DOCSLIB.ORG

Infinite Geometry

Total Page：16

File Type：pdf, Size：1020Kb

Download full-text PDF Read full-text
Infinite Geometry Geometry Homework ©Z h2O0v1a6v HKbuNtzaW lSVoYfstlwtagrVeT nLyL[CM.a \ sAYlqlI WrQi`g`hntxsV `rDevsqeTrDvDeedW. Surface Area AllText (SURAREAALTEXT1) Find the surface area of each figure. Round your answers to the nearest tenth, if necessary. Leave your answers in terms of p for answers that contain p. 1) A cylinder with a radius of 12 km and a height 2) A cylinder with a diameter of 22 in and a of 11 km. height of 7 in. 3) A pentagonal pyramid with a slant height of 12 4) A hexagonal pyramid with a slant height of m and a regular base measuring 7 m on each 12.2 mi and a regular base measuring 6 mi on side with an apothem of 4.8 m. each side with an apothem of 5.2 mi. 5) A pentagonal prism 8 in tall with a regular base 6) A cone with radius 11 m and a slant height of measuring 8 in on each edge and an apothem 24.6 m. of length 5.5 in. 7) A rectangular prism measuring 4 m and 2 m 8) A prism 12 in tall. The base is a trapezoid along the base and 2 m tall. whose parallel sides measure 11 in and 6 in. The other sides are each 5 in. The altitude of the trapezoid measures 4.3 in. 9) A rectangular prism measuring 9 km and 10 km along the base and 5 km tall. 10) A cylinder with a diameter of 12 ft and a height of 10 ft. 11) A rectangular prism measuring 5 km and 7 km along the base and 9 km tall. 12) A pentagonal pyramid with a slant height of 11.8 km and a regular base measuring 9 km on each side with an apothem of 6.2 km. 13) A sphere with a diameter of 24 cm. 14) A hexagonal pyramid with a slant height of 13.1 in and a regular base measuring 6 in on each side with an apothem of 5.2 in. 15) A prism 8 cm tall. The base is a trapezoid whose parallel sides measure 8 cm and 5 cm. The other sides are each 4 cm. The altitude of the trapezoid measures 3.7 cm. 16) A rectangular prism measuring 12 ft and 9 ft 17) A pentagonal prism 5 cm tall with a regular along the base and 9 ft tall. base measuring 6 cm on each edge and an apothem of length 4.1 cm. 18) A trapezoidal prism of height 14 mi. The parallel sides of the base have lengths 12 mi and 6 mi. The other sides of the base are each 6 mi. The trapezoid's altitude measures 5.2 mi. Worksheet by Kuta Software LLC ©E x2P0`1^6Q GKuuDt`aa CSzoefPtAwPaVrAeg qLELRCX.k q IASltlo Xr^isgdhMtTsM proedstecrNvNePd-k.1l V- bMqagdte] swciptlhf gIrncfTi\nYiUtieu cGVeUoJmBeQtbrDyJ. 19) A pentagonal prism 7 ft tall with a regular base measuring 11 ft on each edge and an apothem of length 7.6 ft. 20) A pentagonal prism 6 km tall with a regular base measuring 10 km on each edge and an apothem of length 6.9 km. 21) A rectangular pyramid measuring 6 km and 12 km along the base, with slant heights of 12.5 km and 11.4 km, respectively. 22) A cone with diameter 8 yd and a slant height 23) A pentagonal pyramid with a slant height of of 8.9 yd. 13.8 km and a regular base measuring 12 km on each side with an apothem of 8.3 km. 24) A pyramid with slant height 6.3 ft whose 25) A pentagonal pyramid with a slant height of triangular base measures 7 ft on each side. 10.6 yd and a regular base measuring 8 yd on Each altitude of the base measures 6.1 ft. each side with an apothem of 5.5 yd. 26) A pentagonal prism 6 mi tall with a regular base measuring 7 mi on each edge and an apothem of length 4.8 mi. 27) A prism 12 ft tall. The base is a trapezoid whose parallel sides measure 9 ft and 5 ft. The other sides are each 5 ft. The altitude of the trapezoid measures 4.6 ft. 28) A cone with diameter 24 mi and a slant height 29) A hexagonal prism 11 cm tall with a regular of 26.8 mi. base measuring 11 cm on each edge and an apothem of length 9.5 cm. 30) A rectangular pyramid measuring 4 m and 9 m along the base, with slant heights of 12.8 m and 12.2 m, respectively. 31) A rectangular pyramid measuring 10 km and 32) A square pyramid measuring 4 cm along the 12 km along the base, with slant heights of base with a slant height of 3.6 cm. 13.4 km and 13 km, respectively. 33) A square prism measuring 3 yd along each 34) A cone with diameter 12 ft and a slant height edge of the base and 4 yd tall. of 13.4 ft. 35) A square prism measuring 8 yd along each edge of the base and 5 yd tall. 36) A square prism measuring 7 in along each edge of the base and 11 in tall. 37) A pentagonal prism 7 ft tall with a regular base measuring 10 ft on each edge and an apothem of length 6.9 ft. Worksheet by Kuta Software LLC ©F N2c0k1W6^ LKVuJtfao YSPoBfvtKwba^rCeO xLtLDCl.T c \Aelpl] UrNiqgxhmtWsZ [rceKs[enrYvUeRd-L2.w- x PMOamdVeB IwaiBtxhm jIRn^ftiVnliqtMeD EGMeboumzeutIrOyD. 38) A prism measuring 6 km tall with a triangular 39) A hexagonal prism 11 yd tall with a regular base whose sides measure 6 km, 3 km, and 7 base measuring 8 yd on each edge and an km. In the base, the distance from the 7 km side to the opposite vertex is 2.6 km. apothem of length 6.9 yd. 40) A square prism measuring 12 m along each 41) A cone with radius 4 ft and a slant height of edge of the base and 3 m tall. 10.8 ft. 42) A rectangular pyramid measuring 6 km and 11 km along the base, with slant heights of 8.1 km and 6.7 km, respectively. 43) A prism 18 km tall. The base is a trapezoid whose parallel sides measure 12 km and 6 km. The other sides are each 6 km. The altitude of the trapezoid measures 5.2 km. 44) A rectangular pyramid measuring 6 cm and 8 cm along the base, with slant heights of 12.6 cm and 12.4 cm, respectively. 45) A rectangular prism measuring 6 cm and 3 cm 46) A rectangular pyramid measuring 5 yd and 10 along the base and 3 cm tall. yd along the base, with slant heights of 13 yd and 12.3 yd, respectively. 47) A cone with radius 9 cm and a slant height of 48) A rectangular prism measuring 5 ft and 10 ft 20.1 cm. along the base and 3 ft tall. 49) A rectangular prism measuring 5 km and 10 km along the base and 8 km tall. 50) A pyramid with slant height 9.4 mi whose triangular base measures 9 mi on each side. Each altitude of the base measures 7.8 mi. Worksheet by Kuta Software LLC ©f M2E0x1L6a CK[uwtKam BSFoNfdtiw]aFrWeF tLgLXCM.s X tAelOll \rPi_g\hbtxsQ wr]efsPearYvleEdR.-^ 3n -AMwaDdjew gwMiutUhW NIKnXfHihnWiztUe[ yGbe[oOmxeQtkrHyY. Answers to Surface Area AllText (SURAREAALTEXT1) 1) 552p km² 2) 396p in² 3) 294 m² 4) 313.2 mi² 5) 540 in² 6) 391.6p m² 7) 40 m² 8) 397.1 in² 9) 370 km² 10) 192p ft² 11) 286 km² 12) 405 km² 13) 576p cm² 14) 329.4 in² 15) 216.1 cm² 16) 594 ft² 17) 273 cm² 18) 513.6 mi² 19) 803 ft² 20) 645 km² 21) 283.8 km² 22) 51.6p yd² 23) 663 km² 24) 87.5 ft² 25) 322 yd² 26) 378 mi² 27) 352.4 ft² 28) 465.6p mi² 29) 1353 cm² 30) 197 m² 31) 410 km² 32) 44.8 cm² 33) 66 yd² 34) 116.4p ft² 35) 288 yd² 36) 406 in² 37) 695 ft² 38) 114.2 km² 39) 859.2 yd² 40) 432 m² 41) 59.2p ft² 42) 188.3 km² 43) 633.6 km² 44) 222.8 cm² 45) 90 cm² 46) 238 yd² 47) 261.9p cm² 48) 190 ft² 49) 340 km² 50) 162 mi² Worksheet by Kuta Software LLC ©V k2P0X1k6X oKOuLtBaM ASPoFfetDwZaXrwed cLSLfC[.R j kAMlqlR ^rbidguhDtHsK WrHeksweHrfvN-4em-dH.b x `MHacdxee mwEixtshm wIvn\fqiDnGidthe^ ZGYesoQmXedtnrFyA..
Load more

Recommended publications
  • Pentagonal Pyramid
    Chapter 9 Surfaces and Solids Copyright © Cengage Learning. All rights reserved. Pyramids, Area, and 9.2 Volume Copyright © Cengage Learning. All rights reserved. Pyramids, Area, and Volume The solids (space figures) shown in Figure 9.14 below are pyramids. In Figure 9.14(a), point A is noncoplanar with square base BCDE. In Figure 9.14(b), F is noncoplanar with its base, GHJ. (a) (b) Figure 9.14 3 Pyramids, Area, and Volume In each space pyramid, the noncoplanar point is joined to each vertex as well as each point of the base. A solid pyramid results when the noncoplanar point is joined both to points on the polygon as well as to points in its interior. Point A is known as the vertex or apex of the square pyramid; likewise, point F is the vertex or apex of the triangular pyramid. The pyramid of Figure 9.14(b) has four triangular faces; for this reason, it is called a tetrahedron. 4 Pyramids, Area, and Volume The pyramid in Figure 9.15 is a pentagonal pyramid. It has vertex K, pentagon LMNPQ for its base, and lateral edges and Although K is called the vertex of the pyramid, there are actually six vertices: K, L, M, N, P, and Q. Figure 9.15 The sides of the base and are base edges. 5 Pyramids, Area, and Volume All lateral faces of a pyramid are triangles; KLM is one of the five lateral faces of the pentagonal pyramid. Including base LMNPQ, this pyramid has a total of six faces. The altitude of the pyramid, of length h, is the line segment from the vertex K perpendicular to the plane of the base.
    [Show full text]
  • If Two Polygons Are Similar, Then Their Areas Are Proportional to the Square of the Scale Factor SOLUTION: Between Them
    Chapter 10 Study Guide and Review State whether each sentence is true or false. If 6. The measure of each radial angle of a regular n-gon false, replace the underlined term to make a is . true sentence. 1. The center of a trapezoid is the perpendicular SOLUTION: distance between the bases. false; central SOLUTION: ANSWER: false; height false; central ANSWER: 7. The apothem of a polygon is the perpendicular false; height distance between any two parallel bases. 2. A slice of pizza is a sector of a circle. SOLUTION: false; height of a parallelogram SOLUTION: true ANSWER: false; height of a parallelogram ANSWER: true 8. The height of a triangle is the length of an altitude drawn to a given base. 3. The center of a regular polygon is the distance from the middle to the circle circumscribed around the SOLUTION: polygon. true SOLUTION: ANSWER: false; radius true ANSWER: 9. Explain how the areas of two similar polygons are false; radius related. 4. The segment from the center of a square to the SOLUTION: corner can be called the radius of the square. If two polygons are similar, then their areas are proportional to the square of the scale factor SOLUTION: between them. true ANSWER: ANSWER: If two polygons are similar, then their areas are true proportional to the square of the scale factor 5. A segment drawn perpendicular to a side of a regular between them. polygon is called an apothem of the polygon. SOLUTION: true ANSWER: true eSolutions Manual - Powered by Cognero Page 1 Chapter 10 Study Guide and Review 10.
    [Show full text]
  • Areas of Regular Polygons Finding the Area of an Equilateral Triangle
    Areas of Regular Polygons Finding the area of an equilateral triangle The area of any triangle with base length b and height h is given by A = ½bh The following formula for equilateral triangles; however, uses ONLY the side length. Area of an equilateral triangle • The area of an equilateral triangle is one fourth the square of the length of the side times 3 s s A = ¼ s2 s A = ¼ s2 Finding the area of an Equilateral Triangle • Find the area of an equilateral triangle with 8 inch sides. Finding the area of an Equilateral Triangle • Find the area of an equilateral triangle with 8 inch sides. 2 A = ¼ s Area3 of an equilateral Triangle A = ¼ 82 Substitute values. A = ¼ • 64 Simplify. A = • 16 Multiply ¼ times 64. A = 16 Simplify. Using a calculator, the area is about 27.7 square inches. • The apothem is the F height of a triangle A between the center and two consecutive vertices H of the polygon. a E G B • As in the activity, you can find the area o any regular n-gon by dividing D C the polygon into congruent triangles. Hexagon ABCDEF with center G, radius GA, and apothem GH A = Area of 1 triangle • # of triangles F A = ( ½ • apothem • side length s) • # H of sides a G B = ½ • apothem • # of sides • side length s E = ½ • apothem • perimeter of a D C polygon Hexagon ABCDEF with center G, This approach can be used to find radius GA, and the area of any regular polygon. apothem GH Theorem: Area of a Regular Polygon • The area of a regular n-gon with side lengths (s) is half the product of the apothem (a) and the perimeter (P), so The number of congruent triangles formed will be A = ½ aP, or A = ½ a • ns.
    [Show full text]
  • Influence of Coal Dust on Premixed Turbulent Methane-Air Flames Scott
    Influence of Coal Dust on Premixed Turbulent Methane-Air Flames Scott R. Rockwell A Dissertation Submitted to the Faculty of Worcester Polytechnic Institute In partial fulfillment of the requirements for the Degree of Doctor of Philosophy in Fire Protection Engineering July 2012 APPROVED: _____________________________________________ Professor Ali S. Rangwala, Advisor _____________________________________________ Professor Kathy A. Notarianni, Head of Department _____________________________________________ Professor Simon W. Evans _____________________________________________ Professor Sanjeeva Balasuriya _____________________________________________ Dr. Alfonso F. Ibarreta _____________________________________________ Professor Forman A. Williams Table of Contents Table of Contents ............................................................................................................................ 2 List of figures .................................................................................................................................. 5 List of tables .................................................................................................................................... 6 Nomenclature .................................................................................................................................. 7 Acknowledgments........................................................................................................................... 8 Abstract ..........................................................................................................................................
    [Show full text]
  • HW – Areas of Regular Polygons
    Name _____ Date Period HW – Areas of Regular Polygons In a regular polygon, a segment drawn from the center of the polygon perpendicular to a side of the polygon is called an apothem. In the figure at the right, PS is an apothem. If a regular polygon has an area of A square units, a perimeter of P units, and an apothem of a units, then A = or A = Example: Find the area of a regular pentagon with an apothem of 2.8 cm and a perimeter of 20.34 cm. A = Area of a regular polygon A = (20.34)(2.8) A = 28.476 The area is 28.476 square centimeters. Find the area of each regular polygon described. Round your answers to the nearest tenth. 1. a hexagon with an apothem of 8.7 cm and 2. a pentagon with a perimeter of 54.49 m and sides that are each 10 cm long an apothem of 7.5 m 3. A regular octagon with an apothem 4.8 4. A square with a side 24 inches long and an centimeters long and a side 4 centimeters apothem 12 inches long long Find the apothem for each of the regular polygons below. Then find the perimeter and area for each figure. 5. 6. 7. a ________ a ________ a ________ P = ________ P = ________ P = ________ A ________ A ________ A ________ 8. The perimeter of a regular hexagon is 48 ft. 9. Ms. King wants to add a triangular deck in What is the area of this polygon? the yard behind her house.
    [Show full text]
  • 3Doodler Geometry: Pyramids
    3Doodler EDU 3Doodler Geometry: Pyramids Suitable Ages: Suitable for ages 14+ Skill Level: Basic Materials Required: • 3Doodler 2.0: At a minimum, one 3Doodler per group (six groups per class); if more 3Doodlers are available, one for every one to two students is advisable • 3Doodler PLA or ABS strands: 3 strands per 3Doodler • Pyramid Stencils (N.B.: If PLA is used, it is advisable to apply a layer of masking tape over the stencil to ensure that the shapes can be peeled off the stencil with ease) • The Pyramid Worksheet (pages 16-19) Duration: This classroom activity will take between two and three hours, which can be divided between a number of classroom sessions Instructional Video: Instructional videos showing how to build the Pyramids 1 & 4 of this activity are available at: YouTube: https://youtu.be/f0wQQKNY51w and https://youtu.be/coKS6OJh8WU Vimeo: https://vimeo.com/140039345 and https://vimeo.com/140039344 Dropbox: https://www.dropbox.com/s/hvpr8mcv6f135yi/Example%20Pyramid%201.mpeg?dl=0 and https://www.dropbox.com/s/xf004dw7o4lzcwq/Example%20Pyramid%204.mpeg?dl=0 Written by: Linda Giampieretti Part of the “Fascinating World of Geometric Forms” Project Page 1 of 23 Contents Objective 3 Activity 4 Sequence & Pacing 6 Striving Students 6 Accelerated Students 6 Evaluation Strategies 6 Evaluation Rubric 7 Reference Materials 8 Stencil: Pyramid 1 10 Stencil: Pyramid 2 11 Stencil: Pyramid 3 12 Stencil: Pyramid 4 13 Stencil: Pyramid 5 14 Stencil: Pyramid 6 15 Pyramid Worksheet 16 Worksheet Answer Key 19 Additional Resources 22 Page 2 of 23 Objective Triangles, and in turn, pyramids, form the basis for much of the structural strength in modern architecture and engineering.
    [Show full text]
  • THE EVOLUTION OF. . . the Isoperimetric Problem
    THE EVOLUTION OF. Edited by Abe Shenitzer and John Stillwell The Isoperimetric Problem Viktor Blasj˚ o¨ 1. ANTIQUITY. To tell the story of the isoperimetric problem one must begin by quoting Virgil: At last they landed, where from far your eyes May view the turrets of new Carthage rise; There bought a space of ground, which Byrsa call’d, From the bull’s hide they first inclos’d, and wall’d. (Aeneid, Dryden’s translation) This refers to the legend of Dido. Virgil’s version has it that Dido, daughter of the king of Tyre, fled her home after her brother had killed her husband. Then she ended up on the north coast of Africa, where she bargained to buy as much land as she could enclose with an oxhide. So she cut the hide into thin strips, and then she faced, and presumably solved, the problem of enclosing the largest possible area within a given perimeter— the isoperimetric problem. But earthly factors mar the purity of the problem, for surely the clever Dido would have chosen an area by the coast so as to exploit the shore as part of the perimeter. This is essential for the mathematics as well as for the progress of the story. Virgil tells us that Aeneas, on his quest to found Rome, is shipwrecked and blown ashore at Carthage. Dido falls in love with him, but he does not return her love. He sails away and Dido kills herself. Kline concludes [23, p. 135]: And so an ungrateful and unreceptive man with a rigid mind caused the loss of a potential mathematician.
    [Show full text]
  • Apothem Is the Height of Isosceles Triangle AOB, So It Bisects ∠AOB And
    11-5 Areas of Similar Figures Find the area of the shaded region. Round to the nearest tenth. 35. SOLUTION: The inscribed equilateral triangle can be divided into three congruent isosceles triangles with each central angle having a measure of or 120 . Apothem is the height of isosceles triangle AOB, so it bisects ∠AOB and . Thus, and AT = BT. Use trigonometric ratios to find the side length and apothem of the regular polygon. Use the formula for finding the area of a regular polygon replacing a with OT and P with 3 × AB to find the area of the triangle. eSolutions Manual - Powered by Cognero Page 1 Use the formula for the area of a circle replacing r with OB. Area of the shaded region = Area of the circle – Area of the given triangle Substitute. 36. SOLUTION: The radius of the circle is half the diameter or 3 feet. The area of the shaded region is the difference of the area of the rectangle and the area of the circle. Area of the shaded region = Area of the rectangle – Area of the circle Substitute. 37. SOLUTION: The regular pentagon can be divided into 5 congruent isosceles triangles with each central angle having a measure of or 72. Apothem is the height of the isosceles triangle AOB, so it bisects ∠AOB and . Thus, and AT = BT. Use trigonometric ratios to find the side length and apothem of the polygon. Use the formula for finding the area of a regular polygon replacing a with OT and P with 5 × AB. Use the formula for the area of a circle replacing r with OB.
    [Show full text]
  • From the Center of the Polygon Name______
    From the Center of the Polygon Name___________________ PENTAGON.8xv, HEXAGON.8xv, OCTAGON.8xv Class ___________________ Problem 1 – Area of a Regular Pentagon A regular polygon is a polygon that is equiangular and equilateral. The apothem of a regular polygon is a line segment from the center of the polygon to the midpoint of one of its sides. Start the Cabri Jr. application by pressing A and selecting CabriJr. Open the file PENTAGON by pressing !, selecting Open…, and selecting the file. You are given regular pentagon ABCDE with center R. You are given the length of CD (side of the polygon), RM (apothem), and the area of the polygon. 1. Drag point D to 4 different positions and record the data in the table below. The perimeter and apothem multiplied by perimeter will need to be calculated. The perimeter is the number of sides multiplied by the length of CD . a · P (apothem Position Apothem (a) Perimeter (P) Area times perimeter) 1 2 3 4 2. Using the table discuss how the area and a · P are related. Problem 2 – Area of a Regular Hexagon In the problem, you will repeat the process from Problem 1 for a regular hexagon. Open the file HEXAGON showing a regular hexagon with center R. You are given the length of CD (side of the polygon), RM (apothem), and the area of the polygon. 3. Drag point D to 4 different positions and record the data in the table. The perimeter and apothem multiplied by perimeter will need to be calculated. The perimeter is the number of sides multiplied by the length of CD .
    [Show full text]
  • 11.2 Areas of Regular Polygons
    10.3 Areas of Regular Polygons Geometry Mr. Peebles Spring 2013 Daily Learning Target (DLT) Monday January 14, 2013 • “I can remember, apply, and understand to find the perimeter and area of a regular polygon.” Finding the area of an equilateral triangle • The area of any triangle with base length b and height h is given by A = ½bh. The following formula for equilateral triangles; however, uses ONLY the side length. * Look at the next slide * Theorem 11.3 Area of an equilateral triangle • The area of an equilateral triangle is one fourth the square of the length of the side times 3 s s A = ¼ s2 s A = ¼ s2 Ex. 1: Finding the area of an Equilateral Triangle • Find the area of an equilateral triangle with 8 inch sides. 2 A = ¼ s Area3 of an equilateral Triangle A = ¼ 82 Substitute values. A = ¼ • 64 Simplify. A = • 16 Multiply ¼ times 64. A = 16 Simplify. Using a calculator, the area is about 27.7 square inches. Ex. 2: Finding the area of an Equilateral Triangle • Find the area of an equilateral triangle with 12 inch sides. 2 A = ¼ s Area3 of an equilateral Triangle A = ¼ 122 Substitute values. A = ¼ • 144 Simplify. A = • 36 Multiply ¼ times 144. A = 36 Simplify. Using a calculator, the area is about 62.4 square inches. More . • The apothem is the F A height of a triangle between the center H and two consecutive a E vertices of the G B polygon. • You can find the area of any regular n-gon by dividing the D C polygon into Hexagon ABCDEF with center G, radius GA, congruent triangles.
    [Show full text]
  • 1. in the Figure, Heptagon ABCDEFG Is Inscribed in ⊙P. Identify the Center
    10-4 Areas of Regular Polygons and Composite Figures 1. In the figure, heptagon ABCDEFG is inscribed in Find the area of each regular polygon. Round to ⊙P. Identify the center, a radius, an apothem, and a the nearest tenth. central angle of the polygon. Then find the measure of a central angle. 2. SOLUTION: An equilateral triangle has three congruent sides. Draw an altitude and use the Pythagorean Theorem to find the height. SOLUTION: center: point P, radius: , apothem: , central angle: . A regular heptagon has 7 congruent sides and angles. Thus, the measure of each central angle of heptagon ABCDEFG is . ANSWER: center: point P, radius: , apothem: , central angle: Find the area of the triangle. ANSWER: eSolutions Manual - Powered by Cognero Page 1 10-4 Areas of Regular Polygons and Composite Figures 3. 4. SOLUTION: SOLUTION: The polygon is a square. Form a right triangle. First, find the apothem of the polygon. The central angle of a regular hexagon is Half of the central angle is 30 degrees. This makes this triangle a 30°-60°-90 special right triangle. Use the Pythagorean Theorem to find x. Find the area of the square. Use the formula for the Area of a Regular Polygon; ANSWER: ANSWER: 166.3 cm² eSolutions Manual - Powered by Cognero Page 2 10-4 Areas of Regular Polygons and Composite Figures 5. POOLS Kenton’s job is to cover the community pool C 75 in² during fall and winter. Since the pool is in the shape D in² of an octagon, he needs to find the area in order to SOLUTION: have a custom cover made.
    [Show full text]
  • 1970-2011.3 TOPIC INDEX for the College Mathematics Journal (Including the Two Year College Mathematics Journal)
    1970-2011.3 TOPIC INDEX for The College Mathematics Journal (including the Two Year College Mathematics Journal) prepared by Donald E. Hooley Mathematics Department Bluffton University, Bluffton, Ohio Each item in this index is listed under the topics for which it might be used in the classroom or for enrichment after the topic has been presented. Within each topic entries are listed in chronological order of publication. Each entry is given in the form: Title, author, volume:issue, year, page range, [C or F], [other topic cross-listings] where C indicates a classroom capsule or short note and F indicates a Fallacies, Flaws and Flimflam note. If there is nothing in this position the entry refers to an article unless it is a book review. The topic headings in this index are numbered and grouped as follows: 0 Precalculus Mathematics (also see 9) 0.1 Arithmetic (also see 9.3) 0.2 Algebra 0.3 Synthetic geometry 0.4 Analytic geometry 0.5 Conic sections 0.6 Trigonometry (also see 5.3) 0.7 Elementary theory of equations 0.8 Business mathematics 0.9 Techniques of proof (including mathematical induction 0.10 Software for precalculus mathematics 1 Mathematics Education 1.1 Teaching techniques and research reports 1.2 Courses and programs 2 History of Mathematics 2.1 History of mathematics before 1400 2.2 History of mathematics after 1400 2.3 Interviews 3 Discrete Mathematics 3.1 Graph theory 3.2 Combinatorics 3.3 Other topics in discrete mathematics (also see 6.3) 3.4 Software for discrete mathematics 4 Linear Algebra 4.1 Matrices, systems of linear
    [Show full text]