GRAND TEST-6 Sri Chaitanya IIT Academy, India A.P, TELANGANA, KARNATAKA, TAMILNADU, MAHARASHTRA, DELHI, RANCHI A right Choice for the Real Aspirant ICON CENTRAL OFFICE, MADHAPUR-HYD Sec: Sr.IPLCO/IC/ISB/LIIT Dt: 24-04-16 Time: 09:00 AM to 12:00 Noon Max.Marks: 222
Name of the Student: ______I.D. NO: PAPER-I 24-04-16_ Sr.IPLCO/IC/ISB/LIIT_GTA-6_Weekend Syllabus Mathematics : Total Syllabus
Physics : Total Syllabus
Chemistry : Total Syllabus Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper JEE-ADVANCED-New Model -3–P1 Time: 09.00 AM to 12.00 Noon IMPORTANT INSTRUCTIONS Max Marks: 222 PHYSICS: +Ve - Ve No.of Total Section Question Type Marks Marks Qs marks Sec – I(Q.N : 1 – 10) Questions with Single Correct Choice 4 -2 10 40 Questions with Comprehension Type Integer Sec – II(Q.N : 11 – 16) (3 Comprehensions – 2 +2+2 = 6Q) 3 -1 6 18 Sec – III(Q.N : 17 – 20) Matrix Matching Type 4 -2 4 16 Total 20 74 MATHEMATICS: +Ve - Ve No.of Total Section Question Type Marks Marks Qs marks Sec – I(Q.N : 21 – 30) Questions with Single Correct Choice 4 -2 10 40 Questions with Comprehension Type Integer Sec – II(Q.N : 31 – 36) (3 Comprehensions – 2 +2+2 = 6Q) 3 -1 6 18 Sec – III(Q.N : 37 – 40) Matrix Matching Type 4 -2 4 16 Total 20 74 CHEMISTRY: +Ve - Ve No.of Total Section Question Type Marks Marks Qs marks Sec – I(Q.N : 41 – 50) Questions with Single Correct Choice 4 -2 10 40 Questions with Comprehension Type Integer Sec – II(Q.N : 51 – 56) (3 Comprehensions – 2 +2+2 = 6Q) 3 -1 6 18 Sec – III(Q.N : 57 – 60) Matrix Matching Type 4 -2 4 16 Total 20 74
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 2 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper PHYSICS Max Marks : 74 Section-1 (Only one Option correct Type) This section contains 10 Multiple Choice questions. Each Question has Four choices (A), (B), (C) and (D). Out of Which Only One is correct 1. Prem and Kumar are playing tug-of-war. Prem wins, pulling Kumar into mud. Why did Prem win? A) Prem exerted a greater horizontal component of force on the rope than Kumar exerted. B) The rope exerted a greater horizontal component of force on Kumar than it exerted on Prem. C) Prem exerted a greater horizontal component of force on the ground than Kumar exerted. D) All of the above. 2. An equilateral triangular plate, sides of length b, has a triangle, formed by two corners and the centre of gravity of the original plate, removed. Determine the distance of centre of gravity of the remaining plate from the base of removed triangle. 2 1 b b b 2b A) 3 3 B) 3 3 C) 3 D) 3
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 3 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 3. Which of the following statements about X - rays is incorrect?
A) EEEEEKLKMK (E indicates the energy of photon) B) For the harder X-rays, the intensity is always higher than soft X-rays C) The continuous and characteristic X-rays differ only in the method of creation
D) The cut-off wavelengthmin , depends only on the accelerating voltage applied between the target and the filament. 4. Two hollow-core solenoids, A and B, are connected by a wire and separated by a large distance, as shown in the diagram. Two bar magnets, 1 and 2, are suspended just above the solenoids. If the magnet 1is dropped through solenoid A as shown, then the magnet 2 will simultaneously be
A) Attracted by a magnetic force towards solenoid B B) Repelled by a magnetic force away from solenoid B C) Repelled by an electric force away from solenoid B D) Unaffected by solenoid B. Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 4 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 5. A non-standard vernier callipers has 10 V.S.D coinciding with 7 M.S.D, with each M.S.D equal to 1 mm. The scale has a maximum measurable length of 100 MSD. If 14th M.S.D. is found to coincide with 4th V.S.D, where does the zero of vernier lie? Assume no zero error. A) Between 10th and 11th M.S.D. B) Between 11th and 12th M.S.D. C) Between 9th and 10th M.S.D. D) Exactly on the 10th MSD 6. Given system is released from rest at the position shown in figure . Later on B collides with A and the collision is head on and elastic .After collision A attains
maximum height 1.25 m from its initial position. The value of m0 is
A) 10 kg B) 2 kg C) 8 kg D) 5
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 5 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 7. Which of the following statement is incorrect. A) An object at the focus of a convex lens always produces image at infinity. B) Newton’s second law is not valid in non-inertial frame of reference. C) The velocity of a charged particle may not be always along the direction of applied field. D) In a standing wave formed on a string, in fundamental mode, there is at least a point on string which always has zero potential energy change all the time. 8. A ray is incident on the first prism at an angle of incidence 53º as shown in the
figure. The angle between side CA and BA for the net deviation by both the prisms to be double of the deviation produced by the first prism, can be
1 2 1 2 1 2 1 2 A) 2sin B) sin C) cos D) 2cos 3 3 3 3
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 6 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 9. The streamline flow of a viscous liquid through a capillary tube of radius r due dp to a pressure gradient applied across the tube can be measured by its dx dp volume flow rate Q, which is given by Q C1 r , where C1,,, , are dx dimensionless constants and is the coefficient of viscosity of the liquid. A viscous liquid flows in a streamlined manner through a capillary tube A of radius r, the pressure gradient across it being P , and the corresponding volume flow rate being Q. If the same liquid flows in a streamline through another capillary r tube B of radius , and the pressure gradient across this tube is 2P , the 2 volume flow rate through this tube is Q Q A)4Q B) Q C) D) 4 8 10. Five bulbs A,B,C,D and E with power ratings 50W, 75W, 40 W ,60W and 100 W respectively , at household supply are connected as shown in figure .Which bulb will consume least power (Neglect variation of resistance with temperature)
A) B B) C C) D D) E
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 7 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Section-2 (Paragraph Type With Integer ) This section contains 6 Integer Type questions relating to three paragraphs with two questions on each paragraph. The answer to each of the questions is a single-digit integer, ranging from 0 to 9. For each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero mark if no bubbles are darkened. In all other cases, minus one (-1) mark will be awarded Paragraph for Questions 11 & 12: Steinmetz Solid is the name given to the shape formed from the intersection of two right circular cylinders. Assume the axis of two cylinders are perpendicular. The material density is uniform. Each Cylinder is made of material of density 6 -3 10 kgm and radius R 3 cm . The region of intersection of the two cylinders is considered as shown in figure ii.
Fig: i
Fig : ii
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 8 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 11. The mass of the portion formed as shown in fig-ii is 24 x kg. Find x. 12. The moment of inertia of the shape formed in Fig. ii, about the axis perpendicular to the axis of both the cylinders and passing through the point of 2 intersection of the natural axis cylinders is 1920 x kg mm . Find x. Paragraph for Questions 13 & 14: A positive point charge of charge q 1C and mass m 0.2 kg is projected perpendicular to a uniform constant magnetic field B 2 T which is present all over the space. The magnetic field is directed into the plane of the paper. A rigid elastic wall is present at an angle of 60 to the imaginary dotted line as shown in figure. The length of the wall is 6.5 m. The point charge is projected with a velocity V 10 ms1 perpendicular to the dotted line and is at a distance of 1m from the tip O.[Ignore gravity]
O
Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 9 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 13. The time period of motion of the point charge is approximately n seconds
(take 3.14 ). 14. What is the ratio of maximum time between two collisions to the minimum time between two collisions. Paragraph for Questions 15 & 16: Bohm Aharonov effect : Consider a YDSE experiment done with electrons
The debroglie hypothesis says that electrons behave like waves and so in presence
of double slit, they show interference pattern as shown by dotted line.
But if we introduce a thin strip (w< electrons trajectory would bend by a small angle and so the central maxima shifts up by a distance y . This shift can be easily shown to depend on magnetic field B, charge q, width w, the momentum of electron p, slit distance d and L. Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 10 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper The same result can be derived using principles of quantum mechanics. In quantum mechanics we cannot talk about definite path. So we cannot talk about bending of electron trajectory. There it is found that on passing thorough the region of magnetic field, the electron waves undergo a phase change. So the electron wave coming from upper slit and that from lower slit have a phase difference. Interestingly the path difference resulting from this phase difference predicts the same shift of central maxima y as does the classical theory using magnetism 15. The value of y according to classical physics, if electron momentum is 10-25 -8 kgm/s B=1T, w =10 m, L =1m ,d=500 nm is 4 x mm .Find x 16. In a typical set up, electrons a momentum of 1025 kg m/s, B = 1T, w = 10-8m, L = 1m at what minimum value of d(in nm) will central point be a minimum ? (Take h = 6.4 × 10-34Jsec) Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 11 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Section-3 (Matching List Type) This section contains four questions, each having two matching lists (List-1 & List-II). The options for the correct match are provided as (A), (B),(C) and (D) out of which ONLY ONE is correct. 17. There are two points A and B inside a liquid at constant heights from the bottom as shown in figure. Now the vessel starts moving upwards with an acceleration ‘a’. Match the following : A B Column I Column II (a) Pressure at B will (p) Increase (b) Pressure difference between A and B (q) Decrease will (c) Up thrust on an object inside the (r) remain same vessel will (d) If water continuously leaks through (s) decreases to orifice at bottom then pressure at B atmospheric pressure (t) None of these A) A- ps, B –R, C-qr, D-rs B) A- p, B –p, C-p, D-qs C) A- ps, B –ps, C-ps, D-qs D) A- p, B –rs, C-p, D-qs Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 12 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 18. P-V diagram for cyclic process is shown in column I. (P is pressure of gas, V is volume of gas). Heat absorbed by the gas is Q and work done by the gas is W in the cyclic process. Match the following Column I Column II (a) (p) Qcycle > 0 (b) (q) Qcycle < 0 (c) (r) Wcycle > 0 Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 13 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper (d) (s) Wcycle < 0 A) A- rp, B –sq, C-qs, D-pr B) A- qs, B –ps, C-pr, D-qr C) A- sq, B –rq, C-sq, D-rs D) A- rs, B –qr, C-ps, D-qs 19. Seven identical blocks each of mass 10 kg are arranged as shown in fig. Coefficient of friction between any two surfaces is 0.5. In Column – I numbers of blocks removed from the arrangement at t = 0 are given and in Column – II motion of the block 4 is given. Match the following for the first 32 s of motion in each case. Given that F10 t t 32 s Newton. At t = 0 the system is at rest. (g = 10 ms-2) 1 2 3 4 7 5 6 F Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 14 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Column – I Column – II a) 7 p) rest b) 7, 1 q) uniform velocity c) 7, 1, 2 r) non-uniform velocity d) 7, 1, 2, 3 s) uniform acceleration t) non-uniform acceleration A) A- prt, B –prt, C-prt, D-prst B) A- pqrt, B –pqrt, C-pqrt, D-pqrs C) A- pqrt, B –pqrt, C-pqrt, D-pqrts D) A- prst, B –prst, C-prst, D-prst 20. Figure shows a car moving towards right. Wind is blowing in direction of motion of car. Car emits a horn of frequency f0 , velocity of sound is C .Velocity of wind is small as compared to source. Position of horn is assumed to be midway between observer 3 and 4 .Source and all listeners are assumed to be along same line and sound waves are plane waves. Four observers have been shown in diagram match column –I with column –II Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 15 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Column -I Column –II C f A) Observer –I P) Wavelength received from horn is more than 0 C f B) Observer –II Q) Wavelength received from horn is less than 0 f C) Observer –III R) Frequency received from horn is greater than 0 f D) Observer –IV S) Frequency received from horn is smaller than 0 f T) Frequency received from horn is equal to 0 A) A- qr, B –ps, C-pt, D-qt B) A- qs, B –pr, C-qt, D-pt C) A- t, B –t, C-t, D-t D) A- qr, B –ps, C- qt, D- pt Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 16 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper MATHEMATICS Max Marks : 74 Section-1 (Only one Option correct Type) This section contains 10 Multiple Choice questions. Each Question has Four choices (A), (B), (C) and (D). Out of Which Only One is correct 1 1 1 1 sin x 1 cos x 1 sin x 21. Let x (sin 1,1) and t1 sin x , t2 sin x , t3 cos x and 1 1 cos x t4 cos x , then a) t1 t 2 t 3 t 4 b) t4 t 3 t 1 t 2 c) t t t t d) t t t t 1 2 4 3 3 4 1 2 22. Let f(x) =sin2x sin 2 x 2cos sin x sin x .Which of the following is TRUE ? a) f(x) is strictly increasing in x , b)f(x) is strictly decreasing in x , c) f(x) is strictly increasing in x , and strictly decreasing in x , 2 2 d) f(x) is a constant function 23. Area bounded by the curve yln x tan1 x and x –axis from x =1 to x = 2 , is 5 1 5 1 a) ln2 ln5 2tan1 2 1 b) ln2 ln5 2tan1 2 1 2 2 3 2 2 4 5 1 5 1 c) ln2 ln5 2tan1 2 1 d) ln2 ln5 2tan1 2 1 2 2 4 2 2 4 Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 17 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 24. If areas of triangles OAB,, OBC ODC are 1,3,6 square units respectively , then the area of triangle AOD in the figure given below is a) 5 b) 3 c) 3 d) 2 2 2 25. Image of the curve xy = 1 in the curve x x2 1 y y 2 1 1 ( on coordinate plane ) is 2 2 a) xy =1 b) xy +1 =0 c) xy =0 d) x y 1 x y 1 26. If gradient of a curve at any point P x, y is and it is passes through 2y 2 x 1 origin, then curve is 3x 3 y 2 3x 3 y 2 a) 2 x 3 y ln b) x3 y ln 2 2 3x 3 y 2 c) 3y x ln 3 x 2 y 1 d) 6y 3 x ln 2 Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 18 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 11 1 x1 log3 9 7 1 27. If ninth term in the expansion of 33 is 660 , then the value of 1 x1 log3 3 1 38 x is a) 4 b) 1 or 2 c) 0 or 1 d) 3 28. In which of the following interval Rolle’s theorem hold(s) good for 1 1 f x x2sin x 3 cos ? x2 x 1 2 1 1 1 1 1 3 a) , b) , c) , d) , 3 2 x3 y 1 z 2 29. The plane containing the line is rotated through an angle / 2 2 4 5 about this line to contain the point (4,3,7) .The equation of plane before rotation is a) 4x 8 y 8 z 4 b) 4x 8 y 8 z 4 c) x2 y 2 z 1 d) x2 y 2 z 1 ln x I( k ) dx , k 0 30. Let 2 2 and k I(k) –I (1) = then value of k is 0 x kx k 3 1 a) b) 3 c) e 3 d) e3/2 3 Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 19 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Section-2 (Paragraph Type With Integer ) This section contains 6 Integer Type questions relating to three paragraphs with two questions on each paragraph. The answer to each of the questions is a single-digit integer, ranging from 0 to 9. For each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero mark if no bubbles are darkened. In all other cases, minus one (-1) mark will be awarded Paragraph For Questions 31 & 32 1 2 0 T P 2 1 0 There exists a matrix Q such that PQP N , where 0 0 1 Given N is a diagonal matrix of form N = diag ( n1,, n 2 n 3 ) where n1,, n 2 n 3 are three values of n satisfying the equation det P nI 0, n1 n 2 n 3 [Note : - I is an identity matrix of order 3x3 ] 31. The value of det (adj N) is equal to [Note : - adj M denotes the adjoint of a square matrix M .] 32. If QQIT , then the value of is equal to Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 20 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Paragraph For Questions 33 & 34 Consider two quadratic polynomials as P X x2 2 x a 2 15 a 27 Q x x2 3 b x b , where a,b R 33. If graph of y =P(x) lies above and below the x-axis , then the largest integral value of a is K, where K is equal to 3 34 If minimum value of Q(x)is positivie then sum of all integral values of b is P, where P equal to 5 Paragraph For Questions 35 & 36 Let M be the maximum value of c2 for which O(0,0) and A(1,1) does not lie on 2 opposite side of the straight line a b x ab bc ca 1 y 2 0 for all a, b R . st rd Also lx my n 0 be a variable line, where l , m,n are 1 ,3 and 7th terms of an arithmetic progression and the variable straight line always passes through a fixed point P , 35. If the circles x2 y 2 M 1and x2 y 2 24 x 10 y 2 0 have exactly two common tangents , then the number of possible integral values of is N, where N 5 is equal to 36. The tangent of the circle x2 y 2 M 2at the point 1, 1 also touches the circle x2 y 2 4 x 2 y 20 0 then its point of contact is (a,b), where a+b is equal to Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 21 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Section-3 (Matching List Type) This section contains four questions, each having two matching lists (List-1 & List-II). The options for the correct match are provided as (A), (B),(C) and (D) out of which ONLY ONE is correct. 37. The complex numbers z1 ,z 2 ...... z n represent the vertices of a regular polygon of n sides, inscribed in a circle of unit radius and z3 z n Az 1 Az 2 , x be the greatest integer x . Then Column-I Column-II (When n equals to) Then A (A) 16 (p) 0 (B) 6 (q) 1 (C) 8 (r) 2 (D) 12 (s) 3 A) A-q,B-r,C-q,D-q B) A-p,B-q,C-s,D-r C) A-q,B-p,C-r,D-s D) A-q,B-q,C-r,D-r Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 22 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 38. Match the following: Column – I Column II (A) The maximum value of (p) cos (cos 1) sin(cos x) + cos (sin x), x , is 2 2 (B) The minimum value of (q) 1 + cos 1 sin(cos x) + cos (sin x), x , is 2 2 (C) The maximum value of (r) cos 1 cos (cos(sin x)) is (D) The minimum value of (s) 1 + sin 1 cos(cos (sin x)) A)A-s,B-p,C-r,D-r B) A-s,B-r,C-p,D-r C) A-p,B-s,C-q,D-r D) A-r,B-p,C-q,D-s Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 23 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 39. Let f x be a real valued function defined by minimum { f t : 2 t x }, x [ 2,0) f x x2 2 x and g x maxmi um { f t :0 t x }, x 0,3 Column-I Column-II A) g x is not continuous at x equal to p) -2 B) g x is not derivable at x equal to q) 0 C) Number of integral critical points of r) 1 g x is equal to D) Absolute maximum value of g x is equal to s) 2 t) 3 A) A-qs,B-qr,C-p,D-t B) A-qr,B-qs,C-p,D-t C)A-q,B-qs,C-t,D-t D) A-q,B-qr,C-p,D-t Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 24 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 40 Match the Column-I with Column-II : Column – I Column – II A) If the roots ZZZ1,, 2 3 of the equation p) 1 Z3 Z 2 mZ 1 0 lies on Z 1 and ZZZ13 2 3 3 3 20 then ...... B) AZZZ / 2 2 2 Z 1 BZ/ arg q) 3 Z 2 CZZ / arg 1 Then number of elements of ABC 2 C) If 1, 5 1 then log 1 2 3 r) 0 3 D) Eccentricity of the conic represented by s) 2 m ZZ3 3 9 is then n n Where G.CD m, n 1 A) A-s,B-r,C-s,D-q B) A-r,B-s,C-p,D-q C) A-q,B-p,C-s,D-r D)A-s,B-r,C-s,D-p Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 25 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper CHEMISTRY Max Marks : 74 Section-1 (Only one Option correct Type) This section contains 10 Multiple Choice questions. Each Question has Four choices (A), (B), (C) and (D). Out of Which Only One is correct – 41. The calomel cell Hg, Hg2Cl2/Cl (aq) values of electrode oxidation potentials are plotted at different log[Cl–] variation is represented by A) B) C) D) 42. 100ml of H2SO4 solution having molarity 1M & density 1.5 gm/ml is mixed with 400ml of water. Resultant molarity of H2SO4 solution (density = 1.25 gm/ml) is A) 4.4 M B) 0.145 M C) 0.227 M D) None Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 26 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 43. Which of the following is correct decreasing order of solubility of AgCl ? I) In water II) 0.1M NaCl III) 0.1M BaCl2 IV) 0.1M NH3 A) III > II > I > IV B) IV > I > II > III C) I > IV > II > III D) I > II > III > IV 44. A person having osteoporosis (Defficiency of calcium) is suffering from lead poisioning Ethylene diamine tetra acetic acid (EDTA) is administered for this condition . The best form of EDTA to be used for such administration is A) EDTA B) Tetra sodium salt of EDTA C) Disodium salt of EDTA D) Calcium dihydrogen salt of EDTA 45. Metallic copper dissolves in A) Dilute HCl B) Dilute H2 SO 4 C) Pure ammonia D) Aqeous KCN 46. Of the interhalogen compounds ClF3 is more reactive than BrF3 , but BrF3 has higher conductance in the liquid state .The reason is that A) BrF3 has higher molecular weight B) ClF3 is volatile . C) BrF3 dissociates into BrF2 and BrF4 more easily D) ClF3 is most reactive Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 27 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 47. Which of the following option is correct? A) No of -bonds in 1,2-benzanthracene are 9. B) No of -bonds in 1,2-benzpyrene are 10. C) No of -bonds in 1,2,5,6-dibenzanthracene are 11. D) All of these. 48. Which of the following option is incorrect? A) Adrenaline contains secondary amino group. B) Benadryl contains secondary amino group. C) Benzenediazonium fluoroborate is water insoluble and stable at room temperature. D)None of these. 49. Which of the following is correctly matched? A) Boiling point: N-C4H9NH2 > n-C4H9OH> (C2H5)2NH > C2H5N(CH3)2. B) Bond angle of COH: CH3OH > PhOH. C) Boiling point:n-Butane> Methoxyethane > Acetone > Propanal >Propan-1-ol. D)Basic strength: C6H5NH2 < C6H5CH2NH2 < (CH3)3N < CH3NH2 < (CH3)2NH. Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 28 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 50. Which of the following is incorrectly matched? A) Dipole moment: Propadiene > ethenone B) No of resonance: anthracene > napthalene C) Stability: (4-methylphenyl) methyliumion > (4-ethylphenyl) methylium ion D) Acidic strength: -chloroethanoic acid > Benzoic acid > Benzyl carboxylic acid. Section-2 (Paragraph Type With Integer ) This section contains 6 Integer Type questions relating to three paragraphs with two questions on each paragraph. The answer to each of the questions is a single-digit integer, ranging from 0 to 9. For each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero mark if no bubbles are darkened. In all other cases, minus one (-1) mark will be awarded Paragraph for Questions 51 & 52 The half life for nth order reaction nA products can be calculated as, n1 d A n d A 2 1 Rate Kn A or K n dt : t1/2 where a dt n K n1 an 1 0 A n 0 is initial concentration of A 1 So, t1/2 n1 a0 ST t 51. For a reaction of 1 order, the ratio of 3/4 is a function of t1/2 52. The following data was obtained for a chemical reaction a0(m/l) 0.5 1.1 2.48 t1/2(seconds) 4280 885 174 The order of the reaction is Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 29 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Paragraph For Questions 53 & 54 Valence bond theory successfully explains the magnetic nature of complexes . The substances which contains unpaired electrons are paramagnetic and paramagnetic character increases as the number of unpaired electrons increases. Magnetic moment of a complex can be determined experimentally and by using the formula n n 2 . We can determine is the number of unpaired electrons in it. This information is important in writing electronic structure of complex which in turn also useful in deciding the geometry of complex 53 The magnetic moment of the solid complex Cu NH FeF to the nearest 34 2 6 integer is ------54. How many of the following nickel complexes will be attracted into the magnetic field 2 2 2 Ni CN NiCl Ni CO Ni NH 4 , 4 , 4 , 36 , 2 2 Ni H O , K Ni CN , Ni en 2 6 4 4 3 Paragraph For Questions 55 & 56 Heating allyl phenyl ether to 200°C effects an intramolecular reaction called a Claisen rearrangement. The product of the rearrangement is o-allylphenol: Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 30 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper During the ortho migration, the allyl group undergoes allylic shift, i.e., the carbon atom - to the oxygen atom in the substrate becomes - to the ring in the product. However, in the para migration no change of -atom. No catalyst is required, the reaction follows first-order kinetics, i.e., one molecule is involved in the rearrangement. In general, when both ortho positions are free, the product is ortho compound and when both ortho positions are occupied, the product is para compound. Even when the ortho positions are substituted, the migration still occurs at the ortho position to form otho-substituted dienone. However, the absence of hydrogen at the ortho position prevents enolization, i.e., aromatization. Hence the allyl group undergoes a second migration through a similar cyclic transition state to form a dienone which aromatizes to a phenol with allyl group at position-4. Since the allyl group undergoes double inversion, it is not rearranged in the final product. 55. CH2 O h No of C-H bond(s) that will contribute in the pseudo resonance? Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 31 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 56. CH2 O H3C CH3 + h H 1.O3 B C D(Phenolic compound) + E 2.Zn/H2O A Zn F How many of the following statement(s) is/are false for the following conversion? 1. In ‘A’ to ‘B’ conversion, one of the intermediate does not show tautomerism. 2. In ‘B’ to ‘C’ conversion, the most stabilized canonical form of the intermediate has only one non bonding lone pair. 3. No of enolisable protons in ‘F’ is zero. 4. All the organic products in the given conversion show positional isomerism. 5. ‘B’ and ‘C’ are positional isomers. 6. ‘B’ is more acidic than ‘C’. 7. ‘F’ does not respond positively to the Fehling’s test. 8. Both ‘B’ and ‘C’ shows geometrical isomerism. Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 32 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper Section-3 (Matching List Type) This section contains four questions, each having two matching lists (List-1 & List-II). The options for the correct match are provided as (A), (B),(C) and (D) out of which ONLY ONE is correct. 57. Match the following: B.E. –Binding energy I.E – Ionization energy Column - I Column – II A) B.E . OF He atom in an excited state P) Infrared region B) 7 3 transition in H-atom Q) 3.4 eV C) 51 transition in H-atom R) 13.6 eV D) Series limit of Balmer series in H-atom S) 10 spectral line observed T) Ultra violet region A) A–QR; B-PS; C-PST;D-Q B) A –PR;B-QS;C-PST;D-Q C) A-PR;B-QS; C-ST; D-R D) A –P; B-QS; C-PS; D-Q Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 33 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 58. Match the following: Column – I Column – II Work done in reversible adiabatic (A) (P) dSu,v 0, dH s, v 0 process Entropy of all perfectly crystalline (B) (Q) Perfect differential substance (C) Criteria of spontanity (R) Zero when T 0 PVPV1 1 2 2 (D) Hsublimation (S) 1 A) A – S; B – R; C – P; D – Q B) A – S; B – P; C – Q; D - R C) A – Q; B – R; C – P; D – S D) A – P; B – Q; C – S; D - R Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 34 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 59. Matrix Matching Match the reagent and property given in Column –I with the metal ion given in Column – II Column – I Column –II A) Precipitate with KCN which is soluble p) Fe2 in excess reagent 2 B) Precipitate with NaOH and NH4 OH which is q) Hg Soluble in excess NaOH only C) Coloured precipitate with KI which is soluble in r) Pb2 excess of reagent D) Black precipitate with HS2 which is soluble s) Ag In hot & dil HNO3 A) A-ps,B-r,C-qs,D-rs B) A-ps,B-qr,C-r,D-rs C) A-rs,B-ps,C-qr,D-r D) A-ps,B-r,C-rs,D-rs Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 35 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper 60. Match the following: In the following graphs ,one point(Circled) is fixed and two points are wrongly positioned relatively.Identify those two points. Column – I Column – II *A A: CH2=CHCl 1 B: CH CH Cl N 3 2 D C: CH =CHCH Cl (A) C * 2 2 (P) A * D: PhCH2Cl rate of S * B E: CH3OCH2Cl *E Molecule Cl Cl Cl E NO2 NO2 * A A: B: C: Ar * N C NO2 (B) * Cl Cl (Q) B * NO B NO2 O2N 2 rate ofS * D D: E: Molecule NO NO 2 2 Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 36 Sri Chaitanya IIT Academy 24-04-16_ Sr.IPLCO/IC/ISB/LIIT _JEE-ADV_(New Model-3_P1)_GTA-6_Q’Paper A: C(CH3)4 NC CN E * H3C H D: C B: NC H * (C) * H3C H (R) C B D * H3C CH3 * H3C H A E: C C C C max.no max.no of atoms a on plane C: C C C Molecule H H H3C H Hydrolysis is granted in each case. A eq.hydride A A: PhNO PhN=NPh * 2 E A eq.hydride * B: RCOOH RCH2OH A eq.hydride D: RCONH2 RCH NH (D) C 2 2 (S) D * * A eq.hydride B C: RCONHR RCH2NHR D* No No of equivalents used hydride of A eq.hydride Reaction E:RNO2 RNH2 (T) E A) A – PT; B – PS; C – RS; D – QS B) A – PS; B – PT; C – QS; D - SR C) A – QS; B – PT; C – PS; D – RT D) A – PT; B – PS; C – QS; D - RS Sec: Sr.IPLCO/IC/ISB/LIIT space for rough work Page 37