TOPICS in HYPERBOLIC GEOMETRY the Goal of This

Total Page:16

File Type:pdf, Size:1020Kb

TOPICS in HYPERBOLIC GEOMETRY the Goal of This TOPICS IN HYPERBOLIC GEOMETRY MATH 410. SPRING 2007. INSTRUCTOR: PROFESSOR AITKEN The goal of this handout is to discuss some theorems of Hyperbolic Geometry. Many of these theorems will be given without proof. As mentioned in the previous handout, Euclidean and Hyperbolic Conditions, every theo- rem of Neutral Geometry is a theorem of Hyperbolic Geometry (and Euclidean Geometry). In addition, it was mentioned that the negation of every EC (Eculidean Condition) is also a theorem in Hyperbolic Geometry. In this document, we discuss additional theorems in Hyperbolic Geometry. 1. The Two Types of Parallels in Hyperbolic Geometry Definition 1. If l and m are parallel lines such that there exists a line t perpendicular to both, then we say that l and m are type 1 parallels. If l and m are parallel lines with no such common perpendicular, then we say that l and m are type 2 parallels. There are some things about the two types of parallel lines that are not too hard to prove. Recall that in Hyperbolic Geometry, if l and m are parallel, and if P is a point on m, then there is at most one other point P 0 on m such that P and P 0 are equidistant from l. Proposition 1. Suppose that l and m are parallel lines, and suppose P and P 0 are two points on m that are equidistant from l. Then l and m are type 1 parallel lines. Corollary 1. If l and m are type 2 parallel lines, then any two points of m have different distances from l. Proof. The corollary is just the contrapositive of the proposition, so we just need to prove the proposition. So let l and m be parallel lines, and let P and P 0 be distinct points on m that are equidistant from l. Drop a perpendicular from P to l and let Q be its foot. Drop 0 0 0 0 a perpendicular from P to l and let Q be its foot. Observe that P QQ P is a Sacchari quadrilateral. In the Quadrilateral handout we showed that if M is the midpoint of PP 0 and if N is ←−→ the midpoint of QQ0 then MN is perpendicular to l and m. Thus l and m are type 1 parallels. Proposition 2. Suppose that l and m are type 1 parallel lines. Then the common perpen- dicular to l and m is unique. Proof. Otherwise we could construct a rectangle. But rectangles do not exist in Hyperbolic Geometry. Proposition 3. Suppose that l and m are type 1 parallel lines. Suppose that P ∈ m and ←→ Q ∈ l are chosen so that PQ is perpendicular to both l and m. If A and B are points on m such that A ∗ P ∗ B and AP ∼= PB, then A and B are equidistant from l. Date: Spring 2006 and Spring 2007. Version of May 8, 2007. 1 ∼ ∼ ∼ Proof. By SAS, 4P AQ = P BQ. In particular, AQ = BQ and ∠AQP = BQP . Drop a perpendicular from A to l and let C be its foot. Drop a perpendicular from B to l and let ←→ D be its foot. (One can show that C and D are on opposite sides of PQ so C ∗ Q ∗ D). ∼ ∼ ∼ Since ∠AQP = BQP we get ∠AQC = ∠BQD (complementary angles). Since AQ = BQ ∼ ∼ we get, by AAS, that 4AQC = 4BQD. We conclude that AC = BD. From the above results, we easily get the following: Corollary 2. If l and m are type 1 parallels, then we can find two points on m that are equidistant from l. So two parallel lines are of type 1 if and only if there are two point on one line that are equidistant from the second. Thus, two parallel lines are of type 2 if and only any two points on one line are of non-equal distance from the other line. Finally, we show that as you go away from the common perpendicular, the lines get farther apart: Proposition 4. Suppose that l and m are type 1 parallel lines. Suppose that P ∈ m and ←→ Q ∈ l are chosen so that PQ is perpendicular to both l and m. If A and B are points on m such that P ∗ A ∗ B, then the distance from B to l is greater than the distance from A to l. Proof. Drop a perpendicular from A to l and let C be its foot. Drop a perpendicular from B to l and let D be its foot. Observe that P QCA and P QDB are Lambert quadrilaterals. Thus (by a proposition in the Quadrilateral handout and the fact that rectangles do not exist), ∠CAP and ∠DBP are acute. Since ∠BAC is supplementary to ∠CAP , we have that ∠BAC is obtuse. Thus ∠BAC > ∠DBP . This implies, by a result in the Quadrilateral handout, that BD > AC. Now we discuss some results, but skip the proof. Theorem 1. Let l be a line, and P a point not on l. Then there are exactly two type 2 (limiting) parallels to l passing through P . Definition 2 (Angle of Parallelism). Let l be a line, P a point not on l, and m one of the type 2 (or limiting) parallels to l containing P . If we drop a perpendicular from P to l, ←→ ←→ and call the foot Q, then the line PQ is perpendicular to l. Of course, PQ cannot possibly −→ be perpendicular to m since l and m are type 2 parallels. So there is a ray PA in m such that ∠QP A is acute. This angle is called a angle of parallelism for P and l. Since there are two such limiting (type 2) parallels, there are two angles of parallelism (they turn out to be congruent). Theorem 2. Let l be a line, and P a point not on l. Drop a perpendicular from P to l, and let Q be the foot. Then the measure of the angle of parallelism for l and P depends only on the distance x = PQ . In particular, both angles of parallelism for l and P are congruent. Definition 3. Let l be a line, P a point not on l. Drop a perpendicular from P to l, and call the foot Q. Let ∠QP A be an angle of parallelism and let x = PQ . We define Π(x) to be the measure of ∠QP A. The following in a famous theorem of Bolyai and Lobachevsky 2 Theorem 3 (Bolyai, Lobachevsky). The function Π(x) is strictly decreasing on the interval (0, ∞). Its limit as x → 0 is 90 (measured in degrees). Its limit as x → ∞ is 0. In fact, the function Π(x) is given by the formula Π(x) = 2 tan−1(e−x/k) for some constant k. (Here the tan−1 is chosen so its result is in degrees.) Remark 1. This result illustrates an important principle in Hyperbolic geometry: for short distances Hyperbolic Geometry is a lot like Euclidean Geometry. So for small x, the angle measure Π(x) is close to 90. Observe that in Euclidean Geometry Π(x) = 90. The type 2 parallels to a given line and through a given point P are the limiting parallels. Any line “between” these two will be a type 1 parallel. This is described in the following theorem. Theorem 4. Let l be a line, and P a point not on l. Drop a perpendicular from P to l, and let Q be the foot. Let x = PQ be the distance. Suppose A is a point such that P, Q, A are ←→ not collinear. Then AP is a type 1 parallel to l if and only if Π(x) < | AP Q| < 180 − Π(x). ←→ ∠ Also, AP is a type 2 parallel to l if and only if | AP Q| = Π(x) or | AP Q| = 180 − Π(x) ∠ ←→ ∠ Finally, if if |∠AP Q| < Π(x) or |∠AP Q| > 180 − Π(x) then AP is not parallel to l. 2. The natural unit of length The constant k discussed in the Bolyai-Lobachevsky Theorem is an important constant of Hyperbolic Geometry. As discussed above on small scales, the Hyperbolic Plane “looks like” the Euclidean Plane, and the larger k is, the more Euclidean looking the geometry. For instance, if our universe were hyperbolic the constant k would have to be astronomical since the universe looks Euclidean at the scale of the solar system and the neighboring star systems.1 Note that Π(x) will be very close to 90 when x/k is very small, so if k is huge then for reasonable x we have that Π(x) is approximately 90. If we want, a unit of length can be chosen so that k = 1. As pointed out above, this natural length could be quite large. Theorem 5. Hyperbolic Geometry has a natural measure of length. With respect to this length, Π(x) = 2 tan−1(e−x) The existence of a natural is very surprising since Euclidean Geometry has no such natural length. 1According to a comment on page 390 of our book, if you assume that the universe is hyperbolic, then the constant k would have to be over “six hundred trillion miles” based on the parallax of stars. So, for common distances, x/k is very small, and Π(x) is practically equal to 90. So it would be difficult to do a small scale experiment to decide if we lived in a Euclidean or a Hyperbolic universe. According to Einstein’s theory of general relativity, the universe is neither hyperbolic in the sense of having constant negative curvature, nor Euclidean, but is a four-dimensional manifold of variable curvature.
Recommended publications
  • Point of Concurrency the Three Perpendicular Bisectors of a Triangle Intersect at a Single Point
    3.1 Special Segments and Centers of Classifications of Triangles: Triangles By Side: 1. Equilateral: A triangle with three I CAN... congruent sides. Define and recognize perpendicular bisectors, angle bisectors, medians, 2. Isosceles: A triangle with at least and altitudes. two congruent sides. 3. Scalene: A triangle with three sides Define and recognize points of having different lengths. (no sides are concurrency. congruent) Jul 24­9:36 AM Jul 24­9:36 AM Classifications of Triangles: Special Segments and Centers in Triangles By angle A Perpendicular Bisector is a segment or line 1. Acute: A triangle with three acute that passes through the midpoint of a side and angles. is perpendicular to that side. 2. Obtuse: A triangle with one obtuse angle. 3. Right: A triangle with one right angle 4. Equiangular: A triangle with three congruent angles Jul 24­9:36 AM Jul 24­9:36 AM Point of Concurrency The three perpendicular bisectors of a triangle intersect at a single point. Two lines intersect at a point. The point of When three or more lines intersect at the concurrency of the same point, it is called a "Point of perpendicular Concurrency." bisectors is called the circumcenter. Jul 24­9:36 AM Jul 24­9:36 AM 1 Circumcenter Properties An angle bisector is a segment that divides 1. The circumcenter is an angle into two congruent angles. the center of the circumscribed circle. BD is an angle bisector. 2. The circumcenter is equidistant to each of the triangles vertices. m∠ABD= m∠DBC Jul 24­9:36 AM Jul 24­9:36 AM The three angle bisectors of a triangle Incenter properties intersect at a single point.
    [Show full text]
  • Lesson 3: Rectangles Inscribed in Circles
    NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 3 M5 GEOMETRY Lesson 3: Rectangles Inscribed in Circles Student Outcomes . Inscribe a rectangle in a circle. Understand the symmetries of inscribed rectangles across a diameter. Lesson Notes Have students use a compass and straightedge to locate the center of the circle provided. If necessary, remind students of their work in Module 1 on constructing a perpendicular to a segment and of their work in Lesson 1 in this module on Thales’ theorem. Standards addressed with this lesson are G-C.A.2 and G-C.A.3. Students should be made aware that figures are not drawn to scale. Classwork Scaffolding: Opening Exercise (9 minutes) Display steps to construct a perpendicular line at a point. Students follow the steps provided and use a compass and straightedge to find the center of a circle. This exercise reminds students about constructions previously . Draw a segment through the studied that are needed in this lesson and later in this module. point, and, using a compass, mark a point equidistant on Opening Exercise each side of the point. Using only a compass and straightedge, find the location of the center of the circle below. Label the endpoints of the Follow the steps provided. segment 퐴 and 퐵. Draw chord 푨푩̅̅̅̅. Draw circle 퐴 with center 퐴 . Construct a chord perpendicular to 푨푩̅̅̅̅ at and radius ̅퐴퐵̅̅̅. endpoint 푩. Draw circle 퐵 with center 퐵 . Mark the point of intersection of the perpendicular chord and the circle as point and radius ̅퐵퐴̅̅̅. 푪. Label the points of intersection .
    [Show full text]
  • Regents Exam Questions G.GPE.A.2: Locus 1 Name: ______
    Regents Exam Questions G.GPE.A.2: Locus 1 Name: ________________________ www.jmap.org G.GPE.A.2: Locus 1 1 If point P lies on line , which diagram represents 3 The locus of points equidistant from two sides of the locus of points 3 centimeters from point P? an acute scalene triangle is 1) an angle bisector 2) an altitude 3) a median 4) the third side 1) 4 Chantrice is pulling a wagon along a smooth, horizontal street. The path of the center of one of the wagon wheels is best described as 1) a circle 2) 2) a line perpendicular to the road 3) a line parallel to the road 4) two parallel lines 3) 5 Which equation represents the locus of points 4 units from the origin? 1) x = 4 2 2 4) 2) x + y = 4 3) x + y = 16 4) x 2 + y 2 = 16 2 In the accompanying diagram, line 1 is parallel to line 2 . 6 Which equation represents the locus of all points 5 units below the x-axis? 1) x = −5 2) x = 5 3) y = −5 4) y = 5 Which term describes the locus of all points that are equidistant from line 1 and line 2 ? 1) line 2) circle 3) point 4) rectangle 1 Regents Exam Questions G.GPE.A.2: Locus 1 Name: ________________________ www.jmap.org 7 The locus of points equidistant from the points 9 Dan is sketching a map of the location of his house (4,−5) and (4,7) is the line whose equation is and his friend Matthew's house on a set of 1) y = 1 coordinate axes.
    [Show full text]
  • Chapter 14 Locus and Construction
    14365C14.pgs 7/10/07 9:59 AM Page 604 CHAPTER 14 LOCUS AND CONSTRUCTION Classical Greek construction problems limit the solution of the problem to the use of two instruments: CHAPTER TABLE OF CONTENTS the straightedge and the compass.There are three con- struction problems that have challenged mathematicians 14-1 Constructing Parallel Lines through the centuries and have been proved impossible: 14-2 The Meaning of Locus ᭿ the duplication of the cube 14-3 Five Fundamental Loci ᭿ the trisection of an angle 14-4 Points at a Fixed Distance in ᭿ the squaring of the circle Coordinate Geometry The duplication of the cube requires that a cube be 14-5 Equidistant Lines in constructed that is equal in volume to twice that of a Coordinate Geometry given cube. The origin of this problem has many ver- 14-6 Points Equidistant from a sions. For example, it is said to stem from an attempt Point and a Line at Delos to appease the god Apollo by doubling the Chapter Summary size of the altar dedicated to Apollo. Vocabulary The trisection of an angle, separating the angle into Review Exercises three congruent parts using only a straightedge and Cumulative Review compass, has intrigued mathematicians through the ages. The squaring of the circle means constructing a square equal in area to the area of a circle. This is equivalent to constructing a line segment whose length is equal to p times the radius of the circle. ! Although solutions to these problems have been presented using other instruments, solutions using only straightedge and compass have been proven to be impossible.
    [Show full text]
  • Equidistant Sets and Their Connectivity Properties
    PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 47, Number 2, February 1975 EQUIDISTANT SETS AND THEIR CONNECTIVITY PROPERTIES J. B. WILKER ABSTRACT. If A and B are nonvoid subsets of a metric space (X, d), the set of points x e X for which d(x, A) = d(x, B) is called the equidistant set determined by A and B. Among other results, it is shown that if A and B are connected and X is Euclidean 22-space, then the equidistant set determined by A and B is connected. 1. Introduction. In the Euclidean plane the set of points equidistant from two distinct points is a line, and the set of points equidistant from a line and a point not on it is a parabola. It is less well known that ellipses and single branches of hyperbolae admit analogous definitions. The set of points equidistant from two nested circles is an ellipse with foci at their centres. The set of points equidistant from two dis joint disks of different sizes is that branch of an hyperbola with foci at their centres which opens around the smaller disk. These classical examples prompt us to inquire further about the properties of sets which can be realised as equidistant sets. The most general context in which this study is meaningful is that of a metric space (X, d). If A is a nonvoid subset of A', and x is a point of X, then the distance from x to A is defined to be dix, A) = inf\dix, a): a £ A \. If A and B are both nonvoid subsets of X then the equidistant set determined by A and ß is defined to be U = r5| = {x: dix, A) = dix, B)\.
    [Show full text]
  • Chapter 11 Symmetry-Breaking and the Contextual Emergence Of
    September 17, 2015 18:39 World Scientific Review Volume - 9in x 6in ContextualityBook page 229 Chapter 11 Symmetry-Breaking and the Contextual Emergence of Human Multiagent Coordination and Social Activity Michael J. Richardson∗ and Rachel W. Kallen University of Cincinnati, USA Here we review a range of interpersonal and multiagent phenomena that demonstrate how the formal and conceptual principles of symmetry, and spontaneous and explicit symmetry-breaking, can be employed to inves- tigate, understand, and model the lawful dynamics that underlie self- organized social action and behavioral coordination. In doing so, we provided a brief introduction to group theory and discuss how symme- try groups can be used to predict and explain the patterns of multiagent coordination that are possible within a given task context. Finally, we ar- gue that the theoretical principles of symmetry and symmetry-breaking provide an ideal and highly generalizable framework for understanding the behavioral order that characterizes everyday social activity. 1. Introduction \. it is asymmetry that creates phenomena." (English translation) Pierre Curie (1894) \When certain effects show a certain asymmetry, this asymme- try must be found in the causes which gave rise to it." (English translation) Pierre Curie (1894) Human behavior is inherently social. From navigating a crowed side- walk, to clearing a dinner table with family members, to playing a compet- itive sports game like tennis or rugby, how we move and act during these social contexts is influenced by the behavior of those around us. The aim of this chapter is to propose a general theory for how we might understand ∗[email protected] 229 September 17, 2015 18:39 World Scientific Review Volume - 9in x 6in ContextualityBook page 230 230 Michael J.
    [Show full text]
  • Almost-Equidistant Sets LSE Research Online URL for This Paper: Version: Published Version
    View metadata, citation and similar papers at core.ac.uk brought to you by CORE provided by LSE Research Online Almost-equidistant sets LSE Research Online URL for this paper: http://eprints.lse.ac.uk/103533/ Version: Published Version Article: Balko, Martin, Por, Attila, Scheucher, Manfred, Swanepoel, Konrad ORCID: 0000- 0002-1668-887X and Valtr, Pavel (2020) Almost-equidistant sets. Graphs and Combinatorics. ISSN 0911-0119 https://doi.org/10.1007/s00373-020-02149-w Reuse This article is distributed under the terms of the Creative Commons Attribution (CC BY) licence. This licence allows you to distribute, remix, tweak, and build upon the work, even commercially, as long as you credit the authors for the original work. More information and the full terms of the licence here: https://creativecommons.org/licenses/ [email protected] https://eprints.lse.ac.uk/ Graphs and Combinatorics https://doi.org/10.1007/s00373-020-02149-w(0123456789().,-volV)(0123456789().,-volV) ORIGINAL PAPER Almost-Equidistant Sets Martin Balko1,2 • Attila Po´ r3 • Manfred Scheucher4 • Konrad Swanepoel5 • Pavel Valtr1 Received: 23 April 2019 / Revised: 7 February 2020 Ó The Author(s) 2020 Abstract For a positive integer d, a set of points in d-dimensional Euclidean space is called almost-equidistant if for any three points from the set, some two are at unit distance. Let f(d) denote the largest size of an almost-equidistant set in d-space. It is known that f 2 7, f 3 10, and that the extremal almost-equidistant sets are unique. We giveð Þ¼ independent,ð Þ¼ computer-assisted proofs of these statements.
    [Show full text]
  • Almost-Equidistant Sets∗
    Almost-equidistant sets∗ Martin Balko Department of Applied Mathematics and Institute for Theoretical Computer Science, Faculty of Mathematics and Physics, Charles University, Prague, Czech Republic [email protected] Department of Computer Science, Faculty of Natural Sciences, Ben-Gurion University of the Negev, Beer Sheva, Israel Attila Pór Manfred Scheucher Department of Mathematics, Institut für Mathematik, Western Kentucky University, Technische Universität Berlin, Bowling Green, KY 42101 Germany [email protected] [email protected] Konrad Swanepoel Department of Mathematics, London School of Economics and Political Science, London, United Kingdom [email protected] Pavel Valtr Department of Applied Mathematics and Institute for Theoretical Computer Science, Faculty of Mathematics and Physics, Charles University, Prague, Czech Republic Abstract For a positive integer d, a set of points in d-dimensional Euclidean space is called almost-equidistant if for any three points from the set, some two are at unit distance. Let f(d) denote the largest size of an almost-equidistant set in d-space. It is known that f(2) = 7, f(3) = 10, and that the extremal almost-equidistant sets are unique. We give independent, computer-assisted proofs of these statements. It is also known that f(5) ≥ 16. We further show that 12 ≤ f(4) ≤ 13, f(5) ≤ 20, 18 ≤ f(6) ≤ 26, 20 ≤ f(7) ≤ 34, and f(9) ≥ f(8) ≥ 24. Up to dimension 7, our arXiv:1706.06375v3 [math.MG] 22 Feb 2020 work is based on various computer searches, and in dimensions 6 to 9, we give constructions based on the known construction for d = 5.
    [Show full text]
  • On Convex Closed Planar Curves As Equidistant Sets
    On convex closed planar curves as equidistant sets Csaba Vincze Institute of Mathematics, University of Debrecen, P.O.Box 400, H-4002 Debrecen, Hungary [email protected] February 13, 2018 Abstract The equidistant set of two nonempty subsets K and L in the Euclidean plane is a set all of whose points have the same distance from K and L. Since the classical conics can be also given in this way, equidistant sets can be considered as a kind of their generalizations: K and L are called the focal sets. In their paper [5] the authors posed the problem of the characterization of closed subsets in the Euclidean plane that can be realized as the equidistant set of two connected disjoint closed sets. We prove that any convex closed planar curve can be given as an equidistant set, i.e. the set of equidistant curves contains the entire class of convex closed planar curves. In this sense the equidistancy is a generalization of the convexity. 1 Introduction. Let K ⊂ R2 be a subset in the Euclidean coordinate plane. The distance between a point X ∈ R2 and K is measured by the usual infimum formula: d(X,K) := inf{d(X, A) | A ∈ K}, where d(X, A) is the Euclidean distance of the point X and A running through the elements of K. Let us define the equidistant set of K and L ⊂ R2 as the set all of whose points have the same distance from K and L: {K = L} := {X ∈ R2 | d(X,K)= d(X,L)}.
    [Show full text]
  • An Analogue of Ptolemy's Theorem and Its Converse in Hyperbolic Geometry
    Pacific Journal of Mathematics AN ANALOGUE OF PTOLEMY’S THEOREM AND ITS CONVERSE IN HYPERBOLIC GEOMETRY JOSEPH EARL VALENTINE Vol. 34, No. 3 July 1970 PACIFIC JOURNAL OF MATHEMATICS Vol. 34, No. 3, 1970 AN ANALOGUE OF PTOLEMY'S THEOREM AND ITS CONVERSE IN HYPERBOLIC GEOMETRY JOSEPH E. VALENTINE The purpose of this paper is to give a complete answer to the question: what relations between the mutual distances of n (n ^ 3) points in the hyperbolic plane are necessary and sufficient to insure that those points lie on a line, circle, horocycle, or one branch of an equidistant curve, res- pectively ? In 1912 Kubota [6] proved an analogue of Ptolemy's Theorem in the hyperbolic plane and recently Kurnick and Volenic [7] obtained another analogue. In 1947 Haantjes [4] gave a proof of the hyper- bolic analogue of the ptolemaic inequality, and in [5] he developed techniques which give a new proof of Ptolemy's Theorem and its converse in the euclidean plane. In the latter paper it is further stated that these techniques give proofs of an analogue of Ptolemy's Theorem and its converse in the hyperbolic plane. However, Haantjes' analogue of the converse of Ptolemy's Theorem is false, since Kubota [6] has shown that the determinant | smh\PiPs/2) |, where i, j = 1, 2, 3, 4, vanishes for four points P19 P2, P3, P4 on a horocycle in the hyperbolic plane. So far as the author knows, Haantjes is the only person who has mentioned an analogue of the converse of Ptolemy's Theorem in the hyperbolic plane.
    [Show full text]
  • Hyperbolic Geometry with and Without Models
    Eastern Illinois University The Keep Masters Theses Student Theses & Publications 2015 Hyperbolic Geometry With and Without Models Chad Kelterborn Eastern Illinois University This research is a product of the graduate program in Mathematics and Computer Science at Eastern Illinois University. Find out more about the program. Recommended Citation Kelterborn, Chad, "Hyperbolic Geometry With and Without Models" (2015). Masters Theses. 2325. https://thekeep.eiu.edu/theses/2325 This is brought to you for free and open access by the Student Theses & Publications at The Keep. It has been accepted for inclusion in Masters Theses by an authorized administrator of The Keep. For more information, please contact [email protected]. The Graduate School~ EASTERN ILLINOIS UNIVERSITY'" Thesis Maintenance and Reproduction Certificate FOR: Graduate Candidates Completing Theses in Partial Fulfillment of the Degree Graduate Faculty Advisors Directing the Theses RE: Preservation, Reproduction, and Distribution of Thesis Research Preserving, reproducing, and distributing thesis research is an important part of Booth Library's responsibility to provide access to scholarship. In order to further this goal, Booth Library makes all graduate theses completed as part of a degree program at Eastern Illinois University available for personal study, research, and other not-for-profit educational purposes. Under 17 U.S.C. § 108, the library may reproduce and distribute a copy without infringing on copyright; however, professional courtesy dictates that permission be requested from the author before doing so. Your signatures affirm the following: • The graduate candidate is the author of this thesis. • The graduate candidate retains the copyright and intellectual property rights associated with the original research, creative activity, and intellectual or artistic content of the thesis.
    [Show full text]
  • Isometries of the Hyperbolic Plane Equidistant Curves
    Durham University Epiphany 2019 Pavel Tumarkin Geometry III/IV, Homework: weeks 17{18 Due date for starred problems: Tuesday, March 19. Isometries of the hyperbolic plane 17.1. Show that any pair of parallel lines can be transformed to any other pair of parallel lines by an isometry. 17.2. Let A; B 2 γ be two points on a horocycle γ. Show that the perpendicular bisector to the segment AB (of a hyperbolic line!) is orthogonal to γ. 17.3. Let f be a composition of three reflections. Show that f is a glide reflection, i.e. a hyperbolic translation along some line composed with a reflection with respect to the same line. 17.4. (?) Let f be an isometry of the hyperbolic plane such that the distance from A to f(A) is the same 2 for all points A 2 H . Show that f is an identity map. 17.5. (?) Let a and b be two vectors in the hyperboloid model such that (a; a) > 0 and (b; b) > 0. Let la and lb be the lines determined by equations (x; a) = 0 and (x; b) = 0 respectively, and let ra and rb be the reflections with respect to la and lb. (a) For a = (0; 1; 0) and b = (1; 0; 0) write down ra and rb. Find rb ◦ ra(v), where v = (0; 1; 2). (b) What is the type of the isometry ' = rb ◦ ra for a = (1; 1; 1) and b = (1; 1; −1)? (Hint: you don't need to compute ra and rb).
    [Show full text]