From a Subdivided Tetrahedron to the Dodecahedron: Exploring Regular Colorings
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On the Archimedean Or Semiregular Polyhedra
ON THE ARCHIMEDEAN OR SEMIREGULAR POLYHEDRA Mark B. Villarino Depto. de Matem´atica, Universidad de Costa Rica, 2060 San Jos´e, Costa Rica May 11, 2005 Abstract We prove that there are thirteen Archimedean/semiregular polyhedra by using Euler’s polyhedral formula. Contents 1 Introduction 2 1.1 RegularPolyhedra .............................. 2 1.2 Archimedean/semiregular polyhedra . ..... 2 2 Proof techniques 3 2.1 Euclid’s proof for regular polyhedra . ..... 3 2.2 Euler’s polyhedral formula for regular polyhedra . ......... 4 2.3 ProofsofArchimedes’theorem. .. 4 3 Three lemmas 5 3.1 Lemma1.................................... 5 3.2 Lemma2.................................... 6 3.3 Lemma3.................................... 7 4 Topological Proof of Archimedes’ theorem 8 arXiv:math/0505488v1 [math.GT] 24 May 2005 4.1 Case1: fivefacesmeetatavertex: r=5. .. 8 4.1.1 At least one face is a triangle: p1 =3................ 8 4.1.2 All faces have at least four sides: p1 > 4 .............. 9 4.2 Case2: fourfacesmeetatavertex: r=4 . .. 10 4.2.1 At least one face is a triangle: p1 =3................ 10 4.2.2 All faces have at least four sides: p1 > 4 .............. 11 4.3 Case3: threefacesmeetatavertes: r=3 . ... 11 4.3.1 At least one face is a triangle: p1 =3................ 11 4.3.2 All faces have at least four sides and one exactly four sides: p1 =4 6 p2 6 p3. 12 4.3.3 All faces have at least five sides and one exactly five sides: p1 =5 6 p2 6 p3 13 1 5 Summary of our results 13 6 Final remarks 14 1 Introduction 1.1 Regular Polyhedra A polyhedron may be intuitively conceived as a “solid figure” bounded by plane faces and straight line edges so arranged that every edge joins exactly two (no more, no less) vertices and is a common side of two faces. -
Archimedean Solids
University of Nebraska - Lincoln DigitalCommons@University of Nebraska - Lincoln MAT Exam Expository Papers Math in the Middle Institute Partnership 7-2008 Archimedean Solids Anna Anderson University of Nebraska-Lincoln Follow this and additional works at: https://digitalcommons.unl.edu/mathmidexppap Part of the Science and Mathematics Education Commons Anderson, Anna, "Archimedean Solids" (2008). MAT Exam Expository Papers. 4. https://digitalcommons.unl.edu/mathmidexppap/4 This Article is brought to you for free and open access by the Math in the Middle Institute Partnership at DigitalCommons@University of Nebraska - Lincoln. It has been accepted for inclusion in MAT Exam Expository Papers by an authorized administrator of DigitalCommons@University of Nebraska - Lincoln. Archimedean Solids Anna Anderson In partial fulfillment of the requirements for the Master of Arts in Teaching with a Specialization in the Teaching of Middle Level Mathematics in the Department of Mathematics. Jim Lewis, Advisor July 2008 2 Archimedean Solids A polygon is a simple, closed, planar figure with sides formed by joining line segments, where each line segment intersects exactly two others. If all of the sides have the same length and all of the angles are congruent, the polygon is called regular. The sum of the angles of a regular polygon with n sides, where n is 3 or more, is 180° x (n – 2) degrees. If a regular polygon were connected with other regular polygons in three dimensional space, a polyhedron could be created. In geometry, a polyhedron is a three- dimensional solid which consists of a collection of polygons joined at their edges. The word polyhedron is derived from the Greek word poly (many) and the Indo-European term hedron (seat). -
VOLUME of POLYHEDRA USING a TETRAHEDRON BREAKUP We
VOLUME OF POLYHEDRA USING A TETRAHEDRON BREAKUP We have shown in an earlier note that any two dimensional polygon of N sides may be broken up into N-2 triangles T by drawing N-3 lines L connecting every second vertex. Thus the irregular pentagon shown has N=5,T=3, and L=2- With this information, one is at once led to the question-“ How can the volume of any polyhedron in 3D be determined using a set of smaller 3D volume elements”. These smaller 3D eelements are likely to be tetrahedra . This leads one to the conjecture that – A polyhedron with more four faces can have its volume represented by the sum of a certain number of sub-tetrahedra. The volume of any tetrahedron is given by the scalar triple product |V1xV2∙V3|/6, where the three Vs are vector representations of the three edges of the tetrahedron emanating from the same vertex. Here is a picture of one of these tetrahedra- Note that the base area of such a tetrahedron is given by |V1xV2]/2. When this area is multiplied by 1/3 of the height related to the third vector one finds the volume of any tetrahedron given by- x1 y1 z1 (V1xV2 ) V3 Abs Vol = x y z 6 6 2 2 2 x3 y3 z3 , where x,y, and z are the vector components. The next question which arises is how many tetrahedra are required to completely fill a polyhedron? We can arrive at an answer by looking at several different examples. Starting with one of the simplest examples consider the double-tetrahedron shown- It is clear that the entire volume can be generated by two equal volume tetrahedra whose vertexes are placed at [0,0,sqrt(2/3)] and [0,0,-sqrt(2/3)]. -
Just (Isomorphic) Friends: Symmetry Groups of the Platonic Solids
Just (Isomorphic) Friends: Symmetry Groups of the Platonic Solids Seth Winger Stanford University|MATH 109 9 March 2012 1 Introduction The Platonic solids have been objects of interest to mankind for millennia. Each shape—five in total|is made up of congruent regular polygonal faces: the tetrahedron (four triangular sides), the cube (six square sides), the octahedron (eight triangular sides), the dodecahedron (twelve pentagonal sides), and the icosahedron (twenty triangular sides). They are prevalent in everything from Plato's philosophy, where he equates them to the four classical elements and a fifth heavenly aether, to middle schooler's role playing games, where Platonic dice determine charisma levels and who has to get the next refill of Mountain Dew. Figure 1: The five Platonic solids (http://geomag.elementfx.com) In this paper, we will examine the symmetry groups of these five solids, starting with the relatively simple case of the tetrahedron and moving on to the more complex shapes. The rotational symmetry groups of the solids share many similarities with permutation groups, and these relationships will be shown to be an isomorphism that can then be exploited when discussing the Platonic solids. The end goal is the most complex case: describing the symmetries of the icosahedron in terms of A5, the group of all sixty even permutations in the permutation group of degree 5. 2 The Tetrahedron Imagine a tetrahedral die, where each vertex is labeled 1, 2, 3, or 4. Two or three rolls of the die will show that rotations can induce permutations of the vertices|a different number may land face up on every throw, for example|but how many such rotations and permutations exist? There are two main categories of rotation in a tetrahedron: r, those around an axis that runs from a vertex of the solid to the centroid of the opposing face; and q, those around an axis that runs from midpoint to midpoint of opposing edges (see Figure 2). -
The Crystal Forms of Diamond and Their Significance
THE CRYSTAL FORMS OF DIAMOND AND THEIR SIGNIFICANCE BY SIR C. V. RAMAN AND S. RAMASESHAN (From the Department of Physics, Indian Institute of Science, Bangalore) Received for publication, June 4, 1946 CONTENTS 1. Introductory Statement. 2. General Descriptive Characters. 3~ Some Theoretical Considerations. 4. Geometric Preliminaries. 5. The Configuration of the Edges. 6. The Crystal Symmetry of Diamond. 7. Classification of the Crystal Forros. 8. The Haidinger Diamond. 9. The Triangular Twins. 10. Some Descriptive Notes. 11. The Allo- tropic Modifications of Diamond. 12. Summary. References. Plates. 1. ~NTRODUCTORY STATEMENT THE" crystallography of diamond presents problems of peculiar interest and difficulty. The material as found is usually in the form of complete crystals bounded on all sides by their natural faces, but strangely enough, these faces generally exhibit a marked curvature. The diamonds found in the State of Panna in Central India, for example, are invariably of this kind. Other diamondsJas for example a group of specimens recently acquired for our studies ffom Hyderabad (Deccan)--show both plane and curved faces in combination. Even those diamonds which at first sight seem to resemble the standard forms of geometric crystallography, such as the rhombic dodeca- hedron or the octahedron, are found on scrutiny to exhibit features which preclude such an identification. This is the case, for example, witb. the South African diamonds presented to us for the purpose of these studŸ by the De Beers Mining Corporation of Kimberley. From these facts it is evident that the crystallography of diamond stands in a class by itself apart from that of other substances and needs to be approached from a distinctive stand- point. -
Bridges Conference Proceedings Guidelines Word
Bridges 2019 Conference Proceedings Helixation Rinus Roelofs Lansinkweg 28, Hengelo, the Netherlands; [email protected] Abstract In the list of names of the regular and semi-regular polyhedra we find many names that refer to a process. Examples are ‘truncated’ cube and ‘stellated’ dodecahedron. And Luca Pacioli named some of his polyhedral objects ‘elevations’. This kind of name-giving makes it easier to understand these polyhedra. We can imagine the model as a result of a transformation. And nowadays we are able to visualize this process by using the technique of animation. Here I will to introduce ‘helixation’ as a process to get a better understanding of the Poinsot polyhedra. In this paper I will limit myself to uniform polyhedra. Introduction Most of the Archimedean solids can be derived by cutting away parts of a Platonic solid. This operation , with which we can generate most of the semi-regular solids, is called truncation. Figure 1: Truncation of the cube. We can truncate the vertices of a polyhedron until the original faces of the polyhedron become regular again. In Figure 1 this process is shown starting with a cube. In the third object in the row, the vertices are truncated in such a way that the square faces of the cube are transformed to regular octagons. The resulting object is the Archimedean solid, the truncated cube. We can continue the process until we reach the fifth object in the row, which again is an Archimedean solid, the cuboctahedron. The whole process or can be represented as an animation. Also elevation and stellation can be described as processes. -
Section 1000.00 Omnitopology
Table of Contents ● 1000.00 OMNITOPOLOGY ● 1001.00 Inherent Rationality of Omnidirectional Epistemology ■ 1001.10 Spherical Reference ❍ 1001.20 Field of Geodesic Event Relationships ❍ 1002.10 Omnidirectional Nucleus ❍ 1003.10 Isotropic-Vector-Matrix Reference ❍ 1004.10 An Omnisynergetic Coordinate System ❍ 1005.10 Inventory of Omnidirectional Intersystem Precessional Effects ❍ 1005.15 Volume and Area Progressions ■ 1005.20 Biospherical Patterns ■ 1005.30 Poisson Effect ■ 1005.40 Genetic Intercomplexity ■ 1005.50 Truth and Love: Linear and Embracing ■ 1005.60 Generalization and Polarization ■ 1005.611 Metabolic Generalizations ❍ 1006.10 Omnitopology Defined ■ 1006.20 Omnitopological Domains ■ 1006.30 Vector Equilibrium Involvement Domain ■ 1006.40 Cosmic System Eight-dimensionality ❍ 1007.10 Omnitopology Compared with Euler's Topology ❍ 1007.20 Invalidity of Plane Geometry ❍ 1008.10 Geodesic Spheres in Closest Packing ❍ 1009.00 Critical Proximity ■ 1009.10 Interference: You Really Can t Get There from Here ■ 1009.20 Magnitude of Independent Orbiting ■ 1009.30 Symmetrical Conformation of Flying-Star Teams ■ 1009.40 Models and Divinity ■ 1009.50 Acceleration ■ 1009.60 Hammer-Thrower ■ 1009.69 Comet ■ 1009.70 Orbital Escape from Earth s Critical-Proximity Programmability ■ 1009.80 Pea-Shooter Sling-Thrower. and Gyroscope: Gravity and Mass- Attraction ● 1010.00 Prime Volumes ■ 1010.10 Domain and Quantum ■ 1010.20 Nonnuclear Prime Structural Systems ❍ 1011.00 Omnitopology of Prime Volumes ■ 1011.10 Prime Enclosure ■ 1011.20 Hierarchy of Nuclear -
Dodecahedron
Dodecahedron Figure 1 Regular Dodecahedron vertex labeling using “120 Polyhedron” vertex labels. COPYRIGHT 2007, Robert W. Gray Page 1 of 9 Encyclopedia Polyhedra: Last Revision: July 8, 2007 DODECAHEDRON Topology: Vertices = 20 Edges = 30 Faces = 12 pentagons Lengths: 15+ ϕ = 1.618 033 989 2 EL ≡ Edge length of regular Dodecahedron. 43ϕ + FA = EL 1.538 841 769 EL ≡ Face altitude. 2 ϕ DFV = EL ≅ 0.850 650 808 EL 5 15+ 20 ϕ DFE = EL ≅ 0.688 190 960 EL 10 3 DVV = ϕ EL ≅ 1.401 258 538 EL 2 1 DVE = ϕ 2 EL ≅ 1.309 016 994 EL 2 711+ ϕ DVF = EL ≅ 1.113 516 364 EL 20 COPYRIGHT 2007, Robert W. Gray Page 2 of 9 Encyclopedia Polyhedra: Last Revision: July 8, 2007 DODECAHEDRON Areas: 15+ 20 ϕ 2 2 Area of one pentagonal face = EL ≅ 1.720 477 401 EL 4 2 2 Total face area = 31520+ ϕ EL ≅ 20.645 728 807 EL Volume: 47+ ϕ 3 3 Cubic measure volume equation = EL ≅ 7.663 118 961 EL 2 38( + 14ϕ) 3 3 Synergetics' Tetra-volume equation = EL ≅ 65.023 720 585 EL 2 Angles: Face Angles: All face angles are 108°. Sum of face angles = 6480° Central Angles: ⎛⎞35− All central angles are = 2arcsin ⎜⎟ ≅ 41.810 314 896° ⎜⎟6 ⎝⎠ Dihedral Angles: ⎛⎞2 ϕ 2 All dihedral angles are = 2arcsin ⎜⎟ ≅ 116.565 051 177° ⎝⎠43ϕ + COPYRIGHT 2007, Robert W. Gray Page 3 of 9 Encyclopedia Polyhedra: Last Revision: July 8, 2007 DODECAHEDRON Additional Angle Information: Note that Central Angle(Dodecahedron) + Dihedral Angle(Icosahedron) = 180° Central Angle(Icosahedron) + Dihedral Angle(Dodecahedron) = 180° which is the case for dual polyhedra. -
Are Your Polyhedra the Same As My Polyhedra?
Are Your Polyhedra the Same as My Polyhedra? Branko Gr¨unbaum 1 Introduction “Polyhedron” means different things to different people. There is very little in common between the meaning of the word in topology and in geometry. But even if we confine attention to geometry of the 3-dimensional Euclidean space – as we shall do from now on – “polyhedron” can mean either a solid (as in “Platonic solids”, convex polyhedron, and other contexts), or a surface (such as the polyhedral models constructed from cardboard using “nets”, which were introduced by Albrecht D¨urer [17] in 1525, or, in a more mod- ern version, by Aleksandrov [1]), or the 1-dimensional complex consisting of points (“vertices”) and line-segments (“edges”) organized in a suitable way into polygons (“faces”) subject to certain restrictions (“skeletal polyhedra”, diagrams of which have been presented first by Luca Pacioli [44] in 1498 and attributed to Leonardo da Vinci). The last alternative is the least usual one – but it is close to what seems to be the most useful approach to the theory of general polyhedra. Indeed, it does not restrict faces to be planar, and it makes possible to retrieve the other characterizations in circumstances in which they reasonably apply: If the faces of a “surface” polyhedron are sim- ple polygons, in most cases the polyhedron is unambiguously determined by the boundary circuits of the faces. And if the polyhedron itself is without selfintersections, then the “solid” can be found from the faces. These reasons, as well as some others, seem to warrant the choice of our approach. -
Arxiv:2105.14305V1 [Cs.CG] 29 May 2021
Efficient Folding Algorithms for Regular Polyhedra ∗ Tonan Kamata1 Akira Kadoguchi2 Takashi Horiyama3 Ryuhei Uehara1 1 School of Information Science, Japan Advanced Institute of Science and Technology (JAIST), Ishikawa, Japan fkamata,[email protected] 2 Intelligent Vision & Image Systems (IVIS), Tokyo, Japan [email protected] 3 Faculty of Information Science and Technology, Hokkaido University, Hokkaido, Japan [email protected] Abstract We investigate the folding problem that asks if a polygon P can be folded to a polyhedron Q for given P and Q. Recently, an efficient algorithm for this problem has been developed when Q is a box. We extend this idea to regular polyhedra, also known as Platonic solids. The basic idea of our algorithms is common, which is called stamping. However, the computational complexities of them are different depending on their geometric properties. We developed four algorithms for the problem as follows. (1) An algorithm for a regular tetrahedron, which can be extended to a tetramonohedron. (2) An algorithm for a regular hexahedron (or a cube), which is much efficient than the previously known one. (3) An algorithm for a general deltahedron, which contains the cases that Q is a regular octahedron or a regular icosahedron. (4) An algorithm for a regular dodecahedron. Combining these algorithms, we can conclude that the folding problem can be solved pseudo-polynomial time when Q is a regular polyhedron and other related solid. Keywords: Computational origami folding problem pseudo-polynomial time algorithm regular poly- hedron (Platonic solids) stamping 1 Introduction In 1525, the German painter Albrecht D¨urerpublished his masterwork on geometry [5], whose title translates as \On Teaching Measurement with a Compass and Straightedge for lines, planes, and whole bodies." In the book, he presented each polyhedron by drawing a net, which is an unfolding of the surface of the polyhedron to a planar layout without overlapping by cutting along its edges. -
The Platonic Solids
The Platonic Solids William Wu [email protected] March 12 2004 The tetrahedron, the cube, the octahedron, the dodecahedron, and the icosahedron. From a ¯rst glance, one immediately notices that the Platonic Solids exhibit remarkable symmetry. They are the only convex polyhedra for which the same same regular polygon is used for each face, and the same number of faces meet at each vertex. Their symmetries are aesthetically pleasing, like those of stones cut by a jeweler. We can further enhance our appreciation of these solids by examining them under the lenses of group theory { the mathematical study of symmetry. This article will discuss the group symmetries of the Platonic solids using a variety of concepts, including rotations, reflections, permutations, matrix groups, duality, homomorphisms, and representations. 1 The Tetrahedron 1.1 Rotations We will begin by studying the symmetries of the tetrahedron. If we ¯rst restrict ourselves to rotational symmetries, we ask, \In what ways can the tetrahedron be rotated such that the result appears identical to what we started with?" The answer is best elucidated with the 1 Figure 1: The Tetrahedron: Identity Permutation aid of Figure 1. First consider the rotational axis OA, which runs from the topmost vertex through the center of the base. Note that we can repeatedly rotate the tetrahedron about 360 OA by 3 = 120 degrees to ¯nd two new symmetries. Since each face of the tetrahedron can be pierced with an axis in this fashion, we have found 4 £ 2 = 8 new symmetries. Figure 2: The Tetrahedron: Permutation (14)(23) Now consider rotational axis OB, which runs from the midpoint of one edge to the midpoint of the opposite edge. -
Arxiv:1705.00100V1 [Math.HO] 28 Apr 2017 We Can Get an Elbow That Is 22.5 Degrees (Which Is Half of 45 Degrees)
PVC Polyhedra David Glickenstein∗ University of Arizona, Tucson, AZ 85721 May 2, 2017 Abstract We describe how to construct a dodecahedron, tetrahedron, cube, and octahedron out of pvc pipes using standard fittings. 1 Introduction I wanted to build a huge dodecahedron for a museum exhibit. What better way to draw interest than a huge structure that you can walk around and through? The question was how to fabricate such an object? The dodecahedron is a fairly simple solid, made up of edges meeting in threes at certain angles that form pentagon faces. We could have them 3D printed. But could we do this with “off-the-shelf" parts? The answer is yes, as seen in Figure 1. The key fact to consider is that each vertex corner consists of three edges coming together in a fairly symmetric way. Therefore, we can take a connector with three pipe inputs and make the corner a graph over it. In particular, if we take a connector that takes three pipes each at 120 degree angles from the others (this is called a \true wye") and we take elbows of the appropriate angle, we can make the edges come together below the center at exactly the correct angles. 2 What is the correct elbow angle? Suppose the wye has three length 1 pipes connected to it and the actual vertex v is below the vertexpvW of the wye. Let X and Y be the endpoints of two of the wye segments. Then the segment XY is of length 3 since it is opposite a 120 degree angle in the triangle XY vW : We know that the angle XvY at vertex v has the angle of a regular pentagon, which is 108 degrees.