1- Consider an array of six elements with element spacing d = 3 λ/8. a) Assuming all elements are driven uniformly (same phase and amplitude), calculate the null beamwidth. b) If the direction of maximum radiation is desired to be at 30 o from the array broadside direction, specify the phase distribution. c) Specify the phase distribution for achieving an end-fire radiation and calculate the null beamwidth in this case.
5- Four isotropic sources are placed along the z-axis as shown below. Assuming that the amplitudes of elements #1 and #2 are +1, and the amplitudes of #3 and #4 are -1, find: a) the array factor in simplified form b) the nulls when d = λ 2 .
a)
b)
1- Give the array factor for the following identical isotropic antennas with N and d.
3- Design a 7-element array along the x-axis. Specifically, determine the interelement phase shift α and the element center-to-center spacing d to point the main beam at θ =25 ° , φ =10 ° and provide the widest possible beamwidth.
Ψ=x kdsincosθφα +⇒= 0 kd sin25cos10 ° °+⇒=− αα 0.4162 kd nulls at 7Ψ nnπ2 nn π 2 =±, = 1,2, ⋅⋅⋅⇒Ψnull =±7 , = 1,2,3,4,5,6 α kd2π n kd d λ α −=−7 ( =⇒= 1) 0.634 ⇒= 0.1 ⇒=− 0.264
2- Two-element uniform array of isotropic sources, positioned along the z-axis λ 4 apart is seen in the figure below. Give the array factor for this array. Find the interelement phase shift, α , so that the maximum of the array factor occurs along θ =0 ° (end-fire array).
Nkd sin (cosθ − 1) 1 1 sin[]kd (cosθ − 1) ()AF =2 =,Let 2x =− kd (cosθ 1) n N kd 2 kd sin (cosθ− 1) sin (cos θ − 1) 2 2 1sin2x 12sin x cos x ()AF== == cos xkd cos(cos[][]θ −= 1) cos kd cos θ + α ) n 2 sinx 2 sin x π π maxatθ=⇒=−0 α ( since kd = ) 2 2
1- Aralarındaki faz farkı π 2 olan iki tane izotropik anten y ekseninde y =± λ 4 noktalarına dizilmi ştir. Hangi φ açılarında bu anten dizsinin elektrik alanı sıfır olur? 1- Two isotropic antennas are placed on the y-axis, at y =± λ 4 with an intrinsic phase shift of π 2 . Given that the azimuthal angle, φ , is defined as the angle from the x-axis, for what values of φ are there nulls for the electric field pattern in the xy plane?
2π λ sin[ 1 N (α+ kd cos θ ) ] kd==πθ,() AF =2 , θφ =−→π λ2n N sin[] ( α+ kd cos θ ) 2 sin[]1 N (α+ kd sin) φ sin([]π + πφ sin) π AF ()φ =2 =2 ,π sin φ =→==°° φ sin−1 1 30,150 n 1 π π 2 Nsin([]2 α+ kd sin) φ 2sin([]4 + 2 sin) φ 2 1- k or β= 2 π λ is called the Phase Constant .
sin(nψ 2) The formula was first introduced by Schelkunoff . sin(ψ 2)
The phase change along a distance of a quarter wavelength is π 2 .
sin(nψ 2) As the sign of the formula changes from positive to negative, the phase of sin(ψ 2) the pattern changes by π .
sin(nψ 2) The maximum value of ) is n . sin(ψ 2)
sin(nψ 2) The maximum value of occurs in any direction for which ψ = 0. sin(ψ 2)
For a Broadside Array: the phase difference, α between elements of a “Broadside Array” is α = 0 . in general, as the element spacing is increased, the main lobe beamwidth is decreased. when the element spacing is d ≥ λ grating lobes are introduced as the number of elements increases, the main lobe beamwidth is decreased.
For an End Fire Array: the array radiates in the direction along the line of the array . the phase difference, α between elements of a “Endfire Array” is α = ± kd . as d changes α must change to keep the main beam of the array in the same direction. when the element spacing is d ≥ 0.5 λ grating lobes are introduced. to increase the directivity one can increase the phase difference, α between elements.
2- 5 tane izotropik antenden olu şan anten dizisi aşağıda gösterilmektedir. a) antenler arasındaki faz farkı α ’yı bulun. b) Radyasyonun θ =110 ° ’de maksimum yapması için gereken d’yi λ cinsinden bulun.
c) N=5 için AF n (Ψ ) grafi ğini çizin. d) Radyasyonun olaca ğı ba şlangıç ve biti ş Ψ açılarını bulun. e) Radyasyonu kutupsal koordinatlarda çizin.
2- A 5-element array of isotropic sources is shown below. a) Find the interelement phase shift α . b) Find the value of d λ if the main beam is directed in the direction θ =110 ° . c) Sketch AF n (Ψ ) for N=5. d) Find the visible range in Ψ . e) Sketch the polar plot of the radiation.
απkd θ π kd θ ππ2 d π d λ =Ψ=4, cos +=⇒ 4 0 cos =−⇒ 4λ cos110 °=−⇒= 4 0.365 kdααπ kd π π π ππ −+≤Ψ≤ + →−0.73 +≤Ψ≤4 0.73 + 4 →− 0.48 ≤Ψ≤ 0.98 sin(5Ψ 2) sin5 (kd cosθ + π ) 2 4 N=⇒5 AF () Ψ= → AF ()θ = n 5 sin(Ψ 2) n 5 sin1 (kd cos θ + π 2 4
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Design a 7-element, uniformly excited, equally spaced linear array along the z-axis. Select the element spacing d and linear phasing α such that the beam width is as small as possible and also so that no part of a grating lobe appears in the visible region. Provide the angles where pattern nulls occur, and provide computed-generated polar plots of the patterns when o the main beam at broadside ( θο=90 ).
1sin(7Ψ 2) 126π N=→=7 AF ,α = 0, kd =→= d λ 7 sin(Ψ 2) 7 7
7Ψ Ψ 7 Ψ m nullsatsin= 0&sin ≠→== 0N mπ , m 1,2,3,,,& ≠ 1,2,3, 2 22 7
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Design a 7-element, uniformly excited, equally spaced linear array along the z-axis. Select the element spacing d and linear phasing α such that the beam width is as small as possible and also so that no part of a grating lobe appears in the visible region. Provide the angles where pattern nulls occur, and provide computed-generated polar plots of the patterns when o the main beam at ( θο=80 ).
1 sin(7Ψ 2) N=→7 AF = , Ψ= kd cos80 °+=→=−α 0 α kd cos80 °=− 0.1736 kd 7 sin(Ψ 2) 12 π −0.1736kdkd −≥− →≤ d 0.73λ →=− α 0.1736 kd =− 0.797 7 visible range 0 ≤≤θπ →−kd + α ≤Ψ≤ kd + α →−5.38 ≤Ψ≤ 3.79
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Design a 4-element uniformly excited, equally spaced linear array along the z-axis. The main beam maximum should point to θ = 75 o. Find the d and α such that the beam width is as large as possible and that full main lobe should be visible. Sketch the polar plot of the radiation pattern.
Ψ=kdcosθα +→= 0 kd cos75 °+→=− αα kd cos75 °=− 0.31. kd π kd−0.31 kd =⇒= kd 0.725π ⇒= d 0.3623 λα ⇒=− 0.31(0.725) π =− 0.225 π = 40.43 ° 2
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
6- Array factor of a 5-element uniformly excited, equally spaced linear array is drawn below. Find α , the progressive phase shift and d, the inter-element spacing for a pattern with exactly 3 side-lobes and the main beam at θ = 45 a and a null in the back lobe ( θ =180 a ). kd Ψ=kdcos45 +=→=−α 0 α kd cos45 °=− . 2 8πkd 8 π kd 0.94 π α −=−kd ⇒− −=− kd →= kd0.937π →= d 0.47, λα =−=− =− 0.66 π 5 2 5 2 2
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Determine the progressive phase shift α for a 5-element array equally spaced with
d = λ 2 along the z-axis so that the main beam occurs at θ0 = π 4 . Sketch the polar plot. 3- z-ekseninde yarım dalga boyu aralıkla dizili 5-elemanlı bir anten dizisinin ana huzmesinin
θ0 = π 4 ’da gerçekle şmesi için faz farkı α ’yı bulun. Dizi faktörünü kutupsal çizin. λ kd 2πλ π d=, Ψ= kd cosπ +=⇒=−ααα 0 kd cos π →=− =− =− =− 0.87 π 2 4 4 2λ 22 2
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Design a 7-element array along the z-axis consisting of λ/2 wave dipoles collinear with the z-axis. Specifically, determine the interelement phase shift α and the dipole center-to-center spacing d to point the main beam at θ =5 ° and to provide the widest possible beamwidth.
Ψ=kdcosθα +=⇒=− 0 α kd cos θ =− kd cos 5 ° since we want a wide beamwidth, the dipo les should be as close together as possi ble. ⇒=dλ 2 (any closer thay would touch) so kd =→=−°−π α kd cos 5 ≃ π
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Consider an array consisting of two isotropic radiators positioned symmetrically about z=0 along the z-axis. The elements have uniform amplitude and progressive phase shift α. The spacing between elements is d. For d = λ 2 and α= − π 2 . Sketch the array factor AF (Ψ ) vs. Ψ and sketch also the far field polar plot. sin(Ψ ) sin(π (cos( θ )− 1 )) AF(Ψ= ) =Ψ→= cos( 2) a (θ ) 2 π 1 2 sin(Ψ 2) 2 sin(2 (cos(θ )− 2 ))
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
1- Consider the design of a linear uniformly-spaced phased array of N identical antenna elements with spacing d. The main beam is to be aimed at an angle θ= π 4 radians from the axis of the array. The beamwidth is to be 5.7 degrees and there are to be no grating lobes in the visible range of angle 0≤θ ≤ π . In considering the design ignore the element beam-shape (i.e, assume that the elements radiate isotropically.) a) Specify the progressive phase shift α between the elements in terms of d and λ. b) In order to use the smallest number of elements, you need the greatest spacing d consistent with the absence of grating lobes. Determine this maximum spacing as a fraction of λ and the associated minimum number of elements.
1 sin(N Ψ 2) λα 2πd cos θ 2πd cos π 4 2 π d a)AF = max when cos θ =⇒== α m = n Nsin(Ψ 2)m 2 π d λ λλ kd λ2 λ b) kdkd+cosθπm ≤→+≤⇒≤ 2 kd 2 π d = = 0.5858 λ 2 2+ 1 1.71 4π 5.7 π 180 = →=N 4π = 126 N 180 5.7 π
3- Consider a 4-element uniformly excited equally spaced broadside array along the z-axis with d = λ 2 . Where does the main beam point? Plot the radiation pattern (polar plot).
Nd==⇒=Ψ=+4,λβπ 2 d ,max αβθ d cos max ,Broadside →=°⇒= θ max 90 α 0
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
3- Consider an N-element uniformly excited equally spaced array along the z-axis with d =λ2, α = π 2 . Where does the main beam point? Sketch the polar plot for a) N=4 b) N=5.
λα 1 kd =π(radius), απ = 2 (center), θ m =−=−=° arccos arccos 120 2πd 2
3- Consider an array consisting of two isotropic radiators positioned symmetrically about z=0 along the z-axis. The elements have uniform amplitude and progressive phase shit α. The spacing between elements is d. Sketch AF (Ψ ) and sketch also the far field polar plot for: a) d =λ, α = 0 b) d =λ4, α = 0 c) d =λ4, α = − π 2 d) d =λ4, α = − π 2
sin(Ψ ) AF (Ψ= ) =Ψ cos( 2) 2 sin(Ψ 2)
sin(2π cos( θ )) a(θ ) = 2 sin(π cos( θ ))
sin(π (cos(θ )− 1)) sin(π (cos(θ )+ 1)) a(θ ) = 2 a(θ ) = 2 π π 2 sin(4 (cos(θ )− 1)) 2 sin(4 (cos(θ )+ 1))
1- A 4-element array antenna consists of z-oriented half-wave dipole radiators separated by a distance d = λ 4 along the x-axis. We are interested in radiation in the x-y plane only. a) Assuming initially equal excitation (i.e. α = 0 ), what would be the direction of maximum radiation and the directivity of this array antenna? (To help solve this part, you may want to compare radiated power densities of the array and an isotropic radiator of equivalent Prad, assuming a feed current of 1 [A] and a range of 1 [m]).
b) What excitation phase progression α of the dipoles would be required to obtain maximum radiation at φ =70 ° ?
3- Design a uniform linear array with minimum number of elements and no grating-lobes: a) Find the number of elements such that the side lobe level peak is less than 0.26. The definition of the sidelobe level is the level of the peak of the normalized array function of the side lobe next to main beam.
The definition of a sidelobe level is the relative intensity level of the pattern between the peak of the main beam and the peak of the sidelobe in question. b) Plot the polar pattern if the array is endfire.
3π 1 1 Ψ=SLL ,PSLL = = ,PSLL(N == 2) 0.707, N Nsin(ΨSLL 2) NN sin(3π 2 ) PSLL(N== 3) 0.333,PSLL( N == 4) 0.271,PSLL( N ==⇒= 2) 0.259 N 5
end fire→Ψmax =+αβθd cos max =⇒=− 0 αβ d ForNoGratingLobes⇒≤− 2βππβd 2 2 5 →≤ d 0.8 ππλ → 2 d ≤ 0.8 π →≤ d 0.4 λ
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
4- Consider an array of small loop antennas positioned along the z-axis with interelement spacing d and interelement phase shift α. The loops are oriented such that the plane of each loop is parallel to the xy-plane. Determine the required interelement phase shift α to point the main beam at θ =20 ° . Can this array produce a beam directed at θ =0 ° (i.e., along the z- axis)? Why or why not?
Ψ=kdcosθα +=⇒=− 0 α kd cos θα ⇒=− kd cos20 °=− 0.94 kd No. Individual loops do not radiate towards θ =0 ° 1- Draw the magnitude of the normalized array factor versus Ψ in radians for a 6-element uniformly excited, equally spaced array along the z-axis. If the interelement phase shift is α= 2 π 3 , determine the interelement spacing d to provide the narrowest possible beam without inducing grating lobes. Where does the main beam point? Draw the polar plot of the array factor.
2π 10 π 104 ππ +≤kd →≤ kd − =→=π d 0.5 λ 3 6 66 α λα 2 Ψ=kd cosθαm +=→ 0 cos θ m =−→= θ m arccos − = arccos −= 131.8 ° kd2π d 3 π5 π (visible range) →α −kd ≤Ψ≤ α + kd →− ≤Ψ≤ 3 3
−6 −5 −4 −3 −2 −1 0 1 2 3 4 5 6
4- Dört tane ayni olan anten z ekseninde broadside yayın yapmak için dizilmi şlerdir. a) antenler arasındaki faz farkı α ne olmalıdır? b) grating denen loblar istenmiyorsa d’nin alaca ğı maksimum de ğer ne olmalı? c) side denen loblar istenmiyorsa d’nin alaca ğı maksimum de ğer ne olmalı? d) Dizi faktörünün polar diyagramını α=0,kd = 3 π 2 için çizin.
3- Determine the elements spacing d for a 4-element equally spaced broadside array along the z-axis. Determine the nulls. Sketch the polar plot.
kd3π d 3 kd π d 3 a)α =0, b) =→=→== 3kd 0.75, c) =→=→== 1 kd 0.25 π π 2 24λ2 24 λ n = 1,2,3,.... 1 sin(2Ψ ) nπ n π ()AF = ,nullssin(2)0 ⇒ Ψ=⇒Ψ=±⇒kd cosθ =± , n n n ≠ 0,4,8,12,..... 4 sin(Ψ 2) 2 2
5- 4 tane birbirinin ayni olan anten z ekseninde dizilmi şlerdir. Antenler arasındaki mesafe d ve faz farkları α olsun. Bu dizinin dizi faktörünün a şağıdaki gibi çizildi ğini kabul edelim. Antenlerin dizildi ği eksene dik ı şıma yapılması isteniyor. a) “grating” denen loblar istenmiyorsa d’nin alaca ğı maksimum de ğer ne olmalı? b) “side” denen loblar istenmiyorsa d’nin alaca ğı maksimum de ğer ne olmalı? c) Dizi faktörünün polar diagramını kd = π ve α= π 2 için çizin.
5- Consider a broadside array of 4 identical antennas positioned along the z-axis with interelement spacing d and interelement phase shift α . The array factor is drawn below. a) What is the max. value of d if the grating lobes must be avoided? b) What is the max. value of d if the side lobes must be avoided? c) Sketch the far-field polar pattern due to the array factor if kd =π& α = π 2 .
a) kd=32π ⇒ 2 πλπ d = 32 ⇒= d 34 λ b) kd=π22 ⇒ πλπ d = 2 ⇒= d λ 4 c) For main lobe angle Ψ== 0kd cosθαπθπ += cos + 2 ⇒= θ 120
main lobe grating lobe side lobes
Ψ − π π − π π π π π 2 − 3 − 3 2π 2 2 2 2
α= π 2 kd =π
θ
1- Three half-wave dipoles are aligned parallel to the z-axis, but have their centers located at x = − λ2,0, λ 2 on the x-axis. The dipoles are driven in phase, with equal amplitudes.
a) Sketch the element pattern in the x-y plane.
b) Determine the AF and sketch the polar plot of the AF and the total pattern in the x-y plane.
sin(3Ψ 2) f()1,θ== AF , d == λ 2, α 0 , array and the total pattern is the same. n 3 sin(Ψ 2)
2- Answer true of false: ψ ψ a) The array factor sin(N 2 ) sin( 2 ) applies to arrays with non-uniform current amplitudes. FALSE b) An array with non-uniform (binomial, Chebyshev, etc.) current amplitudes has higher directivity than the same array with uniform current amplitudes. FALSE c) An array of aperture antennas can be analyzed using pattern multiplication. TRUE d) An array of log-periodic dipole arrays can be analyzed using pattern multiplication. TRUE 1- İki tane kısa dipol anten a şağıdaki şekildeki gibi y-eksenine paralel ve x-ekseninde x = ± λ 4 noktalarına yerle ştirilmi ştir. Dipoller aynı genlik ve faza sahipler. a) Çok kısa dipol antenin eleman patternini x-y düzleminde çizin. b) Dizi faktörünü bulun ve dizi patternini x-y düzleminde çizin. c) Toplam patterni x-y düzleminde çizin.
1- Two short dipoles are aligned parallel to the y-axis, but have their centers located at x = ± λ 4 on the x-axis as shown. Dipoles are driven in phase, with equal amplitudes.
a) Sketch the element pattern in the x-y plane. b) Determine the array factor and sketch the polar plot of the array factor in the x-y plane. c) Sketch the total pattern in the x-y plane.
(a) (b) (c) π AF n = cos(2 sinφ )
1- Four short dipoles are arranged in a linear array along the x-axis. The dipoles have a field pattern E dipole = cos( φ). The dipoles are spaced d=λ/2 and fed in phase. a) Derive an expression for the array factor of the four element linear array. since δ = 0
(n− 1) Ψ 3Ψ sin(nΨ 2) j sin(2Ψ ) j AF= e 2 for n=4 AF= e 2 sin(Ψ 2) sin(Ψ 2)
b) What is the expression for the total field pattern, E( φ) of the four dipole array?
Ψ sin(2 ) j3Ψ 2 ETotal = E dipole x E array factor = cos(φ ) e sin(Ψ 2)
c) Explain the principle of pattern multiplication. Show a sketch illustrating this principle.
when you have similar sources, like the dipoles, the total field pattern can be expressed as the product of element pattern times the array factor as expressed in part (b).
d) Does the pattern multiplication apply if the sources in the array are not the same? If yes, demonstrate. If not, how is the field pattern determined?
No! Pattern multiplication does not apply if the sources are dissimilar. In this case you must sum the sources at each point in space to get the total field. 3- Three half-wave dipoles are aligned parallel to the x-axis, but have their centers located at z = ± λ 2 and z = 0 on the z-axis. Assuming that they are driven in phase, with equal amplitudes, use pattern multiplication to sketch the far-field pattern in the zy plane. z
z
y
y x
sin(3π cosθ ) d=λα2, =Ψ= 0, kd cos θπθθ = cos , fN ( ) ==→ 1, 3 AF ( θ ) = 2 n π 3 sin(2 cosθ )
7- Consider a uniform linear array antenna consisting of two vertical half-wave dipoles that are one wavelength apart. The phase difference between the driving currents on the two elements is 90 a . For the horizontal plane (x-y plane) analytically determine the directions of the nulls in the radiation pattern, and generate a plot of the normalized radiation pattern. z I I e jπ 2
y
x π θ = : E =−21cos(kl 2) cossin( ϕ kd 2 +Ψ 2 ) , kl 2= π 2 , kd 2 = π , 2 n Ψ = π 2
=π ϕ +π = ϕ =+ =±± E n 2 cos( sin4 ) 0 when sinn 14, n 0, 1, 2
n =→=0ϕ 14.5, ϕ = 165.5 n =→=1ϕ 311.4, ϕ = 228.6 4- Consider 3 short dipoles, pointed in the x-direction, located on the z-axis at z = ± λ 8, and z = 0 as shown in the figure. Assume that they are driven in phase, with equal amplitudes. z
y
x a) Sketch the far-field pattern for yz-plane and for xz-plane. 1 sin(N Ψ 2) π f(,)θφ=− 1sincos,2 θφ 2 AF = , Nd ==Ψ= 3, λ 8, kd cos θθ = cos N sin(2)Ψ 4 yz−plane(, fθ φ =°= 90) 1 xz − plane(, f θ φ =°= 0) cos θ
3π 3 π 1 sin(cos)8 θ 1 sin(cos)8 θ F(,)θ φ = F (,)θ φ= cos θ π π 3sin(cos)8 θ 3sin(cos)8 θ θ θ
3- A two-element vertical ( z-directed) half-wave dipole array are located one wavelength apart symmetrically along the z-axis.
a) Determine the phase shift between the elements to maximize array factor at θ = 80 o.
jα 2 1 j α 2 AFe=2 cos(cos[ 2 kdθα +=→= ),] kd 2 π AFe 2 cos(cos πθα + 2)
Ψ=+αkdcos θ =→=− 0 α kd cos θπ =− 2cos80 °=− 1.09rad( − 62.5) °
b) Determine the array factor defined in part (a).
AF=2 e −j 0.545 cos(π cos θ − 0.545)
c) Determine the nulls of the array factor of part (a).
π3 π 1 3 πcos θ− 0.545 =± , ± ⋅⋅⋅⇒ cos θ =±+ 0.173, ±+ 0.173, ⋅⋅⋅ 22 2 2 ⇒=−θ cos−1 {} 0.327, 0.673 = 1.904,0.833 rad{} 109.1 °° , 47.7 d) Determine the far field electric field of the array.
jµ I cos(π cosθ ) E =0 0 e−j( kr + 0.545) cos(π cos θ − 0.545) 2 aˆ πr sin θ θ 8- Consider a uniform linear array antenna consisting of two vertical half-wave dipoles that are one wavelength apart. The phase difference between the driving currents on the two elements is 90 o. Analytically determine the directions of the nulls in the radiation pattern and sketch the normalized radiation field pattern in a) the x-z plane; x− z plane:ϕ = 0ora ϕ =→= 180 a sin ϕ 0 ,
cos( kl cosθ ) − cos ( kl ) cos( π cos θ ) E = 22 2 cos ()Ψ , kl 2= π 2 , E = 22 cos ()π n sin θ 2 n sin θ 4
= cosθ = 2n + 1 n = →θ = a , n =1 →θ = 180 a E n 0 when 1 180
z I I e jπ 2 z
y x
x b) the y-z plane; y− z plane:ϕ = 90a or ϕ = 270 a
coskl cosθ − cos kl kd ( 2) ( 2 ) Ψ = π = π E n =2 cos sinθ sin ϕ + , kl 2 2 , kd 2 , sinθ 2 2 Ψ = π 2 = when ( π θ ) = or (π θ ϕπ+) = E n 0 cos2 cos 0 cos sin sin 4 0
( π θ ) = θ = a a cos2 cos 0 for 0 ,180 for ϕ = 90 a , sinθ =n + 14 , n =→=0θ 14.5,a θ = 165.5 a , n =−1 →θ > π for ϕ = 270 a , sinθ = −n − 14 , n = 0 →θ > π , n =−→=1θ 48.6,a θ = 131.4 a
9- At points A and B, the signal strength, when a single dipole antenna operates, is E1A and
E1B , respectively. How will the electric field magnitude change if a second identical antenna is added a distance d = λ 2 from the first antenna, a shown in the figure? The two antennas are driven by currents with equal magnitudes. The current on the second antenna is phase shifted by π 2 . The distance of each points of A and B to the antennas are much larger than
the spacing between the antennas. Express the signal at points A and B in terms of E1A and
E1B , respectively.
B
{ d = λ 2 y I Ie jπ 2
30 a
A x
One antenna : E1
= Two antenna : E F E 1
kd Ψ λkd π πΨ π F =2 cos sinθ sin ϕ + d = ⇒ = Ψ = ⇒ = 2 2 2 2 2 2 2 4 horizontal plane (x-y plane) θ= π 2 , sinθ = 1
π π F =2 cos sinθ sin ϕ + 2 4
π π Point A : ϕ = 30 a → F =2cos sin30a + = 0 , E= F E = 0 A A 2 4 A A1 A
π π Point B : ϕ = 210 a → F =2cos sin210a + = 2 , E= FE = 2 E B B 2 4 BBB1 1 B 1- Sadece tek anten kullanıldı ğında A ve B noktalarındaki elektrik alan şiddeti E1A ve = λ E1B ’dir. Şekilde görüldü ğü gibi d 2 uzaklıkta ikinci bir anten ilave edildi ğinde A ve B noktalarındaki alan şiddetini E1A ve E1B cinsinden hesaplayın. İki antenin akımlarının mutlak de ğeri e şit fakat ikinci antenin faz farkı π 2 ’dir. A ve B noktalarının uzak alanda bulundu ğunu varsayın.
1- At points A and B, the signal strength, when a single dipole antenna operates, is E1A and
E1B , respectively. How will the electric field magnitude change if a second identical antenna is added a distance d = λ 2 from the first antenna, a shown in the figure? The two antennas are driven by currents with equal magnitudes. The current on the second antenna is phase shifted by π 2 . The distance of each points of A and B to the antennas are much larger than
the spacing between the antennas. Express the signal at points A and B in terms of E1A and
E1B , respectively. (Hint: use unnormalized antenna factor expression). z A
jπ 2 Ie a 30 d = λ 2 { y I
B
θ =a → = θ =a → = One antenna: Point A : 60 EAE1 A Point B : 120 EBE1 B θ =a → =θ = a θ =a → Two antenna: Point A : 60 EAAF( 60) E 1 A Point B : 120 =θ = a EBAF( 120) E 1 B
sin(N Ψ 2) sin2cos(π+ π θ ) AF=, Ψ=+π 2 π cos θ → AF = sin2(Ψ ) sin4(π+ π 2cos θ )
a sin(π 2+ π cos 60 ) 0 Point A : AF (θ == 60a ) == 0 , E = 0 sin()π 4+ π 2 cos60 a 1 A