Fundamentals of

Structure of a C Program

1 Our First Simple Program

Comments - Different Modes

2 Comments - Rules

Preprocessor Directives

Preprocessor directives start with # e.g. #include copies a file into the source code before compilation

2 forms…..we will usually see the first #include #include “undefinedFilename” Within “ ” : personal file in your own directory

3 We will almost always use #include

• stdio.h is the standard input/output header • Contains code required for I/O (Input/Output) •.hfiles are header files Includes header ; The .obj part on Linking NO code is generally included except on linking • Header files contain definitions

The function : main()

ALL Programs must have a main() function. Later we will have add other functions. Different Formats: main( ) int main (void ) ***The book likes this void main(void) int main( )

4 main( ) , void main(void) End with return;

************************** int main (void ) , int main( ) End with return 0;

Back To Our First Program

5 Variables A Variable is a block of memory that stores data.

A variable has a particular “Type”, i.e. it stores a particular kind of data

A variable is named with an appropriate Identifier (or Name)

Suppose we have a variable declared as follows:

int number_of_days

This reserves a block of memory which holds an integer

6 Schematic view: number_of_days 365

In the course of the program we might want to change the value in the variable. So that later we might want: number_of_days 7361

• The “actual” view of memory: 4 bytes

number_of_days 01100000 11001010 10010100 00100111

So a variable takes a fixed number of bytes in memory

7 Rules for Naming Variables

1. First character: alphabetic or underscore

2. Consist only of alphanumeric or underscores

3. Only first 31 characters count

4. Cannot duplicate a reserved word

Legal/Illegal Variable Names

Use meaningful names

Legal Illegal a $sum student_name 2names salary stdnt number time_of_day int

8 Standard

Primitive C Data Types

Data Type C-Implementation void void character char (1 byte) unsigned short int (1 byte) unsigned int (2 or 4 bytes) unsigned long int (4 or 8 bytes) integer short int (1 or 2 byte) int (2 or 4 bytes) long int (4 or 8 bytes) float (4 bytes) floating point double (8 bytes) (10 bytes)

9 Variables : Declaration

Variables : Initialization How we put a value in a variable

• At compile time in the declaration:

e.g. int x=5;

• At run time by an assignment:

e.g. x =5;

• At run time by an input statement:

e.g.scanf(“%”,&x);

10 No variable is initialized until you do so!

You can initialize a variable in the declaration char code = ‘B’; char letter = ‘B’; int i = 0; int age = 65; float pie = 3.1415; float salary 27.57; double variable2 = 3.1415926535;

Special Characters

ASCII Character Symbolic Name Null character ’\0’ Alert (bell) ’\a’ Backspace ’\b’ Horizontal tab ’\t’ Newline ’\n’ Vertical Tab ’\v’

11 Special Characters

ASCII Character Symbolic Name Form Feed ’\f’ Carriage return ’\r’ Single quote ’\’’ Double Quote ’\”’ Backslash ’\\’

Strings : Constants

12 Preprocessing : #define Defines constants #define name token

Replaces the name with the token

Example: #define PI 3.1415926535 #define SIZE 1000

Syntax for Define : #define

•Noequals sign

•Nosemicolon at the end

13 Constants

To define a constant define a “variable” (usually, U.C.) with keyword: const This is how it works: const float PI = 3.1415926; This does NOT work: const float PI; PI = 3.1415926; /* not allowed to change it */

May be collected into a header file for general use

Standard Input and Output

14 To OUTPUT you require

#include

printf(format string, data list);

Field specifiers are inside the format string i.e. Controls how the data looks when printed

Standard printf statements #include void main( ) /* This codes prints the values of two variables */

{ int a = 57; int b = 145;

printf( "%d\n%d\n", a,b); return; }

15 What happened? The statements int a = 57; a 57 int b = 145; b 145

The statement printf( "%d\n%d\n", a , b); prints: 57 145

Field Specifiers

%code

Codes: Size Code Type Example none c char %c h d short int %hd none d int %d l or L d long int %Ld none f float %f none f double %f L f long double %Lf

16 Specification of Width

Value %d %4d

12 12 12

123 123 123

1234 1234 1234

12345 12345 12345

Precision specification for floats:

%7.2f

/* this prints the float in a field of seven characters with two characters after decimal: nnnn.dd */

17 Another Example of printf #include int main() /* This codes prints the values of two variables */

{ int months = 9; float salary = 145.35; printf( "%d\n%7.2f\n", months , salary); return 0; }

Another Example of printf #include int main( ) /* This codes prints the values of two variables */ { int months = 9; float salary = 145.35; printf( "the number of months is%4d\nthe salary is%7.2f\n", months,salary); return 0; }

18 The output

the number of months is 9 the salary is 145.35

Input: Getting information into memory: (reading) Requires: #include scanf(format string, address list);

Again : Field specifiers inside the format string

19 Standard scanf Statements scanf(format string, address list); scanf(“%d%f”, &age, &weight);

At keyboard type 23 60.75

60.75 Result: weight age 23

Field Specifiers

%code Remember : There is no precision issue here !!! Codes: Size Code Type Example none c char %c h d short int %hd none d int %d l or L d long int %Ld none f float %f none f double %f L f long double %Lf

20 Rules for scanf formats

Addresses of a variable are specified with: &variableName

A variety of rules apply to conversion

Rules for scanf formats

1. Initial whitespace is ignored (except %c) 2. The conversion operation process until: i. End of file is reached ii. Maximum characters are processed iii. A whitespace character is found after a digit iv. An error is detected

21 Rules for scanf format strings

1. A field specifier for each variable

2. Other characters must be exactly matched

3. Cannot end format string with whitespace

Examples of scanf

scanf(“%d%d%d%c”,&a,&b,&c,&d); scanf(“%d%d%d %c”,&a,&b,&c,&d); scanf(“%-8d%-8d%d”,&a,&b,&c); %-8d /* left justify flag */

22 Working with the variables:

We want to operate on variables: e.g add two variables or subtract them. An Expression: rateOfPay*hours – tax

Operators e.g., + plus -minus * multiply / divide % mod

You create expressions out of operators.

23 Some Expressions 35 2 * 3 + 4 23 + b * 6 -salary Use parenthesis to clarify complicated expressions:

(food + drinks)*(1+gst+pst)

Assignment Assignment expressions evaluate to the expression on the right of the assignment operator.

24 Simple Assignment

Contents of Contents of Expression Value of Result of Variable x Variable y Expression Expression

10 5 x=y+2 7 x = 7

10 5 x=x/y 2 x=2

10 5 x=y%4 1 x=1

Operator Precedence

Operators have a built in order of precedence which is over ridden by using parenthesis

1+2*3+4 answer 11 1*2 + 3*5 answer 17 -5*6+2 answer -28

25 Operators precedence (on the same level they are equal)

1. ( ) takes precedence 2. unary minus -7 unary plus +3 3. * Multiply / Divide 4 % Modulus 5. + add - subtract

Examples Operators • Examples of C statements using these : • The following is a program fragment only • int i, j ,k, l, m; • i = j + k; • i = j + k * l / m; • /* Here i gets the value j + (k*l/m) */ • i = j * k + l * m • /* Here i gets the value (j*k) + (l*m) */

26 Examples Operators

• Examples of C statements using these : • There is one division operator for integer and float but it means different things. • 2 / 5 → 0 • 2.0 / 5.0 → 0.4 • % is the modulus (remainder) operation • 5 % 2 → 1 • 2 % 5 → 2

Unary operator + and -

+a – evaluates to the contents of a

-a – evaluates to the negative contents of a

27 Unary Expressions

Contents of Expression Value of Contents of x Before Expression x After

10 ++x 11 11

10 --x 9 9

Unary operator ++ and --

Post-increment and decrement i++ i-- /*First use the value ; then do operation*/

Pre-increment and decrement ++i --i /*First do operation; then use the value */

28 Unary operator ++ and --

Examples for int i , j , k; • i=1; • i++; /* i → 2 */ • j = i++ ; /*j → 2 and then i → 3 • j =++i ; /* i → 4 and then j → 4 • j = i-- /* j → 4 and then i → 3 • Note that i++ and i=i+1 are equivalent • Note that i-- and i=i-1 are equivalent

Binary Compound Operators

Often a variable is changed as follows : • i = i + 5; /* Take the value of i add 5 and put the result back into the variable i*/. Leads to new assignment operators += -= *= /= %= •i = i + 1; same as i += 1; • j = j * k; same as j *= k ;

29 Compound Assignment

Contents of Contents of Expression Value of Result of Variable x Variable y Expression Expression

10 5 x *= y 50 x = 50

10 5 x /= y 2 x = 2

10 5 x %= y 0 x = 0

10 5 x += y 15 x = 15

10 5 x -= y 5 x = 5

A Simple Program #include int main( void ) { double x, y,z ; printf("Pls. input two real numbers:\n") ; scanf("%f%f",&x,&y); z = x + y; printf("x=%6.2f y=%6.2f z= %6.3f \n",x,y,z); return(0); }

30 A Simple Program The OUTPUT >Please input two real numbers: 23.4 45.6 x= 23.40 y= 45.60 z=69.000

/* A simple program to average 3 numbers*/ #include int main(void) { float number1,number2,number3,sum,average; printf("\n Please enter number1. "); scanf("%f",&number1); printf("\n Please enter number2. "); scanf("%f",&number2); printf("\n Please enter number3. "); scanf("%f",&number3); sum = number1+number2+number3; average = sum/3.0; printf("\nthe sum of %f %f and %f is= %f",number1, number2,number3, sum); printf("\nthe average is = %f\n",average); return 0; }

31 Whats the problem with the previous program?

What if you wanted to average 50 numbers?

It would be very clumsy to repeat 50 times.

Also you have to change the program each time you have a different number of numbers.

Program to calculate tax on a bill

First you have to know the facts. Subtotal = food and drink PST = 0.08 GST =0.06 Tax = subtotal (PST+GST) Total = subtotal + tax

32 /* A simple program calculate restaurant bill: input: food and drink amounts output: subtotal, tax, total bill*/ #include #define PST 0.08 #define GST 0.06 int main(void) { float food,drink,sum,total,tax; printf("\n Please enter food total. "); scanf("%f",&food); printf("\n Please enter drink total. "); scanf("%f",&drink); sum = food + drink; tax = sum*(GST +PST); total= sum+tax; printf("\nthe food total is $%6.2f ",food); printf("\nthe drink total is $%6.2f ",drink); printf("\n ====="); printf("\nthe subtotal is $%6.2f ",sum); printf("\nthe tax is $%6.2f ",tax); printf("\n ====="); printf("\nthe total is $%6.2f\n\n ",total); return 0; }

Whats the problem with the previous program?

The rule is not right. If the subtotal is less than $3.00 the no GST

So we need decision possibility

So we need “CONTROL STRUCTURES”

33 Unary Operator sizeof sizeof is an operator. It is NOT a function

Evaluates to number of bytes for that item sizeof(int) sizeof(x) sizeof(3.256)

34