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“Elementary Particles” Lecture 3

Niels Tuning Harry van der Graaf

Niels Tuning (1) Plan

Theory Detection and sensor techn.

Quantum Forces Field

Interactions Scintillators with Matter PM

Tipsy Accelerators Bethe Bloch Medical Imag. Cyclotron Photo effect X-ray Compton, pair p. Proton therapy Bremstrahlung Cherenkov Experiments Fundamental Astrophysics Charged Particles Cosmics Particles ATLAS Grav Km3Net Si Neutrinos Virgo Gaseous Lisa Pixel …

Special General Gravity Optics Relativity Relativity Laser

Niels Tuning (2) Plan

Theory Today Detection and sensor techn.

Niels 2) Niels 2) Niels 7) + 10) Quantum Quantum Forces Mechanics Field Theory 5) + 8) 4) Harry Particles 3) Harry

Light RelativisticIn

teractions 6) + 9) with Matter Ernst-Jan 1) Harry 11) +12) Martin Fundamental 6) Ernst-Jan Accelerators Martin Physics 13) + 14) Astrophysics Charged Excursions Particles Experiments

1) Niels 9) Ernst-Jan 9) Ernst-Jan 9) Ernst-Jan Special General Gravity Optics Relativity Relativity

Niels Tuning (3) Schedule

1) 11 Feb: Accelerators (Harry vd Graaf) + Special relativity (Niels Tuning) 2) 18 Feb: (Niels Tuning) 3) 25 Feb: Interactions with Matter (Harry vd Graaf) 4) 3 Mar: Light detection (Harry vd Graaf) 5) 10 Mar: Particles and cosmics (Niels Tuning) 6) 17 Mar: Astrophysics and Dark Matter (Ernst-Jan Buis) 7) 24 Mar: Forces (Niels Tuning) break 8) 21 Apr: e+e- and ep (Niels Tuning)

9) 28 Apr: Gravitational Waves (Ernst-Jan Buis) 10) 12 May: Higgs and big picture (Niels Tuning) 11) 19 May: Charged particle detection (Martin Franse) 12) 26 May: Applications: experiments and medical (Martin Franse)

13) 2 Jun: Nikhef excursie 14) 8 Jun: CERN excursie

Niels Tuning (4) Plan

1) Intro: & Relativity 11 Feb 1900-1940 2) Basis 18 Feb 1) Atom model, strong and weak force 2) Scattering theory 1945-1965 3) Hadrons 10 Mar 1) Isospin, strangeness 2) Quark model, GIM 1965-1975 4) Standard Model 24 Mar 1) QED 2) Parity, neutrinos, weak inteaction 3) QCD

1975-2000 5) e+e- and DIS 21 Apr

2000-2015 6) Higgs and CKM 12 May

Niels Tuning (5) Thanks

• Ik ben schatplichtig aan: – Dr. Ivo van Vulpen (UvA) – Prof. dr. ir. Bob van Eijk (UT) – Prof. dr. M. Merk (VU)

Niels Tuning (6) Exercises Lecture 2: QM and Scattering

Niels Tuning (7) Exercises Lecture 2: QM and Scattering

Niels Tuning (8) Answers Homework Theory 2

1 Celebrating Bohr

a) v = (↵qeqp)/(mr) L = mvr = p↵qeqpmr ) 2 b) L =pp↵qeqpmr = ~ r = ~ /(↵qeqpm). ) 9 2 2 19 2 (I tried SI units: ↵qq = keqq =(9 10 Nm /C ) (1.6 10 C) ) 2 34 2 ⇥9 ⇥19 2 ⇥ 30 10 r = ~ /(↵qeqpm)=(10 ) /(9 10 (1.6 10 ) 10 )=0.4 10 m ⇥ ⇥ ⇥ ⇥ ⇥ ↵qeqp ↵qeqp ↵qeqp Etot = Ekin + Epot = 2r r = 2r 2 m(↵qeqp) Etot = 2 . 2~ I tried natural units here: E = ↵2m/2) = (1/137)2 0.5 MeV / 2 = -13.3 eV Exercisestot Lecture 2: ⇥QM and Scattering 3 Spinors 2 Yukawa’s massive force carrier We saw that the requirement of a relativistically correct, but linear equation led to the , (iµ@ m) = 0, with being a four component spinor. 15 µ 15 8 24 a) r 10 m t =r/c =10 /(3 10 )=3 10 s. ⇠ ) ⇥ ⇥ 2 2 2 a) H =(~↵ p~ + m) 22 gives E = p + m24 if the matrices anticommute, ↵i, ↵j = b) E ~/t =6·.6 10 MeVs/(3 10 s) = 200 MeV. { } ⇠↵i↵j + ↵j↵i =⇥ 0. Usually we use⇥ the matrices, =(, ~↵). Show that indeed 12 = 21, using the Pauli-Dirac representation,

- 0 0 ~ = ; ~↵ = . 3 Spinors 0 ~ 0 ✓ ◆ ✓ ◆

ipx µ a)With12 == u(p2)e1 : and pµ i@µ we get ( pµ m)u(p) = 0. Looking for the eigenvectors, it is easier to go back to the! original form; Hu=(~↵ p~ + m)u = Eu, which leads to 10 0 0 0001· 0001 m ~ p~ u u Hu01= 0· 0 A0010= E A 0010 1 = ↵1 = 0 ~ p~ m 1 0uB uB1 = 0 1 00✓ · 10 ◆✓ 0100◆ ✓ ◆ 0 100 with ~ the Pauli matrices,B 00 0 1 C B 1000C B 1000C B C B C B C @ A @ A @ A 01 0 i 10 10 1 = ; 102 = 0 0 ; 3000= i; = 000. i 10 i 0 0 1 01 ✓ ◆ 01✓ 0 0◆ 00✓ i ◆0 ✓ 00◆ i 0 2 = ↵2 = 0 1 0 1 = 0 1 And thus: 00 10 0 i 00 0 i 00 B 00 0 1 C B i 000C B i 00 0C B (~ p~)uB C=(BE m)uA C B (1) C @ · A @ A @ A (~ p~)u =(E + m)u , (2) i 000· A B i 000 where uA and uB are two-component0 i 00 objects. Let’s inspect this two-fold0 i degeneracy,00 and 12 = 0 1 21 = 0 1 find the that distinguishes00 thei 0 two components. 00i 0 B 000i C B 000 i C B C B C Niels Tuning (9) b) Consider an electron@ with the momentumA in the z-direction,@ p~ =(0, 0,p). WhatA do you find for ~ p~ ? · 1 c) What is the eigenvalue of 1~ pˆ for the eigenfunction 2 · 0 = 1 ✓ ◆ withp ˆ = p/~ p~ the vector in the direction of p~ with unit length. What does this value correspond| | to, you think?

1 d) Supposep ˆ can point in any direction, what is then the meaning of 2~ pˆ? What are the possible eigenvalues? ·

2 3 Spinors

We saw that the requirement of a relativistically correct, but linear equation led to the Dirac equation, (iµ@ m) = 0, with being a four component spinor. µ

a) H =(~↵ p~ + m) gives E2 = p2 + m2 if the matrices anticommute, ↵ , ↵ = · { i j} ↵i↵j + ↵j↵i = 0. Usually we use the matrices, =(, ~↵). Show that indeed 12 = 21, using the Pauli-Dirac representation,

0 0 ~ = ; ~↵ = . 0 ~ 0 ✓ ◆ ✓ ◆

ipx µ With = u(p)e and pµ i@µ we get ( pµ m)u(p) = 0. Looking for the eigenvectors, it is easier to go back to the! original form; Hu=(~↵ p~ + m)u = Eu, which leads to · m ~ p~ u u Hu = A = E A ~ p~ m· u u ✓ · ◆✓ B ◆ ✓ B ◆ with ~ the Pauli matrices,

01 0 i 10 10 = ; = ; = ; = . 1 10 2 i 0 3 0 1 01 ✓ ◆ ✓ ◆ ✓ ◆ ✓ ◆ And thus:

(~ p~)u =(E m)u (1) · B A (~ p~)u =(E + m)u , (2) Exercises Lecture 2: QM· andA ScatteringB where uA and uB are two-component objects. Let’s inspect this two-fold degeneracy, and find the observable that distinguishes the two components.

b) Consider an electron with the momentum in the z-direction, p~ =(0, 0,p). What do you find for ~ p~ ? · c) What is the eigenvalue of 1~ pˆ for the eigenfunction 2 · 0 = 1 ✓ ◆ withp ˆ = p/~ p~ the vector in the direction of p~ with unit length. What does this value correspond| | to, you think?

1 d) Supposep ˆ can point in any direction, what is then the meaning of 2~ pˆ? What are the possible eigenvalues? ·

b) 2 p 0 ~ p~ = p = · 3 0 p ✓ ◆ c) 1 1 0 1 0 ( ~ pˆ) = = 2 · 2 3 1 2 1 ✓ ◆ ✓ ◆ The eigenvalue -1/2 is the z-component of the .

d) 1~ pˆ is the spin component in the direction of . 2 · Possible eigenvalue: 1/2. Niels Tuning (10) ± e) Positive and negative helicity:

1000 1 (1) ~ (1) 3 0 uA 0 10 0 0 (1) (⌃ pˆ)u = (1) = 0 1 0 1 =+u · 0 3 u 0010 pz/(E + m) ✓ ◆ B ! B 000 1 C B 0 C B C B C @ A @ A (⌃~ pˆ)u(2) = u(2) ·

4 and

e) d Z Z ↵ 2 1 1 2 = 1 2 =(2mZ Z ↵)2 2 4 ✓ 1 2 2 2 2 ✓ d⌦ mv0 4 sin 4m v0 sin ⇣ ⌘ 2 ⇣ 2 ⌘ 0 2 2 0 2 2 2 2 2 2 2 ✓ q = 0 1 =(mv0) (sin ✓+(1 cos ✓) )=2(mv0) (1 cos ✓)=4m v0 sin mv0 sin ✓ 2 B mv (1 cos ✓) C B 0 C @ A

2 Exercises Lecture 2: QM and Scattering e) Let’s consider the

~ pˆ 0 ⌃~ pˆ · , · ⌘ 0 ~ pˆ ✓ · ◆ b) What are its eigenvalues for p 0 ~ (1)p~ = 3p = (2) (1) u· A (2) 0 uAp u = (1) ,u✓= (2) ◆ uB ! uB ! c) where: 1 1 0 1 0 ( ~ pˆ) = = 3 1 1 1 2 · 12 20 0 u(1) = ,u(1) = ~ p/~ (E+m) ✓ u◆(2) = ✓ ,u◆ (2) = ~ p/~ (E+m) TheA eigenvalue0 -1/2B is· the z-component0 of theA spin. 1 B · 1 ✓ ◆ ✓ ◆ ✓ ◆ ✓ ◆ d) (Hint:1~ pˆ is rotate the spin your component frame such thatin thep~ points direction along of motion.the z-axis, such that you only 2 · needPossible to worry eigenvalue: about p3.)1/2. ± e) Positive and negative helicity: 4 Rutherford scattering 1000 1 (1) ~ (1) 3 0 uA 0 10 0 0 (1) We calculate(⌃ pˆ)u the= distribution of scattering(1) = angles0 for charged particles1 0 on a charged1 tar-=+u · 0 3 u 0010 pz/(E + m) get, like alpha particles✓ scattering◆ o↵B gold! nuclei as done by Ernest Rutherford in 1913. B 000 1 C B 0 C B C B C @ A @ A (⌃~ pˆ)u(2) = u(2) · Niels Tuning (11)

4 Rutherford scattering and Cross section

e) d Z Z ↵ 2 1 1 2 = 1 2 =(2mZ Z ↵)2 2 4 ✓ 1 2 2 2 2 ✓ d⌦ mv0 4 sin 4m v0 sin ⇣ ⌘ 2 ⇣ 2 ⌘ 0 2 2 0 2 2 2 2 2 2 2 ✓ q = 0 1 =(mv0) (sin ✓+(1 cos ✓) )=2(mv0) (1 cos ✓)=4m v0 sin mv0 sin ✓ 2 a) The incoming particle arrives with an impact parameter b, and initial velocity v0. B mv0(1 cos ✓) C The angularB momentum of theC initial state is L = mbv0, whereas the angular mo- mentum somewhere@ after the scatterA can be given by L = mrv = mr d/dr ? Express r in terms of b.

b) The force perpendicular to the direction of the incoming particle is given by Fy = 2 mdvy/dt, and Fy = F sin =(Z1Z2↵/r ) sin . Give the expression for dvy/dt, as a function of b (using the result from a).

3

2 e) Let’s consider the operator

~ pˆ 0 ⌃~ pˆ · , · ⌘ 0 ~ pˆ ✓ · ◆ What are its eigenvalues for

(1) (2) (1) uA (2) uA u = (1) ,u = (2) uB ! uB ! where: 1 1 0 0 u(1) = ,u(1) = ~ p/~ (E+m) u(2) = ,u(2) = ~ p/~ (E+m) A 0 B · 0 A 1 B · 1 ✓ ◆ ✓ ◆ ✓ ◆ ✓ ◆ (Hint: rotate your frame such that p~ points along the z-axis, such that you only need to worry about p3.)

4 Rutherford scattering

We calculate the distribution of scattering angles for charged particles on a charged tar- get, like alpha particles scattering o↵ gold nuclei as done by Ernest Rutherford in 1913.

b) p 0 ~ p~ = 3p = e) Let’s consider the operator · 0 p ✓ ◆ ~ pˆ 0 ⌃~ pˆ · , · ⌘ 0 ~ pˆ c) ✓ · ◆ What are its eigenvalues for

(1) (2) 1 1 0 1 0 (1) uA (2) uA u = (1) ,u = (2) ( ~ pˆ) = 3 = u u B ! B ! 2 · 2 1 2 1 where: ✓ ◆ ✓ ◆ 1 1 0 0 u(1) = The,u(1) eigenvalue= ~ p/~ (E+m) -1/2u(2) = is the,u(2) z-component= ~ p/~ (E+m) of the spin. A 0 B · 0 A 1 B · 1 ✓ ◆ ✓ ◆ ✓ ◆ ✓ ◆ (Hint: rotate1 your frame such that p~ points along the z-axis, such that you only Exercisesneedd) to worry2~ aboutpˆpis3.) the Lecture spin component 2: inQM the directionand Scattering of motion. Possible· eigenvalue: 1/2. 4 Rutherford scattering ± a) The incoming particle arrives with an impact parameter b, and initial velocity v . We calculatee) the Positive distribution of scattering and negative angles for charged particleshelicity: on a charged tar- 0 get, like alpha particles scattering o↵ gold nuclei as done by Ernest Rutherford in 1913. The angular momentum of the initial state is L = mbv0, whereas the angular mo- 1000mentum somewhere after1 the scatter can be given by L = mrv = mr d/dr (1) ? ~ (1) 3 0 uA 0Express10r 0in terms of 0b. (1) (⌃ pˆ)u = (1) = 0 1 0 1 =+u · 0 3 u 0010 pz/(E + m) ✓ ◆ B ! Bb)000 The force perpendicular1 C B 0 to theC direction of the incoming particle is given by F = B BeforeC B C y @ mdv /dt, andA @F = F sin =(A Z Z ↵/r2) sin . ~ (2) y (2) y 1 2 (⌃ pˆ)u Give= theu expression for dv /dt, as a function of b (using the result from a). a) The incoming particle arrives with an impact parameter b, and initial velocity v0. · y The angular momentum of the initial state is L = mbv0, whereas the angular mo- After: mentum somewhere after the scatter can be given by L = mrv = mr d/dr ? Express r in terms of b. dϕ/dt r b) The force perpendicular to the direction of the incoming particle is given by Fy = 3 2 4mdvy/dt Rutherford, and Fy = F sin =(Z1Z2↵/r ) sin . scattering Give the expression for dvy/dt, as a function of b (using the result from a).

3 a) d L = mv b = mr r 0 dt ! 1 r2 = bv 0 d/dt

b) dvy Z1Z2↵ Z1Z2↵ d Fy = m = F sin = 2 sin = sin Niels Tuning (12) dt r bv0 dt c)

v0 sin ✓ Z Z ↵ cos ✓ dv = 1 2 d cos ✓ (1) y mbv Z0 0 Zcos ⇡ Z1Z2↵ v0 sin ✓ = (cos ✓ +1) (2) mbv0 sin ✓ Z Z ↵ = 1 2 (3) cos ✓ 1 mbv2 0 d)

2 e) Let’s consider the operator

~ pˆ 0 ⌃~ pˆ · , · ⌘ 0 ~ pˆ ✓ · ◆ What are its eigenvalues for

(1) (2) (1) uA (2) uA u = (1) ,u = (2) uB ! uB ! where: 1 1 0 0 u(1) = ,u(1) = ~ p/~ (E+m) u(2) = ,u(2) = ~ p/~ (E+m) A 0 B · 0 A 1 B · 1 ✓ ◆ ✓ ◆ ✓ ◆ ✓ ◆ (Hint: rotate your frame such that p~ points along the z-axis, such that you only need to worry about p3.) b) p 0 4 Rutherford scattering ~ p~ = p = · 3 0 p ✓ ◆ We calculate the distribution of scattering angles for charged particles on a charged tar- get, likec) alpha particles scattering o↵ gold nuclei as done by Ernest Rutherford in 1913. 1 1 0 1 0 ( ~ pˆ) = = 2 · 2 3 1 2 1 ✓ ◆ ✓ ◆ The eigenvalue -1/2 is the z-component of the spin.

1 d) 2~ pˆ is the spin component in the direction of motion. Possible· eigenvalue: 1/2. ± e) Positive and negative helicity:

1000 1 (1) ~ (1) 3 0 uA 0 10 0 0 (1) (⌃ pˆ)u = (1) = 0 1 0 1 =+u a) The incoming· particle arrives0 with3 an impactu parameter 0010b, and initial velocity v0. pz/(E + m) ✓ ◆ B ! The angular momentum of the initial state is L = mbvB0,000 whereas the angular1 C mo-B 0 C mentum somewhere after the scatter can be given by BL = mrv = mr d/dr C B C Exercises Lecture 2: QM? and Scattering Express r in terms of b. @ A @ A (⌃~ pˆ)u(2) = u(2) b) The force perpendicular to the direction of the incoming· particle is given by Fy = 2 mdvy/dt, and Fy = F sin =(Z1Z2↵/r ) sin . Give the expression for dvy/dt, as a function of b (using the result from a).

4 Rutherford scattering3 c) We now multiply both sides with dt, and perform the integral from the start until a)the end, so the velocity on the left-hand side ranges from vy =0tovy = v0 sin ✓, and the angle on the right-hand side ranges from =0to = ✓. d Show that L = mv0b = mr r sin(✓/2) Z1Z2↵ 1 dt ! = 2 cos(✓/2) mv0 b 1 r2 = bv d) For a given surface (ring) of possible incoming particles, d 0=dbdbd/dt, the particle is scattered in a certain solid angle d⌦ = sin ✓d✓d. Show that the expression for b)the di↵erential cross section is given by, 2 d b dvdby Z1Z2↵ 1 Z1Z2↵ Z1Z2↵ d Fy == m == F sin2 = 4 ✓ sin = sin d⌦ sin ✓ d✓ mv0 4 sin 2 dt ⇣ ⌘ 2 r bv0 dt

e) Use the 4-vectors pi =(E,0, 0, mv0) and po =(E,0, mv0 sin ✓,mv0 cos ✓) for the in- comingc) and outgoing particle, respectively, and express the di↵erential cross section in terms of the 4-momentum transfer q = p p , instead of ✓. o i v0 sin ✓ Z Z ↵ cos ✓ dv = 1 2 d cos ✓ (1) y mbv 5 Cross section Z0 0 Zcos ⇡ Z1Z2↵ v0 sin ✓ = (cos ✓ +1) (2) Let’s juggle a bit with cross sections and luminosities. mbv0 sin ✓ Z Z ↵ = 1 2 (3) a) The total cross section for proton-proton scattering at the LHC2 is about tot = cos ✓ 1 mbv0 28 2 60 mb. To what surface does this cross section correspond? (1 barn = 10 m .) Niels Tuning (13) What is the size of an object with similar surface? d) b) The cross section for Higgs production at the LHC is approximately pp H+X = ! 30 pb. The “luminosity” is the number of particles produced for a given cross- section, and is an important characteristic of the performance of an accelerator. How 1 many Higgs particles are then produced for a total luminosity of =10fb ? 2 Ltot 34 1 2 c) The “instantaneous” luminosity at the LHC is about inst =10 s cm . How many Higgs particles are thus produced per hour? L

d) Compare the total proton-proton cross section with the cross section for Higgs pro- duction. In what fraction of the proton-proton collisions is a Higgs particle pro- duced?

4 c) WeExercises now multiply both Lecture sides with dt ,2: and performQM theand integral Scattering from the start until the end, so the velocity on the left-hand side ranges from vy =0tovy = v0 sin ✓, and the angle on the right-hand side ranges from =0to = ✓. Show that sin(✓/2) Z1Z2↵ 1 = 2 cos(✓/2) mv0 b d) For a given surface (ring) of possible incoming particles, d = bdbd, the particle is scattered in a certain solid angle d⌦ = sin ✓d✓d. Show that the expression for the di↵erential cross section is given by,

2 d b db Z1Z2↵ 1 = = 2 4 ✓ d⌦ sin ✓ d✓ mv0 4 sin ⇣ ⌘ 2

e) Use the 4-vectors pi =(E,0, 0, mv0) and po =(E,0, mv0 sin ✓,mv0 cos ✓) for the in- coming and outgoing particle, respectively, and express the di↵erential cross section in terms of the 4-momentum transfer q = p p , instead of ✓. o i

5 Cross section

Let’s juggle a bit with cross sections and luminosities.

a) The total cross section for proton-proton scattering at the LHC is about tot = 28 2 60 mb. To what surface does this cross section correspond? (1 barn = 10 m .) What is the size of an object with similar surface?

b) The cross section for Higgs production at the LHC is approximately pp H+X = ! 30 pb. The “luminosity” is the number of particles produced for a given cross- section, and is an important characteristic of the performance of an accelerator. How Niels Tuning (14) 1 many Higgs particles are then produced for a total luminosity of =10fb ? Ltot 34 1 2 c) The “instantaneous” luminosity at the LHC is about inst =10 s cm . How many Higgs particles are thus produced per hour? L

d) Compare the total proton-proton cross section with the cross section for Higgs pro- duction. In what fraction of the proton-proton collisions is a Higgs particle pro- duced?

4 Rutherford

Ø 3d: incoming particle “sees” surface dσ, and scatters off solid angle dΩ Before § Conservation of angular momentum: a) After: § Force: using L conservation Replace r by b, b) c) d)

=(cosθ + 1)

Niels Tuning (15) c) We now multiply both sides with dt, and perform the integral from the start until the end, so the velocity on the left-hand side ranges from vy =0tovy = v0 sin ✓, and the angle on the right-hand side ranges from =0to = ✓. Show that sin(✓/2) Z1Z2↵ 1 = 2 cos(✓/2) mv0 b d)Exercises For a given surface Lecture (ring) of 2: possible QM incoming and particles,Scatteringd = bdbd , the particle is scattered in a certain solid angle d⌦ = sin ✓d✓d. Show that the expression for the di↵erential cross section is given by,

2 d b db Z1Z2↵ 1 = = 2 4 ✓ d⌦ sin ✓ d✓ mv0 4 sin ⇣ ⌘ 2

e) Use the 4-vectors pi =(E,0, 0, mv0) and po =(E,0, mv0 sin ✓,mv0 cos ✓) for the in- coming and outgoing particle, respectively, and express the di↵erential cross section in terms of the 4-momentum transfer q = p p , instead of ✓. o i

5 Cross section e) Let’s juggle a bit with cross sections and luminosities.

a) The total cross section for proton-proton scattering at the LHC is about tot = 28 2 60 mb. To what surface does this cross section correspond? (1 barn = 10 m .) What is the size of an object with similar surface?

b) The cross section for Higgs production at the LHC is approximately pp H+X = ! 30 pb. The “luminosity” is the number of particles produced for a given cross- section, and is an important characteristic of the performance of an accelerator. How 1 many Higgs particles are then produced for a total luminosity of tot =10fb ? L Niels Tuning (16) 34 1 2 c) The “instantaneous” luminosity at the LHC is about inst =10 s cm . How many Higgs particles are thus produced per hour? L

d) Compare the total proton-proton cross section with the cross section for Higgs pro- duction. In what fraction of the proton-proton collisions is a Higgs particle pro- duced?

4 c) We now multiply both sides with dt, and perform the integral from the start until the end, so the velocity on the left-hand side ranges from vy =0tovy = v0 sin ✓, and the angle on the right-hand side ranges from =0to = ✓. Show that sin(✓/2) Z1Z2↵ 1 = 2 cos(✓/2) mv0 b d) For a given surface (ring) of possible incoming particles, d = bdbd, the particle is scattered in a certain solid angle d⌦ = sin ✓d✓d. Show that the expression for the di↵erential cross section is given by,

2 d b db Z1Z2↵ 1 = = 2 4 ✓ d⌦ sin ✓ d✓ mv0 4 sin ⇣ ⌘ 2

e) Use the 4-vectors pi =(E,0, 0, mv0) and po =(E,0, mv0 sin ✓,mv0 cos ✓) for the in- coming and outgoing particle, respectively, and express the di↵erential cross section in terms of the 4-momentum transfer q = p p , instead of ✓. Exercises Lecture 2: QM oand i Scattering 5 Cross section

Let’s juggle a bit with cross sections and luminosities.

a) The total cross section for proton-proton scattering at the LHC is about tot = 28 2 60 mb. To what surface does this cross section correspond? (1 barn = 10 m .) What is the size of an object with similar surface?

b) The cross section for Higgs production at the LHC is approximately pp H+X = ! 30 pb. The “luminosity” is the number of particles produced for a given cross- section, and is an important characteristic of the performance of an accelerator. How 1 many Higgs particles are then produced for a total luminosity of =10fb ? Ltot 34 1 2 c) The “instantaneous” luminosity at the LHC is about inst =10 s cm . How many Higgs particles are thus produced per hour? L

d) Compare the total proton-proton cross section with the cross section for Higgs pro- duction. In what fraction of the proton-proton collisions is a Higgs particle pro- duced?

4

Niels Tuning (17) Lecture 1: Standard Model & Relativity

• Standard Model Lagrangian

• Standard Model Particles

Niels Tuning (18) Lecture 1: Accelerators & Relativity

• Theory of relativity – Lorentz transformations (“boost”) – Calculate energy in collissions

• 4-vector calculus

• High energies needed to make (new) particles

Niels Tuning (19) Lecture 2: Quantum Mechanics & Scattering

• Schrödinger equation – -dependence of function

• Klein-Gordon equation – Relativistic equation of motion of scalar particles

Ø Dirac equation – Relativistically correct, and linear – Equation of motion for spin-1/2 particles – Prediction of anti-matter

Niels Tuning (20) Lecture 2: Quantum Mechanics & Scattering

• Scattering Theory – (Relative) probability for certain process to happen – Cross section

Classic Scattering amplitude in • Fermi’s Golden Rule

– Decay: “decay width” Γ a → b + c – Scattering: “cross section” σ a + b → c + d

Niels Tuning (21) Resonances Quantum mechanical description of decay

State with energy E0 ( ) and lifetime τ To allow for decay, we need to change the time-dependence:

What is the wavefunction in terms of energy (instead of time) ? Ø Infinite sum of flat waves, each with own energy

Ø Fourier transformation:

1 = Ψ0 ⎛ i ⎞ i⎜(E0 − E)− Γ⎟ ⎝ 2 ⎠ Resonance

P Probability to find particle with max Breit-Wigner energy E:

Pmax/2

E0-Γ/2 E0 E0-Γ/2

Resonance-structure contains information on: § Mass § Lifetime § Decay possibilities Rutherford

Ø 3d: incoming particle “sees” surface dσ, and scatters off solid angle dΩ Ø Calculate:

Niels Tuning (25) Scattering Theory

Let’s try some potentials

• Yukawa: (Pion exchange)

• Coulomb: ()

• Centrifugal Barier: (Resonances)

Niels Tuning (26) Well-known resonances e+e- cross-section e+e-→R→ e+e-

Z-boson

J/ψ Outline for today

• Resonances • Quarkmodel – Strangeness – Color • Symmetries – Isospin – Adding spin – Clebsch Gordan coefficients

Niels Tuning (28) Lecture 1: Standard Model & Relativity

• Standard Model Lagrangian

• Standard Model Particles

Niels Tuning (29) Particles

• Quarks and leptons…:

Niels Tuning (30) Particles…

Niels Tuning (31) The number of ‘elementary’ particles

1932: 1936: 1947: electron electron electron proton proton proton neutron neutron neutron muon muon pion

1947

§ 1932: the positron had been observed to confirm Dirac’s theory, § 1947: and the pion had been identified as Yukawa’s strong force carrier,

Ø So, things seemed under control!?

§ Ok, the muon was a bit of a mystery…

§ Rabi: “Who ordered that?” Quark model Discovery strange particles

Discovery strange particles Discovery strange particles

• Why were these particles called strange? Ø Large production cross section (10-27 cm2) Ø Long lifetime (corresponding to process with cross section 10-40 cm2)

Niels Tuning (36) Discovery strange particles

• Why were these particles called strange? Ø Large production cross section (10-27 cm2) Ø Long lifetime (corresponding to process with cross section 10-40 cm2)

• Associated production!

Niels Tuning (37) Discovery strange particles

• Why were these particles called strange? Ø Large production cross section (10-27 cm2) Ø Long lifetime (corresponding to process with cross section 10-40 cm2)

• Associated production!

Niels Tuning (38) Discovery strange particles

• Why were these particles called strange? Ø Large production cross section (10-27 cm2) Ø Long lifetime (corresponding to process with cross section 10-40 cm2)

• Associated production! π

New : Ø Strangeness, S Ø Conserved in the strong K π interaction, ΔS=0 π § Particles with S=+1 and p S=-1 simultaneously Λ produced π Ø Not conserved in individual decay, ΔS=1 Niels Tuning (39) Discovery strange particles

• Why were these particles called strange? Ø Large production cross section (10-27 cm2) Ø Long lifetime (corresponding to process with cross section 10-40 cm2)

Production: • Associated production! - 0 0 π π p→K Λ

New quantum number: Decay: 0 - + Ø Strangeness, S K → π π Λ0 → π-p Ø Conserved in the strong K π interaction, ΔS=0 π § Particles with S=+1 and p S=-1 simultaneously Λ produced π Ø Not conserved in individual decay, ΔS=1 Niels Tuning (40) Intermezzo: conserved quantities

• What is conserved in interactions? – Decays & Scattering

Ø Energy, momentum Ø Electric charge Ø Total angular momentum (not just spin) • Strangeness? • Baryon number • Lepton flavour • Colour? • Parity? • CP ? • … Niels Tuning (41) Kinematics - 0 + π K S π m1 m2 M Specific (m1=m2=m): before after

What is the energy of final-state particles? Kinematics π - Λ0 p

m1 m2 M

Specific: (m1=m2=m)

What if masses of final-state particles differ, m1≠m2 ?

General: M 2 ± Δ(m2 ) E1,2 = p =? 2M 1,2 Strange particles

Mesons Baryons Strangeness Particle Mass S Particle Mass S K0 497.7 +1 Σ+ 1189.4 -1

K+ 493.6 +1 Σ0 1192.6 -1 K- 493.6 -1 - K0 497.7 -1 Σ 1197.4 -1

Λ0 1115.6 -1

Ξ0 1314.9 -2 isdifferent…? What

Ξ- 1321.3 -2

Corresponding anti-baryons have positive Strangeness 50’s – 60’s

• Many particles discovered à ‘particle zoo’

• Will Lamb: “The finder of a new particle used to be awarded the Nobel Prize, but such a discovery now ought to be punished with a $10,000 fine.” • : “If I could remember the names of all these particles, I'd be a botanist.” • : “Had I foreseen that, I would have gone into botany."

Niels Tuning (45) The number of ‘elementary’ particles

“Particle Zoo” Strange particles

The 8 lightest strange baryons: baryon octet

Particle Mass S

n 938.3 0

p 939.6 0

Σ+ 1189.4 -1

Σ0 1192.6 -1

Σ- 1197.4 -1

Λ0 1115.6 -1

Ξ0 1314.9 -2

Ξ- 1321.3 -2

Breakthrough in 1961 (Murray Gell-Mann): “The eight-fold way” (Nobel prize 1969)

Also works for: Eight lightest mesons - meson octet Other baryons - baryon decuplet Strange particles

The Noble Eightfold Path is one of the principal The 8 lightest strange baryons: baryon octet teachings of the Buddha, who described it as the way leading to the cessation of suffering and the achievement of self-awakening. Particle Mass S

n 938.3 0

p 939.6 0

Σ+ 1189.4 -1

Σ0 1192.6 -1

Σ- 1197.4 -1

Λ0 1115.6 -1

Ξ0 1314.9 -2

Ξ- 1321.3 -2

Breakthrough in 1961 (Murray Gell-Mann): “The eight-fold way” (Nobel prize 1969)

Also works for: Eight lightest mesons - meson octet Other baryons - baryon decuplet Strange particles

The 8 lightest strange baryons: baryon octet strangeness: Particle Mass S

n 938.3 0

p 939.6 0

Σ+ 1189.4 -1

Σ0 1192.6 -1

Σ- 1197.4 -1

Λ0 1115.6 -1

Ξ0 1314.9 -2

Ξ- 1321.3 -2

Breakthrough in 1961 (Murray Gell-Mann): “The eight-fold way” (Nobel prize 1969)

Also works for: Eight lightest mesons - meson octet Other baryons - baryon decuplet Discovery of Ω-

Not all multiplets complete…

1232 MeV

1385 MeV

1533 MeV

Gell-Mann and Zweig predicted the Ω- … and its properties Discovery of Ω-

Not all multiplets complete…

1232 MeV

1385 MeV

1533 MeV

1680 MeV

Gell-Mann and Zweig predicted the Ω- … and its properties The Discovery of the Ω– baryon

Ω=sss

- Discovery of Ω Discovered in 1964: K– + p àΩ– + K+ + K0 Not all multiplets complete… Ξ0 + π– Λ0 + 2γ pπ Spectacular confirmation of the quark model 1232 MeV

1385 MeV

1533 MeV

1680 MeV

Gell-Mann and Zweig predicted the Ω- … and its properties The Discovery of the Ω– baryon

Ω=sss

– The Discovery of the - Ω baryon Discovery of Ω Discovered in 1964: K– + p àΩ– + K+ + K0 Not all multiplets complete… Ξ0 + π– Ω=sss Λ0 + 2γ pπ Spectacular confirmation of the quark model 1232 MeV

1385 MeV

1533 MeV

1680 MeV

Discovered in 1964: K– Gell-Mann and Zweig predicted the + p àΩ– + K+ + K0 Ω- … and its properties Ξ0 + π– Λ0 + 2γ pπ Spectacular confirmation of the quark model Quark model

Gell-Mann en Zweig (1964):

“All multiplet patterns can be explained if you assume hadrons are composite particles built from more elementary constituents: quarks”

§ First quark model: § 3 types: up, down en strange (and anti-quarks) § Baryons: 3 quarks ! § Mesons: 2 quarks 26 3+3

mesonen

up down strange baryonen p = uud n = udd Σ+ = uus Λ0 = uds Ξ0 = uss Quark model

• Mesons: – Octet • Baryons: – Octet – Decuplet

Niels Tuning (55) 0 New last year: Ωc (css) • Just discovered 5 excited (ccs) states

• Still active research! 0 The Magic of the Ωc baryon + + – 1. Reconstruct Ξc = csu state 2. Combine Ξc with K :

+ – + Strong decay: Ω 0 àΞ + K– Ξc à p K π c c

0 5 narrow Ωc states ! 0 Ωc = css state

+ Spectrum Ξc sideband

Niels Tuning (56)

5 new particles discovered: 0 0 0 0 0 Ωc(3000) , Ωc(3050) , Ωc(3065) , Ωc(3090) , Ωc(3119) 0 0 + – Excited states of Ωc baryon, decaying as: Ωc àΞc K The number of ‘elementary’ particles “Problems”

1) Are quarks ‘real’ or a mathematical tric? 2) How can a baryon exist, like Δ++ with (u↑u↑u↑), given the Pauli exclusion principle?

Niels Tuning (58) “Problem” of quark model

s s Intrinsic spin: = symmetric Ω- s quarks: = symmetric

u u Intrinsic spin: = symmetric ++ Δ u quarks: = symmetric

J=3/2, ie. fermion, ie. obey Fermi-Dirac statistics: anti-symmetric wavefunction

New quantum number: color! - 3 values: red, green, blue s ! s s s - Only quarks, not the leptons The Particle Zoo mass

Force carier: γ <1x 10-18 eV

- - - Leptons: e ,µ ,τ ,υe,υµ,υτ ~0 – 1.8 GeV

Mesons: π+,π0,π-,K+,K-,K0,ρ+,ρ0,ρ- 0.1-1 GeV

+ - 0 ++ + 0 - 1-few GeV Baryons: p,n,Λ,Σ ,Σ ,Σ ,Δ ,Δ ,Δ , Δ , Ω,…

http://pdg.lbl.gov/ Protons and neutrons

Proton and neutron identical under strong interaction

proton neutron

mp = 938.272 MeV mn = 939.565 MeV

?

Nucleon + internal degree of freedom to distinguish the two Multiplets

Pattern (mass degeneracy) suggest internal degree of freedom

m = 1232 MeV

m = 1385 MeV

m = 1530 MeV

m = 1672 MeV

Baryon decuplet Eightfold way

• Introduction of quarks • Introduction of quantum numbers – Strangeness – Isospin

Niels Tuning (63) Introduction and summary The prospect of hadrons with more thanTetra- the minimal and quarkpentaquarks content (qq or qqq ??)was proposed by Gell-Mann in 1964 [1] and Zweig [2], followed by a quantitative model for two quarks plus two antiquarks developed by Ja↵ein1976[3].Theideawasexpandedupon[4] to include baryons composed of four quarks• Tetraquark plus one antiquark; discovered the name pentaquark in 2003 was coined by Lipkin [5]. Past claimed observations– X(3872) of pentaquark states have been shown to be spurious [6], although there is at least one viable tetraquark candidate, the Z(4430)+ 0 + observed in B 0K⇡ decays [7–9], implying– Also that charged the existence cc and of pentaquark bb states baryon… states would not! be surprising. States that decay into charmonium may have particularly distinctive signatures [10]. 0 Large yields of ⇤b J/ Kp decays are available at LHCb and have been used for ! 0 the precise measurement of the ⇤b lifetime [11]. (In this Letter mention of a particular mode4 implies Details use of its charge of conjugatethe matrix as well.) This element decay can proceed for by the the diagram decay ampli- shown in Fig. 1(a), and is expected to be dominated by ⇤⇤ Kp resonances, as are ! evident intude our data shown in Fig. 2(a). It• couldPentaquark also have exotic discovered contributions, asin indicated2016 by the diagram in Fig. 1(b), that could result in resonant structures in the J/ p mass + 0 – Pc (4450)+ 2 spectrumThe matrix shown in element Fig. 2(b). for ⇤b Kp, µ µ decays must allow for various conven- ! ! + tional ⇤⇤ Kp resonances and exotic pentaquark states Pc p that could interfere with each! other. ! We use the helicity formalism to write down the matrix element. To make the derivation of the matrix element easier to comprehend we start with a brief outline of this formalism 0 and our notation. Then we discuss the application to the ⇤b ⇤⇤ , ⇤⇤ Kp, + ! ! µ µ decay sequence, called hereafter the ⇤⇤ decay chain matrix element. Next we ! 0 0 + + 0 + + discussFigure construction 1: Feynman diagrams of the for⇤ (a)b ⇤ Pc J/K ⇤⇤, andPc (b) ⇤ p,P c K decay.µ µ decay sequence, called !b ! ! b ! ! Niels Tuning (64) hereafter the Pc decay chain matrix element, which can be coherently added to that for the

⇤⇤ 3000decay chain. We also discuss a possible reduction of the number of helicity couplings to be determined from the data using their relationships(b) toLHCb the LS couplings. 2500 (a) LHCb 800

2000 600 Events/(15 MeV) Events/(20 MeV) data 4.11500 Helicity formalism and notation phase space 400 For1000 each two-body decay A BC, a coordinate system is set up in the rest frame of A, ! 3 200 with500zˆ being the direction of quantization for its spin. We denote this coordinate system A A A as (x { },y { },z { }), where the superscript “ A ”means“intherestframeofA”, while 0 0 0 { } the subscript1.4 1.6 1.8“0” 2.0means 2.2 the 2.4 initial coordinates.4.0 4.2 4.4 For 4.6 the first4.8 5.0 particle in the decay chain m [GeV] m ψ [GeV] 0 K p 4 J/ p (⇤b ), the choice of these coordinates is arbitrary. However, once defined, these coordinates 0 Figuremust 2: beInvariant used mass consistently of (a) Kp betweenand (b) J/ allp combinations decay sequences from ⇤ describedJ/ Kp decays. by the matrix element. b ! TheFor solid subsequent (red) curve is decays,the expectatione.g. B from phaseDE space., the The choice background of these has been coordinates subtracted. is already fixed by the transformation from the A !to the B rest frames, as discussed below. Helicity is defined as the projection of the spin of the1 particle onto the direction of its momentum. When the z axis coincides with the particle momentum, we denote its spin projection onto it (i.e. the mz quantum number) as . To use the helicity formalism, the initial coordinate system must be rotated to align the z axis with the direction of the momentum of one of the daughter particles, e.g. the B. A generalized rotation operator can be formulated in three-dimensional space, (↵, , ), that uses Euler angles. Applying this operator results R in a sequence of rotations: first by the angle ↵ about the zˆ0 axis, followed by the angle about the rotated yˆ1 axis and then finally by the angle about the rotated zˆ2 axis. We use asubscriptdenotingtheaxes,tospecifytherotationswhichhavebeenalreadyperformed A A A on the coordinates. The spin eigenstates of particle A, J ,m ,inthe(x { },y { },z { }) | A Ai 0 0 0 coordinate system can be expressed in the basis of its spin eigenstates, J ,m0 ,inthe | A Ai 2We denote J/ as for eciency of the notation. 3The “hat” symbol denotes a unit vector in a given direction. 4When designing an analysis to be sensitive (or insensitive) to a particular case of polarization, the 0 choice is not arbitrary, but this does not change the fact that one can quantize the ⇤b spin along any 0 well-defined direction. The ⇤b polarization may be di↵erent for di↵erent choices.

23 Timeline

• Active research…:

Niels Tuning (65) InIn thethe news News last year

Niels Tuning (66) Patrick Koppenburg Pentaquarks at hadron colliders 18/01/2017 — Physics at Veldhoven [2 / 33] [LHCb, Phys. Rev. Lett. 115 (2015) 072001, arXiv:1507.03414] What is a Pentaquark?

>300 papers citing the result, with many possible interpretations. Niels Tuning (67) Patrick Koppenburg Pentaquarks at hadron colliders 18/01/2017 — Physics at Veldhoven [26 / 33] Symmetries Conserved quantities

Time dependence of observable U: Hamilton formalism:

If U commutes with H, [U,H]=0 (and if U does not depend on time, dU/dt=0)

Then U is conserved: d/dt = 0

U conserved à U generates a symmetry of the system Niels Tuning (69) Other symmetries:

Transformation Conserved quantity

Translation (space) Momentum Translation (time) Energy Rotation (space) Orbital momentum Rotation (iso-spin) Iso-spin Quantum mechanics: orbital momentum

Lx and Ly cannot be known simultaneously Sequence matters!

2 L and Li (i=x,y,z) can be known simultaneously Can both be used to label states

2 [L ,H] =[Lz,H] = 0 Provided V = V(r), ie not θ dependent 2 L and Lz label eigenstates

€ Quantum mechanics: orbital momentum

m m fl =Yl spherical harmonics

Lz

m = -l, -l+1, …, 0, … , l-1, l 22

Different notation: 1

0

Ly

-1

Lx

-2 Quantum mechanics: (intrinsic) spin

Spin is characterized by: - total spin S

- spin projection SZ

Rotations: SO(3) group Internal symmetry: SU(2) group similar

Spin is quantized, Eigenfunctions |s,ms>: just as orbital momentum

spin-½ particles

spin- spin- up down spin-½ particles

Complex numbers

general 2 |α| prob for Sz = +

2 |β| prob for Sz = -

-

Pauli matrices: any complex 2x2 matrix can be written as: A = aσ1+bσ2+cσ3 Isospin Protons and neutrons

Proton and neutron identical under strong interaction

proton neutron

mp = 938.272 MeV mn = 939.565 MeV

?

Nucleon + internal degree of freedom to distinguish the two Protons and neutrons: Isospin

Proton and neutron identical under strong interaction

proton neutron

mp = 938.272 MeV mn = 939.565 MeV

Introduce new quantum number: isospin

Proton and neutron (‘nucleons’): I en I3 Nucleon

+ internal degree of freedom Isospin ’up’ Isospin ‘down’ Possible states for given value of the Isospin Possible states for given value of the Isospin

Iz = +3/2 Iz = +1 Iz = +1/2 Iz = +1/2 Iz = 0 Iz = -1/2 Iz = -1/2 Iz = -1 Iz = -3/2 Possible states for given value of the Isospin

Iz = +3/2 Iz = +1 Iz = +1/2 Iz = +1/2 Iz = 0 Iz = -1/2 Iz = -1/2 Iz = -1 Iz = -3/2

Δ++ π+ proton Δ+ π0 Δ0 neutron π- Δ-

mp ~ 939 MeV mπ ~ 140 MeV mΔ ~ 1232 MeV Iz=-1 Iz=0 Iz=+1

I = 3/2

+ 0 - π π π I = 1

p n I = 1/2

I = 0

Baryon decuplet Adding spin Quantum mechanica: adding spin

|s1,m1> + |s2,m2> à |s,m>

1) Conditions: - S add up m= m + m z 1 2 S = |s -s |, |s -s |+1, .. , s +s -1 s +s 1 2 1 2 1 2 , 1 2 - S can vary between difference and sum

2) Notation:

C: Clebsch-Gordan coefficient Adding spin of two spin-½ particles

Sz S

(1) +1 1

(2) 0 ?

(3) -1 1 Adding spin of two spin-½ particles

Sz S

(1) +1 1

(2a) ( + ) 0 1 (2b) ( - ) 0 0

(3) -1 1 Adding spin of two spin-½ particles 2 ⊗ 2 = 3⊕1

S=1 Triplet (symmetric) ( + )

Singlet S=0 (anti-symmetric) ( - ) Adding spin of two spin-½ particles 2 ⊗ 2 = 3⊕1

Triplet (symmetric)

Singlet (anti-symmetric) Quantum mechanics: adding spin

Clebsch-Gordan coefficient

Specific: adding spin of two spin-1/2 particles:

Triplet (symmetric) ( + )

Singlet (anti-symmetric) ( - ) Why is and not ?

Sz

1

0 ?

Sy

Sx - 1 Griffiths Par 4.4.3 Clebsch-Gordan coefficients

Coefficients can be used “both ways”:

1) add

|s1,m1> + |s2,m2> à |s,m>

2) decay

|s,m> à |s1,m1> + |s2,m2> Clebsch-Gordan coefficients

A) Find out yourself (doable, but bit messy…) Every coefficient has sqrt decay decay Every coefficient has sqrt

scattering Every coefficient has sqrt Every coefficient has sqrt

|s,m> à |s1,m1> + |s2,m2> Decay: Every coefficient has sqrt

|s1,m1> + |s2,m2> à |s,m> 2-particle process: Example: πp scattering

1) π+p→ π+p

§ Iz = 3/2 § è Pure I = 3/2 ! 2) π-p→ π-p § I = 3/2 1 1 1 3 1 2 1 1 z |1,−1〉 | , 〉 = | ,− 〉 − | ,− 〉 § è Mixed I ! 2 2 3 2 2 3 2 2

What is relative cross section to make the I=3/2 resonance?

Niels Tuning (98) Example: πp scattering σ (π + p → Δ++ →π + p)~ 200mb Compare Δ resonance in elastic scattering: 1) π+p→ π+p 2) π-p→ π-p

σ (π − p → Δ0 →π − p)~ 25mb

Niels Tuning (99) Group theory 3 3 8 1 • Mesons: ⊗ = ⊕ – 2 quarks, with 3 possible flavours: u, d, s – 32 =9 possibilities = 8 + 1

q=1

Niels Tuning (100) Group theory 3 3 8 1 • Mesons: ⊗ = ⊕ – 2 quarks, with 3 possible flavours: u, d, s – 32 =9 possibilities = 8 + 1

η'

Niels Tuning (101) Group theory 3⊗3⊗3 =10 ⊕8 ⊕8 ⊕1 • Baryons: S M M A – 3 quarks, with 3 possible flavours: u, d, s – 33 =27 possibilities = 10 + 8 + 8 + 1

ψ sym ψ anti−sym (1 ↔ 2) ψ anti−sym (2 ↔ 3)

Niels Tuning (102) Group theory 3⊗3⊗3 =10 ⊕8 ⊕8 ⊕1 • Baryons: S M M A – 3 quarks, with 3 possible flavours: u, d, s – 33 =27 possibilities = 10 + 8 + 8 + 1

ψ sym ψ anti−sym (1 ↔ 2) ψ anti−sym (2 ↔ 3)

Niels Tuning (103) What did we learn about quarks

Quarks: • Associate production, but long lifetime: strangeness • Many (degenerate) particles: isospin • Pauli exclusion principle: color

• How they combine into hadrons: multiplets • How to add (iso)spin: Clebsch-Gordan

Niels Tuning (104) Plan

Theory Next-next Detection and sensor techn.

Quantum Quantum Forces Mechanics Field Theory

Interactions Light Scintillators with Matter PM

Tipsy Accelerators Bethe Bloch Medical Imag. Next Cyclotron Photo effect X-ray Compton, pair p. Proton therapy Bremstrahlung Cherenkov Experiments Fundamental Astrophysics Charged Particles Physics Cosmics Particles ATLAS Grav Waves Km3Net Si Neutrinos Virgo Gaseous Lisa Pixel …

Special General Gravity Optics Relativity Relativity Laser

Niels Tuning (105) Plan

Theory Next-next Detection and sensor techn.

Niels 2) Niels 2) Niels 7) + 10) Quantum Quantum Forces Mechanics Field Theory 5) + 8) 4) Harry Particles 3) Harry

Light RelativisticIn Next teractions 6) + 9) with Matter Ernst-Jan 1) Harry 11) +12) Martin Fundamental 6) Ernst-Jan Accelerators Martin Physics 13) + 14) Astrophysics Charged Excursions Particles Experiments

1) Niels 9) Ernst-Jan 9) Ernst-Jan 9) Ernst-Jan Special General Gravity Optics Relativity Relativity

Niels Tuning (106) Plan

1) Intro: Standard Model & Relativity 11 Feb 1900-1940 2) Basis 18 Feb 1) Atom model, strong and weak force 2) Scattering theory 1945-1965 3) Hadrons 10 Mar 1) Isospin, strangeness 2) Quark model, GIM 1965-1975 4) Standard Model 24 Mar 1) QED 2) Parity, neutrinos, weak inteaction 3) QCD

1975-2000 5) e+e- and DIS 21 Apr

2000-2015 6) Higgs and CKM 12 May

Niels Tuning (107)