2/20/2015
Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties
Chapter Outline
. 11.1 Energy Changes when Substances Dissolve . 11.2 Vapor Pressure . 11.3 Mixtures of Volatile Substances . 11.4 Colligative Properties of Solutions . 11.5 Osmosis and Osmotic Pressure . 11.6 Using Colligative Properties to Determine Molar Mass
1 2/20/2015
Enthalpy of Solution
. Dissolution of Ionic Solids:
• Enthalpy of solution (∆Hsoln) depends on: » Energies holding solute ions in crystal lattice » Attractive force holding solvent molecules together » Interactions between solute ions and solvent molecules
• ∆Hsoln = ∆Hion-ion + ∆Hdipole-dipole + ∆H ion-dipole • When solvent is water: = » ∆Hsoln ∆Hion-ion + ∆Hhydration
Enthalpy of Solution for NaCl
2 2/20/2015
Calculating Lattice Energies Using the Born-Haber Cycle
Lattice energy (U) is the energy required to completely separate one mole of a solid ionic compound into gaseous ions. It is always endothermic.
2+ - e.g. MgF2(s) Mg (g) + 2F (g)
푄 푥푄 Lattice energy (E) increases as Q 퐸 = 2.31 푥 10−19퐽 ∙ 푛푚 1 2 푒푙 푑 increases and/or as r decreases.
Lattice Q1 is the charge on the cation Compound Energy (U) Q2 is the charge on the anion
d is the distance between the ions MgF2 2957 Q= +2,-1
MgO 3938 Q= +2,-2
LiF 1036 radius F < LiCl 853 radius Cl
3 2/20/2015
Born-Haber Cycles – Calculating Ulattice
Hess’ Law is used to calculate Ulattice The calculation is broken down into a series of steps (cycles)
Steps:
1. sublimation of 1 mole of the metal = ΔHsub
2. if present, breaking bond of a diatomic = ½ ΔHBE
3. ionization of the metal(g) atom = IE1 + IE2 etc
4. electron affinity of the nonmetal atom = EA1 + EA2 etc
5. formation of 1 mole of the salt from ions(g) = ΔHlast = -Ulattice
In General for M(s) + ½ X2(g) MX(s)
M+(g) + X(g) M+(g) + X(g)
EA1 + EA2 etc IE1 + IE2 etc M+(g) + X-(g)
M(g) + X(g)
½ ΔHBE M(g) + ½ X2(g) ΔHlast = -Ulattice
ΔHsub M(s) + ½ X2(g)
ΔHf MX(s)
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Calculating Ulattice
° ΔHf = ΔHsub + ½ ΔHBE + IE + EA + ΔHlast
Rearranging and solving for ΔHlast -
ΔHlast = ΔHf − ΔHsub − ½ ΔHBE − IE − EA
Ulattice = -ΔHlast
Calculating Ulattice for NaCl(s)
Na+(g) + Cl(g) Na+(g) + Cl(g)
EA1 IE1 Na+(g) + Cl-(g)
Na(g) + Cl(g)
½ ΔHBE Na(g) + ½ Cl2(g) ΔHlast = -Ulattice
ΔHsub Na(s) + ½ Cl2(g)
ΔHf NaCl(s)
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Calculating Ulattice for NaCl(s)
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ΔHlast = ΔHf − ΔHsub − ½ ΔHBE − IE1 − EA1
Sample Exercise 11.1 Calculating Lattice Energy
Calcium fluoride occurs in nature as the mineral fluorite, which is the principle source of the world’s supply of fluorine. Use the following data to calculate the lattice energy of CaF2.
ΔHsub,Ca = 168 kJ/mol
BEF2 = 155 kJ/mol
EAF = -328 kJ/mol
IE1,Ca = 590 kJ/mol
IE2,Ca = 1145 kJ/mol
7 2/20/2015
Lattice Energies and Solubility
푄 푥푄 퐸 = 2.31 푥 10−19퐽 ∙ 푛푚 1 2 푒푙 푑
Q1 is the charge on the cation
Q2 is the charge on the anion d is the distance between the ions
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