Electric Potential

Total Page:16

File Type:pdf, Size:1020Kb

Electric Potential Electric Potential • Electric Potential energy: b U F dl elec elec a • Electric Potential: b V E dl a Field is the (negative of) the Gradient of Potential dU dV F E x dx x dx dU dV F UF E VE y dy y dy dU dV F E z dz z dz In what direction can you move relative to an electric field so that the electric potential does not change? 1)parallel to the electric field 2)perpendicular to the electric field 3)Some other direction. 4)The answer depends on the symmetry of the situation. Electric field of single point charge kq E = rˆ r2 Electric potential of single point charge b V E dl a kq Er ˆ r 2 b kq V rˆ dl 2 a r Electric potential of single point charge b V E dl a kq Er ˆ r 2 b kq V rˆ dl 2 a r kq kq VVV ba rrba kq V const. r 0 by convention Potential for Multiple Charges EEEE1 2 3 b V E dl a b b b E dl E dl E dl 1 2 3 a a a VVVV 1 2 3 Charges Q and q (Q ≠ q), separated by a distance d, produce a potential VP = 0 at point P. This means that 1) no force is acting on a test charge placed at point P. 2) Q and q must have the same sign. 3) the electric field must be zero at point P. 4) the net work in bringing Q to distance d from q is zero. 5) the net work needed to bring a charge from infinity to point P is zero. Finding the Electric Field due to Continuous Charge Distributions • When possible, use symmetry to eliminate one or more component of the electric field. • Define a (linear, areal or volume) density to relate small spatial regions to small bits of charge. • Calculate the electric field due to each small kdq dE charge bit: r 2 . • Sum up (integrate) the electric fields to find the total field. Finding the Potential due to Continuous Charge Distributions • When possible, use symmetry to eliminate one or more component of the electric field. • Define a (linear, areal or volume) density to relate small spatial regions to small bits of charge. • Calculate the potential due to each small k dq dV charge bit: r . • Sum up (integrate) the potentials to find the total potential. Spherical shell of charge kQ Erˆ rR out r 2 Ein 0 rR kQ V r R out r kQ Vin a constant R rR .
Recommended publications
  • The Lorentz Force
    CLASSICAL CONCEPT REVIEW 14 The Lorentz Force We can find empirically that a particle with mass m and electric charge q in an elec- tric field E experiences a force FE given by FE = q E LF-1 It is apparent from Equation LF-1 that, if q is a positive charge (e.g., a proton), FE is parallel to, that is, in the direction of E and if q is a negative charge (e.g., an electron), FE is antiparallel to, that is, opposite to the direction of E (see Figure LF-1). A posi- tive charge moving parallel to E or a negative charge moving antiparallel to E is, in the absence of other forces of significance, accelerated according to Newton’s second law: q F q E m a a E LF-2 E = = 1 = m Equation LF-2 is, of course, not relativistically correct. The relativistically correct force is given by d g mu u2 -3 2 du u2 -3 2 FE = q E = = m 1 - = m 1 - a LF-3 dt c2 > dt c2 > 1 2 a b a b 3 Classically, for example, suppose a proton initially moving at v0 = 10 m s enters a region of uniform electric field of magnitude E = 500 V m antiparallel to the direction of E (see Figure LF-2a). How far does it travel before coming (instanta> - neously) to rest? From Equation LF-2 the acceleration slowing the proton> is q 1.60 * 10-19 C 500 V m a = - E = - = -4.79 * 1010 m s2 m 1.67 * 10-27 kg 1 2 1 > 2 E > The distance Dx traveled by the proton until it comes to rest with vf 0 is given by FE • –q +q • FE 2 2 3 2 vf - v0 0 - 10 m s Dx = = 2a 2 4.79 1010 m s2 - 1* > 2 1 > 2 Dx 1.04 10-5 m 1.04 10-3 cm Ϸ 0.01 mm = * = * LF-1 A positively charged particle in an electric field experiences a If the same proton is injected into the field perpendicular to E (or at some angle force in the direction of the field.
    [Show full text]
  • Capacitance and Dielectrics Capacitance
    Capacitance and Dielectrics Capacitance General Definition: C === q /V Special case for parallel plates: εεε A C === 0 d Potential Energy • I must do work to charge up a capacitor. • This energy is stored in the form of electric potential energy. Q2 • We showed that this is U === 2C • Then we saw that this energy is stored in the electric field, with a volume energy density 1 2 u === 2 εεε0 E Potential difference and Electric field Since potential difference is work per unit charge, b ∆∆∆V === Edx ∫∫∫a For the parallel-plate capacitor E is uniform, so V === Ed Also for parallel-plate case Gauss’s Law gives Q Q εεε0 A E === σσσ /εεε0 === === Vd so C === === εεε0 A V d Spherical example A spherical capacitor has inner radius a = 3mm, outer radius b = 6mm. The charge on the inner sphere is q = 2 C. What is the potential difference? kq From Gauss’s Law or the Shell E === Theorem, the field inside is r 2 From definition of b kq 1 1 V === dr === kq −−− potential difference 2 ∫∫∫a r a b 1 1 1 1 === 9 ×××109 ××× 2 ×××10−−−9 −−− === 18 ×××103 −−− === 3 ×××103 V −−−3 −−−3 3 ×××10 6 ×××10 3 6 What is the capacitance? C === Q /V === 2( C) /(3000V ) === 7.6 ×××10−−−4 F A capacitor has capacitance C = 6 µF and charge Q = 2 nC. If the charge is Q.25-1 increased to 4 nC what will be the new capacitance? (1) 3 µF (2) 6 µF (3) 12 µF (4) 24 µF Q.
    [Show full text]
  • Multidisciplinary Design Project Engineering Dictionary Version 0.0.2
    Multidisciplinary Design Project Engineering Dictionary Version 0.0.2 February 15, 2006 . DRAFT Cambridge-MIT Institute Multidisciplinary Design Project This Dictionary/Glossary of Engineering terms has been compiled to compliment the work developed as part of the Multi-disciplinary Design Project (MDP), which is a programme to develop teaching material and kits to aid the running of mechtronics projects in Universities and Schools. The project is being carried out with support from the Cambridge-MIT Institute undergraduate teaching programe. For more information about the project please visit the MDP website at http://www-mdp.eng.cam.ac.uk or contact Dr. Peter Long Prof. Alex Slocum Cambridge University Engineering Department Massachusetts Institute of Technology Trumpington Street, 77 Massachusetts Ave. Cambridge. Cambridge MA 02139-4307 CB2 1PZ. USA e-mail: [email protected] e-mail: [email protected] tel: +44 (0) 1223 332779 tel: +1 617 253 0012 For information about the CMI initiative please see Cambridge-MIT Institute website :- http://www.cambridge-mit.org CMI CMI, University of Cambridge Massachusetts Institute of Technology 10 Miller’s Yard, 77 Massachusetts Ave. Mill Lane, Cambridge MA 02139-4307 Cambridge. CB2 1RQ. USA tel: +44 (0) 1223 327207 tel. +1 617 253 7732 fax: +44 (0) 1223 765891 fax. +1 617 258 8539 . DRAFT 2 CMI-MDP Programme 1 Introduction This dictionary/glossary has not been developed as a definative work but as a useful reference book for engi- neering students to search when looking for the meaning of a word/phrase. It has been compiled from a number of existing glossaries together with a number of local additions.
    [Show full text]
  • Introduction to Electrical and Computer Engineering International
    Introduction to Electrical and Computer Engineering Basic Circuits and Simulation Electrical & Computer Engineering Basic Circuits and Simulation (1 of 22) International System of Units (SI) • Length: meter (m) • SI Prefixes (power of 10) • Mass: kilogram (kg) – 1012 Tera (T) • Time: second (s) – 109 Giga (G) – 106 Mega (M) • Current: Ampere (A) – 103 kilo (k) • Voltage: Volt (V) – 10-3 milli (m) • Temperature: Degrees – 10-6 micro (µ) Kelvin (ºK) – 10-9 nano (n) – 10-12 pico (p) Electrical & Computer Engineering Basic Circuits and Simulation (2 of 22) 1 SI Examples • A few examples: • 1 Gbit = 109 bits, or 103106 bits, or one thousand million bits – 10-5 s = 0.00001 s; use closest SI prefix • 1×10-5 s = 10 × 10-6 s or 10 μs or • 1×10-5 s = 0.01 × 10-3 s or 0.01 ms Electrical & Computer Engineering Basic Circuits and Simulation (3 of 22) Typical Ranges Voltage (V) Current (A) • 10-8 Antenna of radio • 10-12 Nerve cell in brain receiver (10 nV) • 10-7 Integrated circuit • 10-3 EKG – voltage memory cell (0.1 µA) produced by heart • 10×10-3 Threshold of • 1.5 Flashlight battery sensation in humans • 12 Car battery • 100×10-3 Fatal to humans • 110 House wiring (US) • 1-2 Typical Household • 220 House wiring (Europe) appliance • 107 Lightning bolt (10 MV) • 103 Large industrial appliance • 104 Lightning bolt Electrical & Computer Engineering Basic Circuits and Simulation (4 of 22) 2 Electrical Quantities • Electric Charge (positive or negative) – (Coulombs, C) - q – Electron: 1.602 x 10 • Current (Ampere or Amp, A) – i or I – Rate of charge flow, – 1 1 Electrical & Computer Engineering Basic Circuits and Simulation (5 of 22) Electrical Quantities (continued) • Voltage (Volts, V) – w=energy required to move a given charge between two points (Joule, J) – – 1 1 1 Joule is the work done by a constant 1 N force applied through a 1 m distance.
    [Show full text]
  • Chapter 5 Capacitance and Dielectrics
    Chapter 5 Capacitance and Dielectrics 5.1 Introduction...........................................................................................................5-3 5.2 Calculation of Capacitance ...................................................................................5-4 Example 5.1: Parallel-Plate Capacitor ....................................................................5-4 Interactive Simulation 5.1: Parallel-Plate Capacitor ...........................................5-6 Example 5.2: Cylindrical Capacitor........................................................................5-6 Example 5.3: Spherical Capacitor...........................................................................5-8 5.3 Capacitors in Electric Circuits ..............................................................................5-9 5.3.1 Parallel Connection......................................................................................5-10 5.3.2 Series Connection ........................................................................................5-11 Example 5.4: Equivalent Capacitance ..................................................................5-12 5.4 Storing Energy in a Capacitor.............................................................................5-13 5.4.1 Energy Density of the Electric Field............................................................5-14 Interactive Simulation 5.2: Charge Placed between Capacitor Plates..............5-14 Example 5.5: Electric Energy Density of Dry Air................................................5-15
    [Show full text]
  • Physics 2102 Lecture 2
    Physics 2102 Jonathan Dowling PPhhyyssicicss 22110022 LLeeccttuurree 22 Charles-Augustin de Coulomb EElleeccttrriicc FFiieellddss (1736-1806) January 17, 07 Version: 1/17/07 WWhhaatt aarree wwee ggooiinngg ttoo lleeaarrnn?? AA rrooaadd mmaapp • Electric charge Electric force on other electric charges Electric field, and electric potential • Moving electric charges : current • Electronic circuit components: batteries, resistors, capacitors • Electric currents Magnetic field Magnetic force on moving charges • Time-varying magnetic field Electric Field • More circuit components: inductors. • Electromagnetic waves light waves • Geometrical Optics (light rays). • Physical optics (light waves) CoulombCoulomb’’ss lawlaw +q1 F12 F21 !q2 r12 For charges in a k | q || q | VACUUM | F | 1 2 12 = 2 2 N m r k = 8.99 !109 12 C 2 Often, we write k as: 2 1 !12 C k = with #0 = 8.85"10 2 4$#0 N m EEleleccttrricic FFieieldldss • Electric field E at some point in space is defined as the force experienced by an imaginary point charge of +1 C, divided by Electric field of a point charge 1 C. • Note that E is a VECTOR. +1 C • Since E is the force per unit q charge, it is measured in units of E N/C. • We measure the electric field R using very small “test charges”, and dividing the measured force k | q | by the magnitude of the charge. | E |= R2 SSuuppeerrppoossititioionn • Question: How do we figure out the field due to several point charges? • Answer: consider one charge at a time, calculate the field (a vector!) produced by each charge, and then add all the vectors! (“superposition”) • Useful to look out for SYMMETRY to simplify calculations! Example Total electric field +q -2q • 4 charges are placed at the corners of a square as shown.
    [Show full text]
  • Frequency Dependence of the Permittivity
    Frequency dependence of the permittivity February 7, 2016 In materials, the dielectric “constant” and permeability are actually frequency dependent. This does not affect our results for single frequency modes, but when we have a superposition of frequencies it leads to dispersion. We begin with a simple model for this behavior. The variation of the permeability is often quite weak, and we may take µ = µ0. 1 Frequency dependence of the permittivity 1.1 Permittivity produced by a static field The electrostatic treatment of the dielectric constant begins with the electric dipole moment produced by 2 an electron in a static electric field E. The electron experiences a linear restoring force, F = −m!0x, 2 eE = m!0x where !0 characterizes the strength of the atom’s restoring potential. The resulting displacement of charge, eE x = 2 , produces a molecular polarization m!0 pmol = ex eE = 2 m!0 Then, if there are N molecules per unit volume with Z electrons per molecule, the dipole moment per unit volume is P = NZpmol ≡ 0χeE so that NZe2 0χe = 2 m!0 Next, using D = 0E + P E = 0E + 0χeE the relative dielectric constant is = = 1 + χe 0 NZe2 = 1 + 2 m!00 This result changes when there is time dependence to the electric field, with the dielectric constant showing frequency dependence. 1 1.2 Permittivity in the presence of an oscillating electric field Suppose the material is sufficiently diffuse that the applied electric field is about equal to the electric field at each atom, and that the response of the atomic electrons may be modeled as harmonic.
    [Show full text]
  • Magnetic Fields and Forces
    Magnetic Fields and Forces (1) Magnetic Fields are produced by moving charges. (2) Magnetic Fields exert forces on moving charges. (3) Stationary Charges do not produce magnetic fields. (4) Stationary Charges are not affected by stationary magnetic fields. Permanent Magnets There are naturally occurring magnetic substances. These were long used for navigation. As a result, we speak of “north” and “south” magnetic poles, instead of positive and negative magnetic charges. Permanent magnets can also be made by people from raw materials. These magnetic poles also respect an “opposites attract” rule: N S N S attraction N S S N repulsion Earth: North and South Revisited The ancients defined the “north” end of a permanent magnet as the end that is attracted to the “north” pole of the earth. points north S N S Therefore the north geographic pole of earth is a south magnetic pole. N Magnetic Field of a Bar Magnet This is a magnetic dipole field, very similar to the electric dipole field of two opposite electric charges. Note that magnetic field lines are all closed loops, unlike electric field lines that must start and stop on a charge. Important: There is no magnetic “monopole.” N Such a thing has never been observed. North and South magnetic poles always come in pairs of equal strength. Properties of the magnetic force on a charge moving in a B field 1. The magnetic force is proportional to the charge q and speed v of the particle 2. The magnitude and direction of the magnetic force depend on the velocity of the particle and on the magnitude and direction of the magnetic field.
    [Show full text]
  • The Dipole Moment.Doc 1/6
    10/26/2004 The Dipole Moment.doc 1/6 The Dipole Moment Note that the dipole solutions: Qd cosθ V ()r = 2 4πε0 r and Qd 1 =+⎡ θθˆˆ⎤ E ()r2cossin3 ⎣ aar θ ⎦ 4πε0 r provide the fields produced by an electric dipole that is: 1. Centered at the origin. 2. Aligned with the z-axis. Q: Well isn’t that just grand. I suppose these equations are thus completely useless if the dipole is not centered at the origin and/or is not aligned with the z-axis !*!@! A: That is indeed correct! The expressions above are only valid for a dipole centered at the origin and aligned with the z- axis. Jim Stiles The Univ. of Kansas Dept. of EECS 10/26/2004 The Dipole Moment.doc 2/6 To determine the fields produced by a more general case (i.e., arbitrary location and alignment), we first need to define a new quantity p, called the dipole moment: pd= Q Note the dipole moment is a vector quantity, as the d is a vector quantity. Q: But what the heck is vector d ?? A: Vector d is a directed distance that extends from the location of the negative charge, to the location of the positive charge. This directed distance vector d thus describes the distance between the dipole charges (vector magnitude), as well as the orientation of the charges (vector direction). Therefore dd= aˆ , where: Q d ddistance= d between charges d and − Q ˆ ad = the orientation of the dipole Jim Stiles The Univ. of Kansas Dept. of EECS 10/26/2004 The Dipole Moment.doc 3/6 Note if the dipole is aligned with the z-axis, we find that d = daˆz .
    [Show full text]
  • Electromagnetic, Electrostatic and Magnetostatic Fields Electromagnetic Fields Are Characterized by Coupled, Dynamic (Time- Vary
    Electromagnetic, Electrostatic and Magnetostatic Fields Electromagnetic fields are characterized by coupled, dynamic (time- varying) electric and magnetic fields and are governed by the complete set of Maxwell’s equations (four coupled equations). According to Maxwell’s equations, a time-varying electric field cannot exist without the a simultaneous magnetic field, and vice versa. Under static conditions, the time-derivatives in Maxwell’s equations go to zero, and the set of four coupled equations reduce to two uncoupled pairs of equations. One pair of equations governs electrostatic fields while the other set governs magnetostatic fields. This decoupling of Maxwell’s equations illustrates that static electric fields can exist in the absence of magnetic fields and vice versa. Stationary charges produce electrostatic fields while magnetostatic fields are produced by steady (DC) currents or permanent magnets. Maxwell’s Equations (electromagnetic fields) b ` Maxwell’s Equations Maxwell’s Equations (electrostatic fields) (magnetostatic fields) Electrostatic Fields Electrostatic fields are static (time-invariant) electric fields produced by static (stationary) charges. The mathematical definition of the electrostatic field is derived from Coulomb’s law which defines the vector force between two point charges. Coulomb’s Law Given point charges [q1, q2 (units=C)] in air located by vectors R1 and R2, respectively, the vector force acting on charge q2 due to q1 [F12 (units=N)] is defined by Coulomb’s law as where is a unit vector pointing from q1 to q2 and åo is the free-space !12 permittivity [åo = 8.854×10 F/m]. The permittivity of air is approximately equal to that of free space (vacuum).
    [Show full text]
  • (Rees Chapters 2 and 3) Review of E and B the Electric Field E Is a Vector
    ELECTROMAGNETISM SUMMARY (Rees Chapters 2 and 3) Review of E and B The electric field E is a vector function. E q q o If we place a second test charged qo in the electric field of the charge q, the two spheres will repel each other. The strength of the radial force Fr is proportional to the product of the charges and inversely proportional to the distance between them squared. 1 qoq Fr = Coulomb's Law 4πεo r2 -12 where εo is the electric permittivity (8.85 x 10 F/m) . The radial component of the electric field is the force divided by the strength of the test charge qo. 1 q force ML Er = - 4πεo r2 charge T2Q The magnetic field B is also a vector function. Magnetic fields are generated by charges in motion. For example, a current traveling through a wire will produce a magnetic field. A charge moving through a uniform magnetic field will experience a force that is proportional to the component of velocity perpendicular to the magnetic field. The direction of the force is perpendicular to both v and B. X X X X X X X X XB X X X X X X X X X qo X X X vX X X X X X X X X X X F X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X F = qov ⊗ B The particle will move along a curved path that balances the inward-directed force F⊥ and the € outward-directed centrifugal force which, of course, depends on the mass of the particle.
    [Show full text]
  • The Electric Field
    Phys102 Lecture 2 - 1 Phys102 Lecture 2 The Electric Field Key Points • Coulomb’s Law • The electric field (E is a vector!) References Textbook: 16-1,2,3,4,5,6,7,8,9,+. The Electric Field The electric field is defined as the force on a small charge, divided by the magnitude of the charge: The Electric Field An electric field surrounds every charge. The Electric Field For a point charge: The magnitude of the electric field due to charge Q : 1 Q E 2 4 0 r The Electric Field Force on a point charge in an electric field: Example: Electric field above two point charges. Calculate the total electric field (a) at point A and (b) at point B in the figure due to both charges, Q1 and Q2. Example: Electric field above two point charges. Calculate the total electric field (a) at point A and (b) at point B in the figure due to both charges, Q1 and Q2. Problem solving in electrostatics: electric forces and electric fields 1. Draw a diagram; show all charges, with signs, and electric fields and forces with directions. 2. Calculate forces using Coulomb’s law. 3. Add forces vectorially to get result. 4. Check your answer! Field Lines The electric field can be represented by field lines. These lines start on a positive charge and end on a negative charge. Field Lines The number of field lines starting (ending) on a positive (negative) charge is proportional to the magnitude of the charge. The electric field is stronger where the field lines are closer together.
    [Show full text]