Thermodynamics of the Solution of Mercury Metal James Nelson Spencer Iowa State University
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Using the Vapor Pressure of Pure Volatile Organic Compounds to Predict the Enthalpy of Vaporization and Computing the Entropy of Vaporization
Open Access Library Journal Using the Vapor Pressure of Pure Volatile Organic Compounds to Predict the Enthalpy of Vaporization and Computing the Entropy of Vaporization Shawn M. Abernathy, Kelly R. Brown Department of Chemistry, Howard University, Washington DC, USA Email: [email protected] Received 5 September 2015; accepted 21 September 2015; published 28 September 2015 Copyright © 2015 by authors and OALib. This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/ Abstract The objective of this investigation was to develop a vapor pressure (VP) acquisition system and methodology for performing temperature-dependent VP measurements and predicting the en- thalpy of vaporization (ΔHvap) of volatile organic compounds, i.e. VOCs. High quality VP data were acquired for acetone, ethanol, and toluene. VP data were also obtained for water, which served as the system calibration standard. The empirical VP data were in excellent agreement with its ref- erence data confirming the reliability/performance of the system and methodology. The predicted values of ΔHvap for water (43.3 kJ/mol, 1.0%), acetone (31.4 kJ/mol; 3.4%), ethanol (42.0 kJ/mol; 1.0%) and toluene (35.3 kJ/mol; 5.4%) were in excellent agreement with the literature. The com- puted values of ΔSvap for water (116.0 J/mol∙K), acetone (95.2 J/mol∙K), ethanol (119.5 J/mol∙K) and toluene (92.0.J/mol∙K) compared also favorably to the literature. Keywords Vapor Pressure (VP), Enthalpy of Vaporization, Entropy of Vaporization, Volatile Organic Compounds (VOCs), Predict Subject Areas: Physical Chemistry 1. -
Chapter 3. Second and Third Law of Thermodynamics
Chapter 3. Second and third law of thermodynamics Important Concepts Review Entropy; Gibbs Free Energy • Entropy (S) – definitions Law of Corresponding States (ch 1 notes) • Entropy changes in reversible and Reduced pressure, temperatures, volumes irreversible processes • Entropy of mixing of ideal gases • 2nd law of thermodynamics • 3rd law of thermodynamics Math • Free energy Numerical integration by computer • Maxwell relations (Trapezoidal integration • Dependence of free energy on P, V, T https://en.wikipedia.org/wiki/Trapezoidal_rule) • Thermodynamic functions of mixtures Properties of partial differential equations • Partial molar quantities and chemical Rules for inequalities potential Major Concept Review • Adiabats vs. isotherms p1V1 p2V2 • Sign convention for work and heat w done on c=C /R vm system, q supplied to system : + p1V1 p2V2 =Cp/CV w done by system, q removed from system : c c V1T1 V2T2 - • Joule-Thomson expansion (DH=0); • State variables depend on final & initial state; not Joule-Thomson coefficient, inversion path. temperature • Reversible change occurs in series of equilibrium V states T TT V P p • Adiabatic q = 0; Isothermal DT = 0 H CP • Equations of state for enthalpy, H and internal • Formation reaction; enthalpies of energy, U reaction, Hess’s Law; other changes D rxn H iD f Hi i T D rxn H Drxn Href DrxnCpdT Tref • Calorimetry Spontaneous and Nonspontaneous Changes First Law: when one form of energy is converted to another, the total energy in universe is conserved. • Does not give any other restriction on a process • But many processes have a natural direction Examples • gas expands into a vacuum; not the reverse • can burn paper; can't unburn paper • heat never flows spontaneously from cold to hot These changes are called nonspontaneous changes. -
THE ENTROPY of VAPORIZATION AS a MBANS of DIS- Tinguismg NORIKAL LIQUIDS
970 JOEL H. HILDEBRAND. iodide solution are shown to give a constant e. m. f. when measured against an unpolarizable electrode. Freshly cast rods of cadmium are shown to attain this value with time. 4. The behavior of cadmium electrodes in concentration cells is ex- plained as due to an allotropic change. 5. Crystalline electrolytic deposits of cadmium on cadmium rods or platinum are shown to give a reproducible e. m. f. when measured against an unpolarizsMe ekctrode. This e. m. f. is, however, slightly higher than that given by the gray cadmium electrodes. Amalgamated electrodes are not reproducible. 6. Photomicrographs indicate a change in crystalline form and con- firm the conclusions drawn from the e. m. f. measurements. 7. Attempts to inoculate the surface of the freshly cast cadmium with the stable rnaatian indicate that the action is extremely slow. 8. Phobmicrogtsphs indicate that in all cases the change is due to a deposit upon the surface htead of to a pitting of the surface. LHEMICALLAJJOUT~BT, BSYN MAWRCOLLBGE, BlYN MAWR. PA [CONTRIBUTION FROM THE CHEMICAL LABOBATORYOF TaS UNIVERSITY OF cALlmRNIA. I THE ENTROPY OF VAPORIZATION AS A MBANS OF DIS- TINGUISmG NORIKAL LIQUIDS. BY JOSL H. HILDSBRAND. Received February 23. 1915. In a series of studies which we are making on the theory of solutions, it has become necessary to distinguish between deviations from Raoult’s Law, whose cause may be considered physical, and those due to chemical changes. As has been pointed out it1 a previous paper,’ the choice be- tween the alternatives in a given case is possible if we know whether or not the pure liquids are associated. -
Calculating the Configurational Entropy of a Landscape Mosaic
Landscape Ecol (2016) 31:481–489 DOI 10.1007/s10980-015-0305-2 PERSPECTIVE Calculating the configurational entropy of a landscape mosaic Samuel A. Cushman Received: 15 August 2014 / Accepted: 29 October 2015 / Published online: 7 November 2015 Ó Springer Science+Business Media Dordrecht (outside the USA) 2015 Abstract of classes and proportionality can be arranged (mi- Background Applications of entropy and the second crostates) that produce the observed amount of total law of thermodynamics in landscape ecology are rare edge (macrostate). and poorly developed. This is a fundamental limitation given the centrally important role the second law plays Keywords Entropy Á Landscape Á Configuration Á in all physical and biological processes. A critical first Composition Á Thermodynamics step to exploring the utility of thermodynamics in landscape ecology is to define the configurational entropy of a landscape mosaic. In this paper I attempt to link landscape ecology to the second law of Introduction thermodynamics and the entropy concept by showing how the configurational entropy of a landscape mosaic Entropy and the second law of thermodynamics are may be calculated. central organizing principles of nature, but are poorly Result I begin by drawing parallels between the developed and integrated in the landscape ecology configuration of a categorical landscape mosaic and literature (but see Li 2000, 2002; Vranken et al. 2014). the mixing of ideal gases. I propose that the idea of the Descriptions of landscape patterns, processes of thermodynamic microstate can be expressed as unique landscape change, and propagation of pattern-process configurations of a landscape mosaic, and posit that relationships across scale and through time are all the landscape metric Total Edge length is an effective governed and constrained by the second law of measure of configuration for purposes of calculating thermodynamics (Cushman 2015). -
Chemistry C3102-2006: Polymers Section Dr. Edie Sevick, Research School of Chemistry, ANU 5.0 Thermodynamics of Polymer Solution
Chemistry C3102-2006: Polymers Section Dr. Edie Sevick, Research School of Chemistry, ANU 5.0 Thermodynamics of Polymer Solutions In this section, we investigate the solubility of polymers in small molecule solvents. Solubility, whether a chain goes “into solution”, i.e. is dissolved in solvent, is an important property. Full solubility is advantageous in processing of polymers; but it is also important for polymers to be fully insoluble - think of plastic shoe soles on a rainy day! So far, we have briefly touched upon thermodynamic solubility of a single chain- a “good” solvent swells a chain, or mixes with the monomers, while a“poor” solvent “de-mixes” the chain, causing it to collapse upon itself. Whether two components mix to form a homogeneous solution or not is determined by minimisation of a free energy. Here we will express free energy in terms of canonical variables T,P,N , i.e., temperature, pressure, and number (of moles) of molecules. The free energy { } expressed in these variables is the Gibbs free energy G G(T,P,N). (1) ≡ In previous sections, we referred to the Helmholtz free energy, F , the free energy in terms of the variables T,V,N . Let ∆Gm denote the free eneregy change upon homogeneous mix- { } ing. For a 2-component system, i.e. a solute-solvent system, this is simply the difference in the free energies of the solute-solvent mixture and pure quantities of solute and solvent: ∆Gm G(T,P,N , N ) (G0(T,P,N )+ G0(T,P,N )), where the superscript 0 denotes the ≡ 1 2 − 1 2 pure component. -
Lecture 6: Entropy
Matthew Schwartz Statistical Mechanics, Spring 2019 Lecture 6: Entropy 1 Introduction In this lecture, we discuss many ways to think about entropy. The most important and most famous property of entropy is that it never decreases Stot > 0 (1) Here, Stot means the change in entropy of a system plus the change in entropy of the surroundings. This is the second law of thermodynamics that we met in the previous lecture. There's a great quote from Sir Arthur Eddington from 1927 summarizing the importance of the second law: If someone points out to you that your pet theory of the universe is in disagreement with Maxwell's equationsthen so much the worse for Maxwell's equations. If it is found to be contradicted by observationwell these experimentalists do bungle things sometimes. But if your theory is found to be against the second law of ther- modynamics I can give you no hope; there is nothing for it but to collapse in deepest humiliation. Another possibly relevant quote, from the introduction to the statistical mechanics book by David Goodstein: Ludwig Boltzmann who spent much of his life studying statistical mechanics, died in 1906, by his own hand. Paul Ehrenfest, carrying on the work, died similarly in 1933. Now it is our turn to study statistical mechanics. There are many ways to dene entropy. All of them are equivalent, although it can be hard to see. In this lecture we will compare and contrast dierent denitions, building up intuition for how to think about entropy in dierent contexts. The original denition of entropy, due to Clausius, was thermodynamic. -
Jgt3 R:. A) -2ZJ(6 .' .'
2 1. (24) a. In the diagram below to the to the right, helium atoms are represented by unshaded spheres, neon atoms by gray spheres, and argon atoms by black spheres. If the total pressure in the container is 900 mm Hg, wh at is the parti~ressure of helium? A) 90 mm Hg ~ 180 mm HgC) 270 mm Hg D) 450 mm Hg • 0 o b. Which of the following is not a ~ e function? O. A) enthalpy ® heat C) internal energy D) volume .0.o c. Which one of the followin g~ ses will have the high est rate of effusion? A) N02 ~ N20 C) N204 D) N03 SF(" '$ ,..""I"' DI A-r:: Q09/mol d. At what temperature will sulfur hexafluoride molecules have th e same average speed as argon atoms at 20°C? JGt3 r:. A) -2ZJ(6 B) 73.2° C C) 381 °C @ 799°C e. Which substance in each of the following pairs is expected to have the larger dispersion forces? I BrZ o r I Z '" ""o'o....r~SS ~ A) Br2 in set I and n-butane in set" H H H H B) Br2 in set 1 and isobutane in set II I I I I © 12 in set I and n-butane in set" I I E-t-C----,:::-C-C-H o r H I I I I I D) 12 in set I and isobutane in set II H H H H H-C- C---C-H n- bu t ane I I I H H H l.sDbut a na f. -
Solutions Mole Fraction of Component a = Xa Mass Fraction of Component a = Ma Volume Fraction of Component a = Φa Typically We
Solutions Mole fraction of component A = xA Mass Fraction of component A = mA Volume Fraction of component A = fA Typically we make a binary blend, A + B, with mass fraction, m A, and want volume fraction, fA, or mole fraction , xA. fA = (mA/rA)/((mA/rA) + (m B/rB)) xA = (mA/MWA)/((mA/MWA) + (m B/MWB)) 1 Solutions Three ways to get entropy and free energy of mixing A) Isothermal free energy expression, pressure expression B) Isothermal volume expansion approach, volume expression C) From statistical thermodynamics 2 Mix two ideal gasses, A and B p = pA + pB pA is the partial pressure pA = xAp For single component molar G = µ µ 0 is at p0,A = 1 bar At pressure pA for a pure component µ A = µ0,A + RT ln(p/p0,A) = µ0,A + RT ln(p) For a mixture of A and B with a total pressure ptot = p0,A = 1 bar and pA = xA ptot For component A in a binary mixture µ A(xA) = µ0.A + RT xAln (xA ptot/p0,A) = µ0.A + xART ln (xA) Notice that xA must be less than or equal to 1, so ln xA must be negative or 0 So the chemical potential has to drop in the solution for a solution to exist. Ideal gasses only have entropy so entropy drives mixing in this case. This can be written, xA = exp((µ A(xA) - µ 0.A)/RT) Which indicates that xA is the Boltzmann probability of finding A 3 Mix two real gasses, A and B µ A* = µ 0.A if p = 1 4 Ideal Gas Mixing For isothermal DU = CV dT = 0 Q = W = -pdV For ideal gas Q = W = nRTln(V f/Vi) Q = DS/T DS = nRln(V f/Vi) Consider a process of expansion of a gas from VA to V tot The change in entropy is DSA = nARln(V tot/VA) = - nARln(VA/V tot) Consider an isochoric mixing process of ideal gasses A and B. -
Gibbs Paradox of Entropy of Mixing: Experimental Facts, Its Rejection and the Theoretical Consequences
ELECTRONIC JOURNAL OF THEORETICAL CHEMISTRY, VOL. 1, 135±150 (1996) Gibbs paradox of entropy of mixing: experimental facts, its rejection and the theoretical consequences SHU-KUN LIN Molecular Diversity Preservation International (MDPI), Saengergasse25, CH-4054 Basel, Switzerland and Institute for Organic Chemistry, University of Basel, CH-4056 Basel, Switzerland ([email protected]) SUMMARY Gibbs paradox statement of entropy of mixing has been regarded as the theoretical foundation of statistical mechanics, quantum theory and biophysics. A large number of relevant chemical and physical observations show that the Gibbs paradox statement is false. We also disprove the Gibbs paradox statement through consideration of symmetry, similarity, entropy additivity and the de®ned property of ideal gas. A theory with its basic principles opposing Gibbs paradox statement emerges: entropy of mixing increases continuously with the increase in similarity of the relevant properties. Many outstanding problems, such as the validity of Pauling's resonance theory and the biophysical problem of protein folding and the related hydrophobic effect, etc. can be considered on a new theoretical basis. A new energy transduction mechanism, the deformation, is also brie¯y discussed. KEY WORDS Gibbs paradox; entropy of mixing; mixing of quantum states; symmetry; similarity; distinguishability 1. INTRODUCTION The Gibbs paradox of mixing says that the entropy of mixing decreases discontinuouslywith an increase in similarity, with a zero value for mixing of the most similar or indistinguishable subsystems: The isobaric and isothermal mixing of one mole of an ideal ¯uid A and one mole of a different ideal ¯uid B has the entropy increment 1 (∆S)distinguishable = 2R ln 2 = 11.53 J K− (1) where R is the gas constant, while (∆S)indistinguishable = 0(2) for the mixing of indistinguishable ¯uids [1±10]. -
Entropy and Free Energy
Spontaneous Change: Entropy and Free Energy 2nd and 3rd Laws of Thermodynamics Problem Set: Chapter 20 questions 29, 33, 39, 41, 43, 45, 49, 51, 60, 63, 68, 75 The second law of thermodynamics looks mathematically simple but it has so many subtle and complex implications that it makes most chemistry majors sweat a lot before (and after) they graduate. Fortunately its practical, down-to-earth applications are easy and crystal clear. We can build on those to get to very sophisticated conclusions about the behavior of material substances and objects in our lives. Frank L. Lambert Experimental Observations that Led to the Formulation of the 2nd Law 1) It is impossible by a cycle process to take heat from the hot system and convert it into work without at the same time transferring some heat to cold surroundings. In the other words, the efficiency of an engine cannot be 100%. (Lord Kelvin) 2) It is impossible to transfer heat from a cold system to a hot surroundings without converting a certain amount of work into additional heat of surroundings. In the other words, a refrigerator releases more heat to surroundings than it takes from the system. (Clausius) Note 1: Even though the need to describe an engine and a refrigerator resulted in formulating the 2nd Law of Thermodynamics, this law is universal (similarly to the 1st Law) and applicable to all processes. Note 2: To use the Laws of Thermodynamics we need to understand what the system and surroundings are. Universe = System + Surroundings universe Matter Surroundings (Huge) Work System Matter, Heat, Work Heat 1. -
Chemistry 163B Absolute Entropies and Entropy of Mixing
Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) Chemistry 163B Absolute Entropies and Entropy of Mixing 1 APPENDIX A: Hf, Gf, BUT S (no Δ, no “sub f ”) Hºf Gºf Sº 2 1 Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) Third Law of Thermodynamics The entropy of any perfect crystalline substance approaches 0 as Tô 0K S=k ln W for perfectly ordered crystalline substance W ô 1 as Tô 0K S ô 0 3 to calculate absolute entropy from measurements (E&R pp. 101-103, Figs 5.8-5.10) T2 CP S ABCDE,,,, dT ABCDE,,,, T T1 H S T ABCD E S S S S III II III I g 0 + + + + S298.15 SK(0 ) SA S SB S 0 23.66 III II 23.66 43.76 II I at 23.66K at4 3.76K + + + SC + S SD + S SE 43.7654 .39 I 54.3990.20 g 90.30298.15 at54 .39K at90.20 K 4 2 Chemistry 163B Winter 2012 Handouts for Third Law and Entropy of Mixing (ideal gas, distinguishable molecules) full calculation of Sº298 for O2 (g) (Example Problem 5.9, E&R pp103-104 [96-97]2nd) SJ K11 mol S(0K ) 0 SA 0 23.66 8.182 S III II at 23.66K 3.964 SB 23.66 43.76 19.61 S II I at 43.76K 16.98 SC 43.76 54.39 10.13 S I at 54.39K 8.181 SD 54.39 90.20 27.06 Sg at 90.20K 75.59 SE 90.20 298.15 35.27 total 204.9 J K-1 mol-1 5 Sreaction from absolute entropies nAA + nBB ônCC + nDD at 298K 0000 SnSnSnSnS298 298 298 298 reaction CCDAB D A B SK00()298 S reaction i 298 i i S 0 are 3rd Law entropies (e.g. -
SOLUTIONS of EXERCISES 301 Central Role of Gibbs Energy 301:1
SOLUTIONS OF EXERCISES 301 central role of Gibbs energy 301:1 characteristic Numerical values in SI units: m.p = 2131.3; ΔS = 7.95; ΔH = 16943; ΔCP = −11.47. 301:2 a coexistence problem 1) f = M[T,P] – N[2 conditions] = 0 ; this excludes the first option; 2) by eliminating lnP from the two equilibrium equations in the ideal-gas approximation, the invariant point should follow from [60000 + 16 (T/K) = 0]; this excludes the second option. 301:3 trigonometric excess Gibbs energy – spinodal and binodal . -1 2 RTspin(X) = (4000 J mol )π X(1−X)sin2πX; limits at zero K are X = 0 (obviously) and X = 0.75; at 0.75 Tc the binodal mole fractions are about 0.11 and 0.52 301:4 from experimental equal-G curve to phase diagram ΔΩ = 1342 J.mol-1; Xsol = 0.635; Xliq = 0.435; see also van der Linde et al. 2002. 301:5 an elliptical stability field * The property ΔG A , which invariably is negative, passes through a maximum, when plotted against temperature. The maximum is reached for a temperature which is about ‘in the middle of the ellipse’. The property ΔΩ is positive. 301:6 a metastable form stabilized by mixing The stable diagram has three three-phase equilibria: αI + liquid + β at left; eutectic; liquid + β + αII at right; peritectic; αI + β + αII (below the metastable eutectic αI + liquid + αII); eutectoid. 301:7 the equal-G curve and the region of demixing For the left-hand case, where the EGC has a minimum, the stable phase diagram has a eutectic three-phase equilibrium.