CC Geometry H AJ Is

Total Page:16

File Type:pdf, Size:1020Kb

CC Geometry H AJ Is Aim #9: How do we construct a perpendicular bisector? CC Geometry H Do Now: Using the angle below: 1. Bisect the angle. Label the bisector BD. 2. Construct a copy of ≮DBC using vertex B'. A B C B' Relevant Vocabulary Two lines are PERPENDICULAR ( ) if they intersect in one point, and any of the angles formed by the intersection of the lines is a __________ angle. (Two segments or rays are perpendicular if the lines containing them are .) The MIDPOINT of a segment divides a segment into 2 = or _____ parts. A SEGMENT BISECTOR passes through the ____________ of a segment. An ANGLE BISECTOR is a ray (line/segment) that divides an _____ into 2 = or ≅ parts. AJ has been constructed as the angle bisector of ≮BAD. B • Draw BD. • Label C, the point of intersection of BD and AJ. A J Notice: (1) BC = CD so C is a ________________. D Therefore AJ is a ______________ of BD. (2) ≮BCA = ≮DCA. Each of these angles measures____. Therefore, BD and AJ are _______________. AJ is the __________________ ____________________ of BD. The perpendicular bisector of a line segment passes through the ________________ of the segment and forms ___________ angles with the segment. (It is perpendicular to a segment at its midpoint.) Using a compass and straightedge, we will now construct a perpendicular bisector of a line segment. Experiment with your construction tools and the following line segment to establish the steps that result in the perpendicular bisector. [Use what you know about constructing an equilateral triangle.] http://www.mathsisfun.com/geometry/construct­linebisect.html A B Steps for constructing a perpendicular bisector: 1. Draw circle A: center A, radius > 1/2AB and circle B: center B, radius > 1/2BA. 2. Label the points of intersections as C and D. 3. Draw CD. Construct the perpendicular bisector of CD. • Label the midpoint M and label the perpendicular bisector as EF. • Name one right angle:__________. C D Relevant Vocabulary: EQUIDISTANT A point A is said to be equidistant from two different points B and C if AB = AC. Draw a diagram. CDE is the perpendicular bisector of AB. (C, D, and E are collinear points.) Using your compass, what conclusion can you make about the following pairs of segments? 1) AC and BC equal, circle C with rad. CA goes through pt B. 2) AD and BD equal, circle D with rad. DA goes through pt B. 3) AE and BE equal, circle E with rad. EA goes through pt B. Based on your findings, fill in the observation below. Any point on the perpendicular bisector of a line segment is _____________________ from the endpoints of the line segment. Why? Any circle we constructed w/a center on the perp. bisector and a radius that passed through one endpt, also passed through the other endpt. All radii of a circle are equal, so these segments must be equal. Now construct a perpendicular line to line l from a point X not on line l . The steps of the construction have been outlined below for you. X l Step 1: Draw circle X so that the circle intersects line l in two points. Step 2: Label the two points of intersection as B and C. Step 3: Draw circle B: center ____, radius ______. Step 4: Draw circle C: center ____, radius ______. Step 5: Label the unlabeled intersection of circle B and circle C as D. Step 6: Draw the perpendicular bisector: line _______. Exercises 1. Divide segment AB into 4 segments of equal length. A B 2. Construct parallel lines l1 and l2 as follows: Step 1: Construct line l3 which will be perpendicular to line l1 from point A Step 2: Construct line l2 which will be perpendicular to l3 through point A. (Hint: This is the same as bisecting a straight angle.) A l1 3. Here is another method for constructing a line parallel to a given line through a point not on the line, not using perpendicular lines. Using the construction for copying an angle, construct a line parallel to line L through point P. P L 4a) Construct the perpendicular bisector of BC. b) Construct the angle bisector of ≮B. C A B Sum it Up!! A perpendicular bisector of a segment passes through the ______________ofmidpoint the segment and forms ________right angles with the segment. (Mark the diagram to show this.) A A point A is said to be equidistant from two different points B and C if AB = AC. B C (Mark the diagram to show this.) Name ______________________ CC Geometry H Date ________________ HW #9 1. Construct the perpendicular bisector of the segment below. A B 2. Construct the line perpendicular to line l through point A. List all the steps necessary to complete the construction. A l 3. Construct the perpendicular bisectors of AB, BC , and CA on the triangle below. What do you notice about the segments you have constructed? A B C 4. Two homes are built on a plot of land. Both homeowners have dogs, and are interested in putting up as much fencing as possible between their homes on the land, but in a way that keeps the fence equidistant from each home. Use your construction tools to determine where the fence should go on the plot of land. 5. How will the fencing alter with the addition of a third home? Review 1. In ΔABC, ≮B = ≮C. If AB = x2 + 8x, BC = 3x + 5 and AC = 20, find the perimeter ΔABC. 2. In the diagram below, ≮BCA = 8x – 15, ≮DBC = 2x + 12 and ≮BDC = 4x + 9. Find m≮BCD. .
Recommended publications
  • Models of 2-Dimensional Hyperbolic Space and Relations Among Them; Hyperbolic Length, Lines, and Distances
    Models of 2-dimensional hyperbolic space and relations among them; Hyperbolic length, lines, and distances Cheng Ka Long, Hui Kam Tong 1155109623, 1155109049 Course Teacher: Prof. Yi-Jen LEE Department of Mathematics, The Chinese University of Hong Kong MATH4900E Presentation 2, 5th October 2020 Outline Upper half-plane Model (Cheng) A Model for the Hyperbolic Plane The Riemann Sphere C Poincar´eDisc Model D (Hui) Basic properties of Poincar´eDisc Model Relation between D and other models Length and distance in the upper half-plane model (Cheng) Path integrals Distance in hyperbolic geometry Measurements in the Poincar´eDisc Model (Hui) M¨obiustransformations of D Hyperbolic length and distance in D Conclusion Boundary, Length, Orientation-preserving isometries, Geodesics and Angles Reference Upper half-plane model H Introduction to Upper half-plane model - continued Hyperbolic geometry Five Postulates of Hyperbolic geometry: 1. A straight line segment can be drawn joining any two points. 2. Any straight line segment can be extended indefinitely in a straight line. 3. A circle may be described with any given point as its center and any distance as its radius. 4. All right angles are congruent. 5. For any given line R and point P not on R, in the plane containing both line R and point P there are at least two distinct lines through P that do not intersect R. Some interesting facts about hyperbolic geometry 1. Rectangles don't exist in hyperbolic geometry. 2. In hyperbolic geometry, all triangles have angle sum < π 3. In hyperbolic geometry if two triangles are similar, they are congruent.
    [Show full text]
  • A Historical Introduction to Elementary Geometry
    i MATH 119 – Fall 2012: A HISTORICAL INTRODUCTION TO ELEMENTARY GEOMETRY Geometry is an word derived from ancient Greek meaning “earth measure” ( ge = earth or land ) + ( metria = measure ) . Euclid wrote the Elements of geometry between 330 and 320 B.C. It was a compilation of the major theorems on plane and solid geometry presented in an axiomatic style. Near the beginning of the first of the thirteen books of the Elements, Euclid enumerated five fundamental assumptions called postulates or axioms which he used to prove many related propositions or theorems on the geometry of two and three dimensions. POSTULATE 1. Any two points can be joined by a straight line. POSTULATE 2. Any straight line segment can be extended indefinitely in a straight line. POSTULATE 3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center. POSTULATE 4. All right angles are congruent. POSTULATE 5. (Parallel postulate) If two lines intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. The circle described in postulate 3 is tacitly unique. Postulates 3 and 5 hold only for plane geometry; in three dimensions, postulate 3 defines a sphere. Postulate 5 leads to the same geometry as the following statement, known as Playfair's axiom, which also holds only in the plane: Through a point not on a given straight line, one and only one line can be drawn that never meets the given line.
    [Show full text]
  • Geometry Course Outline
    GEOMETRY COURSE OUTLINE Content Area Formative Assessment # of Lessons Days G0 INTRO AND CONSTRUCTION 12 G-CO Congruence 12, 13 G1 BASIC DEFINITIONS AND RIGID MOTION Representing and 20 G-CO Congruence 1, 2, 3, 4, 5, 6, 7, 8 Combining Transformations Analyzing Congruency Proofs G2 GEOMETRIC RELATIONSHIPS AND PROPERTIES Evaluating Statements 15 G-CO Congruence 9, 10, 11 About Length and Area G-C Circles 3 Inscribing and Circumscribing Right Triangles G3 SIMILARITY Geometry Problems: 20 G-SRT Similarity, Right Triangles, and Trigonometry 1, 2, 3, Circles and Triangles 4, 5 Proofs of the Pythagorean Theorem M1 GEOMETRIC MODELING 1 Solving Geometry 7 G-MG Modeling with Geometry 1, 2, 3 Problems: Floodlights G4 COORDINATE GEOMETRY Finding Equations of 15 G-GPE Expressing Geometric Properties with Equations 4, 5, Parallel and 6, 7 Perpendicular Lines G5 CIRCLES AND CONICS Equations of Circles 1 15 G-C Circles 1, 2, 5 Equations of Circles 2 G-GPE Expressing Geometric Properties with Equations 1, 2 Sectors of Circles G6 GEOMETRIC MEASUREMENTS AND DIMENSIONS Evaluating Statements 15 G-GMD 1, 3, 4 About Enlargements (2D & 3D) 2D Representations of 3D Objects G7 TRIONOMETRIC RATIOS Calculating Volumes of 15 G-SRT Similarity, Right Triangles, and Trigonometry 6, 7, 8 Compound Objects M2 GEOMETRIC MODELING 2 Modeling: Rolling Cups 10 G-MG Modeling with Geometry 1, 2, 3 TOTAL: 144 HIGH SCHOOL OVERVIEW Algebra 1 Geometry Algebra 2 A0 Introduction G0 Introduction and A0 Introduction Construction A1 Modeling With Functions G1 Basic Definitions and Rigid
    [Show full text]
  • Points, Lines, and Planes a Point Is a Position in Space. a Point Has No Length Or Width Or Thickness
    Points, Lines, and Planes A Point is a position in space. A point has no length or width or thickness. A point in geometry is represented by a dot. To name a point, we usually use a (capital) letter. A A (straight) line has length but no width or thickness. A line is understood to extend indefinitely to both sides. It does not have a beginning or end. A B C D A line consists of infinitely many points. The four points A, B, C, D are all on the same line. Postulate: Two points determine a line. We name a line by using any two points on the line, so the above line can be named as any of the following: ! ! ! ! ! AB BC AC AD CD Any three or more points that are on the same line are called colinear points. In the above, points A; B; C; D are all colinear. A Ray is part of a line that has a beginning point, and extends indefinitely to one direction. A B C D A ray is named by using its beginning point with another point it contains. −! −! −−! −−! In the above, ray AB is the same ray as AC or AD. But ray BD is not the same −−! ray as AD. A (line) segment is a finite part of a line between two points, called its end points. A segment has a finite length. A B C D B C In the above, segment AD is not the same as segment BC Segment Addition Postulate: In a line segment, if points A; B; C are colinear and point B is between point A and point C, then AB + BC = AC You may look at the plus sign, +, as adding the length of the segments as numbers.
    [Show full text]
  • Historical Introduction to Geometry
    i A HISTORICAL INTRODUCTION TO ELEMENTARY GEOMETRY Geometry is an word derived from ancient Greek meaning “earth measure” ( ge = earth or land ) + ( metria = measure ) . Euclid wrote the Elements of geometry between 330 and 320 B.C. It was a compilation of the major theorems on plane and solid geometry presented in an axiomatic style. Near the beginning of the first of the thirteen books of the Elements, Euclid enumerated five fundamental assumptions called postulates or axioms which he used to prove many related propositions or theorems on the geometry of two and three dimensions. POSTULATE 1. Any two points can be joined by a straight line. POSTULATE 2. Any straight line segment can be extended indefinitely in a straight line. POSTULATE 3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center. POSTULATE 4. All right angles are congruent. POSTULATE 5. (Parallel postulate) If two lines intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. The circle described in postulate 3 is tacitly unique. Postulates 3 and 5 hold only for plane geometry; in three dimensions, postulate 3 defines a sphere. Postulate 5 leads to the same geometry as the following statement, known as Playfair's axiom, which also holds only in the plane: Through a point not on a given straight line, one and only one line can be drawn that never meets the given line.
    [Show full text]
  • Lesson 5: Three-Dimensional Space
    NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 5 M3 GEOMETRY Lesson 5: Three-Dimensional Space Student Outcomes . Students describe properties of points, lines, and planes in three-dimensional space. Lesson Notes A strong intuitive grasp of three-dimensional space, and the ability to visualize and draw, is crucial for upcoming work with volume as described in G-GMD.A.1, G-GMD.A.2, G-GMD.A.3, and G-GMD.B.4. By the end of the lesson, students should be familiar with some of the basic properties of points, lines, and planes in three-dimensional space. The means of accomplishing this objective: Draw, draw, and draw! The best evidence for success with this lesson is to see students persevere through the drawing process of the properties. No proof is provided for the properties; therefore, it is imperative that students have the opportunity to verify the properties experimentally with the aid of manipulatives such as cardboard boxes and uncooked spaghetti. In the case that the lesson requires two days, it is suggested that everything that precedes the Exploratory Challenge is covered on the first day, and the Exploratory Challenge itself is covered on the second day. Classwork Opening Exercise (5 minutes) The terms point, line, and plane are first introduced in Grade 4. It is worth emphasizing to students that they are undefined terms, meaning they are part of the assumptions as a basis of the subject of geometry, and they can build the subject once they use these terms as a starting place. Therefore, these terms are given intuitive descriptions, and it should be clear that the concrete representation is just that—a representation.
    [Show full text]
  • Perpendicular and Parallel Line Segments
    Name: Date: r te p a h Perpendicular and C Parallel Line Segments Practice 1 Drawing Perpendicular Line Segments Use a protractor to draw perpendicular line segments. Example Draw a line segment perpendicular to RS through point T. S 0 180 10 1 70 160 20 150 30 140 40 130 50 0 120 180 6 0 10 11 0 170 70 20 100 30 160 80 40 90 80 150 50 70 60 140 100 130 110 120 R T © Marshall Cavendish International (Singapore) Private Limited. Private (Singapore) International © Marshall Cavendish 1. Draw a line segment perpendicular to PQ. P Q 2. Draw a line segment perpendicular to TU through point X. X U T 67 Lesson 10.1 Drawing Perpendicular Line Segments 08(M)MIF2015CC_WBG4B_Ch10.indd 67 4/30/13 11:18 AM Use a drawing triangle to draw perpendicular line segments. Example M L N K 3. Draw a line segment 4. Draw a line segment perpendicular to EF . perpendicular to CD. C E F D © Marshall Cavendish International (Singapore) Private Limited. Private (Singapore) International © Marshall Cavendish 5. Draw a line segment perpendicular to VW at point P. Then, draw another line segment perpendicular to VW through point Q. Q V P W Line Segments 68 and Parallel Chapter 10 Perpendicular 08(M)MIF2015CC_WBG4B_Ch10.indd 68 4/30/13 11:18 AM Name: Date: Practice 2 Drawing Parallel Line Segments Use a drawing triangle and a straightedge to draw parallel line segments. Example Draw a line segment parallel to AB . A B 1. Draw a pair of parallel line segments.
    [Show full text]
  • Properties of Straight Line Segments
    Properties of straight line segments mc-TY-lineseg-2009-1 In this unit we use a system of co-ordinates to find various properties of the straight line between two points. We find the distance between the two points and the mid-point of the line joining the two points. In order to master the techniques explained here it is vital that you undertake plenty of practice exercises so that they become second nature. After reading this text, and/or viewing the video tutorial on this topic, you should be able to: • find the distance between two points; • find the co-ordinates of the mid-point of the line joining two points; Contents 1. Introduction 2 2. The distance between two points 3 3. Themidpointofthelinejoiningtwopoints 5 www.mathcentre.ac.uk 1 c mathcentre 2009 1. Introduction In this unit we use a system of co-ordinates to find various properties of the straight line between two points. We find the distance between the two points and the mid-point of the line joining the two points. Let’s start by revising some facts about the coordinates of points. Suppose that a point O is marked on a plane, together with a pair of perpendicular lines which pass through it, each with a uniform scale. We shall label the lines with the letters x and y, and we call them the x and y axes. The fixed point O is called the origin, and it is the intersection point of the two axes. This is shown in Figure 1. y A(x, y) y x O x Figure 1.
    [Show full text]
  • Solutions to Exercises
    Solutions to Exercises Solutions to Chapter 1 exercises: 1 i 1.1: Write x =Re(z)= 2 (z + z)andy =Im(z)=− 2 (z − z), so that 1 i 1 1 ax + by + c = a (z + z) − b (z − z)+c = (a − ib)z + (a + bi)z + c =0. 2 2 2 2 − a Note that the slope of this line is b , which is the quotient of the imaginary and real parts of the coefficient of z. 2 2 2 Given the circle (x − h) +(y − k) = r , set z0 = h + ik and rewrite the equation of the circle as 2 2 2 |z − z0| = zz − z0z − z0z + |z0| = r . 1.2: A and S1 are perpendicular if and only if their tangent lines at the point of intersection are perpendicular. Let x be a point of A ∩ S1, and consider the Euclidean triangle T with vertices 0, reiθ,andx. The sides of T joining x to the other two vertices are radii of A and S1,andsoA and S1 are perpendicular 1 if and only if the interior angle of T at x is 2 π, which occurs if and only if the Pythagorean theorem holds, which occurs if and only if s2 +12 = r2. 1.3: Let Lpq be the Euclidean line segment joining p and q. The midpoint of 1 Im(q)−Im(p) Lpq is 2 (p + q), and the slope of Lpq is m = Re(q)−Re(p) . The perpendicular 1 − 1 Re(p)−Re(q) bisector K of Lpq passes through 2 (p + q) and has slope m = Im(q)−Im(p) , and so K has the equation 1 Re(p) − Re(q) 1 y − (Im(p) + Im(q)) = x − (Re(p) + Re(q)) .
    [Show full text]
  • Notes on Hyperbolic Geometry
    Notes on Hyperbolic Geometry Henry Y. Chan July 2, 2013 1 Introduction For people who have taken real calculus, you know that the arc length of a curve in R2 γ :[a; b] ! R2, where γ (t) = (x (t) ; y (t)), is defined as s Z b dx2 dy 2 s = + dt: a dt dt The reason behind this formula is that locally we have (∆s)2 ∼ (∆x)2 + (∆y)2 by the Pythagorean Theorem. More precisely, when “∆t ! 000, we get (ds)2 = (dx)2 + (dy)2 : The differential ds is called the arc length element, or the Riemannian metric, of R2. The Riemannian metric introduced above is called the standard Euclidean metric. One might wonder whether there exists other kinds of metric on R2. In fact, given a positive definite form (ds)2 = a (x; y)(dx)2 + b (x; y) dxdy + c (x; y)(dy)2 (positive definite means that b2 − 4ac > 0 for all x; y), ds allows us to measure arc lengths along curves, and thus allows us to measure the \distance" between two points, i.e. a metric, and to determine the distance minimizing curves, called geodesics. Remark 1.1. In the standard Euclidean metric, the geodesics are straight lines. (You can prove this using the triangle inequality.) Definition 1.2. If (M; d) is a metric space, an isometry is a function f : M ! M such that d (f (x) ; f (y)) = d (x; y) for all x; y 2 M. 1 Proposition 1.3. Isometries send geodesics to geodesics. Proof. This is immediate from the definition of isometries.
    [Show full text]
  • Intermediate Math Circles March 25, 2009 Analytic Geometry I
    1 University of Waterloo Centre for Education in Faculty of Mathematics Mathematics and Computing Intermediate Math Circles March 25, 2009 Analytic Geometry I Analytic Geometry is the use of a coordinate system to translate a geometry problem into an alge- braic problem. Analytic Geometry is NOT using angle theorems, similar triangles, and trigonometry. Instead we will be using points and equations for lines. To solve problems using analytic y l geometry we have to understand the basics: A The coordinate system we will be using is the Cartesian coordinate system, the x xy-plane. Our problems will consist of us- B ing the cartesian plane along with points, lines and line segments. From the diagram, A and B are the points corresponding to the coordi- nates (3; 2) and (−1; −3) respectively. l is the line passing through points A and B. AB is the line segment with endpoints A and B. The difference between a line and a line segment is that a line segment has a fixed length. These are the tools we will be using to solve problems in analytic geometry. Distance Between Points For many problems we need to know the distance between two points, the length of a line segment. If d is the distance between two points A(x1; y1) and B(x2; y2) then: p 2 2 d = (x2 − x1) + (y2 − y1) Example: Find the distance between points A and B above. Solution: We have the points A(3; 2) and B(−1; −3). Substituting into our formula gives us, 2 p p p 2 2 d = (−1 − 3) + (−3 − 2) = 16 + 25p = 41 Therefore line segment AB has length 41.
    [Show full text]
  • Hyperbolic Geometry—Introduction the Basics of the Half-Plane Model
    Hyperbolic Geometry|Introduction The basics of the half-plane model of hyperbolic geometry are explored. Now that we know a lot about general geometry, what can we do that is not Euclidean| where we don't need the parallel postulate? In fact, what can we do to show that the parallel postulate is necessary in order to distinguish Euclidean geometry from something else? Imagine living in a 2-dimensional universe that is in the half-plane y > 0, but where distances are warped. The stretching factor is inversely proportional to the distance from the x-axis. So, if it takes one minute to talk from (0; 1) to (1; 1) along the horizontal line segment then it would take only 30 seconds to walk from (0; 2) to (1; 2) while going from (0; 1=3) to (1; 1=3) takes 3 minutes. This may look strange from the outside, but remember that we are inside this crazy plane, so our rulers and our legs shrink and stretch so that these distances look perfectly normal to us. This is called the hyperbolic plane. One of the more interesting things to note is that you really shouldn't travel along horizontal line segments to get from one place to another. This is because if you bow your trip a little north, you may stretch your legs to be long enough to more than make up for the extra (Euclidean) length you are covering. In fact, it turns out the geodesics in this wacky plane are pieces of circles! Specifically, if we are given two points (x1; y1) and (x2; y2): • If x1 = x2 so that the points are separated only vertically, then the geodesic between them is the vertical line segment, and the distance between them is j ln (y2=y1)j.
    [Show full text]