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CHEM 201 Self Quiz – 2 (Gravimetric analysis/Volumetric analysis) Answer key
1. Calculate the solubility product constant for SrF given the molar concentration of the 2 -4 saturated solution is 8.6 × 10 M.
2+ " SrF2 ! Sr + 2F 2+ ! 2 Ksp = [Sr ][F ] 2+ "4 [Sr ] = [SrF2 ] = 8.6!10 ! !4 !4 [F ] = 2"[SrF2 ] = 2" 8.6"10 =17.2"10 "4 "4 2 "10 Ksp = 8.6!10 ! (17.2!10 ) =1.5!10