Chapter 5 Exponential and Logarithmic Functions- Practice Test
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Chapter 5 Exponential and logarithmic functions- Practice Test
Question 1 can be simplified to: Question 3 2- 3 can be simplified to: 1253 32 5 A x4y6 A 200 B 3x3y2 B C C 25 D x3y2 D E 3x 4 y 6 E 100
Question 2 Question 4 can be simplified to: - 1 4 x8 y 4( x 3 y 6 ) 3 can be simplified to: A 26 m4 A x3y3 B B xy C C x2y2
D D
4 2 E 2 n E
Maths Quest 11 Mathematical Methods CAS 2nd edition 1 Question 5 Question 7 1 The graph has an asymptote and 32-x� 9 5 - 2 x The equation - 2 is true when y-intercept respectively as: 27 3 x has a value of: - - 15 A y = 1, 16 A 9 B y = -1, 15 B 3 C C –1 D x = - 2, 1 8 D 1 9
- E 2 E x = 2, 15
Question 6 Question 8 The values that x can take to solve the equation The graph has a domain and are: range respectively as:
A 1, 4 A
B 2, 4 B
C 0, 2 C D 0, 1 D E 1, 2 E
Question 9 If log2 (0.125) = x, then x must equal: A –1.25
B –3
C 5–3
D –8
E 25
Maths Quest 11 Mathematical Methods CAS 2nd edition 2 Question 10 Question 13 simplifies to: The value of x that satisfies the equation is: A –3 A B
B C C 1.5 D D E 3 E 64
Question 11 equals: Question 14 The value of x that satisfies the equation A 0.5 is: B 216 A
C log6 (75) B D 3
E 12.5 C 1.5
D
Question 12 E 2 equals:
A log4 (48)
B 1
C 1.5
D 3
E 4
Maths Quest 11 Mathematical Methods CAS 2nd edition 3 Question 15 Question 18 Given the equation , the value of x, The graph of has a y-intercept correct to 3 decimal places, is: and horizontal asymptote of:
A 1.862 A y = 1, y = 3 respectively
B 0.931 B y = 2, y = 2 respectively
C 1.500 C y = 3, y = 0 respectively
D 0.862 D y = 6, y = –1 respectively
E 0.500 E y = 12, y = –2 respectively
Question 16 Question 19 Given the equation , the value of The graph depicted below could have the x, correct to 3 decimal places, is: equation:
A –0.606
B –0.604
C –0.608
D –0.602
E –0.600 A
B Question 17 The graph y = 2x + 3 + 4 cuts the y-axis at: C
A 2 D
B 3 E
C 4
D 10
E 12
Maths Quest 11 Mathematical Methods CAS 2nd edition 4 Question 20 Question 21 The graph with equation could If , then when t = 5, M equals: be: A 1.25
B 5 log10 (2)
C 0.5
D 4 A
E 5 log10 (4)
Question 22 - If M = 5 10 0.2t , when M = 2.5, t equals: B A 1.25
B 5 log10 (2)
C 0.5
D 4
C E 5 log10 (4)
D
E
Maths Quest 11 Mathematical Methods CAS 2nd edition 5 Answers Q1 E Q2 C Q3 D Q4 A Q5 E Q6 E Q7 B Q8 E Q9 B Q10 C Q11 D Q12 C Q13 D Q14 D Q15 B Q16 C Q17 E Q18 C Q19 A Q20 A Q21 C Q22 B
Maths Quest 11 Mathematical Methods CAS 2nd edition 6