Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Math 105: Multivariable Calculus Seventeenth Lecture (3/17/10) Steven J Miller Williams College
[email protected] http://www.williams.edu/go/math/sjmiller/ public html/341/ Bronfman Science Center Williams College, March 17, 2010 1 Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Summary for the Day 2 Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Summary for the day Fast Taylor Series. Critical Points and Extrema. Constrained Maxima and Minima. 3 Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Fast Taylor Series 4 Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Formula for Taylor Series Notation: f twice differentiable function ∂f ∂f Gradient: f =( ∂ ,..., ∂ ). ∇ x1 xn Hessian: ∂2f ∂2f ∂x1∂x1 ∂x1∂xn . ⋅⋅⋅. Hf = ⎛ . .. ⎞ . ∂2f ∂2f ⎜ ∂ ∂ ∂ ∂ ⎟ ⎝ xn x1 ⋅⋅⋅ xn xn ⎠ Second Order Taylor Expansion at −→x 0 1 T f (−→x 0) + ( f )(−→x 0) (−→x −→x 0)+ (−→x −→x 0) (Hf )(−→x 0)(−→x −→x 0) ∇ ⋅ − 2 − − T where (−→x −→x 0) is the row vector which is the transpose of −→x −→x 0. − − 5 Daily Summary Fast Taylor Series Critical Points and Extrema Lagrange Multipliers Example 3 Let f (x, y)= sin(x + y) + (x + 1) y and (x0, y0) = (0, 0). Then ( f )(x, y) = cos(x + y)+ 3(x + 1)2y, cos(x + y) + (x + 1)3 ∇ and sin(x + y)+ 6(x + 1)2y sin(x + y)+ 3(x + 1)2 (Hf )(x, y) = − − , sin(x + y)+ 3(x + 1)2 sin(x + y) − − so 0 3 f (0, 0)= 0, ( f )(0, 0) = (1, 2), (Hf )(0, 0)= ∇ 3 0 which implies the second order Taylor expansion is 1 0 3 x 0 + (1, 2) (x, y)+ (x, y) ⋅ 2 3 0 y 1 3y = x + 2y + (x, y) = x + 2y + 3xy.