VM) is developed, which forces problems in the feedback mode. Picoammeters and newer elec- a shunt current (ISH) through the shunt resistance (RSH) of trometers use only the feedback ammeter configuration. The major the cable. Unwanted error currents (IE) are also generated due to various phenomena discussed in the text. difference between picoammeters and electrometers is that elec- trometers are multifunction instruments, while picoammeters mea- When the ammeter is connected in the circuit to be meas- sure only current. Also, a typical may have several ured, the current indicated on the meter is equal to the current decades better current sensitivity than the typical picoammeter. that would flow through the circuit without the ammeter inserted in the circuit, less errors caused by elements in the circuit model. Shunt Picoammeter These errors consist of current flowing through the model shunt Shunting the input of an electrometer voltmeter with a resistor resistance, currents generated by the interconnections, errors forms a shunt ammeter, as shown in Figure 2. The input current (I ) develops an input Circuit analysis shows that: IN Figure 2: Shunt ammeter voltage EIN across the E E + I R = E E = ÐAE , and E = Ð _____OUT shunt resistance OUT IN F IN OUT IN IN A (R ) as follows: – SHUNT A E 1 + _____OUT __ EIN = IINRSHUNT Thus, EOUT + IINRF = Ð and EOUT 1 + = ÐIINRF IIN RA A ( A ) Note that the voltage _____EOUT sensitivity of the circuit RSHUNT EIN E OUT Since A>>1, E = ÐI R and |E | = << E OUT IN F IN A OUT is controlled both by R B Note that the the value of RSHUNT Figure 4: Feedback ammeter with and the relative values amplifier gain can be selectable voltage gain changed as in the volt- of R and R . Thus, R A B RA + RB F E OUT = IIN RSHUNT R meter circuit, using the the output voltage ()B I IN combination shown in (EOUT) is given by: Figure 4. In this case, – R +R R +R A ______A B ______A B + EOUT = EIN = IINRSHUNT RA and RB are R R R ( B )(B ) added to the feedback A EIN Although it might appear advantageous to use a larger loop, forming a multi- E OUT value for RSHUNT, there are actually several good reasons why plier. The gain of the RB RSHUNT should be made as small as possible. First, low value circuit is determined by resistors have better and stability, and a better the feedback resistor voltage coefficient than high value resistors. Second, low resistor and by the relative val- EOUT = –I RF (1 + RA + RB) values reduce the input time constant and result in faster instru- ues of RA and RB and ment response . Finally, for circuit loading considerations, is given as follows: the input resistance RSHUNT of an ammeter should be small to ______RA +RB reduce the voltage burden EIN. EOUT = ÐIINRF ( RB ) However, using an electrometer (or any voltmeter) on its EOUT most sensitive range introduces noise and zero drift into the and again, E = Ð _____ IN A measurement. In contrast, Johnson noise current decreases as the value of RSHUNT increases. Thus, some compromise between these two opposing requirements is usually necessary. Choosing Sources of Current Errors a 1Ð2V full-scale sensitivity and the appropriate shunt resistance Errors in current-measuring instruments arise from extraneous value is often a good compromise. currents flowing through various circuit elements. In the model Feedback Picoammeter circuit of Figure 5, the current (IM), indicated on the meter, is actually equal to the current (I ) through the meter, plus addition- Figure 3 shows the 1 Figure 3: Feedback ammeter al meter uncertainty (U ). I is the signal current (I ), less shunt general configuration M 1 S current (I ) and the sum of all generated currents (I ). of a feedback type SH E ammeter. In this config- IIN RF Figure 5: Sources of current errors uration, the input cur- – A I rent (IIN) flows into the S Input E IN + E OUT Output input terminal of the I1 I1 = IS – ISH – IE amplifier (A), and it also flows through the VII I R I I feedback resistor (R ). SE CE SH RE IE F E OUT = –IINRF The low offset current M of the amplifier changes the current (IIN) by a negligible amount. Current Source IE = ISE + ICE + IRE + IIE Thus, the output voltage is a measure of the input current, IS = Source current RSH = Shunt resistance ISE = Source noise current IRE = Shunt resistance noise I = Interconnection noise current I = Instrument error current and sensitivity is determined by the feedback resistor (RF). The CE IE low voltage burden (EIN) and corresponding fast rise time are achieved by the high gain operational amplifier, which forces The circuit model shown in Figure 5 identifies various E to be nearly zero. IN noise and error currents generated during a typical current measurement. The ISE current generator represents noise currents generated within the source itself. These currents could arise due Figure 7: Piezoelectric effect to leakage, piezoelectric, or triboelectric effects, or through dielectric absorption. Applied Force Metal Terminal Similarly, the ICE current generator represents currents gen- I erated in the interconnection between the meter and the source + circuit. The same sources that generate noise currents in the cir- I cuit under test may produce noise in the interconnection. IRE is generated by the thermal activity of the shunt resistance and the rms value of the noise current and is given by: –– I = 4kTf/R RE SH Piezoelectric + Insulator Conductive Plate where: k = Boltzman’s constant (1.38 × 10Ð23J/K) T = absolute temperature in K Noise currents f = noise bandwidth in Hz Figure 8: Electrochemical effects also arise from electro- RSH = resistance in Printed chemical effects, which Wiring Epoxy Printed Circuit Board Since peak-to-peak noise is about five times the rms value, the are shown in Figure 8. noise current can be ignored when measuring currents above 10Ð14A. Here, chemicals cause or other Finally, I is the specified sum of error currents in the weak batteries between chemical IE I “track” and . two conductors on a + moisture circuit board. For – Noise Currents example, commonly I

The noise current generators ICE, ISE, and IIE in the above model used epoxy printed cir- represent unwanted currents generated at a particular point in the cuit boards can gener- circuit. These currents may arise from triboelectric, piezo-elec- ate currents of several nanoamps when not thoroughly cleaned of tric, and electrochemical effects, or from resistive leakage or etching solution, flux, or other material. To prevent these error dielectric absorption. currents, all interconnecting circuitry should be thoroughly cleaned using a cleaning such as methanol, and then be Triboelectric currents (shown in Figure 6) are generated allowed to dry completely before use. by charges created at the interface between a conductor and an insulator due to friction. Here, free electrons rub off the conduc- Dielectric absorption can occur when a voltage applied tor and create a charge imbalance that causes a current flow. A across an insulator causes positive and negative charges within typical example would be electrical currents generated by insula- that insulator to polarize. When the voltage is removed, the sepa- tors and conductors rubbing together in a coaxial cable. Special rated charges generate a decaying current through external cir- low noise coax and triax cables are available to minimize cuitry as they recombine. The effects of dielectric absorption can this problem. be minimized by avoiding the application of more than a few volts to insulators to be used for sensitive current measure- Figure 6: ments. If this practice is unavoidable, it may take minutes or even hours in some cases for currents caused by dielectric Frictional motion I at boundary due to I absorption to dissipate. cable motion ++ Inner Figure 9 summarizes approximate magnitudes of the vari- Insulation Conductor ous current-generating effects. –– Figure 9: Typical magnitudes of currents generated by low current phenomena

10–7 A 10–8 Outer Outer Dirty Jacket Shield 10–9 cable surface 10–10 Epoxy Coaxial Conductive board Cable lubricant in 10–11 low noise cable 10–12 Clean Low noise surface cable 10–13 Piezoelectric currents (Figure 7) are generated when 10–14 Teflon 109Ω

Typical Current Generated Typical –15 10 12 mechanical stress is applied to certain insulating materials. These Ceramics 10 Ω currents are generated in ceramics and other crystalline materials Triboelectric Mechanical Electrochemical Resistor Effects Stress Effects noise in 1Hz used for insulating terminals and interconnecting hardware. Effects bandwidth Similar stored charge effects occur in many plastics. Current-Generating Phenomena Guarding Another way to reduce the effects of leakage currents is to guard the connection between the diode and the picoammeter so High resistance paths between low current conductors and near- that it is completely surrounded by a conductor connected to the by voltage sources can cause significant leakage currents, which same potential (+15V in this example). The resulting configura- can be eliminated through guarding. Basically, guarding uses a tion is shown in Figure 10c. Since a typical feedback pico- conductor at the same potential as the sensitive current path to ammeter has a maximum voltage burden of only 200µV, the totally surround the input leads carrying the high impedance sig- voltage across RL is reduced to that value, and the leakage cur- nals. This guard conductor is driven by a low impedance source, rent now becomes: and maintaining the conductor at the same potential as the high- impedance source results in drastically reduced leakage currents ≤ ______200µV IL from those leads. 1GΩ ≤ × Ð13 For example, assume that an ammeter is to be used to IL 2 10 A (0.2pA) measure the current ID through the diode shown in Figure 10a. Thus, IL is reduced by four decades and is likely to be If the meter (a picoammeter or electrometer ammeter) is con- insignificant compared to I . nected in series with the diode (Figure 10b), it will measure not D only the diode current (ID), but also the leakage current (IL) that The current flowing through RG is still 15nA, but it is now flows through the leakage resistance path (RL). If RL has a value supplied by the low impedance +15V source, and it does not of 1GΩ (109Ω, a reasonable value for many insulators), the leak- present a problem since it is not measured by the ammeter. age current (I ) would be 15nA (assuming a 15V potential across L Another situation where guarding is beneficial is shown in the circuit, as shown). Figure 11a. In this case, the leakage resistance of a coaxial cable Obviously, the large value of leakage current would whose shield is grounded will reduce the output voltage of a obscure the actual diode leakage current (ID), which is typically high resistance source, as shown in Figures 11a and 11b. Note much lower than 15nA in modern diodes. One way to solve the that voltage actually measured by the high impedance voltmeter Ω problem is to increase the leakage resistance (RL) to 1T , is attenuated by the formed by the source reducing IL to 15pA, which still may be large compared to ID. resistance (RS) and the leakage resistance (RL).

Figure 10a: A diode whose Figure 10b: An ammeter Figure 11a: A high resistance source is to be measured by a reverse current ID is to be measures both ID and IL, high impedance voltmeter. measured. the leakage current.

+15V +15V Source HI RL

RS High R1 R1 I I = IDL + I Impedance I I E O D D Voltmeter E S LO R = 15V R R L I = = 15nA 2 2 1GΩ L 1GΩ

RS Figure 11b: Equivalent circuit of Figure 10a R Figure 10c: By guarding the input to the picoammeter, I is greatly L L showing loading effect of E S RL EROS EO = ES reduced, and the picoammeter measures I accurately. ()RL + R S D the connecting cable resistance R . +15V L

I I = I D Figure 11c: A guarded configuration for the same measurement. R1 ≈ ID No current flows through RL since EG = EO ES.

+ E lectrometer ≤ Voltmeter RL = IL 0.2pA HI R RL – HI 2 1GΩ X1 or Preamp RS Output E O GUARD E G E S I Ω 15V G RG RG = 1G IG = = 15nA 1GΩ LO LO If instead, the shield is connected to a low impedance Figure 12: Constant voltage method for measuring high resistance source of the same potential as the high resistance source, such as the unity-gain or preamp output of an electrometer voltmeter R (Figure 11c), leakage from the center conductor to the shield will vanish, since there is essentially no potential across the insu- HI lator (RL). Leakage current (IG) from the outer guard shield to V IM ground may be considerable, but it is of no consequence since the current is supplied by the low impedance preamp output LO rather than by the high impedance source. Although the main advantage of guarding is in the reduc- tion of leakage resistance effects, another is the reduction of effective input capacitance. Measurement rise time depends both resulting current is measured by the ammeter and the resistance on the equivalent source resistance and the effective meter input is calculated using ’s Law (R = V/I). capacitance, which depends both on the electrometer input Because high resistance is often a function of the applied capacitance and the connecting cable capacitance. Thus, for high resistance measurements, even a small amount of cable capaci- voltage, this method is preferred compared to the constant cur- tance can result in very long rise times. For example, an input rent method. By testing at several voltages, a resistance vs. capacitance of 1,000pF (including the input cable) and a resis- voltage curve can be developed and a “voltage coefficient of tance of 200GΩ results in a time constant of 200 seconds, and resistance” can be determined. Some of the applications that use 1,000 seconds (more than 16 minutes) must be allowed for the this method include testing two-terminal high resistance devices, measurement to settle to within 1% of final value. measuring insulation resistance, and determining the and surface resistivity of insulating materials. Modern electrometers, such as the Models 6514, 6517A, and 6430, have built-in provisions to take full advantage of The constant voltage method requires using an electrome- guarding. In the guarded mode, the effective cable capacitance ter ammeter, so all the techniques and errors sources apply to this can be reduced to about 20pF, speeding up measurements by a method. One common error source when making high resistance factor of 50. measurements is due to the leakage resistance of the cables and fixturing. Two methods for eliminating fixture leakage are guard- ing and baseline suppression. High Resistance Measurements Baseline Suppression When resistances >1GΩ must be measured, an electrometer is usually required. An electrometer may measure high resistance Although the constant voltage method is suitable for measuring by either the constant voltage or the constant current method. very high resistance values and is quite fast, some care should be Some electrometers allow the user to choose either method. The taken to suppress any leakage currents present in the system. constant voltage method utilizes the electrometer ammeter and a Otherwise, any leakage current adds to the test current, reducing voltage source, while the constant current method uses the elec- resistance measurement accuracy. Such leakage currents can be trometer voltmeter and a current source. A description of these nulled out by using baseline suppression. techniques follows. Consider the test circuit shown in Figure 13. In this instance, the test resistance is removed from the system, and any Constant Voltage Method leakage current flowing through RLEAKAGE is measured by the To make high resistance measurements using the constant voltage meter as ILEAKAGE. At this point, the current suppression feature method, an electrometer ammeter or picoammeter and a constant of the meter is enabled to null out the leakage current. voltage source are required. Some electrometers and picoamme- ters have voltage sources built into the instrument and can Figure 13: Leakage resistance (RLEAKAGE) causes a current (ILEAKAGE) automatically calculate the resistance. This section describes this to flow. method and ways to reduce the leakage resistance due to test ILEAKAGE fixturing when making these measurements. HI Basic Configuration RLEAKAGE VS IM The basic configuration of the constant voltage method is shown in Figure 12. In this method, a constant voltage source (V) is LO placed in series with the unknown resistor (R) and an electrome- ter ammeter (IM). Since the voltage drop across the ammeter is Voltage Source negligible, essentially all the voltage appears across R. The Figure 14: Baseline suppression cancels leakage current. Guarding and Capacitive Effects

IR To minimize shunt currents, most electrometer amplifiers include IR + ILEAKAGE a guard connection to their amplifier outputs. Since the guard RS output is a unity-gain output, the voltage potential across insula- tors connected between the input terminal and guard is essential- HI RLEAKAGE ly zero. In general, the same techniques used to minimize VS IM leakage current in low current measuring situations can minimize LO these effects in high resistance measurements. One additional source of error in high resistance measure- ments is parasitic capacitance, normally associated with cables Voltage Source and connectors. At high resistance levels, even a few picofarads of stray capacitance can significantly affect circuit rise times and VS VS IR Without suppression: RM = = thus the settling time required for accurate measurements. For IM IR IR + ILEAKAGE example, a 10TΩ (1013Ω) resistance and a cable capacitance of VS VS With suppression: R = = 100pF results in an RC time constant of 1,000 seconds. Since M I – I I M LEAKAGE R five time constants are required for the circuit to settle to within 1%, more than 80 minutes would be required for the circuit to If we connect the DUT for measurement (Figure 14), the settle adequately. resistance can then be determined based on the present measured Guarding a high resistance measurement reduces the current and the suppressed leakage current previously deter- effects of stray capacitance considerably. The effective capaci- mined: tance is reduced by a factor equal to the open-loop gain of the ______VS amplifier—typically from 104 to 106. RS = IM Ð ILEAKAGE Common Rule for Low Current Connections Example: Assume that VS = 10V, IM = 11pA, and ILEAKAGE = 1pA. Without suppression, the measured resistance is: Always connect the high resistance (HI) terminal of the 10V picoammter or electrometer to the point of highest resistance in R = ______= 909GΩ the circuit under test. Figure 15a shows the correct connections, S 11pA while Figure 15b shows incorrect connections. With suppression, the measured resistance is: 10V R = ______= 1TΩ Figure 15: Proper connections for current measurements S 11pA Ð 1pA RX RX Thus, we see that suppression eliminates an error of about 9% in HI LO this example. Voltage pA Voltage pA Source Source LO HI

a. CORRECT b. INCORRECT Electrometer/Picoammeter Selector Guide Model Features Input Connection Current Voltage Resistance Charge

1 Ω 17Ω 6430 6 ⁄2 digits. 0.4fAp-p noise. Banana, 50aAÐ100mA Source 5µVÐ200V Source 10µ Ð10 Voltage/Current Sources 3-lug Triax 10aAÐ100mA Measure 1µVÐ200V Measure with Measurement. IEEE-488/RS-232 programmable.

18 6517A 61⁄2 digits. Autoranging. Low cost. 3-lug Triax 100aAÐ20mA 10µVÐ200V 10µΩÐ10 Ω 10fC–2µC Analog Output. 1000V Source. IEEE-488/RS-232 programmable.

6514 61⁄2 digits. Low cost. 3-lug Triax 100aAÐ20mA 10µVÐ200V 10mΩÐ200GΩ 10fC–20µC Autoranging. Analog Output. IEEE-488/RS-232 programmable.

6485 51⁄2 digits. Autoranging. Low cost. BNC 10fAÐ20mA IEEE-488/RS-232 programmable.

486 51⁄2 digits. Autoranging. 3-lug Triax 10fAÐ2mA IEEE-488/RS-232 programmable.

487 51⁄2 digits. Autoranging. 3-lug Triax 10fAÐ2mA 500V Source. IEEE-488/RS-232 programmable. 428 Current Amplifier BNC 1fAÐ16mA

Test System Safety Many electrical test systems or instruments are capable of measuring or sourcing hazardous voltage and levels. It is also possible, under single fault conditions (e.g., a programming error or an instrument failure), to output hazardous levels even when the system indicates no hazard is present. These high voltage and power levels make it essential to protect operators from any of these hazards at all times. Protection methods include: ¥ Design test fixtures to prevent operator contact with any haz- ardous circuit. ¥ Make sure the device under test is fully enclosed to protect the operator from any flying debris. ¥ Double insulate all electrical connections that an operator could touch. Double insulation ensures the operator is still protected, even if one insulation layer fails. ¥ Use high-reliability, fail-safe interlock switches to disconnect power sources when a test fixture cover is opened. ¥ Where possible, use automated handlers so operators do not require access to the inside of the test fixture or have a need to open guards. ¥ Provide proper training to all users of the system so they understand all potential hazards and know how to protect themselves from injury. It is the responsibility of the test system designers, integra- tors, and installers to make sure operator and maintenance per- sonnel protection is in place and effective. Specifications are subject to change without notice. All Keithley trademarks and trade names are the property of Keithley Instruments, Inc. All other trademarks and trade names are the property of their respective companies.

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