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German – Jordanian University (GJU)

Electrical Circuits 1 Laboratory

Section 3

Experiment 8 RL & RLC Circuits

Post lab Report

Mahmood Hisham Shubbak

Student number: 12

21 / 12 / 2008

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Objectives:

9 To learn about the behavior of series RL and RLC circuits.

Introduction and Theory:

™ An is a device consists of a coil of conducting wire, and it is designed to store energy in its magnetic field.

™ The of an Inductor is the property whereby an inductor exhibits opposition to the change of current flowing through it, measured in henrys (H).

™ Where: v: the drop across the Inductor. L: the Inductance. i: the current flowing through the Inductor.

L1 47mH

‐ An Inductor –

™ The current in an inductor doesn’t change instantaneously.

™ The energy stored in an Inductor is given by: 1 2

™ We can combine in two ways:

1. In series: ‐ We can replace all the Inductors with an equivalent Inductor whose Inductance is given by:

N

L ‐ Inductors in series are like in series.

2. In parallel: ‐ We can replace all the Inductors with an equivalent Inductor whose Inductance is given by:

N 1 1 ‐ Inductors in Parallel are like Resistors in Parallel.

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™ The Response of an RL circuit is given by the following equation: Where:

™ The Response of an RLC circuit is described by the following equations:

In Series In Parallel α ⁄ ⁄ Ωo ⁄√ ⁄√

We assume: y(t) ≡ I or V

y final ≡ y steady state ,

1. [ If ] Then the Circuit's Response is Overdamped.

2. [ If ] Then the Circuit's Response is Critically damped. [Here S1=S2=S= ‐ α]

3. [ If ] Then the Circuit's Response is Underdamped. [Here S1, S2 are complex numbers = ‐α ± j = a + jb ]

9 This experiment consists of three parts:

Part A:

Procedure:

1. Measure the internal resistance of the inductor. 2. Connect the circuit in the figure below.

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1 L1 2 10mH

Vdc R1 5 V 1kΩ

0

3. Measure VL and VR for the circuit. 4. Measure the current of the circuit I. 5. Compare the experimental values with the calculated. 6. Why was there a non‐zero voltage across the two terminals of the Inductor?

Results:

1. RL = 53.3 Ω

‐ The simulation results of this part are shown in the figure below:

V: 5.00 V V: 5.00 V 12 I: 5.00 mA L1 I: 5.00 mA 10mH

Vdc R1 5 V 1kΩ

V: 0 V 0 I: 5.00 mA

‐ The experimental results of this part are shown in the table below:

Simulation Experimental

VL 0 V 0.44 V VR 5 V 4.56 V I 5 mA 4.7 mA

9 The Reason behind the non‐zero voltage across the two terminals of the Inductor is its internal resistance (in this case our inductor like a connection of an inductor 10mH with 53.3Ω in series). V I RRL

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Part B:

Procedure:

1. Measure the internal resistance of the inductor. 2. Connect the circuit in the figure below. 1 L1 10mH

Square wave XFG1 250 Hz CH1 2Vpp 1V DC offset R 220Ω 0, GND

3. Connect the CH1 and GND of the oscilloscope as shown.

4. Draw the VR then find IL.

Results:

‐ The internal Resistance of the Inductor RL = 53.3 Ω.

‐ The result graphs of this part are shown in the last page of this report.

‐ We can get the IL graph by dividing VR by (R+RL) as: IVR⁄R RL

Part C:

Procedure:

1. Connect the circuit in the figure below. C1 2 L1 10mH 1 2.2uF Square wave XFG1 100 Hz CH1 2Vpp 1V DC offset R 390Ω 0, GND

2. Connect the CH1 and GND of the oscilloscope as shown.

3. Draw the VR then find IL.

4. Calculate α and ωo ,what kind of response does the circuit exhibit?

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Results:

The graphs of this part are drawn on the last page.

This circuit is series RLC circuit, i.e. ⁄ 390⁄ 2 102 19500

0

2 6 ⁄ 1⁄ 10 2.210 45454545. 45 .

Then the Circuit's Response is Overdamped.

Discussion:

Part A is a basic RL circuit with dc source, L acts as a short circuit.

The difference between the theoretical and experimental results is due to the internal resistance of the inductor which was = 53.3Ω

V I 4.7mA RRL .

Part B is also a basic RL circuit but with Ac source.

The difference between the theoretical and experimental results is due to the internal resistance of the inductor which was = 53.3Ω

IVR⁄R RL

IVR⁄1053.3Ω

We had the voltage drop across R with Vpp=1.16V

We notice that the Inductor smooths the voltage.

Part C represents an over damped RLC circuit with Ac source.

The difference between the theoretical and experimental results is due to the internal resistance of the inductor which was = 53.3Ω

We had the voltage drop across R with Vpp=2.62V

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Conclusion

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9 Inductors in series act like resistors and it is given by: Le = Σ Li

9 Inductors in parallel act like resistors and it is given by: 1/Le = Σ 1/Li

9 The energy is given by: 1 2

9 LC circuit response is given by:

9 τ = L/R

9 The response of RLC circuit is given by a 2nd order differential equation and it can be over damped, critically damped or underdamped.

9 An Inductor in the steady state (after a long time) reacts as a short circuit.

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