Shape Rotational Inertia, I I = M1r + M2r + ... (Point Masses) I = ∫ R Dm
Chs. 10 - Rotation & Angular Motion Dan Finkenstadt, finkenst@usna.edu October 26, 2015 Shape Rotational Inertia, I I one aspect of shape is the center of mass I How difficult is it to spin an object about (c.o.m.) any axis? I another is how mass is distributed about the I Formulas: (distance r from axis) c.o.m. 2 2 I = m1r1 + m2r2 + ::: I an important parameter describing shape is called, (point masses) 1. Rotational Inertia (in our book) Z 2. Moment of Inertia (in most other books) I = r2 dm (solid object) 3.2 nd Moment of Mass (in engineering, math books) Solution: 8 kg(2 m)2 + 5 kg(8 m2) + 6 kg(2 m)2 = 96 kg · m2 P 2 Rotational Inertia: I = miri Two you should memorize: Let's calculate one of these: I mass M concentrated at radius R I = MR2 I Disk of mass M, radius R, about center 1 I = MR2 solid disk 2 Parallel Axis Theorem Active Learning Exercise Problem: Rotational Inertia of Point We can calculate the rotational inertia about an Masses axis parallel to the c.o.m. axis Four point masses are located at the corners of a square with sides 2.0 m, 2 I = Icom + m × shift as shown. The 1.0 kg mass is at the origin. What is the rotational inertia of the four-mass system about an I Where M is the total mass of the body axis passing through the mass at the origin and pointing out of the screen I And shift is the distance between the axes (page)? I REMEMBER: The axes must be parallel! What is so useful about I? Rotation I radians! It connects up linear quantities to angular I right-hand rule quantities, e.g., kinetic energy angular speed v ! = rad r s I v = r! 2 2 I ac = r! 1 2 1 2v 1 2 mv ! mr ! I! ang.
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