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 A mirror is in the shape of a regular nonagon with 6 inch sides (nonagon = 9-gon). What is the area of the mirror? 3 ͕ͨ͢20° Ɣ ͕

3 360 ͕ Ɣ  Ɣ Ɣ 40° ͕ͨ͢20° 20° 20° 9

͕ Ɣ 8.24 ͢͝

1 ̻ Ɣ ͕͊ 2 1 ̻ Ɣ 8.24 ʚ9 · 6ʛ 2 70° 70° ̻ Ɩ 222.5 ͢͝ ͦ

3 6 3 Big Ideas Section 11.3  Tri = 3  Octa = 8  Tetra = 4  Nona = 9  Penta = 5  Deca = 10  Hexa = 6  Dodeca = 12  Hepta (Septa) = 7  You are decorating the top of the table with small ceramic tiles. The tabletop is a regular with a radius of 19.6 inches. What is the area you are covering? Whenever we have a word problem,  we should always draw it out. Since it’s about a regular , let’s draw a slice

Since the radius of the polygon is 19.6 in, the congruent sides of the 19.6 in 19.6 in are this length a Time to identify what we need to solve for!

ͥ The area equation is ͕͊ ͦ **Recall ͊ Ɣ ͢ · ͧ**

s To solve for both the apothem and  side length, we need to get the central angle 360  Ɣ Ɣ 45° 22.5° 22.5° 8

19.6 in 19.6 in The apothem will bisect this angle and the side it’s intersecting a Time to figure out which trigonometric ratios to use! If it helps, separate the from inside the isosceles triangle 67.5° 67.5°

ͧ s ͧ 2 2 We have two targets to solve for and the only side we have is hypotenuse. So we must either use sin or cos! 22.5° Apothem Octagon Side 19.6 in ͕ ͧ ͧ͢͝67.5° Ɣ 19.6 ͗ͣͧ67.5° Ɣ 2 a 19.6 or or ͕ ͧ ͗ͣͧ22.5° Ɣ ͧ͢͝22.5° Ɣ 2 19.6 19.6 67.5° ͕ Ɩ 18.11 ͢͝ ͧ Ɩ 15 ͢͝ ͧ 2  You are decorating the top of the table with small ceramic tiles. The tabletop is a regular octagon with a radius of 19.6 inches. What is the area you are covering?

1 ̻ Ɣ ͕͊ 2 1 ̻ Ɣ 18.11 ʚ8 · 15ʛ 2 ̻ Ɩ 1086.5 ͦ͢͝ Since we have the radius of the  regular octagon, all we need is the central angle to solve the area 360  Ɣ Ɣ 45° 8

1 19.6 in 19.6 in ̻ Ɣ ͦͦ͢ · ͧ͢͝ 2 1 ̻ Ɣ 19.6 ͦ 8 · ͧ͢͝45° 2 ̻ Ɩ 1086.5 ͦ͢͝  A mathematician is building a unique sandbox for his children. He plans on building a dodecagonal sandbox with an apothem length of 2ft. What is the total area of the sandbox? ͧ ͕ͨ͢15° Ɣ 2 2 ͧ 360 2͕ͨ͢15° Ɣ  Ɣ Ɣ 30° 2 15° 15° 12 4͕ͨ͢15° Ɣ ͧ 1.07 ͚ͨ Ɣ ͧ 2 1 ̻ Ɣ ͕͊ 2 1 ̻ Ɣ 2 ʚ12 · 1.07ʛ 2 75° 75° ̻ Ɩ 12.84 ͚ͨͦ  Big Ideas Geometry  https://518a613669c95d087a62- ee257dca653275bec786ff52fb0c62c0.ssl.cf1 .rackcdn.com/1208/table_7a_1200__square.j pg