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Modulation and Detection

John Staples, LBNL November 2007

Linear Sum of Two Signals

Equation of sinusoidally-varying voltage: V  t  = V 0 cos 0 t  0

A linear sum of two :

V  t  = V 10 cos 1,0 t  1,0  V 20 cos  2,0 t  2,0

No new are generated.

Modulation is a non-linear process that generates additional frequencies.

Amplitude Modulation

This is a non-linear process, where the of the signal is modulated by another signal.

V  t  = V 0 1  m cos m t  m cos c t  c where 0 < m < 1 is the modulation index, um and uc are the carrier and the modulation frequencies. The first term in the parentheses represents the carrier, and the second term the modulation. Using the trig identity

1 cos A cos B =  cos A−Bcos  AB 2 and ignoring the phases

m V t  = V 0 cosc t    cosm−ct cosmc t [ 2 ]

Three frequencies result, the carrier, and two . The carrier amplitude is unchanged, but the amplitude is directly proportional to the modulation index m.

Graphical Representation of an Amplitude Modulated Signal

The envelope of the carrier reproduces The spectrum consists of the carrier the modulating . However, and two sidebands, each separated by u from the carrier . the carrier itself is not changing amplitude. c m V t  = V 0 cosc t    cosm−ct cosmc t [ 2 ]

In the frame of the rotating carrier vector, the

two sidebands rotate at a frequency of +uc

and -uc. Their vector sum (red) represents the envelope of the signal.

What would the envelope look like if the carrier were eliminated? Carrier and one sideband? Can an AM signal be overmodulated? Is the modulation information still there? Modulation

The instantaneous carrier phase changes with the modulating waveform.

V t  = V 0 cosc t    = V 0 cos  c t  m cosm t 

m is the modulation index and um is the modulating frequency. We will use a trig identity to expand this expression:

cos AB = cos A cos B − sin A sin B

V t  = cosc t  cosm cosm t  − sinc t sinm cosm t  V 0

This expression is further expanded with Bessel functions:

∞ k cos z cos = J 0 z   2∑ −1 J 2k  z  cos2 k  k=1 ∞ k sin  z cos = 2 ∑ −1 J 2k1 z  cos2 k1 k=0

Phase Modulation Spectrum

The PM waveform is a double infinite series, with the carrier in quadrature to the nearest sidebands:

∞ V t k = cosc t  J 0 m  2∑ −1 J 2 k m cos2 k m t  V 0 [ k =1 ] ∞ k sin c t  2∑ −1 J 2 k1 m cos2k 1m t  [ k =0 ]

The first few terms:

V t  = J 0 m cosc t  V 0 2 J 1 m sin c t  cos m t 

2 J 2 m cosc t  cos2 m t 

−2 J 3m sin c t  cos3m t 

−2 J 4 m cosc t  cos4 m t 

2 J 5 m sinc t  cos5m t 

2 J 6 m cosc t  cos6 m t   ⋯

Phase Modulation Spectrum

Finally, we use another trig identity: 2 sin A cos B = sin AB  sin  A−B to find 2 cos A cos B = cos AB  cos  A−B V t  = J 0 m cosc t  V 0  J 1m [sinc  m t  sin c − m  t ]

 J 2 m [cosc  2 m t  cosc − 2m  t ]

 J 3 m [sin c  3 m  t  sinc − 3 m  t ]

 J 4 m [cosc  4 m t  cosc − 4 m  t ]

 J 5m [sinc  5m t  sinc − 5m t ]  ⋯ which shows that the sidebands separated by num have an amplitude proportional to Jn(m). Note that each set of sidebands alternates in phase with respect to the carrier Jn(m)

Note that a modulation index m = 2.405 that the carrier disappears. This is the first zero of J0(z). At high modulation index, the phase of the sideband reverses. m Graphical Representation of a Frequency Modulated Signal is a special case of phase modulation, where the phase shift is given by  f max = f modulation

The spectrum consists of sidebands, spaced

by um, with phase dependent on sideband, and amplitude given by the Bessel functions. The envelope is constant, and the frequency varies with the modulation. In the frame of the rotating carrier vector, the sidebands modulate the phase. Here, the carrier amplitude is not constant, but when all sidebands are included, the carrier is constant.

Can an FM/PM signal be over- modulated?

Demodulation of an Amplitude Modulated Signal

The envelope of an Amplitude Modulated signal contains the information.

Ways to recover information from an AM signal:

1. Rectify and filter out carrier

2. Synchronously detect (sample)

Diode rectifies the modulated signal and filters in with the RC integrator.

Envelope of an Amplitude Modulated Signal

The voltage across the RC integrator approximately follows the carrier envelope of the signal.

The non-linearity of the and the time constant of the integrator may result in some of the recovered modulation.

Envelope modulation does not distinguish envelope variations caused by , or envelope variations caused by, for example, a frequency modulated signal passed through a filter.

Synchronous Demodulation of an Amplitude Modulated Signal

Synchronous detection multiplies the signal with a carrier of the same frequency as the carrier of the original signal.

This way, the phase of the reinserted carrier is significant.

m V t  = V cos t    cos  − t cos  t  × cos t 0[ c 2 m c m c ] c

Filter out the components with frequency 2ut:

V t  1 m = D t  = cos−  [ cosm t  cos−m t ] V 0 2 4

Synchronous Demodulation

1 m Dt = cos−  cos t  cos− t 2 4 [ m m ]

The recovered information depends on the phase of the reinserted carrier

1 m =0 Dt  =  cos  t  In phase: 2 2 m m Quadrature: =/2 Dt  = cos −/ 2  −sin t   sin  t  = 0 4 [ m m ]

If the reinserted carrier is in phase, the recovered modulation um is recovered, along with a d.c. level.

If the reinserted carrier is in quadrature phase, no signal is recovered.

Synchronous demodulation is insensitive to noise in quadrature to the reinserted carrier, and also allows two independent signals to be modulated onto one carrier frequency (e.g. color television chroma information).

Similar schemes are used for single and double sideband, suppressed-carrier .

Logical Phase Detector Circuit

Logical diagram: A signal and its inverse are switched to the output at the rate u2+f.

The switching is call the (LO).

If the switching is in phase with the signal, the average output level integrates to 2/p.

If the switching phase is advanced 90 degrees, the output integrates to zero.

What if the LO is at 180 degrees? Practical Phase Detector Circuit

In the ideal circuit, the local oscillator (LO) performs the switching function. The signal (RF) is chopped, resulting in the (IF) output.

LO LO

IF IF In the actual circuit, are substituted for the switch, and are RF either saturated in the RF forward bias, or open in the reverse bias case.

Actual diodes are not perfect switching devices. They have a current conduction threshold which is temperature dependent. Actual mixers are usually operated with a high LO input level, saturating the diodes, and the IF output may have bias offsets due to mismatch of the diode characteristics.