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Eur. Phys. J. C (2016) 76:314 DOI 10.1140/epjc/s10052-016-4157-y

Regular Article - Theoretical

Superradiantly stable non-extremal Reissner–Nordström black holes

Jia-Hui Huang1,a, Zhan-Feng Mai2 1 Laboratory of Quantum Engineering and Quantum Materials, School of Physics and Telecommunication Engineering, South China Normal University, Guangzhou 510006, China 2 Department of Physics, Center for Advanced Quantum Studies, Beijing Normal University, Beijing 100875, China

Received: 5 March 2015 / Accepted: 25 May 2016 / Published online: 7 June 2016 © The Author(s) 2016. This article is published with open access at Springerlink.com

Abstract The superradiant stability is investigated for hole and grows exponentially. This leads to the superradiant non-extremal Reissner–Nordström black holes. We use an instability of the . algebraic method to demonstrate that all non-extremal The superradiant mechanism has been studied by many Reissner–Nordström black holes are superradiantly stable authors for the (in)stability problem of black holes [14– against a charged massive scalar perturbation. This improves 26]. Recently, for a Kerr black hole under massive scalar the results obtained before for non-extremal Reissner– perturbation, Hod has proposed a stronger stability regime Nordström black holes. than before [27]. The extremal and non-extremal charged Reissner–Nordström (RN) black holes have been proved to The stability problem of black hole is an important topic be stable against a charged massive perturbation [28,29]. in black hole physics. Regge and Wheeler [1] proved that Similarly, the analog of the charged RN black hole in string the spherically symmetric Schwarzschild black hole is sta- theory has also been proved to be stable under a charged ble under perturbations. The stability problems of rotating massive scalar perturbation [30]. or charged black holes are complicated due to the signif- In fact, up to now, the non-extremal charged RN black hole icant effect of . The superradiance effect can is proved to be superradiantly stable when the mass M and occur in both classical and quantum scattering processes [2– charge Q of the black hole satisfy (Q/M)2 ≤ 8/9[28,29]. In 5]. When a charged bosonic wave is impinging on a charged this paper, we demonstrate that the all non-extremal charged , the wave reflected by the RN black hole is stable against a massive charged scalar will be amplified if the wave frequency ω lies in the following perturbation. We find that there is no trapping well outside superradiant regime: the black hole, which is separated from the horizon by a potential barrier. As a result, there is no bound state in the 0 <ω

−iωt lm(t, r,θ,φ)= Rlm(r)Ylm(θ, φ)e , (4) It is obvious that when

ω2 <μ2 where Ylm is the spherical harmonic function, l is the spheri- (12) cal harmonic index, m is the azimuthal harmonic index with −l  m  l, and ω is the energy of the mode. The radial there is a bound state of the scalar field. Klein–Gordon equation obeyed by Rlm (we denote Rlm by In the following, we prove that there is no trapping well R in the following) is given by outside the black hole horizon when the parameters of the   scalar field and the black hole satisfy the bound state con- d dR dition (12) and the superradiance condition of the RN black + UR= 0, (5) dr dr hole, <ω<  = / . where = r 2 − 2Mr + Q2 and 0 q H qQ r+ (13) 1 We define a new radial function φ by φ = 2 R, then the U = (ωr 2 − qQr)2 − [μ2r 2 + l(l + 1)]. (6) radial Eq. (5) can be rewritten as

The inner and outer horizons of the black hole are d2φ  + (ω2 − V )φ = 0, (14) dr 2 r± = M ± M2 − Q2, (7) where and it is obvious that 2 2 2 U + M − Q r+ + r− = 2M, r+r− = Q . V = ω2 − . (15) 2 In order to study the superradiance stability of the black hole against the massive charged perturbation, the asymp- In order to see if there exists a trapping potential outside totic solutions of the radial wave equation near the horizon the horizon, we should analyze the shape of the effective and at infinity will be considered with proper boundary con- potential V . From the following asymptotic behavior of the ditions. We proceed by defining the tortoise coordinate y by potential V : 2 the equation dy = r and a new radial function R˜ = rR. dr 2Mμ2 + 2Qqω − 4Mω2 The radial wave Eq. (5) can be written as V (r →+∞) → μ2 +   r 1 d2 R˜ + o , (16) + U˜ R˜ = 0, (8) r 2 dy2 V (r → r+) →−∞, (17) where we know there is at least one maximum for V outside the   event horizon. It is easy to see that the asymptotic behavior ˜ U d U = − . (9) of the derivative of V is r 4 r 3 dr r 2   2Mμ2 + 2Qqω − 4Mω2 1 It is easy to obtain the asymptotic behavior of the new poten- V  =− + o . 2 3 (18) tial U˜ as r r

(ωr+ − qQ)2 lim U˜ = , lim U˜ = ω2 − μ2. (10) We can prove the coefficient 2Mμ2 + 2Qqω − 4Mω2 > → 2 →∞ r r+ r+ r 0 when ω satisfies the superradiance and the bound state The chosen boundary conditions are ingoing waves at the conditions. Define a quadratic function f for ω horizon (y →−∞) and bound states (exponentially decay- ing modes) at spatial infinity (y →+∞). Then the radial f (ω) =−4Mω2 + 2Qqω + 2Mμ2. (19) 123 Eur. Phys. J. C (2016) 76 :314 Page 3 of 4 314

It is obvious that there are two zero points for f with opposite where sign, and the positive one is a =−4Mω2 + 2qQω + 2Mμ2, (26)  2 2 2 2 2 2 Qq + Q q + 8M μ c = 12r− −4r−ω + 6r−ωqQ ω+ = . (20) 4M 2 2 2 2 −[2q Q + (3r+r− + r−)μ ] − 3(r+ − r−)l(l + 1), (ω) > ω To verify f 0 when satisfies the superradiance and (27) the bound state conditions, we just need to prove ω<ω+. 2 2 1 3 e = 2r−(r+ − r−)(ωr− − qQ) + (r+ − r−) . (28) Case I: ω<μ≤ qQ/r+ 2 > With the obvious relation r+ M, we can get From the asymptotic behaviors of the effective potential at

2 2 the inner and outer horizons and infinity, we know that there qQ q2 Q2 μ2 μr+ μ r+ μ2  ω+ = + + > + + are at least two roots for V (z) = 0 when z > 0. If a trapping 2 2 4M 16M 2 4r+ 16r+ 2 potential existed, there would be at least four positive roots = μ>ω. (21) for V (z) = 0. Next, we will demonstrate that it is impos- sible for the equation V (z) = 0 to have four positive roots Case II: ω + + 0, the numerator of Eq. (25) will be considered only. We 4M 16M2 2 4r+ 16r 2 2r 2  + + denote the roots of V (z) = 0by{z1, z2, z3, z4} and z1, z2 = / >ω. qQ r+ (22) are the two known positive roots (r− < z1 < r+, r+ < z2 < +∞). According to the Vieta theorem, we have the following So when ω satisfies the superradiance and the bound state relations for the roots: conditions, f (ω) > 0. It implies that c z1z2 + z1z3 + z1z4 + z2z3 + z2z4 + z3z4 = , (29) ( →∞) → −. a V r 0 (23) e z z z z = . (30) 1 2 3 4 a This means there is no potential well when r →+∞.In the following, we will show that there is only one maximum The coefficient a(= f (ω)) has been proved to be positive outside the event horizon for V , no trapping potential exists before. Because r+ > r−, it is also easy to see that which is separated from the horizon by a potential barrier and all non-extremal RN black holes are superradiantly stable. e > 0. (31) The explicit expression of the derivative of the effective potential is So from Eq. (30), we find that if z , z are two real roots,  3 4  1 they must be both positive or both negative. V =− (−4Mω2 + 2qQω + 2Mμ2)r 4  3 Taking the superradiance and bound state conditions into account, we will use an algebraic method to prove c < 0for + 4Q2ω2 + 4MQqω − 4M2μ2  the full parameter space of the charged massive scalar pertur- 2 2 2 3 , −2Q (q + μ ) + 2l(l + 1) r bation and non-extremal RN black holes. So z3 z4 cannot be both positive, there is no trapping well outside the horizon +[− 3 ω + 2μ2 − ( + )] 2  6Q q 6MQ 6Ml l 1 r and the RN black hole is superradiantly stable. This is the + 2Q4q2 − 2Q4μ2 − 4M2 + 4Q2 main result of this paper.  The final term of c is non-positive, so in order to prove +2(2M2 + Q2)l(l + 1) r + 4M3 c < 0, we just need to prove  − 2 − 2 ( + ) . 2 2 2 2 2 2 4MQ 2MQ l l 1 (24) 12r−{−4r−ω + 6r−ωqQ −[2q Q + (3r+r− + r−)μ ]} < 0, (32) Defining a new variable z = r − r− is convenient for us to study the property of the effective potential. Then Eq. (24) i.e. can be written as 2 2 2 2 2 2 g(ω) =−4r−ω + 6qQr−ω −[2q Q + (3r+r− +r−)μ ]  −1 V (z) = (az4 + bz3 + cz2 + dz + e), (25) < . 3 0 (33) 123 314 Page 4 of 4 Eur. Phys. J. C (2016) 76 :314

Regarding g(ω) as a quadratic function of ω, when the dis- side the event horizon, that is separated from the horizon criminant of g(ω) (denoting it by ) by a potential barrier. So we conclude that all the non- extremal charged RN black holes are superradiantly stable  2 2 2 2 2 = 4r−[q Q − 4(3r+r− + r−)μ ] < 0, (34) against charged massive scalar perturbations. we have g(ω) < 0 because the coefficient of ω2 is negative. Acknowledgments This work is supported partially by the Natural Below we discuss the case  ≥ 0. According to the Science Foundation of Guangdong Province (No. 2016A030313444).  ≥ properties of a quadratic function, when 0 is satisfied, Open Access This article is distributed under the terms of the Creative there are two positive roots of g(ω), which are denoted by ω1 Commons Attribution 4.0 International License (http://creativecomm and ω2, respectively, and ω1 ≤ ω2. To demonstrate g(ω) < ons.org/licenses/by/4.0/), which permits unrestricted use, distribution, 0, we only need to demonstrate 0 <ω<ω when the and reproduction in any medium, provided you give appropriate credit 1 to the original author(s) and the source, provide a link to the Creative superradiance and bound state conditions are satisfied. We Commons license, and indicate if changes were made. do this for two possible cases. It is easy to get Funded by SCOAP3.

2 2 2 2 3qQ − q Q − 4(3r+r− + r−)μ ω1 = . (35) References 4r−

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